spm trial 2010 bio ans (pahang)
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MARK SCHEME BIOLOGY 1
SPM TRIAL 2010
NO. JAWAPAN NO. JAWAPAN
1. B 26. D
2. D 27. C
3. A 28. B
4. A 29. D
5. C 30. A
6. D 31. D
7. B 32. B
8. C 33. D
9. B 34. D
10. C 35. D
11. C 36. A
12. A 37. D
13. B 38. A
14. A 39. A
15. A 40. C
16. c 41. D
17. B 42. D
18. D 43. C
19. A 44. C
20. C 45. C
21. C 46. A
22. A 47. C
23. D 48. A
24. C 49. B
25. B 50. D
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 1
PERCUBAAN SPM
TAHUN 2010
BIOLOGIKERTAS 2
SKEMA JAWAPAN
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 2
MARKING SCHEME TRIAL SPM BIOLOGY 2010 PAPER 2
SECTION A
No. Marking criteria Marks
1(a)(i)
(ii)
(b)
(i) Able to draw a line to show the location of structure P, Q
and R in the cell.
(ii) Able to complete Table 1 by stating the function of
structure P and R
Sample answer
P- transports protein made by the ribosomes
R- site where cellular respiration occurs // energy isgenerated
Able to explain the synthesis extracellular enzyme from protein
at the ribosome
Sample answer
P1- Protein enter lumen Rough Endoplasmic Recticulum (RER)
P2- Modified in RER into extracellular enzyme
P3- carried to the Golgi body by transporting vesicle
P4- Processed / Packed in the Golgi body for excretion
Note : maximum 3 marks
1
1
1
11
1
1
11
3
2
3
R
P
Q
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 3
1cAble to explain how to ensure the process Y occurs at a
maximum rate in the washing of blood stain on a shirt
Sample answer :
F1- Use (warm) water with temperature of 370C
P1- optimum temperature for enzyme (activity) // Enzymes
work best at this temperature
F2- Add more soap/alkali solution (in the water)
P2- Enzymes / trypsin / protease work best in an alkaline
medium
OR
F3- Add a little vinegar/ acid (in the water)P3- Enzymes/ pepsin work best in an acidic medium
F1 + P1
(Any pair of F2 + P2 or F3 + P3)
Able to suggest two types of enzyme that would need to be
present in a washing powder designed to remove blood stains.
Sample answer
- Lipase / Protease
1
1
1
1
1
1
1
TOTAL
4
1
13
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 4
2(a)
(b)(i)
(ii)
(c)
(d)(i)
(ii)
Able to name the cell division
Sample answerMitosis
Able to arrange the phase K, L, M and N correctlySample answerL, N, K, M
Note : L, N (1 mark)
K, M (1 Mark)
Able to describe the behavior for each stages
Sample answer
L : (early) anaphase
N : MetaphaseK : Sister chromatids separate and move towards the opposite poles
M : Chromosome align at metaphase plate
Able to explain how radiotherapy method can treat cancer
Sample answer
F : Radioactive rays will kill cancer cells
P : When all the cancer cells are destroyed, they cannot reproduce
by mitosis
Able to give differences between Prophase I and Prophase II
Sample answer
Prophase I Prophase II
P1
P2
There is no synapsis occurs
The chromosomes do notcrossing over
Synapsis occurs betweenhomologous chromosomes
Crossing over occursbetween homologous
chromosomes
Able to explain the significant of maintaining the diploid
number of chromosomes.
Sample answer
In order for the offspring to have the same chromosomal number of
their parent
1
11
1
11
1
1
1
1
1
1
TOTAL
1
2
4
2
2
1
12
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BIOLOGI KERTAS 2 5
3(a)
(b)
(c)(i)
(ii)
Able to state the function of alveoli
Sample answer
Place for gaseous exchange // store the oxygen gas before gaseous
exchange occur
Able to state the characteristic of alveoli
Sample answer
P1 : Have very large total surface area //P2 : have moist surface all the time //
P3 : have very thin wall ( only one single layer of cell
Note : (Any one P)
Able to state the characteristic of trachea
Sample answer
F : have C-shaped cartilage rings // cartilage rings
P : keep the trachea open permanently
P2 : avoid the trachea from collapse when the outside pressure ishigher than inside pressure during inhalation
P3 : oxygen can continuously flow through trachea to the alveoli /
Lung
Note : ( F one mark, P one mark)
Able to draw the arrow to show the flow of oxygen in Figure 3.
1
11
1
1
1
1
1
1
1
2
2
Oxygen goes inCarbon dioxide goes out
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 6
(iii)
(d)
Able to describe how intercostals muscle and diaphragm can
change the volume and pressure in the thoracic cavity during
inhalation
Sample answer
P1 : external intercostal muscles contract/ internal intercostalmuscles relax caused the rib cage moves outwards and
upwardsP2 : diaphragm muscles contract, the diaphragm lower and flatten
P3 : the volume of thoracic cavity increase but the pressure
decrease (lower the atmospheric pressure)P4 : air forced into the lung // alveolus
Able to state the differences between the respiratory system in
human and fishSample answer
P1 : gill is the respiratory organ for fish but lung is for human
P2 : gill have filament and lamella to increase the surface area, butlung have alveoli to increase the surface area
P3 : gill touch / surrounded by water all the time, but lung never
touch/ surrounded by waterP4 : gill received oxygen directly from water, but lung received
oxygen from atmosphere via trachea, bronchus and bronchioles
1
1
1
1
1
1
1
1
TOTAL
3
3
12
4(a)(i)
(ii)
Able to name the type of joint showed in Diagram 4.
Sample answerHinge joint
Able to give is the different between the joint mentioned in
(a)(i) and the joint on the shoulder.
Sample answer
P1 Joint in 4(a)(i) allow movement in one planeP2 joint on the shoulder allow rotational movement in all
directions.
1
11
1
2
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 7
(b)(i)
(ii)
(c)
(d)(i)
(ii)
(iii)
Able to name and state the function of R.
Sample answer
R: synovial fluid
F: acts as a lubricant ( which reduces friction between the ends of
bones)
Able to name the disease described in above statement.
Sample answerArthritis // osteoarthritis
Able to explain why the contraction of muscles needs sufficient
blood.
Sample answer
P1 contraction of muscle need more energy from cell respirationP2 need more oxygen and glucose that transported through blood.
(any 2P)
Able to give one necessity for support in plants.
Sample answer
To be in an upright position so their leaves can absorb maximumsunlight for photosynthesis // flower need to be lifted for
pollination
Able to name one tissue that provided support to plant in
Diagram 4.2 (a).Sample answer
schlerenchyma tissue/ xylem tissue
Able to explain how turgidity provides supports to plant in
Diagram 4.2(b).
Sample answer
P1 turgor pressure of liquid content in the vacuoleP2 pushes the cell membrane against the cell wall
P3 creating support for the stem, leaves and roots.
(Any 2 P)
1
1
1
11
1
1
11
1
TOTAL
2
1
2
1
1
3
12
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BIOLOGI KERTAS 2 8
5(a)(i)
(ii)
(b)(i)
(ii)
(c)
Able to label P and Q
Sample answer
P GlomerulusQ Bowman capsule
Able to state the characteristic of QSample answerP1 : have very large surface area
P2 : have many podocyte (that enable the ultrafiltration occurtremendously)
Able to name the process that occurred between P and Q
Sample answerUltrafiltration // filtration
Able to describe the process that mentioned in (b)(i)
Sample answer
P1 : Blood in Glomerulus have very high hydrostatic pressure(Because the diameter of aferent arteriole is larger then
diameter of eferent arteriole)
P2 : All the component of blood plasma diffuse into Bowmancapsule except the bigger molecule (such as protein)
P3 : This fluid known as glomerular filtrate
Able to explain how Antidiuretic hormone control water
absorption in the convoluted tubule and collecting tubule
Sample answer
P1 : If blood osmotic pressure lower than normal level, it can be
detected by osmoreceptor cell in hypothalamusP2 : Hypothalamus will produce less ADH ( and send to kidney)
P3 : Convoluted tubule and collecting duct become less permeable
to water
P4 : Less water will be reabsorb by the tubule thusP5 : Osmotic pressure of blood increase back to normal pressure.
11
1
1
1
1
1
1
1
1
1
11
2
2
1
3
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BIOLOGI KERTAS 2 9
OR
P1 : If blood osmotic pressure higher than normal level, it can bedetected by osmoreceptor cell in hypothalamus
P2: Hypothalamus will produce more ADH ( and send to kidney)
P3 : Convoluted tubule and collecting duct become morepermeable to water
P4 : More water will be reabsorb by thus tubule
P5 : Osmotic pressure of blood become normal again
1
1
1
1
1
TOTAL
3
11
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BIOLOGI KERTAS 2 10
SECTION B
No. Marking criteria (sample answers) Marks
6a.i. Able to explain the meaning of negative feedback
P1:it is a corrective mechanism (which reverses the original change
and brings the system back to normal)
P2: when the blood glucose level decreases, it will increase and finallyback to normal// vice versa
1
1Total =2
a.ii Able to explain how hormone X and Y regulate the blood glucose
level
P1: Hormone X and Y are produced by pancreasP2: Hormone X/glucagon is secreted by alpha cells whereas hormone
Y/insulin is secreted by beta cells
P3:if the blood sugar level is lower than normal, more hormoneX/glucagon is secreted into blood stream
P4: hormone X/glucagon is transported by the blood to the liver
P5: hormone X/glucagon causes/stimulates the liver to breakdown
glycogen to glucoseP6: this causes the level of glucose to rise and back to normal
P7:if the blood sugar level is higher than normal, more hormone
Y/insulin is secretedP8:hormone Y/insulin causes/stimulates the liver to convert glucose
into glycogen
P9:this causes the level of glucose decrease and back to normal
1
1
1
1
1
11
1
1
Any 8Total = 8
b.i. Able to explain the regulation of the body temperature in coolcondition
P1:when the environment is too cold, the stimuli is detected by
receptors in the skinP2:impulse is sent to brain/hypothalamus
P3: hypothalamus send impulse to the effectors
P4:sweat glands are not stimulated so no sweating
P5:vasoconstriction of arterioles in the skin, less blood flows to theskin
P6: so less heat is lost (to surrounding)
P7: erector muscle contracts, hair raise up so trap more heatP8:adrenal gland secrete adrenaline whereas thyroid gland secretes
thyroxin to increase metabolic rate
P9: shivering takes place, this results in increased the production of
heat
1
11
1
1
1
1
1
Any 6 = 6
b.ii Able to state the name of hormones and explain the use of it
F1: auxinP1: promote the growth of adventitious root
P2:induce the development of fruit without
fertilization/parthenocapy/fruit without seed
F1 with any P1-P5=
1+1
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BIOLOGI KERTAS 2 11
P3:kill the dicot weeds
P4: prevent young developing fruit from falling off prematurely
P5:gardeners use auxins to stimulate growth of fruits/to delay fruit
ripening
F2: ethyleneP6:promoting the ripening of fruits // the unripe imported fruit will be
exposed to ethylene gas for sale
F2+P6=1+1
Total=4
7a.i Able to describe the respiratory structures and breathing mechanism
of an insectRespiratory structure
R1: the tracheal system consists of network of trachea
R2: the trachea is lined with chitin to prevent from collapsingR3:spiracle is tiny openings that allow air to go in and out
R4: the trachea branch into fine tubes called tracheoleR5: the tracheole branch throughout the body and penetrate into bodytissues/muscle
Breathing mechanismB1:when the insect inhales, the abdominal muscles relax and spiracles
openB2:air pressure inside the trachea decreases and air is drawn in
B3: when the insect exhale, the abdominal muscles contract
B4:so increase air pressure inside trachea and forces air out through
spiracles
B5:insect inhale and exhale through rhythmic contraction andexpansion of their abdominal muscles
B6:the body movement and contractions of abdominal muscles speedup the rate of diffusion of gases from trachea into body cells
Any 4 = 4m
Any 4 = 4m
Total = 8
b Able to describe the intake of oxygen by plants for respiration
Structure involvedS1: the intake occurs by diffusion mainly through stomata and
lenticels
S2:stomata can be found in epidermis of the leaves /the stems ofherbaceous plants
S3:lenticels can be found on the stems and roots of plants
ExplanationP1:when stomata open, they connect the air spaces (within the leave)
to atmosphereP2:oxygen from atmosphere diffuses into the air spaces
P3:then dissolves in the film of water around the mesophyll cells
P4:so the concentration of oxygen in the cells becomes lower than inthe air spaces
Any 2S =2m
Any 4P=4m
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 12
P5:thus, oxygen diffuse continuously from air spaces to the cell
P6:during daytime, carbon dioxide that is produced during respiration
is used in photosynthesisP7:the excess carbon dioxide diffuses into the air spaces and then
through stomata into atmosphere
Total =6m
c Able to name the organelle correctly
P: mitochondrionQ: chloroplast
Able to explain the differences between the process in organelle P and
Q
Organelle P/Mitochondrion Organelle
Q/chloroplast
Process Respiration Photosynthesis
Aim Release energy Stores energyRaw
materials
Glucose, oxygen Water, carbon
dioxide, light
Products Energy, water, carbon dioxide Glucose/starch,
water and oxygen
Energy Not required Required in form oflight
11
11
1
1
1
Any 4sets=4m
Total = 6m
8.a Able to describe the formation of pollen grains and development ofthe embryo sac
Pollen grainsG1:pollen is produced in the anther (which consists of four pollen
sacs)
G2:each pollen sac contains hundred of pollen mother cells which isdiploid
G3:each mother cells undergoes meiosis to form four haploid
microspores/cells/tetrad
G4:each cell /tetrad develop into pollenG5:the nucleus of each cell/microspore/tetrad undergoes mitosis to
form (pollen) tube nucleus and a generative nucleus
Embryo sac
E1:embryo sac mother cell(diplod/2n) undergoes meiosis to form four
haploid cells/megasporesE2:three of the cells/megaspores degenerate, leaving only one(in the
Any 4G=4m
Any 4E=4m
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 13
ovule)
E3:nucleus of megaspore undergoes mitosis three times to form eight
haploid nucleiE4:three of eight nuclei migrate to one end of the cell to form
antipodal cells
E5:another two nuclei/polar nuclei move to the centreE6:(near the opening of ovule/micropyle) one of three nuclei develops
into egg cell/female gamete flanked by two synergid cellsE7:the structure formed is known as embryo sac Total=8m
8b Able to describe the process of double fertilization in plant
F1:a pollen grain on stigma initiates the fertilization processF2:sugar (solution) in the stigma stimulates the pollen to germinate
and form a pollen tube
F3:the pollen tube grows down the style towards the ovuleF4:(during the growth of pollen tube) the generative nucleus divides
by mitosis and form two male gamete nucleiF5:the male nuclei follow the tube nucleus down the pollen tubeF6:pollen tube reaches ovule through micropyle and tube nucleus
disintergrates
F7:one male gamete nucleus fuses with egg nucleus forming diploidzygote(2n)
F8:other male gamete nucleus fuses with the two polar nuclei forminga triploid nucleus(3n)
Able to explain the importance of double fertilization for the survival
of flowering plants
S1:genetic information of parents plants is passed down to the nextgeneration (diploid zygote)
S2:variation in next generation (as a result of the formation of themale gamete fuses with egg cell)
S3:endosperm provides food for developing embryo during
germinationS4:seeds are surrounded by ovary which develops into fruit, thus fruit
protect the seeds for survival in new habitat
Any 2 from F1-
F6 =2m
F7 & F8 arecompulsory=2m
Any 2S=2m
Total = 6m
c Able to explain the methods to prevent pregnancy(family planning)F1:Diaphragm
P1:inserted into vagina to cover the cervix to stop sperm from entering
the uterus
F2:IUD
P2:fitted into uterus by doctor and can be left in the uterus (2years)and prevent implantation
F3:spermicideP3:chemical cream/gel/foam is applied to vaginal walls before
Any 3 sets =
6m
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 14
copulation and kill the sperms ejaculated into vagina
F4:contraceptive pillsP4:prevents ovulation (by inhibiting the secretion of FSH and LH)
F5:tubal ligationP5:both the fallopian tubes are cut and tied (in an operation) causes
the ovum cannot reach the part of Fallopian tube, fertilization is notoccured
9.a Able to explain how classification system is used
C1:based on Linnaeus Binomial system
C2:the first name begin with capital letter refers to genus whereassecond name begins with small letter refers to species
C3:the names are written in italic
C4:(based on example from question) Panthera is the genus and tigrisis the species
1
1
1
1Total =4m
b Able to name and describe the interaction s shownDiagram 9.2 (i)
F1 : Commensalism
P1:a clown fish gains protection from (predators) by living among seaanemones
P2:sea anemones unaffected
F2:Mutualism
P3:alge synrthesis for itself and for fungus
P4:fungus supplies carbon dioxide and nitrogenous compound for alga
to synthesise its food
1
1
1
F1+ P1/P2=2m
1
1
1F2+P3/P4=2m
Total=4m
9.c Able to describe the benefits of microorganism (fungi) in products forhuman
B1:bread makingP1:flour, sugar and yeast are used. Yeast helps the dough to rise
through fermentation that release carbon dioxide
B2:beer making
P2:two species of yeast are used, beer is brewed from barley grainsB3:wine
P3:is made through fermentation of grape juices produce ethanolB4:soya sauce
P4:is made from soya beans fermented by the action of fungi
11
1
11
11
1
Any 3 sets ofB+P
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SKEMA PERCUBAAN SPM PAHANG 2010 4551/2
BIOLOGI KERTAS 2 15
(correspond)
Notes:
i.if only B isstated without
P, maximum
mark is 2ii. B is correct
and P is wrong,award mark
only for B
Total=6m
d. Able to state three ways to conserve and preserve the biodiversity
F1:replanting programmes after selective logging in rainforestP!:each house/school plant at least one tree
F2:campaign through media/NGO/private sectorsP2:banner/radio/television/pamphletF3:recycle/reuse/reduce waste products
P4:build the centre for recycling/any relevant explanation
F4:stop open burningP4:dig and put the waste in the ground
F5:car pool/use public transportP5:reduce the use of fuel and release of pollutants
F6:any relevant fact
P6: any relevant explanation
any 6 = 6m
total = 6m
END OF MARK SCHEME
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1
4551/3(PP) SULIT
BIOLOGY 3
Peraturan Pemarkahan
Peperiksaan Percubaan SPM 2010
QUESTION 1
1 (a) KB0603 Measuring Using NumbersScore Criteria
3
Able to record all 4 Final length of cylindrical potato strip in the box given correctly.
The concentration of sucrose
solution( M)
The final length of cylindrical potato strip (cm)
0.2
5.6
0.3
5.3
0.4
4.6
0.5 4.2
2Able to record any 3 or 2 final length of cylindrical potato strip correctly.
1 Able to record any one final length of cylindrical potato strip correctly.
0No response or all incorrectly
(b) (i) [KB0601 - Observation]
Score Criteria
3 Able to state any two different observations correctly according to the criteria:
Must state the value of MV and RV:
MV - The concentration of sucrose
RV - The final length of cylindrical potato strip
Sample answers:
1. In concentration of sucrose, 0.2 M, the final length of cylindrical potato strip
is 5.6 cm
2. In concentration of sucrose 0.5M, the final length of cylindrical potato strip is 4.2 cm
3. In concentration of sucrose 0.3M, the final length of cylindrical potato strip is 5.3 cm
4. In concentration of sucrose 0.4, the final length of cylindrical potato strip is 4.6 cm
2 Able to state any one observation correctly.
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2
4551/3(PP) SULIT
or
Able to state any two incomplete observations ( any 2 criteria)
Not state the value one of 2 criteria
Sample answers:
1. In concentration of sucrose lower, the final length of cylindrical potato strip is
5.6cm
2. In concentration of sucrose higher, the final length of cylindrical potato strip is 4.2 cm
3. The concentration of sucrose 0.2M, the final length of cylindrical potato strip is long
// longer
4. The concentration of sucrose 0.5, the final length of cylindrical potato strip is short //
shorter
1 Able to state any one idea of observation.(any 1criteria)
Sample answers:
1. The final length of cylindrical potato depends on the concentration of sucrose.
2. The concentration of sucrose influence the final length of cylindrical potato strip.
3. The concentration of sucrose is different , the final length of cylindrical potato strip
is different
0 No response orwrong response.
Scoring
Score Correct Inaccurate Idea Wrong
3 2 - - -
21 1 - -
- 2 - -
1
1 - 1 -
- - 2 -
- 1 1 -
1 - - 1
0- 1 - 1
- - 1 1
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3
4551/3(PP) SULIT
1 (b) (ii) [KB0604 - Making inferences]
Score Criteria
3
Able to make one inference for each observationbased on the criteria
State the :
o The concentration of sucrose solution
o Reason ( movement of water )
Sample answers:
1. For 0.2 M / 0.3M sucrose solution is hypotonic / more concentration of water molecule
compare the cell sap cause more water molecules move / diffuse into the cell sap of
potato strip by osmosis .
2.For 0.4 M / 0.5M sucrose solution, is hypertonic / more concentration of water compare
the cell sap cause more water molecules move /diffuse out from cell sap of potato strip
by osmosis .
2
Able to make one inference for any one observation.
or
Able to make one and incomplete inference Sample answer:
for each observation.
Sample answers:
1. For 0.2 M / 0.3M sucrose solution more water molecules move / diffuse into the cell
sap of potato strip by osmosis .
2.For 0.4 M / 0.5M sucrose solution, more water molecules move /diffuse out from
cell sap of potato strip by osmosis .
1 Able to make an idea of inference with one criterion.
0 No response orwrong response.
Scoring
Score Correct Inaccurate Idea Wrong
3 2 - - -
21 1 - -
- 2 - -
1
1 - 1 -
- - 2 -
- 1 1 -
1 - - 1
0- 1 - 1
- - 1 1
Note : Cannot repeat observation
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4
4551/3(PP) SULIT
1(c) [KB0610Variables]
3
Able to state all 3 variables and the 3 methods to handle the variable correctly.
Sample Answer :
Variables Method to handle the variable correctly
Manipulated variable
The concentration of sucrose
solution
Use the different concentration of sucrose solution
OR
Change the concentration of sucrose
solution
Responding variable
The final length of (cylindrical)
potato strip
Measure and recordthe length of cylindrical
potato strip by using ruler
Constant variable
The volume/ quantity of sucrose
solution // the initial length of
cylindrical potato strip
Use the same / the volume of sucrose solution //
quantity of sucrose solution // the initial length of
cylindrical potato strip is 5cm
OR
Fixed the volume / quantity of sucrose solution //
the initial length of cylindrical potato strip is 5 cm
.
6 ticks correctly
2
4 - 5 ticks correctly.
Reject way how to handle variable if variable is wrong.
1Able to state 2-3 ticks correctly
0
Able to state 1 tick correctly or no respons
3 mark 6 ticks
2 mark 4-5 ticks
1 mark-2-3 ticks
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1(d) [KB0611- Making Hypothesis]
Score Criteria
3
Able to state a hypothesis to show a relationship between the manipulated variable and
responding variable and the hypothesis can be validated, base on 3 criteria:
manipulated variable (P1)
responding variable (P2)
relationship (H)
Sample answer :
1. if the concentration of sucrose solution is increase / rise/ higher, the final
length of cylindrical potato strip is decrease/ lower // vise versa
2. thehigher concentration of sucrose solution, the lower /shorter final length of
cylindrical potato strip // vice versa
2
Able to state a hypothesis relating the manipulated variable and responding variable
inaccurately with two criteria correctly :
Manipulated variable Responding variable
No relationship/ incorrectly
Sample answer:
1. if the concentration of sucrose solution is different , the final length of
cylindrical potato strip is different
2. the different concentration of sucrose solution, the different final length of
cylindrical potato strip // vice versa
1
Able to state a hypothesis relating the manipulated variable at idea level, with one
criteria correctly
Sample answer:
1.Different concentration of sucrose solution influenced the final length of
cylindrical potato strip
2.The final length of cylindrical potato strip depends on the concentration of
sucrose solution
3.. The final length of cylindrical potato strip affected by the concentration of
sucrose solution
.
0
Not able to response orwrong response.
Note : directly proportional and inversely proportional are not accepted
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1(e)(i) [KB0606 Communicating]
Score Criteria
3 Able to construct a table by using the criteria given
T : State all the title /aspects is given with the correct unit
D : State all data for the 3 aspect
C : All calculation / percentage changes in length correct
Sample answers
The
concentration
of sucrose
solution (M)
The initial length
of potato strip
(cm)
The final length of
potato strip (cm)
The percentage
changes in the length
of potato strip (%)
0.1 5 5.9 18
0.2 5 5.6 12
0.3 5 5.3 6
0.4 5 4.6 -8
0.5 5
4.2
-16
2 Able to record two criterias correctly
1 Able to record one criteria correctly
0 No response orwrong response.
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4551/3(PP) SULIT
1 (e)(ii) [KB0612 Relationship between space and time]
Score Criteria
3
Able to draw the graph correctly with the following aspects:
P(paksi) : Axes :Uniform scales on both horizontal and vertical axis 1 mark
T (titik ) : Points :
All points plotted correctly - 1 mark
B ( bentuk ) : Curve :
Able to join all the points to form a smooth graph / passing
through all point
-ve gradient - 1 mark
Sample answer :X axes : MV the percentage change in lenght (%)
Y axes : RV - concentration of the sucrose solution
2 Any two correct.
1Any one correct
0 No response or wrong response.
1(f) [KB0608 Interpreting Data]
Score Criteria
3 Able to state the concentration of sucrose solution which is isotonic to the
concentration of the cell sap of the potatoes base on the graph and give a reasons.State all the criteria
Criteria:
P1: State the concentration of sucrose solution base on the graph ( intercept / cut
on X axis ) : value accept 0.35M + 0.01
P2: does not cause any changes to the length of the potato stripP3 : amount of water in and out of the potato strip / cell is the same.
Sample answer:
The concentration of sucrose solution which is isotonic to the concentration of the
cell sap of the potatoes base on the graph is 0.35M, that does not cause any changes
to the length of the potato strip because amount of water in and out of the potato strip/ cell is the same.
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4551/3(PP) SULIT
2 Able to state the concentration of sucrose solution which is isotonic to the
concentration of the cell sap of the potatoes base on the graph and give a reasons.
State any two the criteria only.
Sample answer:
The concentration of sucrose solution which is isotonic to the concentration of the
cell sap of the potatoes base on the graph is 0.35M , that does not cause any changes
to the length of the potato strip.
1 Able to state the idea of the relationship used base on one criteria
Sample answer :
Sample answer:
1. The concentration of sucrose solution which is isotonic to the concentration of
the cell sap of the potatoes base on the graph is 0.35M
0 Not able to response orwrong response.
1(g) [KB0605 Predicting]
Score Criteria
3 Able to predict the result accurately.
Relationship :
P1 = Able to state the changes of mustard green stem strips / condition
P2 = Able to state inward
P3 = Able to state the reason (movement of water)
Sample answer:
1. The mustard green stem strip will become shrink/ flaccid and curve inward( epidermis
outside ) because water molecules move out from cell sap (of the mustard green)
2 Able to predict the result less accurate base on two criterias:
Sample answer :
1. The mustard green stem strip will become shrink/ flaccid and curve inward( epidermis
outside ) because ( ANY INCORRECTLY REASON )
1 Able to give idea of the result base on one criterion
Sample answer :
1. The mustard green stem strip will become shrink/ flaccid
0 Not able to response orwrong response.
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4551/3(PP) SULIT
1(i) [KB0609 Defining by Operation]
Score Criteria
3 Able to state correctly the meaning of osmosis process relationship base on three criterias
:
P1 : Osmosis concept based on the observation
P2 : related to the different concentration of sucrose solution
P3 : Effect to the potato strips
Sample answer:
Osmosis is a process which is potato strips immersed in sucrose solution cause water
molecules move in / out of the potato strip across the plasma membrane depends on the
different concentration of sucrose solution that will affect the length of potato strip.
2 Able to state the meaning of osmosis or as a concept base on two criterias :
P1 and P2 // P1 and P3 // P2 and P3
1 Able to state the idea base on one criteria
P1/P2/P3 only
0 Not able to response orwrong response.
1(i) [KB0602 Classifying]
Score Criteria
3 Able to classify all ( 4 pairs)correctly the concentration of sucrose solution with unit
and conditions of mustard green into table 3
Sample answer:
Concentration of sucrosesolution
Conditions of mustard green
0.2 M
0.5 M
0.6 M
0.8 M
B
A
C
D
2 Able to classify 3 pairs correctly into table 3
1 Able to classify 2 pairs correctly into table 3
0 Able to classify one pair or no response
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4551/3(PP) SULIT
QUESTION 2
PROBLEM STATEMENT
No. Mark Scheme Score
2(i)KB061201
Able to state a problem statement relating the manipulated variablewith the responding variable correctly 3
P1 : (Type of) food samples / white bread and cashew nuts.
P2 : energy content/value in food samples/ final water temperature
H : question form and question mark(?)
Sample answer
1. Which types of food samples, the white bread or cashew nuts , has
a higher energy value/content?
2. Do different types of food samples contain similar energy
value / content?
3. Do white bread / cashew nuts has a higher energy value/content
compared to cashew nuts / white bread?
Able to state a problem statement less accurately 2
Sample answer
1. Which types of food samples, the white bread or cashew nuts , has
a higher energy value/content. (no H)
2. Do different samples contain similar energy value / content? (no
P1)
3. Do white bread / cashew nuts has a higher energy value/content ?
(incomplete P1.4. Different types of food samples has different energy value/content?
(no H)
Able to state a problem statement at idea level 1
Sample answer
1. Which food has higher energy? (no P1 and P2)
2. Do white bread has a higher energy value.(no P1 and H)
No response or incorrect response 0
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4551/3(PP) SULIT
AIM OF INVESTIGATION
No. Mark Scheme Score
2 (ii) Able to state the objective of the investigation correctly
KB061203
Sample answer
To determine and compare the energy content/value in white breadand cashew nuts.
HYPOTHESIS
No. Mark Scheme Score
2 (iii)
KB061202
Able to state a hypothesis relating the manipulated variable to the
responding variable correctly 3
P1 : type of food samples / white bread and cashew nuts.
P2 : energy content/value (in food samples)
H : relationship
# P1 must different food class
Sample answer
1. Cashew nuts have a higher energy value/content than white bread.
2. White bread has lower energy value/content than cashew nuts.
2. Different type of food samples contain different energy
value /content.
Able to state a hypothesis inaccurately*Have P1 and P2 or P1/P2 and H 2
Sample answer
1. Type of food samples influences the energy value/content in food
samples. (no H)
2. Cashew nuts have a higher energy value/content. (incomplete P1)
3. Type of food samples contains different energy value /content.
4. Higher final water temperature, higher energy value (P1 twice)
Able to state a hypothesis at idea level 1
Sample answer
White bread / cashew nuts has energy content/value. (only P2)
No response or incorrect response 0
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4551/3(PP) SULIT
VARIABLES
No. Mark Scheme Score
2 (iv) Able to state all three variables correctly
KB061203
Sample answer
Manipulated : (Type of) food samples // cashew nuts and white bread
Responding : The energy value of food samples // final water
temperature
Fixed : Volume of distilled water / the mass of food / Initial
temperature of distilled water
LIST OF APPARATUS AND MATERIALS
No. Mark Scheme Score
2(v)
Able to list all the important apparatus and materials correctly.
6-7 apparatus(A) + 5 materials (M)
## type of food sample must from different food class
3
KB061205
*compulsory apparatus and materials
Sample answer
Apparatus : *boiling tubes, *thermometer, retort stand, pin,
measuring cylinder, Bunsen burner and electronic balance.
Materials : *distilled water, *white bread, *cashew nuts, plasticine
and cotton wool.
Able to list any 4-5 apparatus (including * ) and 3 * materials 2
Able to list any 2-3 apparatus (including * ) and 3 * materials 1
No response or incorrect response 01 apparatus + 3 * materials
Remark :
for title materials and apparatus for planning experiment.
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4551/3(PP) SULIT
TECHNIQUE USED
No. Mark Scheme Score
2 (iv)
KB061203
Able to state the operating responding variable correctly using
suitable apparatus B1 = 1
Sample answer1. Measure and record the final / the increase in temperature of
distilled water using a thermometer.
or
2. Calculate the energy value of food samples using a formula :
Energy value = 4.2 (Jg-1 0
C-1
) x mass of water (g) x
increase in temperature (0C)
(kJg-1
)
Mass of food sample (g) x 1000
PROCEDURE
No. Mark Scheme Score
2 (vii)
Able to describe the steps of experiment correctly based on the
following aspects:
KB061204 K1 : Preparation of materials and apparatus (any 4)
K2 : Operating the constant variable (any 1)
K3 : Operating the responding variable (any 1)
K4 : Operating the manipulated variable (any 1)K5 : Steps to increase reliability of results accurately / precaution
(any 1)
Sample answers
1. Weight and record the mass of white bread.
2. Fill a boiling tube with 20ml of distilled water.
3. Clamp the boiling tube to the retort stand in an upright
position as shown in the diagram.
4. Record the initial temperature of the distilled water in the
boiling tube.
5.
Fix the white bread at the end of the pin.6. Ignite the white bread by holding it in the flame of a Bunsen
burner. Then immediately place it beneath the boiling tube to
heat the water.
7. Stir the water gently with the thermometer.
8. Record the final temperature of the distilled water in the
boiling tube.
9. Repeat steps 1-8 using cashew nuts to replace the white bread.
10.Calculate the energy value of the food samples by using the
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4551/3(PP) SULIT
formula :
Energy value = 4.2 (Jg-1 0
C-1
) x mass of water (g) x
increase in temperature (0C)
(kJg-1
)
Mass of food sample (g) x 1000
11.Record/tabulate all the results in the table.
K1 (any 4)
1.Weight white bread
2. Weight chew nut
3. Fill the boiling tube
4. Clamp
5. Fix at the end of the pin
6. Ignite
7. place burning food under the boiling tube to heat the water.
K2 (any 1)1. Fix the volume of distilled water is 20ml
2. Fix the mass of food samples
3. Fix the initial temperature of water
K3 (any 1)
1. Record the final temperature of water by using thermometer
2. Calculate the energy value of the food samples by using the
formula :
Energy value = 4.2 (Jg-1 0
C-1
) x mass of water (g) x
increase in temperature (0C)
(kJg
-1
)Mass of food sample (g) x 1000
K4 (any 1)
1. Replaced / change the experiment with another food samples (
name the food sample from different food class)
Example:
Replace white bread with cashew nuts
K5 (any 1)
1. Stir the water gently with the thermometer.
2. Repeat experiment to get average reading.
3. Use an insulator shield to reduce heat loss to the surroundings.
4. To ensure that the food is oxidized completely, make sure the food
is burnt completely.
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4551/3(PP) SULIT
All 5 K 3
Any 3 - 4 K 2
Any 2 K 1
No response or incorrect response or 1 K only. 0
Remark:
1K - for title procedure for planning experiment.
No. Mark Scheme Score
2 (viii)
Able to construct a table to record data based on the following
aspects : B2 = 1
KB061203 1. Correct title and units (*titles compulsory)
Sample answer
Types of food samples *
White bread * Cashew nuts *
Mass (g)
Initial temperature (oC)
Final temperature (oC)
Change in temperature (oC) *
Energy value (J/g) / (kJ/g) *
CONCLUSION
No. Mark Scheme Score
2(ix) Able to make the right conclusion correctly
KB061203
Sample answer
Cashew nuts have a higher energy value/content than white bread
Hypothesis accepted
Reject : (only) Hypothesis accepted
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PLANNING OF EXPERIMENT
No. Mark Scheme Score
2(x) Able to write the experimental planning
KB061203
1. Problem Statement
2. Aim
3. Hypothesis
4. Variables
5. Materials and Apparatus
6. Technique
7. Procedure
8. Result
9. Conclusion
7 - 9 ticks 3
4 - 6 ticks 2
2 - 3 ticks 1
0 1 tick
No response or incorrect response 0
END OF MARKING SCHEME
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