8/12/2019 Solucionario de Rm Segundo Examen Ciclo c - 2014

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ffitifl@ipi,EffiJ 2.5. /5- 37. x\i:--,r(-' ->l3to2239\-, \-, \_-, \_-,2 7 /2/7

\-, \-, \-.,5ss

6" Cn t,no^ la let,a@5 /2 /;2,

P\

^)-3, * n5.

JA\A)z---.97_x

+ /= 9B)'/=

+61+l=LO

%4*

\J, \,)(/ rz x3 N',L, , \--, \./,sorPU-vt^/

6"Jrf'rus: G?o Ft, //./,,#*r#galf:,\l\-r@*,68/oifrt \-; \-.t \-,t'.2 2 2\t\4Z +JO*13+....\..,, \..-, \-,ffis sS= 4C? +scf

S= 4(zs) +sW)S= roog*

+= 7'+aQ+

3/@fA,3Wlados l

C-.r I t,a =

t)'A {L-L 5

q=?'tLnfc .-.=>

oS ladosiffirrn, #n;:W*Elffi#WF* ,: :;,*tq;:F,g;i";.W .lti:.,,r,,T;@fu,w'turfuW)^X

,%affi'"'T:"'f;;Wr.+'' l I

8/12/2019 Solucionario de Rm Segundo Examen Ciclo c - 2014

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2+6+,8 +s4v \_, \_,r3 13 rSs=_

-{b S=l02dCR JoB ro8\_r=--r-- k

l-t 2.35 / t /trooL, enarcn/ro = k-..-4f 20

I=4%

{ts

I x - /s (c)= /11 so*inl8" f/ = /2h - ill so nrq = tal Ear

4x = /e(ta)4amtnio srJ"(@) @\

S = Z{s'o:til5-JS: 5t1 I-/3; JoB *se+t2+4+.. .,YY;r33

rbt

{9

%il9o0s() :/5nn ,d,A)< e4*

@ saa y'el nlneroYd-X+-X --28,ry- -29 -',E ,X=8Saa nX, /a ecta/

tnp/earlo /, y'i*ub de frr*fo de a/cdn.eJ: ..'- 2X:4X*1O2X= /O-< X:* e@M@51/2fi /g _x

tt,r' )2x-zo:L|?o-x)2x-20 = /fo.Dzx4x = 2oo - X= 50*4ou/s z)L_u='- '='---4/floary- -- {u = Os-er_Lahr

'1 Y-/o,Y+lO -(rf 8)

Gn*unc[o pnt}onor MDa zlc{.ag..

Cont d.no {.,ngufrs ADe t [eka: ?rb,ctL *eDe z fetyas: b ,bc,?d +3De 3lafres] aa,cde +Qfh- 5 la.lrr ., abe..d .+ J

ab,b", &c -+h