4531-2 skema fiz trial spm 2013

9
1 PENTAKSIRAN DIAGNOSTIK AKADEMIK SBP SIJIL PELAJARAN MALAYSIA 2013 MATAPELAJARAN: FIZIK SKEMA JAWAPAN KERTAS 2 No Answer Marks Total 1 (a) length 1 (b) Tail 1 (c) to measure depth 1 (d) 0.42 cm 1 Total 4 No Answer Marks Total 2 (a) Product of an applied force and displacement / distance //Force X distance 1 1 (b) W = F X S M1 = 110 x0.5 M2 = 55 J / Nm 1 1 2 (c) F = ma M1 110 100 = 10 (a) M2 10 = 10 a a = 1 ms -2 1 1 2 Total 5 No Answer Marks Total 3 (a) Thermionic emission 1 (b) Uniform acceleration 1 (c) (i) V P = 4 V 1 (ii) T = 3 x 0.02 = 0.06 s f = 16.7 Hz 1 (iii) Sinusoidal with one complete cycle 1

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4531-3 Trial SPM 2013 SBP Physics Paper 2 Marking Scheme

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Page 1: 4531-2 Skema Fiz Trial Spm 2013

1

PENTAKSIRAN DIAGNOSTIK AKADEMIK SBP

SIJIL PELAJARAN MALAYSIA 2013

MATAPELAJARAN: FIZIK

SKEMA JAWAPAN KERTAS 2

No Answer Marks Total

1 (a) length 1

(b) Tail 1

(c) to measure depth 1

(d) 0.42 cm 1

Total 4

No Answer Marks Total

2 (a) Product of an applied force and displacement / distance //Force X distance

1 1

(b) W = F X S M1 = 110 x0.5 M2 = 55 J / Nm

1 1

2

(c) F = ma M1 110 – 100 = 10 (a) M2 10 = 10 a a = 1 ms-2

1 1

2

Total 5

No Answer Marks

Total

3 (a) Thermionic emission

1

(b) Uniform acceleration

1

(c) (i) VP = 4 V 1

(ii)

T = 3 x 0.02 = 0.06 s

f = 16.7 Hz

1

(iii) Sinusoidal with one complete cycle 1

Page 2: 4531-2 Skema Fiz Trial Spm 2013

2

Total 6

No Answer Marks Total

4 (a) The amount of heat energy required to increase the the

temperature of 1kg mass by 10 C.

1 1

(b) Pt = mcӨ

c = 48(900)

60

= 720 J kg-1 0

C-1

2 2

(c) M1 Land has a smaller specific heat capacity than sea

// Land faster increase in temperature // Land is

warmer than the sea

M2 Air above the land is heated up and rises

M3 Cooler air from the sea moves towards the land

Or diagram

M1 Label Sea(cold), Land (Hot)

M2 Show Hot air on land rises up

M3 Show Cold air moves towards the sea

1

1

1

3

(d) Sea breeze 1 1

7

No Answer Marks Total

5 (a)(i) Spring balance reading: diagram 5.1 > 5.2 1

(ii) Buoyant force / Upthrust 1 2

Page 3: 4531-2 Skema Fiz Trial Spm 2013

3

(b)(i) Spring balance reading: diagram 5.3 > 5.2 1

(ii) Density of water > density of oil 1

(iii) As density of liquid increases, buoyant force increases 1 3

(c)(i) pressure at Y > pressure at X // vice versa // Y is at

greater depth than X // pressure is directly proportional to

depth.

1

1

(ii) Buoyant force = (Difference in pressure) x A 1 3

Total 8

No Answer Marks Total

6 (a) Longitudinal waves // Mechanical wave 1 1

(b) 1. Loud sound - when antinodes/crest/trough

overlapped/meet/encounter another

antinodes/crest/trough, a constructive interference

occur

2. Soft sound – when nodes/crest/trough

overlapped/meet/encounter another nodes/ trough,

a destructive interference occur

1

1

2

(c) (i) Diagram 6.1 > Diagram 6.2 // vice-versa 1

(ii) Diagram 6.1 < Diagram 6.2 // vice-versa 1

(iii) a α 1 3

(d) M1 frequency// wavelength

M2 amplitude

M3 Distance between loud speaker and observer

(Any two)

1

1

2

8

No Answer Marks Total

7 (a) Reflection 1 1

(b) (i) 1

1

1

3

Page 4: 4531-2 Skema Fiz Trial Spm 2013

4

(ii) Virtual // Upright // Diminished 1 1

(c) 1. Aim the concave mirror to the sun

2. parallel ray from sun reflected and focus to F

3. amount of heat increases as all rays focus at F

Max : 2 points

1

1

2

(d) (i) 1. lens Q

2. f is smaller

1

1

1

(ii) Use concave mirror 1

1

Total 10

No. Answers Marks

8 (a) When a potential difference of 9V is connected across the

bulb, it will produce power of 20J per second.

1 1

(b) (i) P = V/I

20W = 9V/I

I = 20W/9V

= 2.22A

1

1

2

(ii) R = V/I

= 9V/2.22A

= 4.05 Ω

1

1

2

(c) (i) The more the thickness of the wire, the lower the loss of

energy from the filament.

1

2

(ii) Efficiency = Energy Output / Energy Input x 100%

E Filament P = 15 x 100 %

20

= 75.00%

E Filament Q = 28 x 100 %

30

= 93.33%

E Filament R = 43 x 100 %

50

= 86.00%

1

1

1

1

5

(iii) Filament Q has highest efficiency 1

1

2

Total 12

No Answer Marks Total

Page 5: 4531-2 Skema Fiz Trial Spm 2013

5

9 (a) (i) Property of material that enable it to return to its original

shape and size after an external force that acting on it is

removed

1

(ii) Compression of the spring in Diagram 9.2(a) is higher

than 9.1 (a)

Distance moved by the trolley in Diagram 9.2 (b) is

further than 9.1 (a)

Elastic potential energy of the spring Diagram 9.2(a) is

higher than 9.1 (a)

The higher the compression, the further the distance

moved by the trolley

The bhigher the compression, the higher the elastic

potential energy

1

1

1

1

1

(b) The forces between atom are attractive force and

repulsive force

When the force is applied , the distance between atoms

decreases

The repulsive force is acted on the atoms

When applied force is removed, repulsive force pushes

the atoms back to original

1

1

1

1

(c)

Design Reasons

Many springs

(arranged in parallel) High elasticity

Strong material for

frame // steel

Not break easily //

Not rust easily

Low spring constant To get more extension

Nylon// polyethene//

strong fabric Does not tear easily

Has net around / /

bigger diameter of

trampoline

Prevent children from

slipping to the floor

2

2

2

2

2

2

Page 6: 4531-2 Skema Fiz Trial Spm 2013

6

Total 20

No Answer Mark Total

10 (a) A magnetic field is a region in which a magnetic material

will experience a magnetic force

1 1

(b) The number of turns of the coils shown in diagram 10.2

is greater than 10.1

The pattern of magnetic field in diagram 10.2 is denser

than 10.1

The deflection of ammeter in diagram 10.2 is bigger than

10.1

1

1

1

3

(c) The closer the pattern of magnetic field // the denser of

magnetic field, the greater the strength of the magnetic

field.

The strength of the magnetic field increase when the

number of turns of coils increase

1

1

2

(d) (i) 1. Repel each other

1 1

(ii) 1. When current flows, magnetic field is form //

Diagram

2. Direction of magnetic field at the centre is the same

// Magnitude of magnetic field is stronger at the

centre // Diagram

3. Two forces produced is in opposite direction //

Diagram

1

1

1

3

(e) Modification Explanation

More number of

turn for the coil/

Increase the strength of

magnetic field // increase the speed of

motor

Has commutator To reverse the current flow

in the coil // ensure core

1,1

Force Force

Page 7: 4531-2 Skema Fiz Trial Spm 2013

7

rotate in one direction

Brush Enable current flow through the coil

Semicircular

magnet // curved

magnet

To produce radial magnetic field

Soft iron core Concentrate the magnetic field.

1,1

1,1

10

Total 20

11 (a) Archimedes’ Principle states that the buoyant force is

equal to the weight of fluid displaced.

1 1

(b) 1.Density of air decreases as altitude increases

2.Bouyant force become smaller

3.At certain height, weight of displaced air equal to

weight of the balloon.

4.Net force zero

1

1

1

1

4

(c) Characteristics Explanation

Fiber composite Light and strong

Bigger volume High buoyant force

The distance between

plimsoll line from the

surface of the sea is high

Can carry more load

Bigger size of the

propeller

To produce greater

forward thrust

Q is chosen the body is made from

fibre composite, volume

is bigger, the distance

between plimsoll line

from the surface of the

sea is higher and bigger

size of the propeller

2

2

2

2

2

10

(d) (i) F = ρgv

= 1020 × 10 × 5

= 51000 N

1

1

2

(ii) Total weight

15000 + W = 51000 N

W = 36000 N

1

1

1

3

Page 8: 4531-2 Skema Fiz Trial Spm 2013

8

Total 20

No Answer Marks Total

12 (a)

Cosmic ray// radiation from surrounding

//radioactive materials from earth// leakage of

radioactive from nuclear power plant

1

1

(b)(i) Alpha 1 1

(ii) 1. The ray ionises the air molecule

2. Negative ions attracted to the plate

3. Neutralised the electroscope

1

1

1

3

(c) Characteristics Reasoning

Liquid Easy to flow with blood

Short half life Not long in the body //

less harmful

Gamma Ray Cannot ionised the

living cell // high

penetrating power

GM tube detector Can detect ray

effectively// portable

K is chosen Because it is in liquid

state , has short half

life, emits gamma ray

and can be detected

easily detected by GM

tube detector.

2

2

2

2

2

10

Page 9: 4531-2 Skema Fiz Trial Spm 2013

9

(d)(i) (i) m = [235.04392 + 1.00867] – [140.91963 +

92.92157 + 2(1.00867)]

= [236.05259] – [ 235.85854]

= 0.19405u

m = 0.19405 x 1.66 x 10 -27

= 0.0322 x 10 -27

= 3.22123 x 10-28

kg

1

1

1

3

(ii)

E = mc 2

= (3.22123 x 10-29

) (3.0 x 10 8) 2

= 28.99107 x 10-12

= 2.899107 x 10 -11

J

1

1

2

Total 20