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1 PERATURAN PEMARKAHAN PEPERIKSAAN PERCUBAAN SPM 2019 MODUL PINTAS MATEMATIK TAMBAHAN KERTAS 2 NO SOLUTIONS MARKS 1 (a) 0 9 ) 9 ( dy y y y 9 2 2 81 2 81 0 2 81 K1 K1 K1 N1 4 6 (b) (7 × 8) − 21 1 3 34 2 3 K1 N1 2 2 (a) 2 3(1) − 4(1) ∙ 2 1 +2 1 −2 0 K1 N1 2 (b) log = 1 2 (log 24 − log 0.375 − log 729) log = 1 2 (log 24 (0.375)(729) ) log = log ( 64 729 ) 1 2 log = log 8 27 = 8 27 log =3 K1 K1 K1 K1 N1 N1 6 10 SET 1 Visit https://boardedu.org for more support

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  • 1

    PERATURAN PEMARKAHAN PEPERIKSAAN PERCUBAAN SPM 2019

    MODUL PINTAS

    MATEMATIK TAMBAHAN KERTAS 2

    NO SOLUTIONS MARKS

    1 (a)

    0

    9

    )9( dyy

    y

    y

    92

    2

    81

    2

    810

    2

    81

    K1

    K1

    K1

    N1

    4

    6

    (b) (7 × 8) − 211

    3

    342

    3

    K1

    N1

    2

    2 (a) 23(1) − 4(1) ∙ 21 + 21 − 2

    0

    K1

    N1

    2

    (b) log𝑎 𝑁 =1

    2(log𝑎 24 − log𝑎 0.375 − log𝑎 729)

    log𝑎 𝑁 =1

    2(log𝑎

    24

    (0.375)(729))

    log𝑎 𝑁 = log𝑎(64

    729)1

    2

    log𝑎 𝑁 = log𝑎8

    27

    𝑁 =8

    27

    log𝑎 𝑁 = 3

    K1

    K1

    K1

    K1

    N1

    N1

    6

    10

    SET 1

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  • 2

    3 (a) (i) 3a

    (ii) -a + b

    (iii) PA = 1

    3 PQ

    - 1

    3 +

    1

    3 𝐛 (accept answer without working)

    N1

    N1

    K1

    N1

    4

    6

    (b) 𝑂𝐵 ⃗⃗⃗⃗ ⃗⃗ ⃗⃗ = 9

    5 (𝑂𝑃⃗⃗⃗⃗ ⃗ + 𝑃𝐴⃗⃗⃗⃗ ⃗)

    6

    5 a +

    3

    5𝐛

    K1

    NI

    2

    4 (30.2 𝑥 20.4) − 𝑥𝑦 = 500

    2𝑥 + 2𝑦 = 43.2

    𝑥 = 21.6 − 𝑦

    (21.6 − 𝑦)(𝑦) = 116.08

    𝑦2 − 21.6𝑦 + 116.08 = 0

    𝑦 =−(−21.6)±√(−21.6)2−4(1)(116.08)

    2(1)

    05.10,55.11 xy or 55.11,05.10 xy

    Perimeter of the ungrazed field =101.2

    P1

    P1

    K1

    K1

    K1

    N1

    N1

    7

    7

    5 (a) (62 × 18) + (88 × 23) + (16 × 28) + (13 × 33) +(11 × 38) + (10 × 43)

    (62 × 18) + (88 × 23) + (16 × 28) + (13 × 33) + (11 × 38) + (10 × 43)

    200

    24. 33

    (62 × 182) + (88 × 232) + (16 × 282) + (13 × 33) + (11 × 382) + (10 × 432)

    √(62 × 182) + (88 × 232) + (16 × 282) + (13 × 332) + (11 × 382) + (10 × 432)

    200− (24.33 )2

    6.828

    K1

    K1

    N1

    K1

    K1

    N1

    6

    (b) Mean will reduce 5 and standard deviation unchanged N1 1 7

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  • 3

    6 (a)

    t

    tt

    ttt

    sin2

    sincos

    )sin(cossin2

    K1

    K1

    N1

    3

    6

    (b)

    P1

    P1

    P1

    3

    7 (a)

    275.52 104.48

    8cos COP or or

    1.823

    K1

    N1

    2

    (b) 10

    37.76kos

    or

    228 2

    37.7612.65 3.142

    180

    8.338PB or

    2.65BC or PD = 12.65

    8.338 2.65 7.746

    18.73

    K1

    K1

    K1

    K1

    N1

    5

    (c) 2

    1(12.65) 0.6591

    2 or

    1(10) 7.746

    2

    21

    (12.65) 0.65912

    - 1

    (10) 7.7462

    14.01

    K1

    K1

    N1

    3

    10

    Use identity:

    sin 2t = 2 sin t cos t

    or cos 2t = 1- 2 sin2t

    Shape: sin t or cos t

    Amplitude=2

    Cycle = 1 20 t

    v

    2

    -2

    t

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  • 4

    8

    ( 2) 3( )

    7 3 2

    ka

    k = 4

    K1

    N1

    2

    10

    7 3 4 ( 2)( ) ,

    2 2b

    51

    18

    m

    )1(4

    78 xy

    4

    39

    4

    7 xy

    K1

    K1

    K1

    N1

    4

    (c) )1)(2()3(4)7(8)8(3)2(7)8(1

    2

    1

    or

    )5(3)2(6)4(1)1(2)3(4)6(52

    1

    26 or 6.5

    5.6

    26

    4 : 1

    K1

    K1

    K1

    N1

    4

    9 a) p =

    2

    5 or q =

    3

    5

    (i) 1- P (X=0) – P (X=1) – P (X=2) or

    1- 0.0467 – 0.1866 – 0.31104

    0.4557

    (ii) 1308

    𝜎 = 28.01

    b)(i) 13−10

    4 @ 0.75 𝑠𝑒𝑒𝑛

    0.7734

    (ii) P ( 𝑋 > 136 ) or P ( X < 9.6)

    0.1841 x 145 or 0.4602 x 145

    13: 33

    P1

    K1

    N1

    N1

    N1

    K1

    N1

    K1

    K1

    N1

    5

    5

    10

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  • 5

    10 (a) All values of x and log10y correct

    x 1 2 3 4 5 6

    log 10 y 0.26 0.43 0.61 0.78 0.96 1.05 (b) refer graph

    N1

    K1

    K1N1

    4

    (c) (i) y incorrect =11.22 and yactual valu e= 13.49

    (ii) pkxy logloglog 1010

    175.0log k (0.17 - 0.175)

    50.1k (1.48 - 1.50)

    85.0log p

    p = 7.079

    N1

    P1

    K1

    N1

    K1

    N1

    6

    10

    11 (a)A = πr2 + 2πrh + 2 πr2

    A = 3πr2 + 2πrh

    V = πr2h + 2

    3πr3

    K1

    N1

    N1

    3

    10

    (b) 3πr2 + 2πrh = 20π

    220 3

    2

    rh

    r

    V = πr2220 3

    2

    r

    r

    + 2

    3πr3

    V = 10πr - 5

    6 πr3

    K1

    K1

    K1

    N1

    4

    (c)

    2

    2

    510

    2

    510 (1.5) 0.4

    2

    1.75

    dvr

    dr

    K1

    K1

    N1

    3

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  • 6

    12 (a)(i) 2t – 6 = 0

    v = (3)2 – 6(3) + 8

    v = -1

    (ii) (t – 2)(t – 4) = 0

    𝑡3

    3− 3𝑡2 + 8𝑡

    (43

    3− 3(4)2 + 8(4)) - (

    23

    3− 3(2)2 + 8(2))

    4

    3

    K1

    K1

    NI

    K1

    K1

    K1

    N1

    7

    10

    (b)

    N1

    N1

    N1

    3

    13

    (a) 𝑥

    3.50x100 = 125 or

    6

    𝑦x100 = 110 or

    5.50

    4.00x100 = 𝑧

    𝑥 = 4.38

    𝑦 = 5.45

    𝑧 = 137.5

    K1

    N1

    N1

    N1

    4

    10

    (b) (120x5) + (125x3) + (110x4) + (137.5x1)

    (120x5) + (125x3) + (110x4) + (137.5x1)

    13

    119.42

    K1

    K1

    N1

    3

    (c) 119.42x115

    100

    𝑝

    40x100 = 137.33

    RM 54.93

    K1

    K1

    N1

    3

    Shape graph ∪

    Graph intersect x-axis at 2 and 4

    3 < 𝑡 ≤ 7

    v

    t

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  • 7

    14

    (a) (i) 4.72 = 6.52 + 52 – 2(6.5)(5) cos A

    45.99

    (ii) 02.88sin

    5

    99.45sin

    BD

    3.598

    K1

    N1

    K1

    N1

    4

    10

    P1

    K1

    N1

    N1

    4

    1( ) (6.5)(4.7)(sin 38.09)

    2c

    9.423

    K1

    N1

    2

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  • 8

    15 (a) 𝑥 ≥ 50

    𝑦 ≥ 180

    24 𝑥 + 8 𝑦 ≤ 8000 or 3 𝑥 + 𝑦 ≤ 1000

    𝑥 + 𝑦 ≤ 800

    N1

    N1

    N1

    N1

    4

    10

    (b) Refer to graph paper

    One *straight line drawn correctly

    All * straight line drawn correctly

    Correct region

    K1

    K1

    N1

    3

    (c) (i) 180 ≤ x ≤ 390

    (ii) Pmax = 30 x + 10 y

    30 ( 100 ) + 10 (700 )

    1000

    N1

    K1

    N1

    3

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  • 9

    QUESTION 10

    Plot log10 y against x with correct axes,

    uniform scales and at least one point K1

    6 points plotted correctly K1

    Line of best fit N1

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  • 10

    QUESTION 15

    1000

    900

    0 100 200 300 400 500 600 700

    100

    200

    300

    400

    500

    600

    700

    800

    800

    R

    100 200 300 400 500 600 700

    100

    200

    300

    400

    500

    600

    700

    800

    800

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