Download - Mg 15 Latihan Soal Rangka Batang
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SOAL
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SOAL 1 MA = 0
10 . 3 – 4 . 3 - RBv.4 = 0
30 – 12 – 4 RBv = 0 RBv = 18/4 RBV = 4,5 Ton
MB = 0
RAv. 4 – 10 . 1 – 4 . 3 = 04 RAv – 10 - 12 = 0 RAv = 22/4 RAv = 5,5 Ton
MS = 0 … (bagan A-S!
- RA". 5 – RAv . 2= 0
- 5 RA" – 5,5 . 2 = 0 RA" = 11/5 RA" = 2,2 Ton
MS = 0 … (bagan B-S!
10 . 1 # 4 . 2 – RBv . 2 – RB" . 5 = 0
10 # 8 – 4,5 . 2 – 5 RB" = 0 RB" = $/5 RB" = 1,8 Ton
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%ag&a' B%RAv = 5,5 Ton
RA" = 2,2 Ton
RBv = 4,5 Ton
RB" = 1,8 Ton
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%ag&a' S%S% ) **+
A = RA" = -2,2 Ton
1 = -2,2 Ton
2 = RAv = 5,5 Ton
S = 5,5 Ton
1 = 5,5 Ton
2 = 5,5 – 10 = - 4,5 Ton
2 = 5,5 – 10 = - 4,5 Ton
%1 = - 4,5 Ton
%2 = 2,2 Ton
1 = 2,2, Ton
2 = 2,2 – 4 = - 1,8 Ton
B = -1,8 # RB" = 0
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%ag&a' % % a)a ba*ang
A- = RAv = 5,5 Ton (*+an!
-% = RA" = 2,2 Ton (*+an!
%-B = RBv = 4,5 Ton (*+an!
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%ag&a' BM%
Mo'n a)a **+
A = B = S = 0
= - RA". 5 = - 2,2 . 5 = -11 T'
% = - RA". 5 # RAv . 3 = -2,2 . 5 # 5,5 . 3 = 5,5 T'
= - (4 . 2 – 1,8 . 5! = -8 # $ = 1 T'
= - (- 1,8 . 3 ! = 5,4 T'
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SOAL 2 MA = 0
(3.2.1! – (2.2.3! - RBv.4 = 0
– 12 - 4 RBv = 0 RBv = -/4 RBv = -1,5 Ton
MB = 0
RAv. 4 – (3.2.3! – (2.2.3! = 0
4 RAv – 18 - 12 = 0 RAv = 30/4 RAv = ,5 Ton
MS = 0 … (bagan A-S!
- RA". 4 – RAv . 2= 0
- 4 RA" – ,5 . 2 – (3.2.1!= 0 RA" = $/4 RA" = 2,25 Ton
MS = 0 … (bagan B-S!
(2.2.1! # RBv . 2 # RB" . 4 = 0
4 # 1,5. 2 # 4 RB" = 0 RB" = / 4 RB" = 1,5 Ton
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%ag&a' B%RAv = ,5 Ton
RA" = 2,25 Ton
RBv = 1,5 Ton
RB" = 1,5 Ton
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%ag&a' S%S% ) **+
A = RA" = -2,25 Ton
1 = -2,25 Ton
2 = RAv = ,5 Ton
S = ,5 – (3.2!= 1,5 Ton
%1 = 1,5 Ton
%2 = 2,25 Ton
= 2,25 – (2.2! = -1,5 Ton
B = -1,5 # RB" = 0
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%ag&a' % % a)a ba*angA- = RAv = ,5 Ton (*+an!
-% = RA" = 2,25 Ton (*+an!
%-B = RBv = 1,5 Ton (*a&+!
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%ag&a' BM%
Mo'n a)a **+
A = B = S = 0
= - RA". 5 = - 2,25 . 4 = -$ T'
% = - RA". 4 # RAv . 4 – (3.2.3! = -$ # 30 – 18 = 3 T'
= - (-RB" . 2! = 1,5 . 2 = 3,5 T'
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SOAL
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MA = 0
(2.4.2) + 6.5 – 10.2 - RBv.4 = 0
16 + 30 - 20 – 4 RBv = 0
RBv = 26/4 RBv = 6,5 Ton
MB = 0
RAv. 4 – (2.4.2) + 6.1 – 10.2 = 0
4 RAv – 16 + 6 - 20 = 0
RAv = 30/4 RAv = 7,5 Ton
MS = 0 … (bagian A-S)
- RAh. 4 + RAv . 2 – (2.2.1) = 0
- 4 RAh + 7,5 . 2 – 4 = 0 RAh = 11/4 RAh = 2,75 Ton
MS = 0 … (bagian B-S)
(2.2.1) + 6.3 + 10.2 – RBv . 2 – RBh . 4 = 0
4 + 1 + 20 – 13 - 4 RBh = 0 RBh = 2!/4 RBh = 7,25 Ton
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%ag&a' B%RAv = 7,5 "#n
RAh = 2,75 "#n
RBv = 6, 5"#n
RBh = 7,25 "#n
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%ag&a' S%S$% &i 'i'i
A = RAh = -2,75 "#n*1 = -2,75 "#n
*2 = RAv = 7,5 "#n
S = 7,5 – (2.2)= 3,5 "#n
%1 = 3,5 – (2.2)
= -0,5 "#n
%2 = -0,5 +RBv = 6 "#n = 6 – 6 = 0 "#n
%3 = 2,75 "#n
$1 = 2,75 – 10 = -7,25 "#n
$2 = -7,25 "#n
B = -7,27 + 7,25 = 0
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%ag&a' %$% a&a ba'angA-* = RAv = 7,5 "#n ('an)
*-% = RAh = 2,75 "#n ('an)
%-B = RBv = 6,5 "#n ('an)
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%ag&a' BM%
M#n a&a 'i'i
A = B = = S = 0
* = - RAh. 5 = - 2,75 . 4 = -11 "
%1 = RAv.4 – RAh.4-(2.4.2) = 7,5 . 4 – 2,75 . 4 – 16 = 30 – 11 – 16 = 3 "
%2 = - (6.1) = -6 "
%3 = - (10.2 – 7,25 .4) = -20 + 2! = ! "$ = -(-RBh . 2) = -(-7.25 . 2) = 14,5 "
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ORTAL MA = 0
. 3 # 10 . 3 - RBv.5 – RB" . 3 = 0
48 – 5 RBv – 3 RB" = 0 …..(&a'aan 1!
MS = 0 … (bagan B-S!
10 . 1 - RBv.3 # RB" . 2 = 0
10 – 3 RBv # 2 RB" = 0 …..(&a'aan 2!
MB = 0
. 0 - 10 . 2 # RAv.5 – RA" . 3 = 0
-20 # 5 RAv – 3 RA" = 0 …..(&a'aan 3!
MS = 0 … (bagan A-S!
- . 2 # RAv.2 - RA" . 5 = 0
-12 # 2 RAv - 5 RA" = 0 …..(&a'aan 4!
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48 – 5 RBv – 3 RB" = 0 …..(&a'aan 1!
10 – 3 RBv # 2 RB" = 0 …..(&a'aan 2!
-20 # 5 RAv – 3 RA" = 0 …..(&a'aan 3!
-12 # 2 RAv - 5 RA" = 0 …..(&a'aan 4!
$ – 10 RBv - RB" = 0 … ( 6 2!
30 – $ RBv # RB" = 0 … ( 6 3!
12 – 1$ RBv = 0 RBv = 12/1$ = ,32
10 – 3 RBv # 2 RB" = 0 …..(&a'aan 2!
10 – 3 . ,32 # 2 RB" = 010 – 1$,8$ # 2 RB" = 0
RB" = $,8$/2 = 4,$48
-100 # 25 RAv – 15 RA" = 0 …..( 6 5 !
-3 # RAv - 15 RA" = 0 …. ( 6 3 !
-4 # 1$ RAv = 0 RAv = 4/1$ = 3,38
-12 # 2 RAv - 5 RA" = 0 …..(&a'aan 4!
-12 # 2 . 3,38 – 5 RA" = 0-12 # ,3 – 5 RA" = 0
RA" = 5,24/5 = - 1,052
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