spm trial 2010 bio ans (pahang)

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    MARK SCHEME BIOLOGY 1

    SPM TRIAL 2010

    NO. JAWAPAN NO. JAWAPAN

    1. B 26. D

    2. D 27. C

    3. A 28. B

    4. A 29. D

    5. C 30. A

    6. D 31. D

    7. B 32. B

    8. C 33. D

    9. B 34. D

    10. C 35. D

    11. C 36. A

    12. A 37. D

    13. B 38. A

    14. A 39. A

    15. A 40. C

    16. c 41. D

    17. B 42. D

    18. D 43. C

    19. A 44. C

    20. C 45. C

    21. C 46. A

    22. A 47. C

    23. D 48. A

    24. C 49. B

    25. B 50. D

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 1

    PERCUBAAN SPM

    TAHUN 2010

    BIOLOGIKERTAS 2

    SKEMA JAWAPAN

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 2

    MARKING SCHEME TRIAL SPM BIOLOGY 2010 PAPER 2

    SECTION A

    No. Marking criteria Marks

    1(a)(i)

    (ii)

    (b)

    (i) Able to draw a line to show the location of structure P, Q

    and R in the cell.

    (ii) Able to complete Table 1 by stating the function of

    structure P and R

    Sample answer

    P- transports protein made by the ribosomes

    R- site where cellular respiration occurs // energy isgenerated

    Able to explain the synthesis extracellular enzyme from protein

    at the ribosome

    Sample answer

    P1- Protein enter lumen Rough Endoplasmic Recticulum (RER)

    P2- Modified in RER into extracellular enzyme

    P3- carried to the Golgi body by transporting vesicle

    P4- Processed / Packed in the Golgi body for excretion

    Note : maximum 3 marks

    1

    1

    1

    11

    1

    1

    11

    3

    2

    3

    R

    P

    Q

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 3

    1cAble to explain how to ensure the process Y occurs at a

    maximum rate in the washing of blood stain on a shirt

    Sample answer :

    F1- Use (warm) water with temperature of 370C

    P1- optimum temperature for enzyme (activity) // Enzymes

    work best at this temperature

    F2- Add more soap/alkali solution (in the water)

    P2- Enzymes / trypsin / protease work best in an alkaline

    medium

    OR

    F3- Add a little vinegar/ acid (in the water)P3- Enzymes/ pepsin work best in an acidic medium

    F1 + P1

    (Any pair of F2 + P2 or F3 + P3)

    Able to suggest two types of enzyme that would need to be

    present in a washing powder designed to remove blood stains.

    Sample answer

    - Lipase / Protease

    1

    1

    1

    1

    1

    1

    1

    TOTAL

    4

    1

    13

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 4

    2(a)

    (b)(i)

    (ii)

    (c)

    (d)(i)

    (ii)

    Able to name the cell division

    Sample answerMitosis

    Able to arrange the phase K, L, M and N correctlySample answerL, N, K, M

    Note : L, N (1 mark)

    K, M (1 Mark)

    Able to describe the behavior for each stages

    Sample answer

    L : (early) anaphase

    N : MetaphaseK : Sister chromatids separate and move towards the opposite poles

    M : Chromosome align at metaphase plate

    Able to explain how radiotherapy method can treat cancer

    Sample answer

    F : Radioactive rays will kill cancer cells

    P : When all the cancer cells are destroyed, they cannot reproduce

    by mitosis

    Able to give differences between Prophase I and Prophase II

    Sample answer

    Prophase I Prophase II

    P1

    P2

    There is no synapsis occurs

    The chromosomes do notcrossing over

    Synapsis occurs betweenhomologous chromosomes

    Crossing over occursbetween homologous

    chromosomes

    Able to explain the significant of maintaining the diploid

    number of chromosomes.

    Sample answer

    In order for the offspring to have the same chromosomal number of

    their parent

    1

    11

    1

    11

    1

    1

    1

    1

    1

    1

    TOTAL

    1

    2

    4

    2

    2

    1

    12

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 5

    3(a)

    (b)

    (c)(i)

    (ii)

    Able to state the function of alveoli

    Sample answer

    Place for gaseous exchange // store the oxygen gas before gaseous

    exchange occur

    Able to state the characteristic of alveoli

    Sample answer

    P1 : Have very large total surface area //P2 : have moist surface all the time //

    P3 : have very thin wall ( only one single layer of cell

    Note : (Any one P)

    Able to state the characteristic of trachea

    Sample answer

    F : have C-shaped cartilage rings // cartilage rings

    P : keep the trachea open permanently

    P2 : avoid the trachea from collapse when the outside pressure ishigher than inside pressure during inhalation

    P3 : oxygen can continuously flow through trachea to the alveoli /

    Lung

    Note : ( F one mark, P one mark)

    Able to draw the arrow to show the flow of oxygen in Figure 3.

    1

    11

    1

    1

    1

    1

    1

    1

    1

    2

    2

    Oxygen goes inCarbon dioxide goes out

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 6

    (iii)

    (d)

    Able to describe how intercostals muscle and diaphragm can

    change the volume and pressure in the thoracic cavity during

    inhalation

    Sample answer

    P1 : external intercostal muscles contract/ internal intercostalmuscles relax caused the rib cage moves outwards and

    upwardsP2 : diaphragm muscles contract, the diaphragm lower and flatten

    P3 : the volume of thoracic cavity increase but the pressure

    decrease (lower the atmospheric pressure)P4 : air forced into the lung // alveolus

    Able to state the differences between the respiratory system in

    human and fishSample answer

    P1 : gill is the respiratory organ for fish but lung is for human

    P2 : gill have filament and lamella to increase the surface area, butlung have alveoli to increase the surface area

    P3 : gill touch / surrounded by water all the time, but lung never

    touch/ surrounded by waterP4 : gill received oxygen directly from water, but lung received

    oxygen from atmosphere via trachea, bronchus and bronchioles

    1

    1

    1

    1

    1

    1

    1

    1

    TOTAL

    3

    3

    12

    4(a)(i)

    (ii)

    Able to name the type of joint showed in Diagram 4.

    Sample answerHinge joint

    Able to give is the different between the joint mentioned in

    (a)(i) and the joint on the shoulder.

    Sample answer

    P1 Joint in 4(a)(i) allow movement in one planeP2 joint on the shoulder allow rotational movement in all

    directions.

    1

    11

    1

    2

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 7

    (b)(i)

    (ii)

    (c)

    (d)(i)

    (ii)

    (iii)

    Able to name and state the function of R.

    Sample answer

    R: synovial fluid

    F: acts as a lubricant ( which reduces friction between the ends of

    bones)

    Able to name the disease described in above statement.

    Sample answerArthritis // osteoarthritis

    Able to explain why the contraction of muscles needs sufficient

    blood.

    Sample answer

    P1 contraction of muscle need more energy from cell respirationP2 need more oxygen and glucose that transported through blood.

    (any 2P)

    Able to give one necessity for support in plants.

    Sample answer

    To be in an upright position so their leaves can absorb maximumsunlight for photosynthesis // flower need to be lifted for

    pollination

    Able to name one tissue that provided support to plant in

    Diagram 4.2 (a).Sample answer

    schlerenchyma tissue/ xylem tissue

    Able to explain how turgidity provides supports to plant in

    Diagram 4.2(b).

    Sample answer

    P1 turgor pressure of liquid content in the vacuoleP2 pushes the cell membrane against the cell wall

    P3 creating support for the stem, leaves and roots.

    (Any 2 P)

    1

    1

    1

    11

    1

    1

    11

    1

    TOTAL

    2

    1

    2

    1

    1

    3

    12

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 8

    5(a)(i)

    (ii)

    (b)(i)

    (ii)

    (c)

    Able to label P and Q

    Sample answer

    P GlomerulusQ Bowman capsule

    Able to state the characteristic of QSample answerP1 : have very large surface area

    P2 : have many podocyte (that enable the ultrafiltration occurtremendously)

    Able to name the process that occurred between P and Q

    Sample answerUltrafiltration // filtration

    Able to describe the process that mentioned in (b)(i)

    Sample answer

    P1 : Blood in Glomerulus have very high hydrostatic pressure(Because the diameter of aferent arteriole is larger then

    diameter of eferent arteriole)

    P2 : All the component of blood plasma diffuse into Bowmancapsule except the bigger molecule (such as protein)

    P3 : This fluid known as glomerular filtrate

    Able to explain how Antidiuretic hormone control water

    absorption in the convoluted tubule and collecting tubule

    Sample answer

    P1 : If blood osmotic pressure lower than normal level, it can be

    detected by osmoreceptor cell in hypothalamusP2 : Hypothalamus will produce less ADH ( and send to kidney)

    P3 : Convoluted tubule and collecting duct become less permeable

    to water

    P4 : Less water will be reabsorb by the tubule thusP5 : Osmotic pressure of blood increase back to normal pressure.

    11

    1

    1

    1

    1

    1

    1

    1

    1

    1

    11

    2

    2

    1

    3

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 9

    OR

    P1 : If blood osmotic pressure higher than normal level, it can bedetected by osmoreceptor cell in hypothalamus

    P2: Hypothalamus will produce more ADH ( and send to kidney)

    P3 : Convoluted tubule and collecting duct become morepermeable to water

    P4 : More water will be reabsorb by thus tubule

    P5 : Osmotic pressure of blood become normal again

    1

    1

    1

    1

    1

    TOTAL

    3

    11

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 10

    SECTION B

    No. Marking criteria (sample answers) Marks

    6a.i. Able to explain the meaning of negative feedback

    P1:it is a corrective mechanism (which reverses the original change

    and brings the system back to normal)

    P2: when the blood glucose level decreases, it will increase and finallyback to normal// vice versa

    1

    1Total =2

    a.ii Able to explain how hormone X and Y regulate the blood glucose

    level

    P1: Hormone X and Y are produced by pancreasP2: Hormone X/glucagon is secreted by alpha cells whereas hormone

    Y/insulin is secreted by beta cells

    P3:if the blood sugar level is lower than normal, more hormoneX/glucagon is secreted into blood stream

    P4: hormone X/glucagon is transported by the blood to the liver

    P5: hormone X/glucagon causes/stimulates the liver to breakdown

    glycogen to glucoseP6: this causes the level of glucose to rise and back to normal

    P7:if the blood sugar level is higher than normal, more hormone

    Y/insulin is secretedP8:hormone Y/insulin causes/stimulates the liver to convert glucose

    into glycogen

    P9:this causes the level of glucose decrease and back to normal

    1

    1

    1

    1

    1

    11

    1

    1

    Any 8Total = 8

    b.i. Able to explain the regulation of the body temperature in coolcondition

    P1:when the environment is too cold, the stimuli is detected by

    receptors in the skinP2:impulse is sent to brain/hypothalamus

    P3: hypothalamus send impulse to the effectors

    P4:sweat glands are not stimulated so no sweating

    P5:vasoconstriction of arterioles in the skin, less blood flows to theskin

    P6: so less heat is lost (to surrounding)

    P7: erector muscle contracts, hair raise up so trap more heatP8:adrenal gland secrete adrenaline whereas thyroid gland secretes

    thyroxin to increase metabolic rate

    P9: shivering takes place, this results in increased the production of

    heat

    1

    11

    1

    1

    1

    1

    1

    Any 6 = 6

    b.ii Able to state the name of hormones and explain the use of it

    F1: auxinP1: promote the growth of adventitious root

    P2:induce the development of fruit without

    fertilization/parthenocapy/fruit without seed

    F1 with any P1-P5=

    1+1

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 11

    P3:kill the dicot weeds

    P4: prevent young developing fruit from falling off prematurely

    P5:gardeners use auxins to stimulate growth of fruits/to delay fruit

    ripening

    F2: ethyleneP6:promoting the ripening of fruits // the unripe imported fruit will be

    exposed to ethylene gas for sale

    F2+P6=1+1

    Total=4

    7a.i Able to describe the respiratory structures and breathing mechanism

    of an insectRespiratory structure

    R1: the tracheal system consists of network of trachea

    R2: the trachea is lined with chitin to prevent from collapsingR3:spiracle is tiny openings that allow air to go in and out

    R4: the trachea branch into fine tubes called tracheoleR5: the tracheole branch throughout the body and penetrate into bodytissues/muscle

    Breathing mechanismB1:when the insect inhales, the abdominal muscles relax and spiracles

    openB2:air pressure inside the trachea decreases and air is drawn in

    B3: when the insect exhale, the abdominal muscles contract

    B4:so increase air pressure inside trachea and forces air out through

    spiracles

    B5:insect inhale and exhale through rhythmic contraction andexpansion of their abdominal muscles

    B6:the body movement and contractions of abdominal muscles speedup the rate of diffusion of gases from trachea into body cells

    Any 4 = 4m

    Any 4 = 4m

    Total = 8

    b Able to describe the intake of oxygen by plants for respiration

    Structure involvedS1: the intake occurs by diffusion mainly through stomata and

    lenticels

    S2:stomata can be found in epidermis of the leaves /the stems ofherbaceous plants

    S3:lenticels can be found on the stems and roots of plants

    ExplanationP1:when stomata open, they connect the air spaces (within the leave)

    to atmosphereP2:oxygen from atmosphere diffuses into the air spaces

    P3:then dissolves in the film of water around the mesophyll cells

    P4:so the concentration of oxygen in the cells becomes lower than inthe air spaces

    Any 2S =2m

    Any 4P=4m

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 12

    P5:thus, oxygen diffuse continuously from air spaces to the cell

    P6:during daytime, carbon dioxide that is produced during respiration

    is used in photosynthesisP7:the excess carbon dioxide diffuses into the air spaces and then

    through stomata into atmosphere

    Total =6m

    c Able to name the organelle correctly

    P: mitochondrionQ: chloroplast

    Able to explain the differences between the process in organelle P and

    Q

    Organelle P/Mitochondrion Organelle

    Q/chloroplast

    Process Respiration Photosynthesis

    Aim Release energy Stores energyRaw

    materials

    Glucose, oxygen Water, carbon

    dioxide, light

    Products Energy, water, carbon dioxide Glucose/starch,

    water and oxygen

    Energy Not required Required in form oflight

    11

    11

    1

    1

    1

    Any 4sets=4m

    Total = 6m

    8.a Able to describe the formation of pollen grains and development ofthe embryo sac

    Pollen grainsG1:pollen is produced in the anther (which consists of four pollen

    sacs)

    G2:each pollen sac contains hundred of pollen mother cells which isdiploid

    G3:each mother cells undergoes meiosis to form four haploid

    microspores/cells/tetrad

    G4:each cell /tetrad develop into pollenG5:the nucleus of each cell/microspore/tetrad undergoes mitosis to

    form (pollen) tube nucleus and a generative nucleus

    Embryo sac

    E1:embryo sac mother cell(diplod/2n) undergoes meiosis to form four

    haploid cells/megasporesE2:three of the cells/megaspores degenerate, leaving only one(in the

    Any 4G=4m

    Any 4E=4m

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 13

    ovule)

    E3:nucleus of megaspore undergoes mitosis three times to form eight

    haploid nucleiE4:three of eight nuclei migrate to one end of the cell to form

    antipodal cells

    E5:another two nuclei/polar nuclei move to the centreE6:(near the opening of ovule/micropyle) one of three nuclei develops

    into egg cell/female gamete flanked by two synergid cellsE7:the structure formed is known as embryo sac Total=8m

    8b Able to describe the process of double fertilization in plant

    F1:a pollen grain on stigma initiates the fertilization processF2:sugar (solution) in the stigma stimulates the pollen to germinate

    and form a pollen tube

    F3:the pollen tube grows down the style towards the ovuleF4:(during the growth of pollen tube) the generative nucleus divides

    by mitosis and form two male gamete nucleiF5:the male nuclei follow the tube nucleus down the pollen tubeF6:pollen tube reaches ovule through micropyle and tube nucleus

    disintergrates

    F7:one male gamete nucleus fuses with egg nucleus forming diploidzygote(2n)

    F8:other male gamete nucleus fuses with the two polar nuclei forminga triploid nucleus(3n)

    Able to explain the importance of double fertilization for the survival

    of flowering plants

    S1:genetic information of parents plants is passed down to the nextgeneration (diploid zygote)

    S2:variation in next generation (as a result of the formation of themale gamete fuses with egg cell)

    S3:endosperm provides food for developing embryo during

    germinationS4:seeds are surrounded by ovary which develops into fruit, thus fruit

    protect the seeds for survival in new habitat

    Any 2 from F1-

    F6 =2m

    F7 & F8 arecompulsory=2m

    Any 2S=2m

    Total = 6m

    c Able to explain the methods to prevent pregnancy(family planning)F1:Diaphragm

    P1:inserted into vagina to cover the cervix to stop sperm from entering

    the uterus

    F2:IUD

    P2:fitted into uterus by doctor and can be left in the uterus (2years)and prevent implantation

    F3:spermicideP3:chemical cream/gel/foam is applied to vaginal walls before

    Any 3 sets =

    6m

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 14

    copulation and kill the sperms ejaculated into vagina

    F4:contraceptive pillsP4:prevents ovulation (by inhibiting the secretion of FSH and LH)

    F5:tubal ligationP5:both the fallopian tubes are cut and tied (in an operation) causes

    the ovum cannot reach the part of Fallopian tube, fertilization is notoccured

    9.a Able to explain how classification system is used

    C1:based on Linnaeus Binomial system

    C2:the first name begin with capital letter refers to genus whereassecond name begins with small letter refers to species

    C3:the names are written in italic

    C4:(based on example from question) Panthera is the genus and tigrisis the species

    1

    1

    1

    1Total =4m

    b Able to name and describe the interaction s shownDiagram 9.2 (i)

    F1 : Commensalism

    P1:a clown fish gains protection from (predators) by living among seaanemones

    P2:sea anemones unaffected

    F2:Mutualism

    P3:alge synrthesis for itself and for fungus

    P4:fungus supplies carbon dioxide and nitrogenous compound for alga

    to synthesise its food

    1

    1

    1

    F1+ P1/P2=2m

    1

    1

    1F2+P3/P4=2m

    Total=4m

    9.c Able to describe the benefits of microorganism (fungi) in products forhuman

    B1:bread makingP1:flour, sugar and yeast are used. Yeast helps the dough to rise

    through fermentation that release carbon dioxide

    B2:beer making

    P2:two species of yeast are used, beer is brewed from barley grainsB3:wine

    P3:is made through fermentation of grape juices produce ethanolB4:soya sauce

    P4:is made from soya beans fermented by the action of fungi

    11

    1

    11

    11

    1

    Any 3 sets ofB+P

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    SKEMA PERCUBAAN SPM PAHANG 2010 4551/2

    BIOLOGI KERTAS 2 15

    (correspond)

    Notes:

    i.if only B isstated without

    P, maximum

    mark is 2ii. B is correct

    and P is wrong,award mark

    only for B

    Total=6m

    d. Able to state three ways to conserve and preserve the biodiversity

    F1:replanting programmes after selective logging in rainforestP!:each house/school plant at least one tree

    F2:campaign through media/NGO/private sectorsP2:banner/radio/television/pamphletF3:recycle/reuse/reduce waste products

    P4:build the centre for recycling/any relevant explanation

    F4:stop open burningP4:dig and put the waste in the ground

    F5:car pool/use public transportP5:reduce the use of fuel and release of pollutants

    F6:any relevant fact

    P6: any relevant explanation

    any 6 = 6m

    total = 6m

    END OF MARK SCHEME

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    1

    4551/3(PP) SULIT

    BIOLOGY 3

    Peraturan Pemarkahan

    Peperiksaan Percubaan SPM 2010

    QUESTION 1

    1 (a) KB0603 Measuring Using NumbersScore Criteria

    3

    Able to record all 4 Final length of cylindrical potato strip in the box given correctly.

    The concentration of sucrose

    solution( M)

    The final length of cylindrical potato strip (cm)

    0.2

    5.6

    0.3

    5.3

    0.4

    4.6

    0.5 4.2

    2Able to record any 3 or 2 final length of cylindrical potato strip correctly.

    1 Able to record any one final length of cylindrical potato strip correctly.

    0No response or all incorrectly

    (b) (i) [KB0601 - Observation]

    Score Criteria

    3 Able to state any two different observations correctly according to the criteria:

    Must state the value of MV and RV:

    MV - The concentration of sucrose

    RV - The final length of cylindrical potato strip

    Sample answers:

    1. In concentration of sucrose, 0.2 M, the final length of cylindrical potato strip

    is 5.6 cm

    2. In concentration of sucrose 0.5M, the final length of cylindrical potato strip is 4.2 cm

    3. In concentration of sucrose 0.3M, the final length of cylindrical potato strip is 5.3 cm

    4. In concentration of sucrose 0.4, the final length of cylindrical potato strip is 4.6 cm

    2 Able to state any one observation correctly.

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    2

    4551/3(PP) SULIT

    or

    Able to state any two incomplete observations ( any 2 criteria)

    Not state the value one of 2 criteria

    Sample answers:

    1. In concentration of sucrose lower, the final length of cylindrical potato strip is

    5.6cm

    2. In concentration of sucrose higher, the final length of cylindrical potato strip is 4.2 cm

    3. The concentration of sucrose 0.2M, the final length of cylindrical potato strip is long

    // longer

    4. The concentration of sucrose 0.5, the final length of cylindrical potato strip is short //

    shorter

    1 Able to state any one idea of observation.(any 1criteria)

    Sample answers:

    1. The final length of cylindrical potato depends on the concentration of sucrose.

    2. The concentration of sucrose influence the final length of cylindrical potato strip.

    3. The concentration of sucrose is different , the final length of cylindrical potato strip

    is different

    0 No response orwrong response.

    Scoring

    Score Correct Inaccurate Idea Wrong

    3 2 - - -

    21 1 - -

    - 2 - -

    1

    1 - 1 -

    - - 2 -

    - 1 1 -

    1 - - 1

    0- 1 - 1

    - - 1 1

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    3

    4551/3(PP) SULIT

    1 (b) (ii) [KB0604 - Making inferences]

    Score Criteria

    3

    Able to make one inference for each observationbased on the criteria

    State the :

    o The concentration of sucrose solution

    o Reason ( movement of water )

    Sample answers:

    1. For 0.2 M / 0.3M sucrose solution is hypotonic / more concentration of water molecule

    compare the cell sap cause more water molecules move / diffuse into the cell sap of

    potato strip by osmosis .

    2.For 0.4 M / 0.5M sucrose solution, is hypertonic / more concentration of water compare

    the cell sap cause more water molecules move /diffuse out from cell sap of potato strip

    by osmosis .

    2

    Able to make one inference for any one observation.

    or

    Able to make one and incomplete inference Sample answer:

    for each observation.

    Sample answers:

    1. For 0.2 M / 0.3M sucrose solution more water molecules move / diffuse into the cell

    sap of potato strip by osmosis .

    2.For 0.4 M / 0.5M sucrose solution, more water molecules move /diffuse out from

    cell sap of potato strip by osmosis .

    1 Able to make an idea of inference with one criterion.

    0 No response orwrong response.

    Scoring

    Score Correct Inaccurate Idea Wrong

    3 2 - - -

    21 1 - -

    - 2 - -

    1

    1 - 1 -

    - - 2 -

    - 1 1 -

    1 - - 1

    0- 1 - 1

    - - 1 1

    Note : Cannot repeat observation

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    4551/3(PP) SULIT

    1(c) [KB0610Variables]

    3

    Able to state all 3 variables and the 3 methods to handle the variable correctly.

    Sample Answer :

    Variables Method to handle the variable correctly

    Manipulated variable

    The concentration of sucrose

    solution

    Use the different concentration of sucrose solution

    OR

    Change the concentration of sucrose

    solution

    Responding variable

    The final length of (cylindrical)

    potato strip

    Measure and recordthe length of cylindrical

    potato strip by using ruler

    Constant variable

    The volume/ quantity of sucrose

    solution // the initial length of

    cylindrical potato strip

    Use the same / the volume of sucrose solution //

    quantity of sucrose solution // the initial length of

    cylindrical potato strip is 5cm

    OR

    Fixed the volume / quantity of sucrose solution //

    the initial length of cylindrical potato strip is 5 cm

    .

    6 ticks correctly

    2

    4 - 5 ticks correctly.

    Reject way how to handle variable if variable is wrong.

    1Able to state 2-3 ticks correctly

    0

    Able to state 1 tick correctly or no respons

    3 mark 6 ticks

    2 mark 4-5 ticks

    1 mark-2-3 ticks

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    4551/3(PP) SULIT

    1(d) [KB0611- Making Hypothesis]

    Score Criteria

    3

    Able to state a hypothesis to show a relationship between the manipulated variable and

    responding variable and the hypothesis can be validated, base on 3 criteria:

    manipulated variable (P1)

    responding variable (P2)

    relationship (H)

    Sample answer :

    1. if the concentration of sucrose solution is increase / rise/ higher, the final

    length of cylindrical potato strip is decrease/ lower // vise versa

    2. thehigher concentration of sucrose solution, the lower /shorter final length of

    cylindrical potato strip // vice versa

    2

    Able to state a hypothesis relating the manipulated variable and responding variable

    inaccurately with two criteria correctly :

    Manipulated variable Responding variable

    No relationship/ incorrectly

    Sample answer:

    1. if the concentration of sucrose solution is different , the final length of

    cylindrical potato strip is different

    2. the different concentration of sucrose solution, the different final length of

    cylindrical potato strip // vice versa

    1

    Able to state a hypothesis relating the manipulated variable at idea level, with one

    criteria correctly

    Sample answer:

    1.Different concentration of sucrose solution influenced the final length of

    cylindrical potato strip

    2.The final length of cylindrical potato strip depends on the concentration of

    sucrose solution

    3.. The final length of cylindrical potato strip affected by the concentration of

    sucrose solution

    .

    0

    Not able to response orwrong response.

    Note : directly proportional and inversely proportional are not accepted

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    4551/3(PP) SULIT

    1(e)(i) [KB0606 Communicating]

    Score Criteria

    3 Able to construct a table by using the criteria given

    T : State all the title /aspects is given with the correct unit

    D : State all data for the 3 aspect

    C : All calculation / percentage changes in length correct

    Sample answers

    The

    concentration

    of sucrose

    solution (M)

    The initial length

    of potato strip

    (cm)

    The final length of

    potato strip (cm)

    The percentage

    changes in the length

    of potato strip (%)

    0.1 5 5.9 18

    0.2 5 5.6 12

    0.3 5 5.3 6

    0.4 5 4.6 -8

    0.5 5

    4.2

    -16

    2 Able to record two criterias correctly

    1 Able to record one criteria correctly

    0 No response orwrong response.

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    4551/3(PP) SULIT

    1 (e)(ii) [KB0612 Relationship between space and time]

    Score Criteria

    3

    Able to draw the graph correctly with the following aspects:

    P(paksi) : Axes :Uniform scales on both horizontal and vertical axis 1 mark

    T (titik ) : Points :

    All points plotted correctly - 1 mark

    B ( bentuk ) : Curve :

    Able to join all the points to form a smooth graph / passing

    through all point

    -ve gradient - 1 mark

    Sample answer :X axes : MV the percentage change in lenght (%)

    Y axes : RV - concentration of the sucrose solution

    2 Any two correct.

    1Any one correct

    0 No response or wrong response.

    1(f) [KB0608 Interpreting Data]

    Score Criteria

    3 Able to state the concentration of sucrose solution which is isotonic to the

    concentration of the cell sap of the potatoes base on the graph and give a reasons.State all the criteria

    Criteria:

    P1: State the concentration of sucrose solution base on the graph ( intercept / cut

    on X axis ) : value accept 0.35M + 0.01

    P2: does not cause any changes to the length of the potato stripP3 : amount of water in and out of the potato strip / cell is the same.

    Sample answer:

    The concentration of sucrose solution which is isotonic to the concentration of the

    cell sap of the potatoes base on the graph is 0.35M, that does not cause any changes

    to the length of the potato strip because amount of water in and out of the potato strip/ cell is the same.

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    8

    4551/3(PP) SULIT

    2 Able to state the concentration of sucrose solution which is isotonic to the

    concentration of the cell sap of the potatoes base on the graph and give a reasons.

    State any two the criteria only.

    Sample answer:

    The concentration of sucrose solution which is isotonic to the concentration of the

    cell sap of the potatoes base on the graph is 0.35M , that does not cause any changes

    to the length of the potato strip.

    1 Able to state the idea of the relationship used base on one criteria

    Sample answer :

    Sample answer:

    1. The concentration of sucrose solution which is isotonic to the concentration of

    the cell sap of the potatoes base on the graph is 0.35M

    0 Not able to response orwrong response.

    1(g) [KB0605 Predicting]

    Score Criteria

    3 Able to predict the result accurately.

    Relationship :

    P1 = Able to state the changes of mustard green stem strips / condition

    P2 = Able to state inward

    P3 = Able to state the reason (movement of water)

    Sample answer:

    1. The mustard green stem strip will become shrink/ flaccid and curve inward( epidermis

    outside ) because water molecules move out from cell sap (of the mustard green)

    2 Able to predict the result less accurate base on two criterias:

    Sample answer :

    1. The mustard green stem strip will become shrink/ flaccid and curve inward( epidermis

    outside ) because ( ANY INCORRECTLY REASON )

    1 Able to give idea of the result base on one criterion

    Sample answer :

    1. The mustard green stem strip will become shrink/ flaccid

    0 Not able to response orwrong response.

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    4551/3(PP) SULIT

    1(i) [KB0609 Defining by Operation]

    Score Criteria

    3 Able to state correctly the meaning of osmosis process relationship base on three criterias

    :

    P1 : Osmosis concept based on the observation

    P2 : related to the different concentration of sucrose solution

    P3 : Effect to the potato strips

    Sample answer:

    Osmosis is a process which is potato strips immersed in sucrose solution cause water

    molecules move in / out of the potato strip across the plasma membrane depends on the

    different concentration of sucrose solution that will affect the length of potato strip.

    2 Able to state the meaning of osmosis or as a concept base on two criterias :

    P1 and P2 // P1 and P3 // P2 and P3

    1 Able to state the idea base on one criteria

    P1/P2/P3 only

    0 Not able to response orwrong response.

    1(i) [KB0602 Classifying]

    Score Criteria

    3 Able to classify all ( 4 pairs)correctly the concentration of sucrose solution with unit

    and conditions of mustard green into table 3

    Sample answer:

    Concentration of sucrosesolution

    Conditions of mustard green

    0.2 M

    0.5 M

    0.6 M

    0.8 M

    B

    A

    C

    D

    2 Able to classify 3 pairs correctly into table 3

    1 Able to classify 2 pairs correctly into table 3

    0 Able to classify one pair or no response

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    4551/3(PP) SULIT

    QUESTION 2

    PROBLEM STATEMENT

    No. Mark Scheme Score

    2(i)KB061201

    Able to state a problem statement relating the manipulated variablewith the responding variable correctly 3

    P1 : (Type of) food samples / white bread and cashew nuts.

    P2 : energy content/value in food samples/ final water temperature

    H : question form and question mark(?)

    Sample answer

    1. Which types of food samples, the white bread or cashew nuts , has

    a higher energy value/content?

    2. Do different types of food samples contain similar energy

    value / content?

    3. Do white bread / cashew nuts has a higher energy value/content

    compared to cashew nuts / white bread?

    Able to state a problem statement less accurately 2

    Sample answer

    1. Which types of food samples, the white bread or cashew nuts , has

    a higher energy value/content. (no H)

    2. Do different samples contain similar energy value / content? (no

    P1)

    3. Do white bread / cashew nuts has a higher energy value/content ?

    (incomplete P1.4. Different types of food samples has different energy value/content?

    (no H)

    Able to state a problem statement at idea level 1

    Sample answer

    1. Which food has higher energy? (no P1 and P2)

    2. Do white bread has a higher energy value.(no P1 and H)

    No response or incorrect response 0

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    4551/3(PP) SULIT

    AIM OF INVESTIGATION

    No. Mark Scheme Score

    2 (ii) Able to state the objective of the investigation correctly

    KB061203

    Sample answer

    To determine and compare the energy content/value in white breadand cashew nuts.

    HYPOTHESIS

    No. Mark Scheme Score

    2 (iii)

    KB061202

    Able to state a hypothesis relating the manipulated variable to the

    responding variable correctly 3

    P1 : type of food samples / white bread and cashew nuts.

    P2 : energy content/value (in food samples)

    H : relationship

    # P1 must different food class

    Sample answer

    1. Cashew nuts have a higher energy value/content than white bread.

    2. White bread has lower energy value/content than cashew nuts.

    2. Different type of food samples contain different energy

    value /content.

    Able to state a hypothesis inaccurately*Have P1 and P2 or P1/P2 and H 2

    Sample answer

    1. Type of food samples influences the energy value/content in food

    samples. (no H)

    2. Cashew nuts have a higher energy value/content. (incomplete P1)

    3. Type of food samples contains different energy value /content.

    4. Higher final water temperature, higher energy value (P1 twice)

    Able to state a hypothesis at idea level 1

    Sample answer

    White bread / cashew nuts has energy content/value. (only P2)

    No response or incorrect response 0

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    4551/3(PP) SULIT

    VARIABLES

    No. Mark Scheme Score

    2 (iv) Able to state all three variables correctly

    KB061203

    Sample answer

    Manipulated : (Type of) food samples // cashew nuts and white bread

    Responding : The energy value of food samples // final water

    temperature

    Fixed : Volume of distilled water / the mass of food / Initial

    temperature of distilled water

    LIST OF APPARATUS AND MATERIALS

    No. Mark Scheme Score

    2(v)

    Able to list all the important apparatus and materials correctly.

    6-7 apparatus(A) + 5 materials (M)

    ## type of food sample must from different food class

    3

    KB061205

    *compulsory apparatus and materials

    Sample answer

    Apparatus : *boiling tubes, *thermometer, retort stand, pin,

    measuring cylinder, Bunsen burner and electronic balance.

    Materials : *distilled water, *white bread, *cashew nuts, plasticine

    and cotton wool.

    Able to list any 4-5 apparatus (including * ) and 3 * materials 2

    Able to list any 2-3 apparatus (including * ) and 3 * materials 1

    No response or incorrect response 01 apparatus + 3 * materials

    Remark :

    for title materials and apparatus for planning experiment.

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    13

    4551/3(PP) SULIT

    TECHNIQUE USED

    No. Mark Scheme Score

    2 (iv)

    KB061203

    Able to state the operating responding variable correctly using

    suitable apparatus B1 = 1

    Sample answer1. Measure and record the final / the increase in temperature of

    distilled water using a thermometer.

    or

    2. Calculate the energy value of food samples using a formula :

    Energy value = 4.2 (Jg-1 0

    C-1

    ) x mass of water (g) x

    increase in temperature (0C)

    (kJg-1

    )

    Mass of food sample (g) x 1000

    PROCEDURE

    No. Mark Scheme Score

    2 (vii)

    Able to describe the steps of experiment correctly based on the

    following aspects:

    KB061204 K1 : Preparation of materials and apparatus (any 4)

    K2 : Operating the constant variable (any 1)

    K3 : Operating the responding variable (any 1)

    K4 : Operating the manipulated variable (any 1)K5 : Steps to increase reliability of results accurately / precaution

    (any 1)

    Sample answers

    1. Weight and record the mass of white bread.

    2. Fill a boiling tube with 20ml of distilled water.

    3. Clamp the boiling tube to the retort stand in an upright

    position as shown in the diagram.

    4. Record the initial temperature of the distilled water in the

    boiling tube.

    5.

    Fix the white bread at the end of the pin.6. Ignite the white bread by holding it in the flame of a Bunsen

    burner. Then immediately place it beneath the boiling tube to

    heat the water.

    7. Stir the water gently with the thermometer.

    8. Record the final temperature of the distilled water in the

    boiling tube.

    9. Repeat steps 1-8 using cashew nuts to replace the white bread.

    10.Calculate the energy value of the food samples by using the

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    4551/3(PP) SULIT

    formula :

    Energy value = 4.2 (Jg-1 0

    C-1

    ) x mass of water (g) x

    increase in temperature (0C)

    (kJg-1

    )

    Mass of food sample (g) x 1000

    11.Record/tabulate all the results in the table.

    K1 (any 4)

    1.Weight white bread

    2. Weight chew nut

    3. Fill the boiling tube

    4. Clamp

    5. Fix at the end of the pin

    6. Ignite

    7. place burning food under the boiling tube to heat the water.

    K2 (any 1)1. Fix the volume of distilled water is 20ml

    2. Fix the mass of food samples

    3. Fix the initial temperature of water

    K3 (any 1)

    1. Record the final temperature of water by using thermometer

    2. Calculate the energy value of the food samples by using the

    formula :

    Energy value = 4.2 (Jg-1 0

    C-1

    ) x mass of water (g) x

    increase in temperature (0C)

    (kJg

    -1

    )Mass of food sample (g) x 1000

    K4 (any 1)

    1. Replaced / change the experiment with another food samples (

    name the food sample from different food class)

    Example:

    Replace white bread with cashew nuts

    K5 (any 1)

    1. Stir the water gently with the thermometer.

    2. Repeat experiment to get average reading.

    3. Use an insulator shield to reduce heat loss to the surroundings.

    4. To ensure that the food is oxidized completely, make sure the food

    is burnt completely.

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    4551/3(PP) SULIT

    All 5 K 3

    Any 3 - 4 K 2

    Any 2 K 1

    No response or incorrect response or 1 K only. 0

    Remark:

    1K - for title procedure for planning experiment.

    No. Mark Scheme Score

    2 (viii)

    Able to construct a table to record data based on the following

    aspects : B2 = 1

    KB061203 1. Correct title and units (*titles compulsory)

    Sample answer

    Types of food samples *

    White bread * Cashew nuts *

    Mass (g)

    Initial temperature (oC)

    Final temperature (oC)

    Change in temperature (oC) *

    Energy value (J/g) / (kJ/g) *

    CONCLUSION

    No. Mark Scheme Score

    2(ix) Able to make the right conclusion correctly

    KB061203

    Sample answer

    Cashew nuts have a higher energy value/content than white bread

    Hypothesis accepted

    Reject : (only) Hypothesis accepted

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    PLANNING OF EXPERIMENT

    No. Mark Scheme Score

    2(x) Able to write the experimental planning

    KB061203

    1. Problem Statement

    2. Aim

    3. Hypothesis

    4. Variables

    5. Materials and Apparatus

    6. Technique

    7. Procedure

    8. Result

    9. Conclusion

    7 - 9 ticks 3

    4 - 6 ticks 2

    2 - 3 ticks 1

    0 1 tick

    No response or incorrect response 0

    END OF MARKING SCHEME

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