spm mm ans (kedah)

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    PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA

    SEKOLAH MENENGAH

    NEGERI KEDAH DARUL AMAN

    PEPERIKSAAN PERCUBAAN SPM 2008 1449/1MATHEMATICS

    ANSWER FOR PAPER 1

    1 C 11 D 21 C 31 C

    2 B 12 C 22 A 32 C

    3 D 13 A 23 D 33 A

    4 B 14 D 24 D 34 D

    5 C 15 C 25 B 35 B

    6 B 16 A 26 B 36 D

    7 A 17 B 27 D 37 A

    8 C 18 C 28 A 38 B

    9 D 19 D 29 B 39 C

    10 B 20 A 30 A 40 A

    ANALISIS

    A 10

    B 10

    C 10

    D 10

    NOTA: MARKAH PELAJAR = 100140

    )21(

    +KK

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    1449/2 (PP)

    Matematik

    Kertas 2

    Peraturan

    Pemarkaha

    n

    17 Sept2008

    PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA

    SEKOLAH MENENGAH

    NEGERI KEDAH DARUL AMAN.

    PEPERIKSAAN PERCUBAAN SPM 2008

    UNTUK KEGUNAAN PEMERIKSA SAHAJA

    MATHEMATICS

    Kertas 2

    PERATURAN PEMARKAHAN

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    Peraturan pemarkahan ini mengandungi 17 halaman bercetak

    Section A

    [ 52marks]

    Question Solution and Mark Scheme Marks

    1(a)

    (b)

    Note:

    SetPQ correctly shaded, award K1

    K1

    K2 3

    P Q R

    PQ

    R

    PQ

    R

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    Question Solution and Mark Scheme Marks

    2 3 21p q or2

    2 143

    p q or equivalent

    5 25p or 5 103 q or equivalent

    OR

    4

    2

    qp

    or 4 2q p or equivalent (K1)

    5 25p or5

    103 q or equivalent (K1)

    OR

    1711

    31 4

    1 1 2 2 13

    p

    q

    or equivalent (K2)

    5p

    6q

    Note :

    Accept

    1. 56

    pq

    as final answer, award N1

    2.

    111

    31

    1 1 2 2 13

    or equivalent seen, award (K1)

    K1

    K1

    N1

    N1 4

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    Question Solution and Mark Scheme Marks

    3 23 10 0x x

    3 5 2 0x x or equivalent

    2x

    5

    3x or 1 67

    Note : 1. Accept without = 0

    2. Accept three terms on the same side, in any order.

    3. Do not accept solutions solved not using factorisation.

    4. Accept 5 5

    2 0, with , 2

    3 3

    x x x

    for KK2

    K1

    K1

    N1

    N1 4

    4 Identify UPT or TPU

    tan2 2

    7

    5 4UPT

    or equivalent

    66 8 or 66 48'

    P1

    K1

    N1 3

    5(a)

    (b)

    3

    2y

    Gradient SR = 4

    *6 41

    y

    x

    or *6 4 1 c or equivalent

    4 10y x

    or equivalent

    10

    N1

    P1

    K1

    N1

    N1 5

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    Question Solution and Mark Scheme Marks

    6(a)

    (b)

    Non-statement P1

    Implication 1 : Ifxp >yp , thenx >y K1

    Implication 2 : Ifx >y, thenxp >yp K1

    (c) If k is a multiple of 9, then it is multiple of 3 P1

    True dep P1

    (d) Premise 2 : 384 is divisible by 12

    or

    384 boleh dibahagi tepat dengan 12 K1 4

    7(a)

    (b)

    90 222 14

    360 7 or

    60 222 7

    360 7

    14 +90 22

    2 14360 7

    +60 22

    2 7360 7

    + 7 + 7

    172

    3 or

    157

    3 or 57 33

    290 2214

    360 7 or 2

    180 227

    360 7 or 2

    60 227

    360 7

    290 22 14360 7

    2180 22

    7360 7

    + 260 22

    7360 7

    308

    3 or

    2102

    3 or 102 67

    Note :

    1. Accept for K mark.2. Correct answer from incomplete working, award KK2.

    K1

    K1

    N1

    K1

    K1

    N1 6

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    Question Solution and Mark Scheme Marks

    8(a)

    (b)

    1 2

    3 5

    2

    15

    1 2 1 3 1 3

    3 5 3 5 3 8

    Note :1 2

    3 5 or

    1 3

    3 5 or

    1 3

    3 8 , award K1

    (with condition of not more than 3 pairs)

    165

    360 or

    55

    120 or

    11

    24 or 0 458

    K1

    N1

    K2

    N1 5

    9(a)

    (b)

    10k

    3p

    4 2 41

    3 1 24 1 2 3

    x

    y

    2x

    1y

    Note :

    1.

    *inverse 4

    matrix 2

    x

    y

    or

    4 21

    3 14 1 2 3

    seen,

    award K1

    2. Do not accept

    *inverse 1 2

    matrix 3 4

    or

    *inverse 1 0

    matrix 0 1

    .

    3.2

    1

    x

    y

    as final answer, award N1.

    4. Do not accept any solution solved not using matrices.

    P1

    P1

    K2

    N1

    N1 6

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    Question Solution and Mark Scheme Marks

    10(a) 9 P1

    (b)

    9 3 3 9

    5 0 0 5or

    K1

    6 11 1 25 5or or N1

    Note: Without working, award K1N1

    (c) 1 1

    3 9 5 5 9 9 21 16 1532 2

    t t or equivalent K2

    12 N1 6Note : Allow one mistake in distance expression for any two or

    one correct areas for K1.

    11 40

    1 223 3 5

    3 7

    40 1 22

    3 3 53 7

    232 8 232 9

    Note:

    1. Accept for K mark

    2. Correct answer from incomplete working, award KK2

    K1

    K1

    K1

    N1 4

    Question Solution and Mark Scheme Marks

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    12(a)

    (b)

    (c)(i)

    (ii)

    (d)

    10

    5

    Note : Konly meant for table value

    Graph

    Axes drawn in correct direction, uniform scales in 3 5 x 4and 34 y 11

    7 points and *2 points correctly plotted or curve passes through

    these points for 3 5 x 4

    Smooth and continuous curve without any straight line and passes

    through all 9 correct points using the given scales for3 5 x 4

    Note : 1. 7 or 8 points correctly plotted, award K1

    2. Ignore curve out of range

    2 5 2 7y

    2 45 2 40x

    Identify equation 3 2y x or equivalent

    Straight line 3 2y x correctly drawn

    Values ofx : 1 8 1 7x

    2 7 2 8x

    Note : 1. Allow P mark or N mark if values ofy andx

    shown on graph

    2. Values ofy andx obtained by computations, award

    P0 or N0

    (> 2 decimal places)

    K1

    K1

    P1

    K2(does not

    depend on P)

    N1(depends on

    P and K)

    P1

    P1

    K1

    K1

    N1(dep 2nd K1)

    N1(dep 2nd K1)

    2

    4

    2

    4

    12

    Values ofx on the

    graph must correct

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    y

    O 1 2 3 4

    5

    10

    1234

    5

    10

    15

    25

    35

    20

    30

    15

    22 5 8 y x x

    3 2y x

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    Question Solution and Mark Scheme Marks

    13(a)(i) (5, 4) P1

    (ii) (5, 2) P2 3

    Note : (1, 0) or (5, 2) marked on diagram, award P1

    (b)(i) W: Rotation 90 anticlockwise at centre ( 1, 2) orequivalent. P3

    Note :

    1. P2: Rotation 90 anticlockwise orRotation at centre ( 1, 2),

    2. P1: Rotation.

    (ii) V: Enlargement centre ( 5, 5) with scale factor 3 P3 6

    Note :

    1. P2: Enlargement centre ( 5, 5) orEnlargement scale factor 3.

    2. P1: Enlargement.

    (c)198

    *(3)K1

    198198 198 22

    *(3)or K1

    176 N1 3

    OR198

    1618

    OR198

    89

    or 2198

    83

    , award K2

    12

    Question Solution and Mark Scheme Marks

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    14(a)

    (b)

    (c)

    (i)

    Upper boundary : (II to VIII)

    Frequency : (II to VIII)

    Cumulative frequency : (II to VIII)

    Note:Allow one mistake in frequency for P1

    (ii) 74 5

    Axes drawn in correct direction and uniform scale for29 5 99 5x and 0 y 40

    *8 points correctly plotted

    Note :

    *6 or *7 points correctly plotted or curve passes through usingat least 6 correct upper boundary, award K1

    Smooth and continuous curve without any straight line passes all

    8 correct points for using given scales 29 5 99 5x

    First Quartile = 56 0 0 5 or Third Quartile = 75 5 0 5

    Interquartile range = * *75 5 56.0

    = 19 5 0 5

    P1

    P2

    P1

    P1

    P1

    K2

    N1

    K1

    K1

    N1

    5

    4

    3

    12

    Upper

    Boundary

    Sempadan

    Atas

    Frequency

    Kekerapan

    Cumulative

    Frequency

    Kekerapan

    Longgokan

    29 5 0 0 I

    39 5 2 2 II

    49 5 3 5 III

    59 5 8 13 IV

    69 5 10 23 V

    79 5 11 34 VI

    89 5 4 38 VII

    99 5 2 40 VIII

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    0

    5

    10

    15

    20

    25

    30

    35

    40

    39.5 49.5 59.5 69.5 79.5 89.5 99.529.5

    Marks

    Cumulative

    Frequency

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    Question Solution and Mark Scheme Marks

    15 Note :

    (1) Accept drawing only (not sketch).

    (2) Accept diagrams with wrong labels or without labels.

    (3) Accept correct rotation of diagrams.

    (4) Lateral inversions are not accepted.

    (5) If more than 3 diagrams are drawn, award mark to the

    correct ones only.

    (6) For extra lines (dotted or solid) except construction lines, nomark is awarded.

    (7) If other scales are used with accuracy of 0.2 cm one way,deduct 1 mark from the N mark obtained, for each part

    attempted.

    (8) Accept small gaps extensions at the corners.

    For each part attempted :

    (i) If 0 4 cm, deduct 1 mark from the N mark obtained.

    (ii) If > 0 4 cm, no N mark is awarded.

    (9) If the construction lines cannot be differentiated from theactual lines:

    (i) Dotted line : If outside the diagram, award the Nmark.

    If inside the diagram, award N0.

    (ii) Solid line : If outside the diagram, award N0.If inside the diagram, no mark is

    awarded.

    (10) For double lines or non-collinear or bold lines, deduct 1mark from the N mark obtained, for each part attempted.

    Question Solution and Mark Scheme Marks

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    15(a)

    Correct shape with rectanglesJFGR ,JKPNand

    square NPQR

    All solid lines.

    JFFGGQ = QR =RN >NJ

    Measurement correct to 0 2 cm (one way) and all anglesat vertices of rectangles = 901

    K1

    K1

    dep K1

    N1 depK1K1

    3

    Question Solution and Mark Scheme Marks

    R Q G

    N P

    J K F

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    15(b)

    Correct shape with the triangleFEV, rectangleJKPNand

    hexagonABFEKJ

    All solid lines

    AB>EV>EF=JA =NP>BF= NJ= VP

    Measurement correct to 0 2 cm (one way) and all angles at the

    vertices of rectangles = 901

    K1

    K1dep K1

    N2 dep

    K1K1 4

    Question Solution and Mark Scheme Marks

    A B

    E

    N P

    J K

    F

    V

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    15(c)

    Correct shape with rectanglesBCGF, GWVUandFULK

    All solid lines

    Note : IgnorePQ

    Pand Q joined with dotted line to form squarePQGUorrectanglePQWV

    CW>BC> VL > VW=BK>KL > UL =LP=PV=BF=FK

    Measurement correct to 0 2 cm (one way) and all angles atthe vertices of rectangles = 901

    K1

    K1

    dep K1

    K1 dep

    K1K1

    N2 dep

    K1K1K1

    5

    12

    U

    B C

    G

    P

    LK

    F

    WV

    Q

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    Question Solution and Mark Scheme Marks

    16(a)

    (b)(i)

    (ii)

    (c)

    (36N, 70W)

    Note: 70oW or (65N, W/ 70E), award P2

    36N or (180

    110), award P1

    50 36 60 or equivalent

    5160

    140 60 cos50 or equivalent

    5399 52

    Note : Usage of cos 50 or 30 110 , award K1

    180 60 cos36 or 8737 38

    Note : Usage of cos 36 or 70 110 , award K1

    180 60 cos36 *

    800

    10 92 or 10 hours 55 minutes

    P3

    K1

    N1

    K2

    N1

    K2

    K1

    N1

    3

    5

    4

    12

    END OF MARK SCHEME