skema trial sbp physics 2007

7/30/2019 Skema Trial SBP Physics 2007

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SEKTOR SEKOLAH BERASRAMA PENUH

BAHAGIAN SEKOLAH

KEMENTERIAN PELAJARAN MALAYSIA

PEPERIKSAAN PERCUBAAN

SIJIL PELAJARAN MALAYSIA 2007

FIZIK

PERATURAN PERMARKAHAN

KERTAS 1

KERTAS 2

KERTAS 3


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2

Jawapan kertas 1

Percubaan SPM SBP 2007

Soalan Jawapan Soalan Jawapan Soalan Jawapan Soalan Jawapan Soalan Jawapan

1 A 11 D 21 D 31 C 41 C2 D 12 B 22 B 32 E 42 A

3 D 13 B 23 A 33 C 43 A

4 C 14 B 24 D 34 A 44 A

5 B 15 C 25 D 35 C 45 C

6 B 16 D 26 B 36 A 46 A

7 B 17 A 27 A 37 D 47 D

8 C 18 D 28 D 38 C 48 B

9 A 19 C 29 C 39 D 49 D10 B 20 D 30 D 40 C 50 D

Skema FIZIK kertas2

PEPERIKSAAN PERCUBAAN SPM 2007

SOALAN SELARAS SBP

NO ANSWER MARK

1(a)(i) State the name of liquid correctly- mercury

1

(a)(ii) State the correct physical change- Expansion / increase in volume

1

(b)(i) State the choice of instrument correctly

-thermometer X

1

(b)(ii) Give one correct reason.- The smallest division is smaller // able to detect the smaller /smallestchange

1

TOTAL 4

2(a)(i) Total internal reflectionPantulan dalam penuh

1

(a)(ii) The refractive index of Y is higher than the refractive index of X//Vice versa

Ketumpatan optik Y lebih besar daripada ketumpatan optik X

1

(b)Sin c =

n

1=

1.2

1= 0.4762

1

1


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3

c = 28.44o

// 280

26

(c) Prism periscope // prism binoculars // camera// endoscope and etc.Periskop berprisma/binokular berprisma/kamera/endoskop dll

1

TOTAL 5

3(a)(i) Constant/ uniform velocity // acceleration is zero

Halaju seragam / pecutan sifar

1

(a)(ii) Constant acceleration // increasing velocity uniformly followed by

zero acceleration // constant velocityPecutan seragam / halaju bertambah seragam diikuti dengan pecutan sifar /

halaju seragam

1

(b)(i) zero //F = 0sifar // F = 0

1

(b)(ii) constant / uniform velocity // acceleration is zero

halaju seragam / pecutan sifar

1

(c) 1- a curve with the increasing gradient (from 2.00 pm 2.01 pm)2- Straight line (> 2.01pm) 2

TOTAL 6

NO ANSWER MARK

4 (a) Reflection of wave 1

(b) 1- The incident ultrasonic waves is reflected by the big rock to form

reflected ultrasonic waves.

2- The incident angle is equal to reflected angle

1

1

(c)(i)d=

2

vt=

2

5.11560

= 1170 m

1

1

(c)(ii) 1- Distance between two pulses is 3 cm

2- Amplitude is smaller

1

1

TOTAL 7

5(a)(i) The wall of a dam in Figure 4.2 is much thicker at the bottom than atthe top and withstand the higher pressure at the bottom of the lake.

1


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(a)(ii) Pressure at B is higher than at A // vice versa 1

(b)(i) Dam in Diagram 5.2 1

(b)(ii) 1- When depth increases, pressure increases.

2- Thicker at the base can withstand high pressure.

1

1

(c)(i) Siphon system 1

(c)(ii) Diffrence in water level will cause different in pressure 1

(c)(iii) 1

TOTAL 8

NO ANSWER MARK

6(a) Induced current 1

(b)(i) 1- Number of turns in Diagram 6.1 is greater.

2- Angle of deflection for galvanometer in diagram 6.1 is bigger.

1

1

(ii) 1- as the number of turns increases, the rate of change of magnetic flux

increases2- hence, induced more current

1

1

(c) Lenzs law

(d) 1- The current induced produces north pole on the left side2- so as to oppose the oncoming magnet

TOTAL 8

7(a) n-p-n transistor 1

(b)(i) 12 V 1

(b)(ii) 27 + 3 = 30 k 1

(b)(iii)VYZ =

273

3

x 12

= 1.2 V

1

1(c) 1- Lamp L will not glow

2- because the voltage across YZ (i.e 1.2 V) is less than the

base-emitter potential difference of 2V

1

1

(d) Resistor R1 and R2 are swapped places 1

(e) 1-Resistor R1 is replaced by a thermistor.2- Lamp L is replaced by an electric bell.

11

TOTAL 10


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8(a) Atoms of elements which have same proton number, but differentnucleon numberIsotop ialah atom satu unsure yang mempunyai nombor proton yang sama, tetapi

nombor nucleon yang berlainan

1

(b)(i) 1- Show the line in the graph

2- T1/2 = 4 days

1

1

(b)(ii)

Shape of graph

One point is correctTwo or more point

1

1

2

(c)(i) Geiger- Muller tube 1

(ii) Back ground reading 1

(iii) 562 20/19/21 = 542/ 543/ 541 counts/min 1

(iv) 5 cm 1

(v) 1- At 5 cm, the reading form detector increase rapidly

2- In large scale/ number, shows the existing of

-particles

1

1TOTAL 12

Number Answer Mark Remark

9 (a) Heat is the quantity of energy that is transformed from one hot objectto a cold object.

1

(b) 1-Figure 9.1 shows a situation where a solid changes into liquid /

Figure 9.2 shows a situation where a liquid change into gas2-Both processes have a change in the state of matter.

3-Both processes require heat.

4-The heat absorbed is not to raise the temperature, to overcome theforce between the molecule particles during the physical change.

5-Concept involved is Latent Heat

1

1

1

1

1

(c)(i)

(ii)

1-Water evaporates from the skin when we sweat.2-for water to evaporate it use heat from the body

1-Steam condenses to form water so,2-latent heat of vaporization of steam is let out more steam.

11

11


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(d)

Suggestion Explanation

Use insulator behind theabsorber panel

To prevent the loss ofheat energy

Use an absorber panelwhich is painted black.

A black surface is a goodabsorber of radiation so it will

absorb heat fasterThe pipe inside the plate

must be made of metal

Metal is a good heat conductor,

so it will transmit heat towater easily

Pipe embedded in platemust be long

Longer pipe will enlargesurface area will absorbs heat

faster

A storage tank must be

place at a higher level

To give higher pressure

Use glass cover on the topof the panel

To trap heat energy.(energy is radiated in,but cannot radiate out again).

Any five suggestions and explanation[ 10 marks ]

2

2

2

2

2

Total 20

Number Answer Mark Remark

10 (a) State the energy transformations correctly

Chemical energy electrical energy

1

(b) Compare the arrangement of dry cells correctly

1 Figure 10.1(a): The dry cells connected in parallel,Figure 10.1(b): The dry cells connected in series

Compare the voltage supplied correctly2 The voltage supplied in Figure 10.1(a) is smaller

Compare the ammeter reading correctly

3 The ammeter reading in Figure 10.2(a) is smaller

State correctly the relationship between the voltage supplied

and the energy transferred4 The greater the voltage supplied, the greater the energy

transferred to flow the electric charges around the circuit

State correctly the relationship between the current flowing andthe energy transferred

5 The greater the current flowing around the circuit, the

faster that the energy is transferred

1

1

1

1

1

(c) State the situation when touching the live wire correctly1 Our bodies are at earth potential (0V)

2 If we touch the live wire, there will be a large potential

2


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difference (p.d) the live wireand our body. A large current flow through it, probably

fatal.

State the situation when touching the neutral wire correctly

3 The neutral wire stays at earth potential (0V), roughly at thesame potential as our

bodies.4 If we touch the neutral wire, there is no p.d. across us and so

no current flows.

2

(d) State the method to make the cabin wiring more effective

The electric appliances are connected in parallel//diagram

State the correct reason

Allow each electric appliances to be switched on and off

independently

State the method to protect electric appliances from damage

Fit fuse at the live wire in the fuse box //diagram// Useminiature circuit breakers (mcbs)


To stop the flow of current by melting when a high voltageof electric current flows through the circuit // switches itself off

very quickly if the current exceeds e.g. 15A (for 15A mcb)

State the method to prevent electric shockEarth connection to the metal case of electrical appliances

State the correct reasonEarth wire connected to earth, so that when a fault occurs

and a current flows through the live wire and the earth wire, the

fuse in the live wire will blow and cut off the supply. It will

protect a person who may touch a faulty or live appliance

State the method to increase energy efficiency

Use low power lamps / install fluorescent lampRegularly cleaning and removing dust from the air filters of

air conditioners

Do not put more water in a kettle than needed for hot drinks


To save the energy

1

1

1

1

1

1

1

11

1

Total 20

11 (a) When an object is immersed in a fluid, the buoyang force on theobject is equal in size to the weight of fluid displaced by the object.

1


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Apabila objek terendam didalam bendalir, daya tujah ke atas yangdikenakan keatas objek itu adalah sama dengan berat bendalir yang

disesarkan.

(b) - B is denser than A.- B lebih tumpat dari A.

- The weight of water displaced is the same of the weight of

the rod.- Berat air disesarkan sama dengan berat rod.

- Weight of B is greater than weight of A- Rod B lebih berat dari rod A

- B will displace more volume of water- B menyesarkan isipadu air yang lebih banyak.

1

1

1

1

(c) - Material made from glass- Diperbuat daripada kaca

- Glass does not corrode with acid- Kaca tidak dihakis oleh asid

- Small diameter of capillary tube- Diameter tube kapilari yang kecil

- To increase the sensitivity of the hydrometer- Menambahkan kepekaan hidrometer- High density of shots- Bebuli berketumpatan tinggi

- Makes the hydrometer stays upright- Supaya hidrometer tegak

- Big diameter of bottom bulb- Diameter bebuli kaca besar

- To obtaine a bigger upthrust.- Menghasilkan daya tujah ke atas yang besar

- Choose N- Pilih N

- N is made from glass, has small diameter of capillary tube,

high density of shots and a big diameter of bottom bulb.- N diperbuat dari kaca, mempunyai diameter kapilari yang kecil,

bebuli berketumpatan tinggi dan bebuli kaca berdiameter besar.

1

1

1

1

1

1

1

1

1

1

(d)(i) Weight of boat = weight of water displaced

2500 N = 1000 x V x 10V = 0.25 m3

1

1

(d)(ii) Maximum weight = maximum water displaced

= 1000 x 4 x 10= 40000 N

maximum mass = 4000 kg

maximum load = 4000 250 = 3750 kg.

11

1

Total 20

12 (a)(i) A transformer is a device that steps up or steps down the voltage of

an alternating current. [1]

1

(ii) Transformer Q

Ns>Np

1

1

(b)(i) Vs = Ns Vp = 500 x 240 1


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9

Np 2000

= 60V 1

Vs = 1000 x 110500

= 220 V

1

1

(c) Heating effect in the coils Eddy currents in the coils

Leakage of magnetic flux The magnetisation and demagnetisation of the core

Maximum 3

11

1

Characteristic Explanation

Low resistivity To reduce heat loss in the cables

Low density The cables will be lighter

Low cost Cost of project will be lower

Low rate of thermal

expansion

The cables will not expand under hot

weather

Cable Q

Low resistivity, low density, medium cost, low rate of thermalexpansion

2

22

21

1

Total 20


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10


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SKEMA PERMARKAHAN KERTAS 3

No. 1 Answer Mark(a) (i) Manipulated variable = length of wire, l 1(a)(ii) Responding variable = Resistance of wire, R 1(a)(iii) Constant variable = Material of wire, cross-sectional area and temperature 1

(b) Tabulate ,l, V, I and R correctly in the table.

A Shows a table which have l, V, I and R

B State the correct unit of l /cm, V/V, I /A and R /

C All values of V are correct

D Values of I are correct

E Values of R are correct

F All values of are consistent

l /cm V / V I / A R /

20.0 0.5 0.2 2.5

30.0 0.7 0.2 3.540.0 0.9 0.2 4.5

50.0 1.1 0.2 5.5

60.0 1.3 0.2 6.5

111111

(c) Draw the graph of R against l .

A - Label y-axis and x-axis correctly

B - States the unit at the axis correctly

C - Both axes with the even and uniform scale:D -5 points correctly plotted:

E - a smooth best straight line

F - minimum size of the graph is 5 x 4Squares of 2 x 2 cm:

Number of Score6 5

5 4

3-4 3

2 2

1 1

5

(d) State the correct relationship based on the candidates graph

R is directly propotional to l.

1

(e) State ONE correct precaution so as to produce an accurate result of

the experimentThe position of the eye perpendicular to the scale when taking the

reading to avoid errors due to parallax/systematic error

1

TOTAL 16


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2 (a) Shows extrapolation on the graph , intercept y-axis

7 N

1

1

(b) (i)

(ii)

Frictional force

.a increased

1

1(c) (i)

(ii)

(iii)

Shows on the graph appropriate right triangle ( > 5 x 4)

Gradient , m = 35 10

9 1

= 3.125 N m-1s2

Marked on the graph

a = 5.5 ms-2

6.0 ms-2

Fincreases linearly with a

1

1

1

1

1

1

(d) Mass 1

(e) 1. Make sure elastic strings are stretched at constant length.

2. The position of the eye perpendicular to the scale of the metre rulewhen measuring the ticker tape to avoid errors due to

parallax/systematic error

1

TOTAL 12


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3 (a) The depth of the boat in water is affected by the weight/mass of the loadKedalaman bahagian bot di dalam air dipengaruhi oleh berat/jisim beban

1

(b) When the weight (of load) increases, the volume of liquid/water displacedincreases.

orWhen the number of slotted masses increases, the volume of liquid/ waterdisplaced increases

Apabila berat muatan bertambah, isipadu cecair/air yang tersesar

bertambah.

atau

Apabila bilangan pemberat berslot bertambah, isipadu ceacir/air yangtersesar bertambah.

1

(c)(i) To study the relationship between weight/number of slotted masses and thevolume of liquid/water displaced.

Untuk mengkaji perhubungan antara berat/bilangan pemberat berslot dan

isipadu cecair/air yang tersesar.

1

(ii)

(iii)

(iv)

Manipulated variable : weight, W / number of slotted masses

pembolehubah manipulasi : berat, W / bilangan pemberat berslot

Responding variable: volume of liquid/water displaced, V

Pembolehubah bergerak balas isipadu cecair/air yang tersesar, V

Fixed variable: density of liquid,

Pembolehubah dimalarkan ketumpatan cecair,

List of apparatus/material:

slotted masses, wooden block, water, beaker, measuring cylinder/rulerpemberat berslot, bongkah kayu, bikar, silinder penyukat/ pembaris

Arrangement of apparatusSusunan radas

1

1

1

(v)- Set-up the apparatus as shown

- A slotted mass of 20g is placed on a wooden block- The volume of liquid/water displaced is measured and recorded.

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Volume of li uid/water dis laced, V

(vi)

(vii)

- Experiment is repeated by placing 2, 3, 4 and 5 slotted masses on thewooden block and the corresponding volume is recorded.

Weight, W /mass,m/number of slotted masses

Volume of liquid//water displaced, V

1

1

1

TOTAL 12

Weight, W / number of slotted masses


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END OF MARKING SCHEME

4 (a) Inference : The Crane (b) had attracted more load of scrapped irons than the cranebecause of its larger no. of coils/turns of the solenoid // the strength of the magnetic fielddepends on the no. of turns/coils of the solenoid.

1

(b) Hypothesis : Bigger number of turns in the solenoid , the stronger will be itselectromagnetic field strength 1

(c) Aim : To investigate the relationship between the number of turns and theelectromagnetic field strength 1

Variables : Manipulated : number of turns in the solenoidResponding :electromagnetic field strength / no. of pins attracted 1

Constant Variable : Current ; soft iron core . 1List of apparatus : Solenoid, PVC tube / large iron nail , iron nails/ pins/paper clips,

ammeter, rheostat and power supply.1

Arrangement of apparatus:

1

Control of Manipulated Variable : Wind the insulated wire around the large iron nail/PVC tube, starting with 50 coils . 1

Measurement of Responding Vble : Lower the solenoild until it touches the iron nails. Record the number of iron nails attracted by it. 1Repeat the experiment & procedure 4 more times with no. of coils at 100 , 150 , 200 and 250. 1

Tabulation of data

No. of turns No of nails attracted50

100

150200

250

1

Analysis of data.Sketch the graph of no. of coils against no. of nails attracted 1

TOTAL 12

skema trial sbp physics 2007

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