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SULIT 1449/2(GMP) 1449/2(GMP) Mathematics Kertas 2 ( Set 1 ) Peraturan Pemarkahan 2017 SKEMA PRAKTIS BESTARI PROJEK JAWAB UNTUK JAYA (JUJ) 2017 MATHEMATICS Kertas 2 SET 1 PERATURAN PEMARKAHAN UNTUK KEGUNAAN GURU MATA PELAJARAN SAHAJA Peraturan pemarkahan ini mengandungi 13 halaman bercetak [Lihat halaman sebelah 1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

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  • SULIT 1449/2(GMP)

    1449/2(GMP)

    Mathematics

    Kertas 2 ( Set 1 )

    Peraturan

    Pemarkahan

    2017

    SKEMA PRAKTIS BESTARI

    PROJEK JAWAB UNTUK JAYA (JUJ) 2017

    MATHEMATICS

    Kertas 2

    SET 1

    PERATURAN PEMARKAHAN

    UNTUK KEGUNAAN GURU MATA PELAJARAN SAHAJA

    Peraturan pemarkahan ini mengandungi 13 halaman bercetak

    [Lihat halaman sebelah

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

  • SULIT 2 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    1(a)

    (b)

    P1

    P2

    3

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang

    L

    K M

    K L

    M

  • SULIT 3 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    2

    (3x + 2)2 = ½ (4x + 8)4x

    x2 - 4x + 4 = 0

    (x – 2)(x-2)

    Perimeter = 32

    K1

    K1

    KI

    N1

    4

    3

    p + 2q = - 9 ------------ (1)

    (1) × 5

    5p + 10q = - 45 ------------ (2)

    5p - q = - 1 ------------ (3)

    (2) - (3),

    11q = -44

    q = - 4

    5p + 4 = - 1

    5p = - 5

    p = -1

    ∴ p = -1, q = - 4

    K1

    K1

    N1N1

    4

    [ Lihat halaman sebelah

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

  • SULIT 4 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    4 (a) ∠SVR

    (b) tan ∠SVR =

    11

    9

    ∠SVR = tan−1 11

    9

    = 39.29° or 39o 19’

    P1

    K1

    N1

    3

    5

    3

    4m

    C )1(3

    48 or C )5(

    3

    40

    C = 3

    20

    3

    20

    3

    4 xy

    DF = 6 unit or DE = 8 unit or EF = 10 unit

    Coordinate of point G is (5, 10)

    P1

    K1

    K1

    K1

    N1

    5

    6

    = 6 × (10 × 3 × 2)

    = 360 𝑐𝑚3

    = 4

    3

    22

    7× 0.53

    = 0.52

    = 40 0.52

    = 20.8

    = 360 𝑐𝑚3 20.8 = 17.31 17 necklaces

    K1

    K1

    K1

    N1

    4

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

  • SULIT 5 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    7

    (a) i. True

    ii. False

    (b) Implication 1 : If 15x > 45 then x > 3 Implication 2 : If x > 3 then 15 x > 45

    (c) ABCD is a trapezium

    P1

    P1

    P1

    P1

    P1

    5

    8. m = 5 , k = -9

    (4 39 8

    ) (𝑥𝑦) = (

    611

    )

    (𝑥𝑦) =

    1

    4(8) − 3(9)(

    8 −3−9 4

    ) (6

    11)

    (𝑥𝑦) = (

    3−2

    )

    𝑥 = 3 𝑦 = −2

    P1,P1

    P1

    K1

    N1N1

    6

    9.

    )7()7

    22()2(

    2

    1)14()

    7

    22()2(

    360

    240or

    )7()7

    22()2(

    2

    1)14()

    7

    22()2(

    360

    24014

    = 94.67

    )14)(14()7

    22(

    360

    240 or )7)(7()7

    22(

    2

    1

    )14)(14()7

    22(

    360

    240 )7)(7()7

    22(

    2

    1

    = 333.67

    K1

    K1

    N1

    K1

    K1

    N1

    6

    [ Lihat halaman sebelah

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

  • SULIT 6 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    10

    (a) (E,2) (E,0) (E,1) (E,7) (X,2) (X,0) (X,1) (X,7) (A,2) (A,0) (A,1) (A,7) (M,2) (M,0) (M,1)(M,7)

    (b) (i) (E,2) (A,2)

    1

    8

    (ii) (E,1) (E,7) (X,1) (X,7) (A,1) (A,7) (M,2) (M,0) (M,1) (M,7)

    5

    8

    P2

    K1

    N1

    K1

    N1

    6

    11 (a) 8 – 5 = 3

    (b) 05

    050

    = 10

    (c) 105050

    k

    k = 10

    P1

    K1

    N1

    K1

    N1

    5

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

  • SULIT 7 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    12

    (a)

    (b)

    (c)

    (d)

    Graph

    Axes are drawn in the correct direction, uniform scale for

    -5 x 3.

    7 points and 2 points* plotted accurately

    Smooth and continuous curve without straight line(s) and

    passes through all the 9 correct points for -5 x 3.

    (i) 6 < y < 8

    (ii) 2.6 < x < 2.7, -3.0 < x < -3.1

    Note: Do not accept the values of x and y obtained by calculation

    The straight line y = 7x + 30 drawn correctly

    Identify the equation y = 7x + 30 or equivalent award K1

    The value of x: -2.9 < x < - 2.7

    x -3.5 0.5

    y 23.25 - 8.75

    P1P1

    P1

    K2

    N1

    P1

    P1P1

    K2

    N1

    [ Lihat halaman sebelah

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

    12

  • SULIT 8 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    13(a)

    (i)

    (ii)

    (b)(i)

    (ii)

    ( 0, - 2 )

    ( 4 , - 1 )

    ( 6 , 2 ) seen or plot on graph award K1

    M : Rotation 900 , anticlockwise, at ( 0, - 3 )

    N : Enlargement with scale factor 3 at centre E

    ( 32 x 35 ) - 35

    280 m2

    P1

    P2

    P3

    P3

    K2

    N1

    14.

    (a)

    (b)

    Column I Column II Column III

    Weight

    Berat

    Midpoint

    Titik tengah

    Frequency

    Kekerapan

    30 – 39 34.5 2

    40 – 49 44.5 6

    50 – 59 54.5 7

    60 – 69 64.5 10

    70 – 79 74.5 8

    80 – 89 84.5 4

    90 – 99 94.5 3

    Column I (all class interval correct)

    Column II (all midpoint correct)

    Column III (all frequency correct)

    40

    )3(5.94)4(5.84)8(5.74)10(5.64)7(5.54)6(5.44)2(5.34

    64.50

    P1

    P1

    P2

    K2

    N1

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

    12

  • SULIT 9 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    (c)

    (d)

    Refer graph:

    Axes drawn in the correct directions with uniform scales,

    for 29.5 ≤ x ≤ 99.5 and 0 ≤ y ≤ 10.

    Horizontal axis labelled by using upper boundary ormidpoint or class

    interval and 7* bars drawn correctly

    Histogram drawn correctly

    Note :

    1. 5 or 6 bars drawn correctly award K1

    2. Other uniformed scales used award N0.

    The modal class is 60 – 69 or

    any correct information about the weight of meat sold each day.

    P1

    K2

    N1

    K1

    15

    (a)

    The shape must be correct. All lines must be fully drawn.

    Measurement must be accurate to 0.2 cm and all angles = 90o 1

    *Note: The shape is correctly drawn award 1 m

    K1

    K1

    N1

    [ Lihat halaman sebelah

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

    12

    6 cm

    T/S X/R

    U/P V

    Y/Q

    2 cm 2 cm W

  • X/W Y/I

    R/S

    H/E G/F

    Q/P

    V

    U T

    2 cm

    3 cm

    1 cm 4 cm

    6 cm

    SULIT 10 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    (b)(i)

    The shape must be correct. All lines must be fully drawn.

    Measurement must be accurate to 0.2 cm and all angles = 90o 1

    *Note: The shape is correctly drawn award 1 m

    (ii)

    The shape must be right with the rectangles. All lines included the dotted

    lines must be shown completely.

    Measurement must be accurate to 0.2 cm and all angles at rectangle

    vertex = 90o 1

    *Note: The shape is correctly drawn award 1 m

    K1K1

    N2

    K1K1K1

    N2

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

    V/I/W Y/X

    G/H

    Q/R P/S

    F/E

    U/T 4 cm

    1 cm

    4 cm

    3 cm

    2 cm

    12

  • SULIT 11 1449/2(GMP)

    Question Solution and Mark Scheme Marks

    16

    (a)

    (b) R(46oU , 110oT)

    (c) (i) (70 +110) 60 kos 46 + 2760

    10262.3

    (ii). 600

    3.10262

    17.10

    P1 P1

    P1

    P1P1P1

    K1K1K1

    N1

    K1

    N1

    [Lihat Sebelah

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

    P

    Q R

    12

  • SULIT 12 1449/2(GMP)

    1449/2(GMP) © 2017 Hak Cipta JUJ Pahang SULIT

    y

    x

    60

    50

    40

    30

    20

    10

    0

    -10

    -20

    -30

    -40

    -5 - 4 - 3 - 2 - 1 1 2 3

  • SULIT 13 1449/2(GMP)

    Question 14 Histogram

    34.5 44.5 54.5 64.5 74.5 84.5 94.5

    94.5

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10

    0

    Frequency

    Weight