stpm trial 2009 che q&a kelantan

8/14/2019 STPM Trial 2009 Che Q&A Kelantan

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JABATAN PELAJARAN KELANTANJALAN DOKTOR, 15000 KOTA BHARU.

TRIAL EXAMINATION2009CHEMISTRY (KIMIA)

SIJIL TINGGI PERSEKOLAHAN MALAYSIA(MALAYSJA HIGHER SCHOOL EDVCATlON)PAPER 1 (KERTAS 1)

MULTIPLE-CHOICE (ANEKA PiLlMAN)One hour Ind f o r t y ~ f i v e minutes (Satu jam empat pulvb tima min it)

Instructions to candidates :DO NOT OPEN THIS BOOKLET UNTIL YOU TOLD TO DO SO

There are fifty questions in this paper. For each question.low suggested answers aregiven. Choose one correct answer and indicale iJ on the mu/tiple-clwice answer sheetprovided.Read the instructions at, the multiple-choice answer sheet very carefully,Answer all questions. Marks will not be deaucledfor wrong answers.Arabln kepada c:aIOD :

JANGAN BUKA BUKU SOALAN INI SEHINGGA ANDA DmENARKANBERBUAT DEMIKlAN

Ada lima pulub soaJon do.lam kerlas in;, Bag; setiup soaian, empal cadanganjawapan diberikan. Pilih satu jawopan yang belul dan randolcan jawopan iIU padnhelaian jawapan aneka pilihan yang dibekalkan.Boca arahan pada helalan jawapan ontko pillluJ" ilU dengan reliti.Jawab semua soolan. Marlwh lidal olean dUolak lxlgijawapan yang salah.

This qUestiOD paper con,ists of 13 printed pages(Kertu loaran iai terdiri daripada 13 balaman Mrutak)

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CONFIDENTIAL -2 -SECTION A

Four suggested answers labelled A, 0, C and 0 are given/or each question. Choose onecorrect a 1. Glucose (C6HI206) is the most importanillutrient in the Living cell fo r generatingchcmjcal potential energy. How many grams ofcarbon are in 16.55 g of glucose?

[Relative Atomic Mass: C- 12; 0>


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CONFIDENTIAL - 3 -5. Use partiaJ orbital diagrams to describe bow mixing ofatomic orbitals on the

centntl .tom leads to lbe bybrid orbital of the methanol, CH,OHA. It i t It i t I

sp'Blt It It I

sp'C. It I t I

spO. It I t I t I t I t I

sp'd

6. Which of the following unil cell does not have all axis . t right angles?A. OrthorhombicB. MonoclinicC. CubicD. Tetragonal

7. In which or the following liquids the particles are held together by Van der W.. sforces?A. SilverB. Sodium chlorideC. WaterD. Silicone dioxide

96211 CONFIDENTIALTh.is question paper is CONFIDENTIAL until the examination is over.

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CONFIDENTIAL -4 -8. The distribution of the kinetic enelSJ ofSa_us molecules at 279 K and 289 K isrepresented by the Maxwell-Boltzman distribution curve below:

Numberofmolecules

279 K289K

Kinetic energy,

Which of the following best explains why the rate of reaction is double when thetemperature is increaserl from 279 K to 289 K?A. The total area under the curve increases two foldsB. The average velocity of the molecules increases two foldsC. 10e number of collision between the particles increases two foldsD. The number of molecules having energy greater or equal to the activation

enelgy, fa, increases by two folds9. The values for 7jnc and silver are given below;

Z r a " + 2e - Zn,AS" + e - AgIt can be concluded that

E' - -0.74 VE' - -H).80 V

A silver is a stronger oxidising agent than zincB 202" is a stronger reducing agent than Ag+C silver is the cathode in the electric cell formed from the combination of thetwo half-celJsD silver will reduce Zn 2+ to Zn

10. In the elcctrolysis of aqueous sodiwn chloride using a mercury cathode, the Na'" ioninstead of the H+ ion is discharged. This is because

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ABCD

mercury is a liquid at room conditionssodium is more reactive than hydrogensodium is above hydrogen in the electrochemical serieshydrogen has a high overvoltage at the mercury electrode

CONFIDENTIALl1tis question puper is CONFID ENTIAL until the examination is over.

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CONFIDENTIALII. Consider the balf-cells below:

Cu '" + e -+ Cueu1++ e _ Cu '"What is the E for the reaction :2Cu - Cu2" + CuA +0.36 VB -0.36 VC +0.68 Vo -0.68 V

12 . Consider the following half-cclls :Fel + e _ Fe lih + 2e -+ 2rSn4 t + 2c _ S04.Cc.l+ + 3e -+ Ce

It can be concluded that iodine willA reduce eel .. to CeB oxidise Ce to CeltC reduce Peh to FeZ+o reduce So4+ to Sn2-f.

-5-

13 . The rate expression for 8 given reaction is:- d fAJ = k [A]

dl

E' - +0.52 VE' - +O.16 V

E' - +0.74 VE' - +0.55 VE'=+O.15 VE' = -2.33 V

Which of the following statements about the reaction is not correct?A It is the fttSt order reaction.B The half-life of the reaction is a constant.C The reaction could be a radioactive decay.D The rate of reaction is independent of the temperature

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CONFIDENTIAL 7

19. Kais better measure for the strengths ofweak acids as compared to pH becauseA its value is easier to measureB its value docs not depend on tempetatureC its vaJue does not depend on the concentration of the acido its value is a whole number20. Consider the following reaction:

' \X+Y " 2ZWhen 8 mixture consisting of 5.0 mol of X and 3.0 mol ofY is allowed to reachequilibrium. 2.0 mol ofZ is fonn. The for the reaction isA 0.125B 0.250C 0.267D 0.500

21. ' \2NO,(g) " N,O. (g) t l l I == negative valueWhich of the following factors is likely to increase the value ofKcfor the abovereaction ?A Addition of the cataJystB Decreasing temperatureC Adding more NO,D Increasing temperature

22. CH,CH,I __ tlw>_ _k_K ..NY isA CH,COONaB CH, CH,COONaC CH,CH,COOHD CH ,CH,CH,cOOH

x y

23. Which of the following alcohol gives 2-methylpropanoic acid when it is ox.idised?A IbutanolB 2 butanolC 2.methyllpropanolD 2methyl.2propanol

96211 CONFlDENTLALThis questioD paper is CONFIDENTIAL until the examination is over.

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CONFIDENTIAL -8-

24. Which of the following comoounds does not Rive a yellow DreciDitate with alkalineodin ?e.A EthanolB EthanaiC Methno81D Pheny lethanone25. II, (g) 2H (g)

BI'l (8) 2Br (g)H, (g) +Br, (g) 2fIBr(g)6 H +436 kJ6H= + 194 kJ6H= -104 kJ

Use the above data to determine Mi for the following reaction.!i(g) + Br(g) - HBr(g)

A -288 kJB -367 kJC +263 kJo +526 kJ26.The enthalpy data for sodium, bromine and sodium bromide are as follows:

EnthaJpy ofatomisation ofNa - +108 kJ mor lEnthalpy ofatomisation ofBr = +112 kJ mor lFirst ionisation energy ofNa = +496 kJ mor lEnthalpy of formation ofNaBr = -361 kJ mor', ~ . 4-"\ ,a.. - 3 ~ ....rWhat is the enthalpy change for the reaction?NaBr (5) No' (g) + Br (g)

A -331 kj molB -752kJmolC +33 1kJ molo +752 kJ rnol27 .Which of the following equations represent the standard enthalpy of atomisation foriodine?

A I , (g) - 2 1(g)B Y, I (g) - I(S)C y, I, (5) -I g)o 1(5) -1(g)

96211 CONFIDENTIALTh.is question paper is CONFIDENTIAL until the examination is over.

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CONFIDENTIAL 9 28 . R is a second period element with a valence electronic configuration ofns1np",Which of the following is Dot a compound ofR?A. RF,B. Na,RC. RCI ,D. H,R29. Compared 10 barium, berylliumA. is 8 stronger reducing agentB. forms a more basic oxide.C. reacts more vigorousl y with water.D. fonns more covalent compoWKis .30. Which of the following stalements is true aboUI NoCI and NaI?A. NoI is less volatile than NoCI.B. r has a higher chargc density than cr.C. Nal is a stronger reducing agent than NaC!.D. NoCI and Nal arc both while solids.31. The following oxides are amphoteric esc.eptA. AhO ,B. PhO,C. SnOD. SiD,32. The following is true of nitric acid ucept

I 'd' F , . F :l


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CONFIDENTIAL - 10 -34. Which of the series of oxides shows increasing melting point?A. CI,O, Al,O,. SO,. Sio,.B. SO,. Al,O,. Sio, Cho,.C. SO,. CI,O,. Sio,. AI,O,.D. Sio,. Al,o,. Cho,. So,.35 \\ hieh o f tile' fnllo,",ing in n q \ l ~ o u s so lution of equa l COnCf'll lrnTioll


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CONFIDENTIAL - II -39 . Pheny lamine is a weaker bnse than ammonia becauseA ammonia is an ionic compOlmd while phenylamine is a covalent compoundB the lone pair electrons in phenylamine can be delocalized into the benzene ring.e ammonia is soluble in water while phenylamine is not.D the large phenyl group in phenylamine hinders the attacks by H,O'

40 . Which oflhe following statements is true of 21ass?A. It consists ofwell-ananged silicate Wlits.B. It withstands the aetion of strong alkaline.C. It softens at a wide range oftempetBlures.D. It can be coloured by arlding soda lirn


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CONFIDENTIAL - 12 -42. Which of the following statements is true ofelectrons occupying an atom?

1 Electrons occupy orbitals based on the Aufbau Principle.2 Each orbital can contain a maximum of two electrons.J The two electrons in an orbital have opposite spin

43. The quantity of substances produced during electrolysis depends onJ the magninlde oflhe current2 temperature3 the concentration of the aqueous ion

44. Which oflhe following solutions wilJ produce hydrogen gas when eJectrotysed usingplatinum electrodes ?1. dilute sodium hydroxide2. dilute sodium cbloride3. dilute hydrochloric acid

45. During the anodisation of aluminiumI. oxygen is liberated at the aluminium electrode2. the electrolyte used is an aqueous solution ofaJuminium sulphate3. aluminium is made the cathode

46. The following graph shows the energy profile for the reaction: P '; ! QEne rgy

E,

Which of the foUowioe. are true ?1 The activation of the reverse reaction is Ez2 The enthaJpy change of reaction is E1-

reaction pathway

3 Addition of a catalyst can aJler the value of E. llDd E::z

%211 CONFIDENTIAL*This question paper is CONFIDENTIAL Wlul the examination is over.

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CONFIDENTIAL - 13 -

47. The mte equation for the reaction: A + B - products, is

The value of k depends onI . catalyst2. the values ofx and y3. the concentration ofA and B

48. Which of the following compounds will react with ethanoyl chloride?I Water2 Phcnylamine3 Propanal

49 . Which of the following arc characteristic of the benzene molecule?I. It is planar2. It undergoes electrophilic substitution reaction3. All the carbon a10m undergoes Sp2 bybridisation

50. Which of the following molecules have polar bond but have no overal l dipoles ?

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I CI,2 C,H,3 'BeCl,

THE END OF QUESTION PAPER

CONFIDENTIALThis question paper is CONFIDENTIAL until the examination is over.

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962/2JABATAN PELAJARAN KELANTAN

JALAN DOKTOR, 15000 KOTA BHARU.TRIAL EXAMINATlON2009CHEMISTRY (KIMlA)

SIJIL TlNGGI PERSEKOLAHAN MALAYSIA(MALAYSIA HIGHER SCHOOL EDUCATION)PAPER 2 (KERTAS 2)

Two aod I bllf bour (Duo jam . . . .ngab )DO NOT OPEN TlDS BOOKLET UNTIL YOU TOLD TO DO SO

Arahan kepada calon :Jawab $(!JfUlII soaJan da/am &ltaglllif A d%m l'1Iong yang disl!diaJtan.Setnua ierja mesliJd ditunj uU(l'1. Bag; jawapan MrangAa. unitmrstllah dinyolakon manu-mana yang suuoi.Jawab mono-mana myHIt Soa/on daripada Bda,l i I l I B. Unlukbohogian in f, ,ulis jawopon andu poda he/aian Jawupon yangdibellI/ion. Mllldkansellap jawapan poda helalan k "'m yang baru.dan StlSun jawapan anJa mettgiiul tl!Nib berongk4 /lealMlo ianJ(m'apon ando busama bub soo/an in i.Jowapan b o I ~ d/lulis do/am hohaso Mclayu DUJU bahasa 'nggerls.BuA" D{I(a dlbela/Um.Instructions to candidates :Anmer .u he quut/OU In St/o" A in Ihe spaces provided. AllO f ' k ,"lUI be s/JQwn. FiX numer ical ( ~ ' e n units IffJIst quoted

Vo'hUffVU they (ll 'e approprlUlLAn,wv anyfo,,, quesliOlU from Section IJ. For Ihis section, wr /le youranswers on Ihe answer shuts provided Begin eoclr on afre3hsheet ofpafWr, and arrange your QtJ.nI.crs in numerical ordu. TieYO III'atJ.nl.'t'I" sheets to Ihu booAlel,Answers may be y.'rinen In eillwr Malay or English.A Doto lJoojjet isprovided

Untuk kegunaanpemcriksa( For examiner 's use12J -+56,89 +10

Jumlabl..m>t!!llThis question paper consists of 13 printed pages(KertaJ sollan iui ferdin dllnpada 13 hal.man bercetak)

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CONFIDENTIAL 2SECTION A [40 mar .

Answer all qlltrtinn.


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CONFIDENTIAL 3

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(ii) If the ratio of chlorine-35 10 chJorine-37 is 3: I and bromine-7910 bromine-81 isI : I calculate the relative abundance of the peaks. [3marks]

mle Relative abundance154

156

158

b) Phosphorus is an element of group 15. PhosphOrus react W1ln Chlonne to lormphosphorus trich loride, PCI, and phosphorus pcntachloride, PCI ,.(i) Write the electronic configuration afthe phosphorus atom.

[I mark]

.................... ................ .. ... ......... ...................... ... ....... ...... .....(ii) Stale the typc ofhybridisalion in PCI, and PCI,

[I mark]

(iii) Suggestwbethcr nitrogen will form a pcllthachloridc, Nels. Explain youranswer. [2mark]

.. ....... ...... ..... .... ... .. ...... ... ...... .. ... ................ ........................... 0 0

.... 0000 .. .. . ...... ........ ..... . ...... . .. . . .. ............... .. .................... 0 .. . .. . .

...... ........................................... ......................... ..................... ..............................CONFIDENTIAL

This question paper is CONFIDENTIAL until the examioaljon is over.

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CONFIDENTIAL 42. The decomposition ofbydrogcn peroxide is a fir.Jl order reaction.

2H,o, (oq) - 2H,O (I) + 0 , (g)(8) Explain what is meant by order o/reaction ? [2marks]

. .. ... -........ ... ..................... . ............... .......... .... ...... ............. ... .. ....... . . . . . . . . . . . . . . . . .

(b) Write the rate equation for the decomposition of hydrogen peroxide. (1 mark)

(c) The rate constant for the reaction at 298K is 3.42 x mol d r SO (i) Calculate the rate of decomposition of hydrogen iX'iOKide when the concentrationis 1.25 x 10-' mol dro- [1 mark]

:ii) is the rate ofproduction of oxygen at the same instant ? [1 mark]

(iii) Calculate the half-life of the reaction . [2 marks]

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CO NFlDENTIAL 5c) Sketch a graph to show the variation of the concentration ofhydrogen peroxide

with time. You may assume that the initial concentrationofhydrogen peroxideis t .Omol dm .

[31

96212 CONfIDENTIAL*This question paper is CONFIDENTJAL Wltil the examination is over.

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CONF IDENTIAL 6

3. An important use of silicon compounds is to make glass. The simp lest fonn ofglass is soda glass which is produced by melting silica (Sio,), sodium carbonateand calc ium carbonate at about 1800 K.

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(a) Name a subslance which can be added to soda glass in order to(i) increase its melting point. [I mark]

(ii) give a coloured product. [I rom]................ ... .... ............... ..... ...... ... ....... ..... .... .. ........ .. ......... ..

(b) Give a difference in terms ofbonding and structure between glass and ioniccrystal. [2marlcsJ... ....................... .. ............ ... ..... .......... .... ... ... ....... .. ...... .. ............ .. .... ... . . . . . . .... . . . . .... . .

(c) Group 14 clements can react with chlorine to fonn a tetrachloride.i) In the following table, give the name of the process (if any) and the

equation of the reaction which occurs.

[4marlcs]ii) Explain the differences of the reaction between the three tetrachlorides abovewith water [2marks]

..... ..... .... ........ ............ ............ .. .. ... .... ... .... .......... .. ... .. .... ..... ... .. ........ ...... ... ........ ..... ................... ...... .......... .... .... ................. ......

CONFIDENTIALThis question paper is CONF IDENTIAL until the examination is over.

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CONFIDENTIAL 7

..l . or8MUc compouud x: of1ll0h'U" U l a ~ ~ o f 136.9g I UO r l h.n\ tbe followingc O l u l ' o ~ i t i o u by 1l1:l'So'So:I I(AI Dctenni'1C' rhe lnolec\llt1 r foron'lf! ofX .

l 2: w."u'ks ](b \Vbcu X is boiled under n::flux with aqueous ,,"odium hydroxide. 2.mcthyl l prop :''lUol is formed .( i ) DJ'OW the su 'ucnu'nl fOl"llluln of X

( u ) Srmc the meCh:lul'illl of th e I'cnetion. . .. . ... ,. ...... . . . .. ..... . ... ...... ...... _.. .... ..... ..... . ..... ......

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CONFIDENTIAL 8

(c, \,"hen X i i lI'c:afcd with:m olc:oholic ioluriou o f sodium hycboxide . :\11 olkcuc Yi i fonncd . Y 1"C,'Ch with h Y c U o ~ c n bromide to tOl"Ul Z which i i 111 io;OOlCf of X

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( i) Y h.u tOUl' i . o m e ~ Give: the \tt''Ucfiu-ol fOrlnuln fOI" the i",oJ\lcr thatexhibih ilcom,ctric:d is.omcTiwl

( u) Dl":1w tbe 'iotJ"\lcmrRI tOJ"1\lu!n for Z

( ii i) 5!r:nc oue i'JOlUer of Alkene Y th..."If produce\. c.:uWu dIOXide wbeu healedwith couccutnuc:d acidified Ja.JuO.;':' Qj,c 3l } equation for the 1 ~ . 1 C f I l ]somt>I""

\d) Z renct\. with .1que-om \odilUU hydroX1de 10 fOl'll1 AU alcohol PSU,i:g:cst (1 .. uuple chClmC31 Ie . ' 10 diifcl'cnri :nc Ixtwccn 31cohol P2-lllcthyl. J-pl'op:mol

.. .... ... ... . . - . , . . . . . . . . .. . .. . . . .. . ... . . .. ... ..... .. .. .. ....... ... .. ... ....... ................ .. ... .. .... .. ... ... . ..... . .

.. .... . .. .... ....... ........ ... .... ...... .... .... ...... .. ...... ....... .. .

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CONFIDENTIAL 9SECfION B [60 marko]

Answer any four queslions in this section.5(0) The boiling points and solubilities ofammonia, hydrogen chloride and carbondioxide gases are given in the table below.

Relative Molecular Boiling Solubility inGas Formula pointl'C waterMass, M, I mol drn'Ammonia NH, 17.0 -33 18Hydrogen HCI 36.5 -85 23chlorideCarbon CO 2 44.0 -78 0.033dioxide

(i) Explain the variation in the boiling points and solubilities of the gases relating tobonding. [5 marks](ii) Ammonia dissolves in water to produce ammonium ion. Draw the Lewis structureand predict the shape of ammonium ion. [3 marksJ

(b) A galvanic cell consists ofa zinc electrode and a hydrogen electrode as shown in thed.iagram below;& voltmetere

PI(+) A-. eLOa Sait bridge.. , Zn(-)

- - --------H' (aq) :: ~ J ~ L : : : ~ : : ----------------- ZnSO .(i.Omol drn-' )

at 298 K------------- . - . - - - - - - - - - ---------------------- - - - - - - - - - - ----

In experiment. the emf of the cell is found to be +0 .54 V at 25C. The pressure of thehydrogen gas is 1.0 atm and the concentration of zinc sulphate is l.O mol dm J

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(i) Calculate the concentration of the W ion in the hydrogen halfcell. [5 marks](ii) What is the effect on the emfof the cellcell is increased ? if the pH of the acid in the hydrogen half[2 marksJ

CONFIDENTIAL-This question paper is CONFIDENTIAL until the exam ination is over.

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CONFIDENTIAL 106. (a) State the Le ClulieUer 's Principle. [2marl


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CONFlDENTW. II

7. (a) Define the standard fonnation and lattice energy of sodium chloride crysta1line.[4 marks]

(b) The possible fluorides formed by an clement M are MF and MF,EntbaplyofatomisationofM = +284.6 kJmor'First ionization energy orM = +731.0 kJmor 'Second ionization energy orM =- +2073 kJmor'Enthaply ofatomisation ofF = +79.0 kJmor'Electron affmity ofF = -322 .0 kJmor'Lattice fonnalioD energy ofMF .. kJmor'Lattice formation energy of MF l D -2260 kJmor l

Using the data above,(i) Draw a Born-Haber cycle for the ronnatioD ofMF.(ii) Calculate the enthalpy of formation ofMF .

[6 marks)[2 marks]

(iii) If the enthalpy of formation ofMF, is + 342.6kJmor', which compoundwill most probably be formed when M reacts with F. [3 marks)

8. (3) What ismeant by a transition clement? [I mark]

(b) Transition clement complexes are often coloured whereas compounds ofothermeWs are usually white . For example , a solution of [ C u ( H 2 0 complex ion isblue but a solut ion of [Cueh]" complex ion is colourless. Explain theseobservations in terms of electronic configurations. [5 marks]

(c) (i) Carbon, silicon, germanium, tin and lead are elements in Group 14 of the PeriodicTable . Describe the variation in acidbasc character of their oxides.

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[5 marks](ii) Lead (TV) oxide is a dark-brown solid. When lead (IV) oxide is healed with anaqueous so lution ofa manganese ( II) salt in the presence of excess nitric (V) acid, thereaction that takes place is as follows.

2Mn' + 4H+ + 5PbO, - 2MnO' + 5Pb>+ + 2H,OExplain how lead (IV) oxide reacts. and state what is observed .

[4 marks)

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CONFIDENTIAL 129 Give an explanation for the foUowing observations to identify the compounds orG, J, K.L.Mand N and write the cbemicaJ equation involved.

(a) The chlorine atom in compound G (C,H,cI) can be replaced readily as a result ofreacljon with dilute aqueous sodium hydroxide. However. the chlorine atom in isomer Jis not affected by the above reaction. [5 marks]

(b) If oompound K (C.H,N) is """ted first with bromine and then ethanoyl chloride ,oompound L (C.HoBr;NO) is obtained. IfK is treated firsl with ethanoyl cbloride and thenfollowed by bromine, oompound M (CaH.BrNO) is the product. [5 marks](c) Compound N (c..HIOO). can exist as a pair of optical isomers and reacts withphosphorous pcnlachloride to give hydrogen chloride. [5 marks]

10. The amino acid tyrosine, lysine and glycine are constituents ofmany proteins.0I

H,N C,.. C 0"I 0IIC H ~ C- 1 ,N -CH -C - OH II(YH,) H,N Oi C _ 011,,

11NH2OHtymsine lysine glycine

a) State the reagents and conditions you could use to break proteins down into amino acids.[2marks]

b) Draw a nnR around each chiraJ centre in the above molecuJes.[2 marks]

c) In aqueous solution amino acids exist as zwiuerions. Draw the zwitteronic structure ofglycine.

[I mark]

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CONFIDENTIAL 13

d) For each of the following reactions, draw the structure oftbe organic compound fonned.(i) glycine + excess NaOH(aq).(ii) tyrosine + excess NaOH(aq)(iii) lysine + excess HCI(aq)(iV) tyrosine + excess Br,(aq) [5marksl

e) Draw the structuml formula of a tripeptide formed from aU three of these ruTtino acids,showing clearly peptide bonds.

[2 marks)I) The formula ofpan of chain of a synthetic polyamide is shown below.

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(i) Identify the repeat unit of polymer by drawing square brackets around iton the above formula .

(ii)' Draw the structure of two monomers from which the polymer couJd bemade.

(iii) Name the type ofpolymeri7.ation of po lym er shown above.[3 marks]

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Answer

1. B 26. D

2. D 27. C

3. D 28. A4. A 29. D

5. A 30. C

6. B 31. D

7. C 32. D

8. D 33. A

9. C 34. C

10. D 35. B

11. A 36. D

12. B 37. A

13. D 38. A

14. C 39. B

15. D 40. C

16. C 41. A17. A 42. D

18. D 43. A

19. C 44. D

20. D 45. A

21. B 46. D

22. B 47. A

23. C 48. B

24. C 49. D

25. B 50. C

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(b)

SECfIONA

I. (a) (i)mi.154156

158(ii)

mi.154

156

158

,STPM Trial exam2009PAPER 2Kelantan

IonsC H,"CI" Br ,C, H,"sr"C I+c,Hl 'CI"Br, C,H} 'Br"CI+c,Hl 'C I" Br , C,H." Br"CI +c)Hl7CI8I Br"" C,H." Br"CI'

Relative abundance"CI"sr : or 3

: ) "CI" Br : (lx l )2 - 1-8 or 4"CI" Br : ( lxl)2 2 or I

(i) I , ' 2,' 2p'3, ' 3p'(ii) PCI , - ,p ' and PCI, - ,p' d(iii) Nitrogen cannot form a penthachloride, Nels becausenitrogen do not have d orbital.

I

(1+1+1]

[1 +1+ 1](I](1+I][I + ]

Total 11Muimum 10

2. (a) The power to which the concentration ofa substance is raised in an experimentallydetermined the rate equation . [2J(b) Rate k[H,O,](c)(i) Rate (3.42 X 10 ' X1.25 X 10.2 )


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3.

In 2(e) H a l f l i f e k0.693

- 3.42xI0 )

(f)[H,o,)moldm -)

- 202.6 s

1.0

0.5

0.25

(a) (i) Boron oxide(ii) Nickel oxide

(b) In glass , there is no regular arrangement of particles.The arrangement is just like in liquid.

Time I s

However, in crystalline ionic so lids, the ions are arranged in an ordered andclole;lyoacked manner.

(e) (i)

PbCI. +

i l lTotal 10

[I]

[ I)

[I )[I)[I)

[11

[4)(ii) S i C ~ and b C ~ have empty d orbitals which are snacked by lone pair electrons of water molecules.

But in eeL.. the carbon atom does not contain d orbitals. [ 1+1]Total: 10

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... .4 (a)

C H BrNo . ofmoles 135 .2112 = 2.9 I 6.5 /1= 6.5 I 58 .3/80 = 0.73II Mole . . io 4 9 1 1m

Molar mass : 136 .9Molecular fonnula : C.H,Br lUI

:!:@ I (i) I I .. . ICH ,I 1mCH, - CH - CH,B,

(U) Nucleophilic substitution SN2 (primary haloi:t'n alkanes) 1m(e) (Q H HI I 1mCH.J - C = C- CH, or CH, CH = CHCH,

(n) CH ,I 1mCH, - C - CH,IBr(iU) I SOMer . CH ) CH2 - CH "" CH2 or CH,- C - CH, 1mICH,

EquIJrlo,. :CH, CH, - CH - CFh + 5(OJ CH, CH2 - COOH +C0z+ HP lIDOr C(CH,lFCH, + 4[0] (CH,),C-o + CO , + H2O

(d) -Wann wit h aqueous acidified KMnO . 1m.Alcohol P does oot decolourisc the purple solution.-2-metbyl- l- propanol decolour1ses the purpk solution. (oxidation of 1mLE ' alcohols10m

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SECTION B5(a)(i)

NH,

HCI

co,

bonds between> r e

dcr Waals forces orbetween Co, HCI + H,O 7 H,O' + crmolecules arestronger than van derWaals forces betweenHCI molecules

H +

are nonwhereas water molecules arepolar

(a)(ii) H 'til HH

N 5e4H 4eCharge +1 8e 4 bonding pair.;Shape : Tetrahedron

5(c) (i) Zn (s) +. 2W(aq) 7 Zn" (aq) + H,(g)-+1).54 =

+0 .54 =

[z '- ]?E' 0.059 I n H ,"" - 2 og [H ' ]'(0-(-0.76 _ 0.059 10 1. 0% 1.02 g [W ] '+0. 76 + 0.059 x 210g[W]2

log [H1 = -3.73pH - -log [H']- 3.73(ii) If the pH of acid increases, IWI decreases

emf of the cell decreases

[I+ I]

[1 +1+1]

-[ I]

[I][I ]

[I]

[ I]

[ I ]

[I][ I][I][I]-1Total IS

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5

6.(a) Le Chlltelier 's principle states that if asys tem in eq uilibrium is disturbed, the equilibriumwill shift to ca .Dcel out the effect of the change. [2)

(b) (i) Increasing the pressu", will couse the equilibriwn shift to the left [I]

(ii)

because the foward reaction involves an increase in the number ormolcs of gas .or I mol? 2 mol [I](ii) The reaction to the ripht is endothermic . [I]Thus heating will cause the equilibrium position ti l move to the right. [IJ(iii) The equilibrium will shift to the right because more cr04' ions react r ]with W ions to produce CC20,"and H20.Thus the concentration ofW ions can be reduced. [I]

(c) (i) Total gas ratio - 2+ I =3Initial paroal press"", of So, = 2/3 x J = 2 atmInitial partial press"", of0, - 113 x J - I atm2So,(g)+ O,(g) +:! 2S0,(g)

1.9atm

[ I]

From the equation above, to produce 1.9 atm o[SO), 1.9 aIm S02and 0.95 atm 0[02 mustreact.Psm = 2 - 1.9 - 0.1 atmPo, = I - 0.95 - 0.05 atmPlOW "" PSOl + POl + POOl= 0.1 + 0.05 + 1.9

[I][I)

= 2.05 atm [I]Percentage of cbange from So, to SO, .JQitial pressure of S(h is 2 atm. 1.9 atm of S02 has reacted to become SOJ.Therefore, percentage of change - 1.9 / 2.0 x 100 - 95% [I]2S0,(g) + 0, 2S0, (g)Kp =

( P ~ ) (Pm)- iH;'(OO5)= 7220 atm-!

[I )

[I]7

Total : 15

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6

7 (a) 0) The enthalpy change when one mole of an ionic compound is fonned from its element, alstandard condition. [I J

1Na (,) + 2" Ch (J) - NaCI (,)[I + IJ

(ii) The energy released when one mole of an ionic comoound is fonned from itsgaseous ion at standard condition.

(b) (i)

(ii)

-969.0

---'O!MFW+731.0 322.0+284 .6 +79 .0

M (s) +

6 H((M) = + 284.6 +731.0 + 79 .0 - 322.0 - 969 .06 H((MF) = -196 .4 icJmor '

[lJ[I + IJ

[5J[lJ[lJ

(iii) MF because its enthalpy of fannalian is more exothermic . This show s thatMF is more stable since its enthaJpy is lower. [2JTotal: IS

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8.(a) Transition elements are defined as d-block elements that can form at least one stable ion withpartially-filled d orbital. [I]

[Notes:

3d 4s(b) Cu ' in [CuC],]" 1 1 ~ 1 1 ~ 1 1 j j 1 ~ 1 1 ~ 1 Q

CU"in[Cu(H,Ol6]" 1 1 ~ 1 1 v 1 1 0 1 0 1 I 0Splitting of the energy of the 3d-orbitals occur.

[I][I]

[I]Electrons in the low energy 3d-level of Cu2+ absorbs (red) light and move into the high energy3d- level. I dod transition occurs. [I]No dod transition occurs. [I]

(c) (i) The basicity of the oxides increases down the group.CO is neutral .Si02 and C02 are acidic.Oxides ofGe, Sn and Pb are amphoteric.

[I][I]

[I + ][ IJ

(ii) Lead (IV) oxide I PbO, is an oxidizing agent.I Pb4+ is reduced to Pb 2+.! +2 oxidation state of lead is more stable than +4 oxidation state.Mn 2+ is oxidized to Mn 7+ MnO,,' .! Oxidation state for Mn change from +2 to +7.A redox reaction occurs.Solution turns purple ! violet ! pink at the end of reaction.! dark-brown solid dissolves. ! solid dissolves.

[IJ[I][I J[I]

Total: 15

Transition complexes are coloured because of electronic transition between non-degenerate d orbitals.The transition .(Oetal ions have incomplete 3d sub-shells, d l to d9. As a result, d-d electronic transition ispossible resulting in pair of the visible light spectrum being absorbed. Other non -transition metal ions haveeither completely filled 3d orbital or no 3d electron at all. Hence, dod electronic transition is not possible,they are colourless or white. ]

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9(a)In G, the CI atom is bonded to the side chain hence it can be replaced by hydroxideduring hydrolysis.

Gis 0 -CH,CIo CH ,CI + NaOH 7 o _CH ,OH + NaCIIn J. the Cl atom is attached to the aromatic rin2. The C- CI bond in H is less polar and strong .

J s or CI - CH ,CICI

9(b)K is o NH,With aqueous bromine. 2,4,6-tribromophenylamine is fonned as a white precipitate.

o -NH , + 3Br, 7 Br- o Br. -NH ,Br

With etbanoyl chloride. a substituted amide is fonned.Sr Sr

+ 3HBr

-NH , + CH,COCI 7 B.r- .-NHCOCH,Br (L ) Br + HCI

K with ethanoyl chlorideo NH, + CH,COCI 7 NHCOCH, + HCIWith bromine J substitution occurs at benzene ringo _NHCOCH, + Br, 7

[I][I ]

[I]

[I ]

[I]5

[I]

[I]

[11

[I]

[I ]

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9(c)

N has a ch iral center because it exists as a pair of enantiomers .It is an a1cohol as it reaclS wi th PCI,: to give He) gas.N is CH,CH(OH)CH,CH,

[I][I ][I]C!i,CH(OH)CH,CH, + PCI, CH, CHCICH,CH, + HCI + POC!, [I]

CH,IHif'J "'-CH,CH,H

,,,,,,

No n- superimpossable[I]

5Total : 15

9 (a) He l or H2S0"or H+ .. acidconc(ifHCIoDlyVdilute/aqueo us+ heal1m1m

(b) two ri.ngs only ( I ring around the (I-C ofryrosinc & I around me (Z -e of lysine) 1m(e) C H ~ ~ (or disp layed ronnuta) 1m(d) (i) NH 2CH2C02. (Ns (e ither -C02"Na"'0' -C02Na but NOT -CO-O-Na) 1m

(ii) (N.,) '-Q-C6H4-CH2CH(NH,)CO'- (No ') Iw+lm(iii) (C I)+NH )(CH,).CH(NH)' )CO , H (Cl) Im+lm

(6m )

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(el

(I)(Q(Q.g.

(i)

'0

CH CO.H

stnktWt [IJIII least one peptide group identified [I J

anorOl -01 - 00 'If"CI\- CI\- H1!-

IIIIII

[I)

orClCOI---

(iii) Condensat ion polyrnerisationMaximum :

2m

3m

15m

fllTOIaI : 16

15

paper

stpm trial 2009 che q&a kelantan

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