terangganu-answer physics p2-trial spm 2007

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JABATAN PELAJARAN TERENGGANUPEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 2007PHYSICS MARKING SCHEME PAPER 1, 2 and 3PEPERIKSAAN PERCUBAAN SPM 2007 SCHEME PAPER 1 QUESTION NO. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 ANSWER A E B B B C C C B E C A B A D C B D A D D D D B C QUESTION NO. 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 ANSWER B B A C C D D C C C A C C B B B A D C B C B B C DSECTION AQuestion 1Part (a) (b)(i) (b)(ii) (c

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JABATAN PELAJARAN TERENGGANU

PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 2007PHYSICS MARKING SCHEME PAPER 1, 2 and 3

PEPERIKSAAN PERCUBAAN SPM 2007 SCHEME PAPER 1 QUESTION NO. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 ANSWER A E B B B C C C B E C A B A D C B D A D D D D B C QUESTION NO. 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 ANSWER B B A C C D D C C C A C C B B B A D C B C B B C D

SECTION AQuestion 1Part (a) (b)(i) (b)(ii) (c) Total Mark 1 1 1 1 4 Answer Name the container X correctly Lead container / concrete container Underlining thee correct phrase in the box correctly a beta particle Give the reason correctly Negatively charge Give the reason correctly The mass of ray P < ray Q // The speed f ray P > ray Q Note

Question 2No 2 2 a) 2 b) 2 c) 2 d) 1M 1M 1M 1M 1M Quantity matters in a material //An object at rest tends to remain at rest // an object in motion tends to stay in motion The car Mass // Inertia is smaller v2 = u2 + 2as 02 = 152 + 2a(375) - 0.3 ms -2

Question 3 Section Marks (a) 1 (b) (c) (d) 1 1 6 marks Question 4No 4 4 a) 4 b) 4 c) 4 d) 1M 1M 1M 1M 1M 1M 1M

Answer There is no net flow of heat between two objects and they have same temperature 45 0C The heat from block P transfer to the water Until the rate of heat transfer between P and water become equal E = mc = 0.3 x 900 x 55 = 14 850 J

Catatan

1 1 1

v = 5 x 0.8 = 4 ms -1 The wave are circular Wavelength remains unchanged Diffraction Waves pass through an aperture or round a small obstacle Waves spread out.

Question 5 Q5/S5 (a)(i) 1 (b)(i) 1 (ii) (iii) (c)(i) (ii) (d) (e) 1 1 1 1 1 1 2 Density is the mass per volume Level of the boat is higher in the sea than in the river. Water displaced in the sea is less than in the river. Density of sea water is higher than river water. The lower the density of water, the greater /higher the volume of water displaced. Weight of the boat = Weight of the water displaced Archimedes principle // Bouyancys law Ballast tank filled by sea water Weight of submarine > upthrust

Maximum 1 mark (Any one mark)

Tot/Jum : 8QUESTION 6 Part (a) Mark 1 1 (b) 1 1 (c) 1 (c) 1 1 (d) Total 1 State the correct function of the two resistors As the voltage divider 8 Give the reason correctly The mass of ray P < ray Q // The speed f ray P > ray Q Complete the circuit correctly The two resistors in series One of the resistor in base circuit Answer Name the current I1 correctly Base current Name the current I2 correctly Collector current State two observations correctly I1 < I2 // I1 = 0 and I2 = 0 The small changing of I1 give the large changing of I2 or I1 is directly proportional to I2 Note

QUESTION 7 Part (a)(i) Mark 1 1 Answer Complete the ray diagram in Diagram 7.2 correctly Two reflected rays are shown (diagram) Angle of incidence = Angle of reflection (diagram) Note

(a)(ii) (a)(iii) (b)(i)

1 1 1

State the phenomenon involved correctly Reflection State the problem that happens correctly The driver in car P cannot see car Q // field of view very small Name the curve mirror correctly Convex mirror

Part (b)(ii)

Mark 1 1

Answer Complete the ray diagram in Diagram 7.3 correctly Two reflected rays are shown (diagram) Angle of incidence = Angle of reflection (diagram)

Note

(b)(iii) (a)(iii) (b)(i) (c)(i) (c)(ii)

1 1 1 1 1

State the solution of the problem in (a) (iii) correctly The convex mirror increase the field of view State the problem that happens correctly The driver in car P cannot see car Q // field of view very small Name the curve mirror correctly Convex mirror Give the correct answer Unchanged Give the reason correctly The characteristics of image of a convex mirror not depends on the focal length

Total

10

Question 8 Bhg (a) (b) Markah 1 1 1 1 1 1 1 1 1 (d) 1 1 1 Jawapan Isotope that are not stable Isotop yang nukleusnya tidak stabil D The reading of ratemeter is highest Bacaan meter kadar paling tinggi26 2 8 8

Catatan

(c) (i) (c) (ii)

Ra

22 2 8 6

Rn +

4 2

He

Symbol alfa betul - 1 Persamaan seimbang -1

100% 50% 25% 12.5% Sodium-24 : 3T = 45 T = 15 hours Cobalt-60 : T = 15.9/3 = 5.3 years Radium-226 : T = 4860/3 = 1620 years Sodium-24 Half life is short @ activity decreases faster Setengah hayat pendek @ keaktifan cepat berkurang Emmits beta rays @ can penetrate ground but cant penetrate pipe Memancarkan sinar beta @ boleh menembusi tanah tetapi tidak boleh menembusi paip

12 markah

SECTION BQuestion 9 Bhgn. Markah Jawapan Area per unit square // P = F / A 200 / 0.2 = 1000 N m-2 800 / 0.8 = 1000 N m-2 Pressure at P = Q =R Force is directly proportional to the surface area Pressure is applied to the toothpaste (tube) The toothpaste carry and apply the pressure of the equal magnitude to the whole tube Pascals Principle modification piston of bigger crosssectional area Low density material Non-compressible liquid Longer handle Apply released valve between small and main reservoir explanation Can support greater force (weight) Lightweight // easy to carry Piston can be lifted up Less effort needed to press the small piston Liquid can flows into small reservoir Catatan Define symbols used With unit Accept without unit Soalan 9 (a)(i) 1 (ii) 1 1 1 1 1 1 1 1 1

(b)

(c) 1,2 3,4 5,6 7,8 9,10

Accept any reasonable modification

Question 10 Q10/S10 Sect. Mark (a)(i) 1 (b) 6

1 1

State the definition of current correctly The rate of charge flows.

(c)

3

(d)

10

State the correct comparison of the type of circuit connection Diagram 10.1 connected in series and Diagram 10.2 connected in parallel. 2 State the correct comparison of the ammeters reading The reading of ammeter in Diagram 10.2 is greater than in Diagram 10.1. 3 State the correct comparison of the voltmeters readings The reading of voltmeter in Diagram 10.1 > Diagram 10.2. 4 State the correct comparison of the effective resistance The effective resistance in Diagram 10.2 < Diagram 10.1. 5 State the correct relation between the effective resistance and the current flows Effective resistance increases, the current flows decreases. 6 State the correct relation between type of circuit connection and effective resistance. Circuit connected in parallel, the effective resistance decreases. 1 State the correct happens of the ammeter reading The ammeter reading increased 2 State the correct happens of voltmeter reading The voltmeter reading decreased. 3 State the correct reason Effective resistance in the circuit decreased. State the correct extra device attached and correct reason 1 Attach one fuse to the live wire in the consumer unit/ fuse box. 2 To break/switch off the circuit when large current before the wire become hotter and produce fire. State the correct choosing of wire/cable and correct reason 3 Using the insulating wires // thicker wires 4 To prevent short circuit // To reduce resistance, improve efficiency. State the correct adjustment of each lamp and the correct reason 5 Attach switch for each lamp. 6 To allows each lamp to be switched on and off independently. State the correct modification of connection of metal fitting lamp and give the correct reason 7 Connect the metal fitting lamp to the earth wire/cable. 8 To flows electron (extra) to earth to avoid lethal shock. State the correct using of bulbs and give the correct reason 9 Using only 240 V light bulb. 10 To ensure the bulbs light up with normal brightness.

Total : 20

SECTION CQuestion 11 Bhg Mrk Soalan 11 (a) 1 (b) (i) 1 2 3 ( ii ) 1 Aerofoil / airfoil The shape of cross section of the wing causes the speed of airflow Above the wings to be higher than the speed of airflow below When the speed of moving air is higher ,the pressure is lower Hence air pressure below the wings is higher compare to above the wings Bernoullis principle A shape of cross section which is upper side is longer than the bottom To produced the speed of airflow Above the wings to be higher than the speed of airflow below The larger the area of the wing The larger the lift force The less density of the wing materials Less weight // produce more upward resultant force The higher the difference in speed of air The higher the difference in pressure The most suitable choice is P Because it has A shape of cross section which is upper side is longer than the bottom The larger the area of the wing The less density of the wing materials The higher the difference in speed of air P= F/A F=PA F=500 x 40 F = 20000N Resultant force = 20000 900(9.8) = 11180N Upward F =ma a=F/m Jawapan Catatan

( c)

1 2 3 4 5 6 7 8 9 10

(d)(i) 1 2 (ii) 1 (iii) 2

Total

1 20

a=12.42ms-2

Question 12 Section Mark 12(a) (b) 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

Answer Electric to sound Current flows and soft iron core is magnetised Hammer hit the gong Contacts open Soft iron core loses its magnetism Size of the hammer is big Surface area contact is big Larger distance between the hammer and the gong The force applied on the gong is greater The number of turns of the coil is greater The strength of the magnetism is greater High curvature of the gong The area of air molecule vibrate is greater Q Size of the hammer is big, Larger distance between the hammer and the gong, The number of turns of the coil is greater, High curvature of the gong I=1 0 1 2

(c)

(d)(i) 1 1 (ii) 1 1 1

0.83 A (with unit) 10 x100 PI = 80 = 12.5 W I= 1 .5 2 / 0.052 A (accept e.c.f) 20 4

TOTAL

20 M

section A1

(a) (i) (ii) (iii) (b)

Refractive index, type of transparent material / n Refracted angle / r Incident ang