trial terengganu spm 2013 biology ques_scheme all paper

7/27/2019 Trial Terengganu SPM 2013 BIOLOGY Ques_Scheme All Paper

1/84

SULIT 4551/1

SULIT

4551/1BiologiKertas 1Ogos/Sept201311/4 jam

PENTAKSIRAN SUMATIF 3SIJIL PELAJARAN MALAYS IA 2013

B IOLOGIKer tas 1Satu jam lima belas minit

J ANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

1. Kertas soalan ini mengandungi 50 soalan.2. Kertas soalan in i disediakan dalam dwibahasa.3. Jawab semua soalan.4. Jawab dengan menghitamkan ruangan yang betul pada kertas jawapan yang

disediakan.5. Sekiranya andahendak menukarkan jawapan, padamkan tanda yang telahdibuat.Kemudian hitamkan jawapan yang baru.6. Rajah yang mengiringi soalan dimaksudkan untuk memberi maklumat yangberguna bagi menjawab soalan. Rajah tidak dilukis mengikut skala kecuali

dinyatakan.7. Anda dibenarkan menggunakan kalkulatur saintifikyang tidak boleh diprogram.

Kertas soalan inimengandungi 24 halaman bercetak.TERENGGANU NEGERIANJUNG ILMU

Dibiayai oleh:Kerajaan Negeri TerengganuDicetak Oleh:Percetakan Yayasan Islam Terengganu Sdn. Bhd.

Tel: 609-666 8611/6652/8601 Faks: 609-666 0611/0063


2/84


3/84


4/84


5/84


6/84


7/84


8/84


9/84

h // d h l


10/84


11/84

h // d h l


12/84

htt // d j h tl


13/84

h // d h l


14/84

htt // d j h tl


15/84

htt // d j h tl


16/84

htt // d j h tl


17/84

h // d h l


18/84

htt // d j h tl


19/84


20/84


21/84

h // d h l


22/84

htt // d j h tl


23/84

http // d j h tl


24/84

h // d h l


25/84

htt // d j h tl


26/84


27/84


28/84


29/84

SULIT

NAMA:SULIT4551/2BiologiKERTAS 2Ogos/Sept 20132 '/a jam

TINGKATAN:

PENTAKSIRAN SUMATIF 3SIJIL PELAJARAN MALAYSIA 2013

B IOLOG IKertas 2Dua jam tiga puluh minit

JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

/. Kertas soalan ini mengandungi tiga bahagian :Bahagian A, BahagianB danBahagian C.2. Jawab semua soalan dalam Bahagian A. Jawapankepada Bahagian A hendaklah ditulisdalamruangjawapanyang disediakan3. Jawab dua soalan dari Bahagian B danjawapan kepada

Bahagian B hendaklah ditulisdalamruangbergarisyangdisediakan dibahagianakhirkertassoalan. Andadimintamenjawab denganlebihterperinci untuk Bahagian B,Jawapanmestilahjelas dan Iogik, Dalamjawapananda,persamaan.gambar rajah, jadual,grafdancaralainyangsesuai untukmenjelaskan jawapanandabolehdigunakan.4. Rajah yangmengiringi soalan tidakdilukis mengikut skala

kecuali dinyatakan.5. Markah yang diperuntukkan bagi setiap soalan atauceraian soalan ditunjukkan dalam kurungan.6. Sekiranyaanda hendakmembatalkan sesuatujawapan,

buatgarisan di atasjawapan itu.7. Andadibenarkanmenggunakankalkulatorsaintifikyangtidakbolehdiprogram. Walau bagaimanapun, langkahmengiraperlu ditunjukkan8. Masayangdicadangkan untukmenjawab Bahagian A ialah90minit, Bahagian B 60minit.9. Semuakertasjawapan hendaklahdiserahkandi akhirpeperiksaan.

Kod Pemeriksa

Bahagian Soalan MarkahPenuh

Markah

A

1 12

2 12

3 12

4 12

5 12

B

6 20

7 20

8 20

9 20

Jumlah

Kertas soalan inimengandungi 18halaman bercetak.TERENGGANU NEGERIANJUNG ILMU

Dibiayai oleh:Kerajaan Negeri TerengganuDicetak Oleh:Percetakan Yayasan Islam Terengganu Sdn. Bhd.

Tel: 609-666 8611/6652/8601 Faks: 609-666 0611/0063

4551/2


30/84


31/84


32/84


33/84


34/84


35/84


36/84


37/84


38/84


39/84


40/84


41/84


42/84


43/84


44/84


45/84


46/84


47/84

SULIT

SULIT4551/3BiologiKertas 3Ogos/Sept20131 Vz jam

NAMA : T INGKATAN :

PENTAKSIRAN SUMATIF 3SIJIL PELAJARAN MALAYSIA 2013

B IOLOG IKertas 3

Satu jam tiga puluh minit

JANGAN BUKA KERTAS SOALAN IN I SEHINGGA DIBERITAHU1. Tuliskannoma dan tingkatan andapacta

mangyang disediakan2. Jawab semua soalan3. Jawapan anda hendaklahditulis dalam

mangyang disediakan dalam kertassoalan4. Rajah yangmengiringi soalandimaksudkan untuk memberi maklumatyang berguna bagi menjawab soalan.Rajah tidak dilukis mengikut skalakecuali dinyatakan.5. Markahyang diperuntukkan bagi setiapsoalan dan ceraian soalan ditunjukkandalam kumngan

6. Anda dibenarkan menggunakankalkulator saintifikyang tidak bolehdiprogram.

KodPemeriksa

Soalan MarkahPenuh

MarkahDiperolehi

1 33

2 Respons17

TOTAL

Kertas soalan ini mengandungi 13 halaman bercetak dan 0 halaman tidak bercetakTERENGGANU NEGERI ANJUNG ILMU

Dibiayai oleh:Kerajaan Negeri Terengganu

Dicetak Oleh:Percetakan Yayasan Islam Terengganu Sdn. Bhd.Tel:609-666 8611/6652/8601 Faks: 609-666 0611/0063

4551/3

4551/3

SUL IT


48/84


49/84


50/84


51/84


52/84


53/84


54/84


55/84


56/84


57/84


58/84


59/84


60/84

TRIAL 2013SCHEME BIOLOGY PAPER 1

NUM. ANSWER NUM. ANSWER

1 A 26 A

2 B 27 A

3 A 28 D

4 D 29 D

5 C 30 C6 D 31 A

7 B 32 D

8 D33 D

9 D 34 A

10 C 35 D11 B 36 A

12 D 37 D

13 B 38 C

14 C 39 D15 A 40 C

16 C 41 B

17 B 42 A

18 D 43A

19 B 44 C

20 C 45 B

21 B 46 C

22 C 47 A

23 B 48 B

24 A 49 C

25. B 50 D

http://edu.joshuatly.com


61/84

NUM1(a)

Kb) (i)

1(b) (ii)

1(c)

Kd)

Marking SchemePaper 2 (Section A)

SCORING CRITERIAAble to match correctly,A n s w e r :1 B2 A3-D4 CAble to name system and two organsA n s w e r :System: reproductive systemOrgan : testis/penisAble to explain the adaptationSuggested answer:Fl: numerous ofmitochondriaEl :provide energy tomove the tailF2: have a long tailE2: easy to swim reach an ovum

Able to explain without mitochondriaSuggestedanswer:F : sperm cannot ge t energyE l: cannot swim to reach ovumE2:fertilisation cannot occur

Any F and E

Able to explainnecessity of cell specialisationSuggested answer:El: multicellular organisms are consist ofmany cells butunicellular made up thebodyone cell onlyE2multicellularneed specialised cells to carry out differentfunctions tobody but unicellular can do any life function its ownone cellE3: thecellofmulticellular very far from environment and itshardfor diffusion, but unicellur cell nearest to environment anddiffusion very easy/fast.

MARKS

All/3/2/

F l/E l/OrF2/E2/

FandanyE l /E2

3m2mlm

2m

2m

lm

lm

3m

TO TAL 12 mark s



62/84

NO.

2.(a)(i)

2.(a)(ii)

2(b)(1)

2(b)(ii)

MARKING CRITERIA

Able to name P, O an d RSample answer:P : Lac toseQ: LactaseR: Lactase-Lactose-complexAble to drawthe diagram in the spaces SandT provided inDiagram 2.1 to complete the mechanism oftheenzymereaction.Sample answer:

Able to explain one characteristic ofthe enzyme based ondiagram 2.1Sample answer:PI :Enzyme ishighly specific, can only catalyse one kind ofsubstrate // Enzyme has specific sitecalled active siteto

bind to specific substrate (Actspecifically)P2 :Enzyme is not destroyed by the reactions they catalyse //Can be reused // Remain unchanged at the end of thereact ion

Able describe the enzyme action based on this hypothesisSample answer:PI : The substratemolecule represents the 'key ' and the

enzyme molecule represents the Tock'P2 : The substrate molecule binds to the active siteP3 : to form an enzyme-substrate complexP4 :The enzyme catalyses the substrate to form products, (then

the product leaves the active site)P5 :The enzyme molecule isnow free to bind tomore substratemolecules

(Any 3)

MARKS

Note:3 V1-2 V

1+1

2mlm

2m

2m

jm



63/84

2(c) Able to explain the enzymes action at O.Sample answer:P1: AtQ, the enzyme reaction is at amaximum rate //the rate of

reaction will not increase further (and become constant)P2: AtQ, theconcentration of substrate is high//access ofsubstrate molecules.P3: The active siteof enzymemolecules are filled/fullyoccupied bythesubstrate molecules//The enzyme molecules

is said to be saturated.P4:The concentration of enzymes become a limiting factor.

(Any 3)TO TAL

3m

12MARKS



64/84

NUM3(a) (i)3(a) (ii)

3(b)

3(c)

3(d)

3(e)

SCORING CRITERIAAble to label to n ame the structureSuggested answer: VillusAble to state how the structure is adapted to its functionSuggested answer:PI: the epithelial liningisonlyone cell thickP2: epithelial cell have a lining ofmicroscopic projection calledmicrovillus

P3: each villus has a network of blood capillariesAny 2

Abl e t o state th e function o fX and YSuggested answer:X: absorb fatty acid and glycerol/vitamin A,D,E,KY: absorbed glucose/amino acids/mineral/vitamin B.CAble to explainthe function of liver inassimilationSuggested answer:PI :act as check pointP2: which control the amount of nutrients released into blood

circulatory system

Able to explain the assimilationof nutrient PA n s w e rF - nutrient P is glucosePI - which is converted into glycogen and stored in the liverP2 - when there is lack of bloodglucoselevel, stored glycogen isconverted back to glucoseP3- glucose are transported to the cells to produceenergy Any 2

Able to explain why assimilation of lipids do notoccur in liverSuggested answer:F: Lipids are not transported to the liverPI: Fatty acids an glycerols/lipids are absorbed into lacteal not into

blood capillariesP2: from lacteal lipids is transported through lymphatic system to

blood circulatory systemP3:excess lipid stored in adipose tissue

Any 3To ta l

MARKS

1.2



65/84

NUM4(a)(i) Sample answer :

Lymph

SCORING CRITERIA

4(a)(ii) Sample answer :X does not h av e

erythrocyteprotein plasma

- haemoglobinAny tw o

4(b) Suggested answer:- fatty acid and glycerol diffuse into lacteal of villi- transport by lymphatic system via lymph nodes- back to blood circulatory systemvia left and right subclavian vein(and then transport to body cells)

Any two4(c)(i) Answer:

X: Artificial active immunityY : Artificial passive immunity

4(c)(ii)

4(c)(iii)

Suggested answerX : To increase the production of antibodies as a prevention againstfuture in f ec t ion .Y : To supply enough antibodies up to the levelof immunity andab1e to destroy pathogens quicklySuggested answer

Individual X Individual Y

Long lasting orpermanent

Short lasting ortemporary

Slow response Immedia teresponse

4(d) Suggested answerbecause HIV viruses destroy the white blood cells /lymphocytes

MARK S

Tota l 12



66/84

Num Scoring Criteria Mar k sMa r k s R ema r k s5(a) Able to name the mechanism involve to regulate body

temperatureAnswer: Negative FeedbackMechanism 1 1

5(a)(ii) Able to state the way organ X and gland Y response toregulate body temperatureA n s w e r :Organ X : PhysicalGland Y : Metabolic process

11 2

5(b) Able to explain the roles of the erectormuscle, bloodcapillary and sweat gland in maintaining the bodytemperature on a hot day.Suggested answerF l : erec tor musc le r elaxPI: hair follicle lie down to trap thin airF2: blood capillary expand / diameter increase /vasodilationP2: more heat release through radiationF3: sweat gland active / secrete more sweatP3: evaporation of sweat release heat

6

5(c) Able to explain how gland Y helps to regulate thestudent's body temperature.Suggested answer:PI: hypothalamus stimulate adrenal gland / gland YP2: adrenal gland / gland Y secrete adrenalineP3: to increase the metabolic rateP4: more heat produceP5: body temperature increase

Max 3

Tota l 12



67/84

NUM6(a)

6(b)

6(c)

Sec t ion B

SCORING CRITERIAAble tostate the differences between microorganisms P and Q.ND l

D2

D3D4

P i s Bacte ri aClassified into kingdom ofmonera

P is unicellular organisms(which have a basic cellstructure)Composed ofDNAExist in th e fo rm o fspherical / rod-shaped /spiral

Able toname the diseasefaced by Y.Answer: Tuberculosis / TBAble to explain howthisdisease infected Y.S amp l e ans w e r s :

QQ is VirusCannot be classified in anyof the kingdomIs not living cell (cannotsurvive/ reproduce on itsown outside the host)Composed ofDNA or RNAExist as (chemical) crystals(outside the host cell)

FE lE2E3E4E5

Through droplet transmissionWhenX sneeze / cough / speak / spitthe droplets from the mouth / noseare released and f loat in th e ai rThese droplets breathed in byYIf droplets contain (TB) bacteria cause Y to fall ill

Able to explain the role ofmicroorganisms R, S, T, U, VandW inthis cycleS amp l e answers:R / Nitrogen fixing bacteria /Azotobacteria sp. /Nostoc sp. IClostridium sp IRhizobium sp.convertnitrogeninto ammonium compoundS / Nitrifying bacteria / Nitrosomonas sp convert ammonium

compounds into nitritesT / Nitrifying bacteria / Nitrobacter sp. convert nitrites intonitrates(Nitrate) are absorbed by plants tomakeproteinWhenanimalseats the plants, theprotein is transferred to theanimalsWaste material / faeces / urea / excretory nitrogenous plantsWhen animals / plants dieare decomposed byU/ decaying bacteria / saprophyticbacteria / fungiBreak them down to ammoniumcompound in the soilV/ Denitrifying bacteria converts nitrates into nitrogen

T O T A L

E l

E2E3

E4

E5E6

E7E8E9

E10E l l

8

MARKS

Max4

Max5

M ax10

20 M



68/84

No

7(a)

7(b)

7(c)

Mark Scheme

Able to explain the movement of the forelimb inhumanSuggested answerFl: forelimb/arm being bentEliwhen the bicepsmuscle contract the tricepsmuscle relaxesF2: Forelimb/arm being straightE2: when the triceps muscle contract, the bicepsmuscle relaxesAble to explain how the structure in the earthworm involve in their movementas shown in the diagram.SuggestedanswerFl: hydrostatic skeletonEl: fluid in the body cavity helps the earthwormto moveF2: muscle at the body wall are longitudinal and circular muscle / antagonisticmuscleE2: contraction of circular muscles cause segment to extend while thelongitudinal muscles relaxE3: contraction of longitudinal muscles cause segment to shorten whilethecircular muscles relaxF3: chaetaeE3:secure the shorted segments inthe posterior to the ground whilethe anteriorsegments extended owing to contractions ofthecircular muscles

Maximum 6

Able to state the problems that could befacedbyfishand the bird in supporta n d l o co m o t io nAnswer: Fish - Water resis tanceBird - Air resistanceAble to explain the similarities and differences between thefishand the bird'son the structural adaptation for support system and locomotion.Suggested answerSI: both fish and bird has antagonistic muscleEl: able the organismmove inthe habitatS2: both fish and bird has endoskeletonE2: able to give support to organismDl: fish has streamlined shapes/ skin covered with skin but the shape of bird /body covered with fursE3: toovercomes theproblem ofwater resistant in fish and air resistant in birdD2: fish has myotome arranged in segments on both side of left and right sideof the body butthebird has pectoralis major and minor at their limbE4: for fish to swim and bird to fly (in their habitat)D3: fish has unstable problem in water while swimming / Yawing / Pitching /Rolling but bird has unstable problem while flying/ lifting forceE5: instability offish isovercome by fin but instability of bird isovercome bythe shape of an aerofoil wings

max imum

SubMark

TOTAL

TotalMark

1020



69/84

No8(a)

Ma r k SchemeAble to explain the differences between the two human activitiesCriteria1. State the types of phenomena2. C: t he c au se s3. E: t he e ffec ts4. S: ways to overcomeS a mp l e a n s w e r sFl: (The phenomenon is) acid rainThe causes:CI: Combustion/Burning of fossil fuels inpower stations/

factories/ motor vehiclesC2: release sulphur dioxide/ S02 andoxides of nitrogen/

NO and NO?C3: Form sulphuric acid and nitricacidwhencombine

with water vapourC4: Fall to Earth as acid rain/ snow/ hail / fog/ frost/ dewThe effectsAgriculture:El: Leachingof minerals// the soil becomeacidicAquatic ecosystem:E2: Increaseacidity in the aquatic ecosystem//killphytoplankton// destroyed photosynthetic tissues//

accumulate insoluble aluminium ions in lakes andrivers which kill aquatic organisms

H e a l t h :E3: Acidic soil releases ions of certain heavy metals/contaminate the supply of drinkingwater// irritate thelungs/ makebreathing difficult/asthma/ bronchitis.

E4: Corrode metal railing/bridges/damage buildings/statues/ automobiles/ structures made of stone/ metal/historic buildings

The ways to overcome / solutionsSI: Use scrubbers (to clean up emissions from power

stations and industrial plants)S2: Use catalytic converters (to clean up emissions from

vehicle exhausts)

Must have F, C, E and S (at least one point)

10

Any 10

Ma r k Tota l

10m



70/84

8(b) Able to explain the importance of sustainable management of tropicalrainfores t .Sample answers

F: (Sustainable development refers to) the measuresundertaken to ensure that human activity optimallyutilize Earth's natural resources such that they can be 1replenished naturally//suitable explanation

Fl: Replanting trees in areas that have been logged// 1reforestation

El: to keep the ecosystems in their natural state (whichprovides aesthetic values for humans) // preservenatural resources f or ou tdoo r/ recreational activit ies/ / 1eco-tourism // reduce stress// promote healthy life style

E2: to maintain soil fertility 1E3: to prevent flood/ soil erosion / landslide/ (muddy) flood/ 1

(flash) floodE4: to avoid species extinction// to prevent extinction of 1

flora and fauna/ organisms/ speciesE5 : As an economic r esour ce // s ou rce o f raw mater ials for

construction industry / piling / furniture / boats /houses/ production of charcoal / tannin / food / other 1suitable example // provide foods to human //resources for study / education / research

F2: Selective loggingE5: to maintain a balanced ecosystem// to allow maximum 1

interaction among the living organisms/ biotic factors(in the ecosystem) and interaction between biotic andabiotic factors

E6: to maintain major sources of human food/ e.g: ulam/ 1ferns/ meats/ honey// sources ofmedicinal plant/ eg:herbs

E7: to sustain food web/ food chain in the ecosystem 1E8: to prevent disruption of natural cycle of water/ carbon/ 1

balance between photosynthesis and respiration//balance oxygen and CO2 in the atmosphere // provide02 // reduce C02

E9: to decrease the carbon dioxide level in th e 1atmosphere // to reduce the greenhouse effect/ globalwarming

1

11



71/84

Num

ElO: to maintain the biodiversity of the forest// maintaining/ increasing biodiversity / complexity / variety oforganisms / species / flora and fauna

El 1: to avoid lost ofwildlife/ potential resourcesE12: to avoid loss ofwatershed areas // provide natural

water ca tchment areaEl3: maintaining(normal) weather (patterns) byminimize

climatic change / drought / harsh climate / maintaintemperature

El4 : As a site for breeding / feeding of flora and fauna /serving as valuable nursery area for organisms

Must have F and any 10T O T A L

SCORING CRITERIA9(a) Able to(i) Statethe example of continuous variation and discontinuous

variation and th e difference of continuous variation anddiscont inuous var ia t ion

Sample answer:Example of continuous variation: Height orweightExampleof discontinuous variation: ABOblood groupDifferences

Cont inuous varia tion Discontinuous variationGraf distribution shows a normaldistribution

Graf distribution shows adiscrete distribution

The characters are quantitative /can be measured and graded (fromone extreme to the other)

The characters are qualitative/ cannot be measured andgraded (from one extreme tothe other)Exhibits a spectrum of phenotypes

with in termediate characterExhibits a few distinctivephenotypes with nointermediate character

Influenced by environmentalfactors

Is not Influenced byenvironmental factors

Two or more genes control thesame characte r

A single genes determines thedifferences in th e traits of thecharacter

The phenotype is usually controlledby many pair of alleles

The phenotype is controlledby a pair of alleles

12

Mar k

10m

2 0M

Rema r k

Max 7



72/84

Num

(ii)Able to state the importance of variation to organismSample answer:PI: variation provided better adaptation for organism to survive inthechanging environmentP2: variation are essential to the survival of species / to survive moresuccessfullyP3; variationbe able to organism explore a new habitatP4: to ensure organism survival from predator

Any 3

SCORING CR ITER IA9(b) Able to explain the possibilities of the blood group and the genotypes ofthe offspring when the father's blood group isAand the mother's bloodgroup is B.Sample answer:There are four possibilities;(a) Parent's genotype:Gamete

Genotype FlPhenotype F1

jAjA X IBIB

jAjBAll offspring haveBlood group AB

(b) Parent's genotype: I I X jBjOGamete

Genotype FlPhenotype Fl

jB ,0

50% of offspring have blood group ABand 50% have blood group A13

Total 10

Ma r k Rema r k



73/84

(c) Parent's genotype: IA1 X IBIB

Gamete jA jO TB 1 3

\x 1Genotype Fl jAjB jBjO 1Phenotype Fl 50%) of offspring have blood group AB

and 50%)have blood group B

(d) Parent's genotype: jA jO X TB JO

Gamete I[M, 1 3Genotype Fl I \ rB tA tO tB tO tO tO

1

Phenotype Fl AB A B 025% chance that offspring has blood groupAB, A , B, 0

1

Max 10

14



74/84

SUGGESTED ANSWER FO R 4551/3

QUESTION 1

ITEMNO

(a)

(b) (i)

SCORE EXPLANATION

KB0603 - Measuring using numbersAble to record all data correctlySample answer :Volume o fwater in take

(ml)Volume of urine produced

(ml)F i rs t t ime Second t ime

500 ml 230 2521 00 0 m l 450 470

Able to record 3 data correctlyAble to record 2 data correctlyNot able to give any response or wrong response

KB0601- ObservingAble to state any two observations correctlySample answer:

1. When 500ml mineral water were intake by twostudents, first student produces urine about 230mland the second student produces urine about252ml.

2. When 1000ml mineral water were intake by twostudents, first student produces urine about 450mland second student produces urine about 470ml.

Able to state any one of the above observation correctlyand on e i de a o f observationSample answer

1. When group of students A drinks less mineralwater, they produced less urine.

2. When group of students B drinks more mineralwater, they produced more urine

REMARKS

AcceptedAnysui tableanswer



75/84

1 Able to state two ideas o f th e above observationscorrectlySample answer

1. Group A produced less urine2. Group B produced more urine

0 Not able to give any response or wrong response

(b) (ii) KB0604 - Making inferenceAble to state two possible inference for each observationbased on the following:PI: More / less water r eabsorbed f rom the tubule o f

kidney into blood capillaryP2: High/ low blood osmotic pressureSample answer

1. Group A produces less urine because more wateris reabsorbed from the tubule of kidney into bloodcapillary due to high blood osmotic pressure

2. Group B produces more urine because less water isreabsorbed from the tubule of kidney into bloodcapillary due to low osmotic pressure

2 Able to state any one possible inference for eachobse rvat ion and one in ference that l e s s accura teSample answer1. Group A produce less urine because more wateris reabsorbed from the tubule of kidney intoblood capillary //due to high blood osmoticpressure

2. Group B produce more urine because lesswateris reabsorbed from the tubule of kidney intoblood capillary // due to low blood osmotic pressure

1 Able to s ta te two i nf er en c es but less accura teSample answer1. Group A kidney's tubule reabsorbs more water2. Group B have low osmotic pressure



76/84

0 Not able to give any response or wrong response

(c) KB0610 - Controlling variables

oJ Able to state any 5-6 items from the table

Constantvariable :Acceptedany suitableanswer

Variable Particular to be implementedManipulatedvariableVolume o fwater in take

Used diffe rent volume o fwater intake by each group ofstudent such as 500m l a nd1000ml

RespondingvariableVolume o furineproduce

Record t he v ol ume o f urineproduce by using a measuringcylinder

ConstantvariableTime(beforecollectingurine)Same ages tudent

Fixed the tim e a bo ut 3 0minutes before collecting theurine produced by each groupo f student

// carry out by the same age ofstudent

2 Able to state any 3-4 i tems from the above1 Able to state any 2 items from the above0 Not able to give any response or wrong response

(d) KB0611 - Stating a hypothesis



77/84

(e)

Able to write a complete hypothesis statement showingthe relationship between manipulated variableandresponding variable correctly.PI = manipulated variableP2 = responding variableH = Link/ relationship

Sample answer:1. The higher the volume of water intake, the higherthe volume of urine produced/ output.2. If more / higher volumeof water intake, so more /higher volume of urine produced/ output

Able to wri te any two from the abovePI and P2 // PI and H / / P 2 and HSample answer :

1. The different volume ofwater intake, the differentvolume of urine produced

2. The volume of water intake affec t the volume o furine produced

Able to write any one from the aboveSample answer :

1. The volume of water intake affect urine producedNot able to give response or wrong response

KB0606 - CommunicatingAble to prepare a table and shows the following:H - Heading in the table are labeled with correct unitsD - All data a re co rr ec tP - All t he s tudent s are correct

Group ofstudent

Volume o fwater intake

(ml)Volume o f

urine produce(ml)

Averageo f urineproduce(ml)irst second

A 500 230 252 241B 1000 450 470 460

PI -volume o fwater intake

P2-volume o furineproducedH-relationship* wronghypothesiswas

accepted*



78/84


79/84

1 Able to predict theSample answer :El - volume of urine produced increased /

more than 460mlE2 - because temperature is low/reduceE3 - causing less water is reabsorbed from the tubule ofthe kidney into blood capillary//due to less sweat is

produced

2 Able to state any two from the above

1 Able to state any one from the above0 Not able to give response or wrong response

00 KB0609 - Defining by operation3 Able to describe the concept of osmoregulation correctly

based on the observat ion

Sample answerOsmoregulation isEl - a process ofmaintaining blood osmotic pressure

of the four student/student of group A and BE2 - which can be determined by the volume of

urine produced by both student.E3 - Volume of urine produced is affected by the

volume o f water intake.

2 Able to state any two from the above

1 Able to state any one from the above

0 Not able to give response or wrong response(i) KB0602 - Classifying



80/84

3 Able to classify correctly the list of apparatus andmaterials according to the variablesSample answer :

VariablePembolehubah

ApparatusRadas

MaterialBahan

ManipulatedManipulasi

Mineral bottle Minera l wate r

RespondingBergerakbalas

Measuringcylinder

Urine

ControlledDimalarkan

Stopwatch Student

2 Able to classify the list of apparatus and materialsaccording to any two variables

1 Able to state the materials in any one class completely

0 Not able to give response or wrong response

Suggested answer for Question 2KB061201 - ( Problem statement)Question Score Explanation Rema r k s

2(i) ->j Able to state the problem statement correctly :PI : vigorous activities //different duration of running onthe spotP2 : Percentage of carbon dioxide gas in exhaled air /length of air column after being treated withpotassium hydroxide solution.

H : Question formSample answer:1. Does the different duration of running on the spot affectpercentage of carbon dioxide gas in exhaled air /

length of air column after being treated with potassiumhydroxide solution ?

2. How do vigorous activities affect the percentage ofcarbon dioxide gas in exhaled air / length of air columnafter being treated with potassium hydroxide solution?



81/84

3. What is the effect ofvigorous activities againstpercentage of carbondioxide gas in exhaled air?2 Able to state a problem statement less accurately.

Sample answer:1. What activity affects the carbon dioxide gas in exhaled

ai r

2. Can running on the spot affects carbon dioxide gas inexha led a i r?

3. What is the effect of miming on the percentage of carbondioxide gas in exhaled air?

1 Able to state a problem statement at idea levelSample answer:1. Exhalation gives out carbon dioxide gas.

2. Carbon dioxide content depend on vigorous activity /different duration of activity.

0 No response or wrong response

KB061202 ( KB061203 - Making Hypothesis )Question Score Explanation Rema r k s2 (iii) 3 Able to state the hypothesis based on the following aspects:

PI = Manipulated variable = vigorous activity//differentduration of rumiing on the spot

P2 = Responding variable = percentage of carbon dioxidegas in exhaled air // length of air column after beingtreated with potassium hydroxide solution.

R = Relationship / LinkSample answer :

1. As duration of running on the spot increases, the higherthe percentage of carbon dioxide gas in exhaled air /length of air column after being treated with potassiumhydroxide solution, (vice versa)2. As more vigorous of an activity, the higher thepercentage of carbon dioxide gas in exhaled air / lengthof air column after being treated with potassiumhydroxide solution, (vice versa)

Wronghypothesisacceptedas longthere isP1JP2

2 Able to write a hypothesis statement less accuratelySample answer:



82/84

1. As act ivi ty increases, the carbon dioxide also increase.2. Different activities affect different percentage of carbon

dioxide gas1 Able to state a hypothesis at idea levelSample answer:

1. Carbon dioxide produced in exhaled air0 No response or wrong response

VARIABLE2(iv)

Able to state all the three variables correctlySample answers :

Manipulated variable = vigorous activity//different duration of running onthe spotResponding variable = percentage of carbon dioxide gasin exhaled air // length of aircolumn after being treated withpotassium hydroxide solution.

Constant variable = same student / type of J-tubeKB06i205 - (Apparatus and materials)Question Sco r e Explanation Rema r k s2(v) -> Able to list out all the important apparatus and materials

correctly.Sample answers:

Apparatus:J-tube, boiling tubes, rubber tubing, ruler , stopwatchMaterials:Student, water basin, potassium hydroxide solution,exhaled air, distilled water

2 Able to list 3 apparatus and 3 materials correctly1 Able to list 2 apparatus and 2 materials correctly0 No response or incorrect response

KB061204 (Experimental Procedure)Question Score2(vii)

ExplanationAble to describe all the steps of the experiment correctlyNote:Kl: preparation ofmaterials and apparatusK2: operating the constant variable

Rema r k s



83/84

K3: operating responding variableK4: operating manipulated variable To getK5: Step to increase reliability of result Kl, mustaccurately/precaution include a t

l ea s t 4K1Sample answers

1. J -tube i s unscrew c lockwise to the end . K l2. The open endof J-tube is lowered into a basinofwater K l3. 5cm ofwater is drawn into the J-tube by turning K1 /K2

anticlockwise. The screw is turned clockwise again toexpel somewater. The J-tube is placed into the basin.4. When student is resting for 0 minute, a sample of K lexhaled air is collected through rubber tubing which is

inserted into a boiling tube filled with water5. Then the open end of J-tube is placed into the boiling K ltube containing exhaled air

6. The scr ew is turned anticlockwise to draw some exhaled K lair into the capillary tube.7. Then the open end of J-tube is dip into potassium K lhydroxide solution.

8. The scr ew i s t ur ned c lo ckwi se and anticlockwise toallow carbon dioxide being absorb by potassium K lhydroxide solution.

9. Record the length of air column in J-tube by using a ruler K3after being absorbed by potassium hydroxide solution.Avoid touching the J-tube K510. Repeat Step 4 until 9 to the same student by running on K2 /K4the spot for 1 minute, 2 minutes and 3 minutes .

11. Al l r esul ts a re r ecorded in a Table. K l-1 A ll the 5 K 's2 Any 3-4 K's1 Any 1-2 K's0 No response or incorrect response

KB061206 ( Presentation of Data)Question Score Explanation Remarks



84/84

Presen ta t iono f Data2(viii)

Able to present all the data with units correctlyBas ed o n :PI: Title with correct unitsP2: Sample for vigorous activitySample answer:

(Types of)vigorous

activity//Durationof running on the

spot

Length of air columnafter being treated withpotassium hydroxide

solution (cm)

Percentage ofca rbon d iox id ein capillary tube

/J-tube (%)Resting for 0

minuteRunning on thespot for 1minuteRunning on thespot for 2 minutesRunning on thespot for 3 minutes

Any PI orP2

trial terengganu spm 2013 biology ques_scheme all paper

Documents