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BAHAGIAN PENGURUSAN SEKOLAH BERASRAMA PENUH SEKOLAH KECEMERLANGAN KEMENTERIAN PELAJARAN MALAYSIA MARKING SCHEME PERFECT SCORE & X A-PLUS MODULE PHYSICS 2012

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1. BAHAGIAN PENGURUSAN SEKOLAH BERASRAMA PENUH SEKOLAH KECEMERLANGAN KEMENTERIAN PELAJARAN MALAYSIA MARKING SCHEME PERFECT SCORE & X A-PLUS MODULE PHYSICS 2012 2. SECTION II - COMMON MISTAKES AND MISCONCEPTIONS 8. Physical Quantity Physical quantity measured Physics Unit and symbol Stop watch time Second. s voltmeter Voltage, V Volt, V thermometer temperature Kelvin or oCelsius Bourdon gauge Gas pressure Pascal, Pa Ammeter Electric current Ampere, A 9. Terms Common Mistake Correct Answer a [The type of energy when the object is at P] Potential energy Gravitational Potential Energy b Pressure Force acting on surface area Force/area A product of depth, density and gravitational acceleration Normal force acting on a unit of surface area c Pascals principle In a close container, force is transmitted equally In a close container, pressure is transmitted equally. d Latent heat of vaporization Heat absorbed to change by 1oC Heat absorbed to change 1 kg of liquid to gas without any changes in temperature. e Temperature Transfer from hot body to cold body Amount of kinetic energy in an object f [Physics phenomena in a prism] Reflection Total internal reflection 3. Terms Common Mistake Correct Answer g Critical angle Critical angle is when the refracted angle is 90o Critical angle is the incident angle when the reflected angle is 90o Critical angle is the incident angle in denser medium which produces when the refracted angle in less dense medium is 90o h Virtual image The image that formed behind the lens The image that cannot be formed on the screen i Monochromatic light A colour of one light light of one frequency / wavelength / colour j Amplitude Maximum point of the highest displacement .. displacement of any particle/oscillating system from its .. .. k Period One complete oscillation The time taken for any particle to make one complete oscillation l Specification: 240 V, 1000 W 1000 W of energy is supplied when the power supplied is 240 V. 1000 W of energy is consumed in 1 s when connected to a 240 V power supply. j electromagnet When the current flow through magnet Is a combination of electric and magnetic field A conductor which can produce magnetic field when current passes through it. k Beta particles Negative charge Fast moving electron 4. B. Misconceptians Examples: Num Misconceptions Correction 1 Oil is used in hydraulic jack because it has higher boiling point .. because it is not easily evaporate. 2 Snells law state that: The sine of incident angle = Refractive indexThe sine of refracted angle The sine of incident angle = constant The sine of refracted angle 3 Container A Container B The force exerted at X > the force exerted at Y because smaller surface area (P = F /A) Pressure at X = Pressure at Y because X and Y are at the same depth, same gravitational acceleration and in the same type of liquid that has same density. ( P = hg) To increase the efficiency of ac/dc GENERATOR: - Use more number of turns to produce stronger magnetic field Generator the current is induced The ship can float in sea water because the buoyant force is bigger than the weight of the ship The ship can float in sea water because the total density of the ship is less than the density of water The buoyant force is equals to the total weight of the ship water 5. C. Paper 3 1. Data Tabulation Title - no unit Content- not consistent Example: Common Mistake Correct Answer Electric Current Voltage 0.1 0.5 0.12 1 0.14 1.5 Electric Current, I (A) Voltage, V (V) 0.10 0.5 0.12 1.0 0.14 1.5 TOV 1 SPM FORMAT SET 1 4531/2 SECTION A Question 5 No Answer Scheme Mark a The force that gravitation exerts upon a body 1 b(i) The mass of slotted weigh in Diagram 5.1 > Diagram 5.2 1 b(ii) The nett force in Diagram 5.2 > Diagram 5.1 1 b(iii) The acceleration in Diagram 5.2 > Diagram 5.1 1 c The greater the nett force , the greater the acceleration 1 d(i) Net force in Diagram 5.1 > Diagram 5.3 1 d(ii) The acceleration in Diagram 5.1 > Diagram 5.3 1 d(iii) The weight of 20 N in Diagram 5.1 is perpendicular to the tension of the string 1 Question 6 No Answer Scheme Mark a(i) Diagram 6.1 : no relative motion Diagram 6.2 : there is a relative motion 2 a(ii) Number of turns in Diagram 6.3 > Diagram 6.2 1 b(i) The greater the number of turn of coil, the greater the change in magnetic flux 1 b(ii) The greater the number of turn of coil, the greater the magnitude of induced current 1 c Faradays Law 1 d When the magnet is pulled away from the coil Reason : the current will flow in such direction that oppose the change that cause it 2 6. Question 7 No Answer Scheme Mark a Depth of water 1 b P = hg5 = 2.5 x 103 x 10 = 2.5 x 104 N m-2 2 c Less different of water pressure 1 d(i) Place the water tank P higher than water tank R // use water pump It will increase the water pressure // sufficient water supply 2 d(ii) Bigger base area //thicker wall at the bottom Less pressure exerted on the ground // could withstand water pressure 2 d(iii) Low density material // fiber tank Light // can withstand stronger pressure 2 Question 8 No Answer Scheme Mark 1. (a) (b) (c)(i) (ii) (iii) (iv) (d) Atmospheric pressure is the weight of the atmosphere on an object 1. Vacuum pump is used to pump out the air from the suction cup 2. Partial vacuum is created in the suction cup 3. Higher atmospheric pressure push the glass sheet onto the suction cup Low pressure Larger difference in pressure Big diameter cup Greater force Triple cups Greater force R Straw/syringe/siphon/vacuum cleaner 1 3 1 1 1 1 1 1 1 1 12 Question 9 No Answer Scheme Mark a The force exerted by the gas molecules onto a unit of surface area 1 7. No Answer Scheme Mark b When temperature increases, the average kinetic energy increases Rate of collision also increase Rate of change of momentum increase Force exerted on a unit of surface area increase 4 c Temperature of gas : 9.3 > 9.2 Volume of gas : 9.3 = 9.2 Reading of pressure gauge : 9.2 < 9.3 Temperature increase, reading of pressure gauge Pressure Law 5 d Characteristics Explaination Large radius Rate of rotation is less // Temperature does not increase easily Many tyres Increase the surface area // less pressure Tyres with treads Provide a gripping surface Strong tyre Prevent from deformation High melting point Can withstand high temperature 10 Question 10 No Answer Scheme Mark a Electromagnetic induction 1 b 4 c Number of turns of coil : Diagram 10.3 > Diagram 10.4 Speed of magnet : same Deflection of galvanometer : Diagram 10.3 > 10.4 When number of turns of coil increased, deflection also increased Faradays Law 5 d Characteristics Explaination Curve magnet Produce radial magnetic field Stronger magnet Produce stronger magnetic field Replace component X with commutator Current is induced in one direction Copper wire coil Good conductor Thick copper wire Less resistance 10 8. Question 11 (a) Distance between optical centre and focal point (b)(i) M1 correct substitution into formula or correct answer M = v/u = 60/20 = 3 (b)(ii) M1 correct substitution into formula: M2 Answer with correct unit f = 15 cm = 0.15 m (b)(iii) M1: P = 100/f = 100/15 M2: Answer with correct unit: = 6.67 D (c) M1: Parallel light rays from the hot sun at infinity pass through a convex lens// labeled diagram M2: Light rays are focused after passing through the lens // labeled diagram M3: Light rays are converged onto a focal point of the lens M4: At the point, the intensity of lights is great (and the light energy) causes an increases in temperature. When the spot on the paper become hot enough, the paper start to burn // light energy change to heat energy. Aspect Reason Low power of eye piece Focal length is longer // eyepiece must be more longer focal length than objective lens High power objective lens Focal length is shorter / objective lens must be powerful lens than eyepiece lens// Objective lens must be shorter focal length than eyepiece lens. Distance between lenses : >fo + fe To produce bigger image from the eyepiece // to increase the magnification Position of the specimen : fo< u < 2fo To produce real, inverted and magnified image The most suitable is : microscope M Focal length of eyepiece is longer than objective lens, distance between lenses is greater than (fo + fe), and the position of the specimen is between fo and 2 fo 9. Question 12 Answer: (a) frequency (b) 1 High pitch, high frequency / pitch directly propotional to frequency 2 frequency is inversly propotional to wave length // high frequency has shorter wave length 3 Short / high f / high pith at C, will diffract / spread out/ bend less 4 Sound easily diffracted / bending / spread out during low pitch/ low f/long / at A,B,C (c) Characteristic Reason Large diameter Receive more signal Same as focal length Signal are focused/converged to the receiver Microwave Has high frequency / high energy High The signal is not blocked / easy to be detected Choose K because Because it has large diameter, Same as focal length, use microwave and locate at high position. (d)(i) v = 2s/t = (2 x 90)/0.12 = 1 500 m/s (i) V = f = 1 500/50 000 = 0.03 m = 3 cm TOV 2 SPM FORMAT SET 2 4531/2 SECTION A QUESTION 5 No Answer Scheme Mark a The size of the coin in Diagram 6.1 < Diagram 6.2 1 b Refraction of light wave 2 c Light travels from water to air // denser to less dense medium Light is refracted away from normal line The image is seen bigger and closer to the observer eye 3 d n = rd/ad = H/h h = 16/(4/3) = 12 cm 2 e Use liquid with bigger refractive index 1 10. QUESTION 6 No Answer Scheme Mark a(i) Kinetic energy to electric energy 1 a(ii) Rotating coil will cut the magnetic flux Emf is produced The commutatorwii ensure the current flow in one direction 3 b(i) The ratio Np : Ns is 6 : 1 1 b(ii) diode 1 b(iii) Capacitor Reason : it can store and discharge charges 2 c Copper wire // laminated iron core Reason : good conductor // reduce eddy current 2 QUESTION 7 No Answer Scheme Mark a Temperature increases Pressure increases 2 b When temperature increases, the average kinetic energy increases Rate of collision also increase Rate of change of momentum increase Force exerted on a unit of surface area increase 3 c) P1 = 200 kPa T1 = 273 + 30 = 303 K P2 = 225 kPa T2 = (T1P2)/ P1 = (303 x225) /200 = 340.875 K 3 d(i) More 1 d(ii) Able to support greater mass // heavier load 1 d(iii) Grips efficiently 1 11. QUESTION 8 No Answer Scheme Mark (a) (b) (c)(i) (ii) (iii) (iv) Concave mirror 1. Object between F and pole of mirror 2. Light parallel to principal axis reflected to F 3. Light through C reflect back original path 4. Extend the lines to back of mirror and draw a virtual image Concave To focus light Big size To collect and reflect more light At focal point of the mirror Light/energy will focus after light reflected Z 1 4 1 1 1 1 1 1 1 12 QUESTION 9 No Answer Scheme Mark a(i) Real image is an image which can be formed / projected on a screen. 1 a(ii) object distance in 9.1 is shorter than 9.2 Size of image formed in 9.1 is bigger than in 9.2 Image distance in 9.1 is smaller /shorter The shorter the object distance, the bigger the size of the image formed When the object distance is shorter, the magnification scale is bigger. 5 b 4 P 12. No Answer Scheme Mark 1. Object is placed between F and P 2. Parallel light ray from top of object to mirror and reflected to F 3. Light ray from top to mirror and reflected back to C 4. Extrapolation of both rays and its intersection behind the mirror and an upright image is drawn. d suggestion Explanation Use higher power bulb Higher intensity of light / more light produced. The filament of the bulb is at the focus point of the concave mirror The light ray focuses to one point. More curvature Increase the intensity. lens between f and 2f To produce real and enlarge / bigger images. Increase the distance / further away the screen Larger image produced 10 QUESTION 10 No Answer Scheme Mark 10 (a) Monochromatic light: light of one frequency / wavelength / colour 1 (b) In figure 10.1(a), distance between the double slit and screen, D is smaller 1 In figure 10.1(b), distance between two successive bright fringes, x is smaller 1 In figure 10.1(b), the number of fringes is bigger / more fringes 1 In figure 10.1(b), the width of fringes is smaller / narrower 1 When the distance between the double slit and screen, D increases, the distance between two successive fringes, x increases. 1 5 (c) Microwaves are transmitted by the radar 1 the radar transmits the signal towards the aeroplane 1 it detects the reflected signal from the aeroplane t seconds later. 1 calculate the distance of aeroplane from the radar,s by using formula s = vt/2, where v is the speed of microwaves in air. 1 4 13. No Answer Scheme Answer Scheme Modification Explanation Shape of the boat is streamline To reduce the water resistance / drag Material used is strong Can withstands high water pressure Uses ultrasonic waves Have high energy / sounds can travel at further distance Put fish in a polisterine box containing ice Ice has larger latent heat / ice can absorb a large quantity of heat from fish as it melts / fish can be kept at a low temperature for an extended period of time Made of fiber glass / less dense material The boat is lighter 10 TOTAL 20 QUESTION 11 No Answer Scheme Mark 11(a) Volume = area x height 1 (b) 1st : pressure of air is inversely proportional to the volume of air 2nd : the pressure inside the air bubbles is equal to the water pressure which is high at the bottom 3rd : so the volume of air bubbles is small. 4th : as air bubble goes up to the surface, the pressure decreases., so the volume of air bubbles increases. 4 (c) 1st : safety valve is needed 2nd : to releases extra steam so that the pressure is the cooker does not reach a dangerous stage 3rd : Thickness of the pot is high 4th : to withstand high pressure 5th : specific heat capacity of the pot is low 10 14. No Answer Scheme Mark 6th : heats up quickly and food will be cooked faster 7th : specific heat capacity of the handle is high 8th : heats up slowly and can be held with bare hands 9th : K is chosen 10th : Reasons: It has a safety valve, high thickness, low specific heat capacity of the pot, high specific heat capacity of the handle (d) 1st : P1= 75 cm Hg, V1 = 10 cm 2nd : P2 = 75 + 3 = 78 cm Hg 3rd : P1V1 = P2V2 4th : (75)(10) = (78) (V) 5th : V2 = 9.62 cm 5 TOTAL 20 15. QUESTION 12 16. Exercise No Answer Scheme Mark a The force that gravitation exerts upon a body 1 b Stone is denser than water When the stone is immersed in the water , it experienced buoyant force, F The tension which is the reading of spring balance, T = W-F Archimedes Principle 4 c i. 4.4.kg ii. (44-36) = 8 N iii. F = Vg V = F/(g) = 8/(103 x 10) = 8x10-4 m3 5 d Characteristics Explaination Denser material So the hydrometer stand up right Large diameter of bulb Displaced more acid// stay floating Long hydrometer To measure wide range of density of acid Glass hydrometer Does not react with acid The best choice is U because it is denser material, large diameter of bulb, long hydrometer and glass hydrometer 10 SECTION III UNDERSTANDING (Paper 2 Section B and C) Question 1 [ Introduction to Physics ] 1. Consistency is the ability of the instrument to give the same readings close to each other when repeated measurement are done 2. each measurement with little deviation among readings/ draw diagram bulls eye target. 3. Accuracy is the ability of an instrument to give a measured reading to the actual reading. 4. The value determined is accurate if it is near to the actual value/ draw diagram bulls eye target. Question 2 [Forces and Motion] 1. Fuel burns in the combustion chamber 2. Hot gases expelled at high speed / high momentum 3. A large downwards momentum is produced 4. The rocket gains upwards momentum of equal magnitude. Question 3 [Forces and Motion (i) Elasticity is the property of matter to return back to its original size or shape when the force that acting on it is removed (ii)1. There are two types of force; attraction and repulsive force between the particles of the solid. 17. 2. When the solid is stretched, the molecules displaced away from each other 3. Attractive forces are acting to oppose the stretching 4. When the solid is compressed, the molecules displaced closer to each other 5. Repulsive forces are acting to oppose the compression Question 4 [Forces and Motion] (ii) The force forward = friction The resultant force is zero The object move with constant velocity Question 5 [Forces and Pressure] 1. High altitude has low density of air 2. Air molecules has low temperature / low kinetic energy 3. Less collision of air molecules with surface 4. Rate of change of momentum decreases. Question 6 [Forces and Pressure] 1. When air is pumped out , pressure inside decrease. 2. Atmospheric pressure outside is higher 3. Difference in pressure produces a forceto lift the mirror 4. Force is greater than the weight of the mirror. Question 7 [Forces and Pressure] (a) (i) Archimedes Principle states that buoyant force equal to the weight of fluid displaced. (a) (ii) 1. Volume of air displaced equal to volume of aballoon 2. Density of air decreased as a altitude increase 3. Weight of displaced air becomes smaller 4. At certain height weight of displaced air equal to weight of the balloon. Question 8 [Forces and Pressure] 1. Hydrometer displaces water. 2. Weight of water displaced equal to weight of hydrometer. 3. The denser the liquid is, the less volume of water displaced. 4. Hydrometer will float higher. Question 9 [Heat] (i) Thermal equilibrium occurs when the net transfer of heat between two objects in thermal contact is zero. (ii) 1. Thermometer is placed in the boiling water. 18. 2. Heat is transferred from boiling water to the thermometer 3. Thermal equilibrium between the thermometer and boiling is reached when the net rate of heat transfer is zero. 4. The thermometer and the boiling water are at the same temperature. Question 10 [Heat] 1. Molecules moving freely in random motion 2. When temperature increase, kinetic energy//velocity increase 3. Molecules strike the walls of pressure cooker more frequently The rate of change of momentum increase 4. Force exerted on the walls increase, pressure (P = F/A) increase Question 11 [Heat] 1. The specific heat capacity of the land is less than sea water. 2. During daytime, the land warms up faster than the sea. 3. Air above the land becomes hot and less dense, so it will rise up. 4. The cooler air from sea moves to the land. Question 12 [Light] 1. The air close to the surface is much colder than the air above it 2. Light travels from denser to less dense medium 3. Light rays refracted away from normal line and bend downward toward the surface/total internal reflection occur. 4. The observer will see the image of the ship due to light travels in a straight line. Question 13 [Light] 1. The parallel rays of the sun will pass through the a convex lens 2. After entering the lens, the light rays is focused at the principal focus of the lens 3. At the principal focus, the light ray is focused on one small area 4. Heat energy causes an increase in temperature, the paper starts to burn Question 14 [Waves] (i) Sonar is a reflected ultrasonic waves. (ultrasonic echoes) (ii) ultrasonic wave has a higher frequency waves , it has more energy so it can move further it do not produce noise (iii) 1. attach ultrasonic transmitter to a ship 2. use a microphone receiver to detect ultrasonic pulses 3. direct the ultrasonic pulses from the transmitter to the seabed 4. use microphone receiver to pick up the reflected pulses from the seabed 5. measure the time taken by the pulses to travel to the seabed and return 6. calculate the depth of the water using the formula 2 txv d Question 15 [Waves] 1. The airplane engine produces noise which cause the air to vibrate 2. All particles in a material/matter/glass vibrate at its natural frequency 3. Due to resonance, the glass vibrate at a higher/maximum amplitude 4. Need strong glasses to withstand the effect of resonance/ the strong vibration/ high amplitude, so that it does not break easily. Question 16 [Electricity] 1. A parallel circuit can run several devices using the full voltage of the supply. 2. If one device fails, the others will continue running normally 3. If the device shorts, the other devices will receive no voltage, preventing overload damage. 4. A failure of one component does not lead to the failure of the other components. 19. 5. More components may be added in parallel without the need for more voltage. Question 17 [Electricity] 1. The two dry cells are connected in parallel 2. The effective e.m.f. remains the same 3. The effective internal resistance of the two cells is smaller 4. A larger current will flow through the bulb to make it brighter Question 18 [Electromagnetism] 1. When the switch is on, the soft iron core becomes electromagnet. End A becomes north pole. 2. End B becomes south pole 3. Magnet P repels from end A 4. Magnet Q attracts to end B Question 19 [Electromagnetism] 1. The (magnadur) magnets produce a magnetic field / diagram 2. The current in the wire produces a magnetic field / diagram 3. The two magnetic fields interact/combine to form a resultant / catapult field / diagram 4. Same direction of magnetic field produces stronger resultant magnetic field. Opposite direction cancel each other and produce weaker magnetic field. Question 20 [Electromagnetism] 1. When too high current flow, magnetic field strength become very strong / wire expand 2. electromagnet pull the soft iron armature / pulled to the right by spring P. 3. release the catch, contact separate and current does not flow 4. When reset button is pressed, spring Q pulls the soft iron armature back to its original position Question 21 [Electromagnetism] (i) Ideal transformer is when the efficiency is 100% / power output equal to power input (ii) 1. When a.c. voltage is supplied to primary coil, (alternating current will flow) and the soft iron core is magnetized. 2. The magnet produced varies in magnitude and direction. 3. This causes a changing magnetic flux pass through the secondary coil. 4. An induced e.m.f. across the secondary coil is produced Question 22 [Electromagnetism] 1. Electric supply is continuous 2. Electric supply idepends on region, the region like city needs more electric supply than interior region. 3. Peak hour need more electric supply. 4. If one region black out, the source of electric supply can be taken from another region. 5. Reduce the cost. 6. Easy to manage and to repair * Choose any FOUR from the list. S N 20. Question 23 [Electronic] 1. Connect the dry cell terminal to the Y-input of CRO. 2. The Y-gain setting is recorded 3. The vertical displacement is measured = h. 4. Potential difference = ( Y-gain scale) x (Vertical displacement of direct current wave) Question 24 [Radioactivity] 1. Put the radioactive source opposite the detector 2. Detector is connected to the thickness indicator 3. Detector detect the reading of the changes in counts 4. Thickness is measured with the thickness indicator. If the reading of the detector is less than the specified value, the thickness of the paper is too tick/ vice versa Question 25 [Radioactivity] (a) Unstable isotopes which decay and emit radioactive particles / ray (b)1. Radioisotope is injected into the pipe 2. G-M tube as detector is used to find the leakage 3. Reading on detector increases when near a leakage Question 26 [Radioactivity] 1. Neutron bombarded a uranium nucleus and produced three neutral 2 The new neutron bombarded a new uranium nucleus 3. For every reaction, the neutrons produced will generate a chain reaction 4. Diagram of chain reaction 21. SULIT 21 SECTION IV DECISION MAKING (Paper 2 Section A Question 8; Section C ) Question 1 Characteristics Explanation Streamlined shape To reduce water resistance High strength of metal To withstand high water pressure Wide base cross section area So that ship can float / prevent from overturn // ship more stable // ship not sink deeper High volume of air space in the ship Increase buoyant force Structure U Because it has streamlined ship, high strength of metal, wide base cross section area, high volume of air space in the ship. Question 2 [Force and Pressure] Specification Reason Straight cut shape bottle Move faster/increase the speed The body is streamline shape Reduce air friction The angle of launching is 450 The rocket can achieve maximum distance The volume of water 1/3 of the bottle To produce optimum momentum/speed The rocket has functional fins Increase stability The best water rocket is T, because it has straight cut shape, body is streamline, angle of launching is 450 the volume of water is 1/3 of the bottle and the rocket has functional fins. Question3 [Force and Pressure] Specification Reason With ABS To reduce jerking when it stopped immediately / can be controlled if direction changes / does not move side ways Wide tyres Better support / more stable / safer when turn Low mass Lighter, can move faster / low inertia Low seat height Lower centre of gravity / more stable C because it has ABS, wider tyres, low mass, low seat height. Question 4 Specification Reason High specific heat capacity The rate of temperature increased caused by friction is low High melting point Does not easily change in shape when the temperature is high Difficult to compress Pressure will be transmitted uniformly in all directions. Use ceramic Can withstand high temperature // less dust produced S because it has high specific heat capacity, high melting point, difficult to compress and use ceramic. Question 5 Specification Reason Size of the tyre is large Prevent backhoe from sinking into soft ground Fluids used in hydraulic system is liquid Not easy compress compared to the gases // high power Large mass Avoid backhoe from moving Large base area Ensure that the backhoe will not collide 22. SULIT 22 Centre of gravity is low More stable The most suitable backhoe is M. Large tyre, fluids use in hydraulic system is liquid, large mass, large base area and the centre of gravity is low. Question 6 [Force and Pressure] Specification Reason A shape of cross section which is upper side is higher Than the bottom//aerofoil To produce the speed of airflow above the wings to be higher than the speed of air below Large area of the wing The larger the lift force Low density of the wing material Less weight// produce more upward force The higher the difference in speed of air The higher the difference in pressure P was chosen because shape of aerofoil,large area of the wing, Low density of the wing and the higher the difference in speed of air Question 7[Force and Pressure] Specification Reason Volume of the balloon is bigger Produced bigger buoyant force / displaced more volume of air Material used for balloon is nylon Stronger / does not break easily Material used for basket is rattan Lighter / low mass / increase the time impact / reduce impulsive force Temperature of air inside the balloon is higher Reduce the density of air / reduce the mass of air in the balloon / increase upward resultant force / can carry more load The best chosen is K because volume of the balloon is bigger, material used for balloon is nylon, material used for basket is rattan and temperature of air inside the balloon is higher Question 8[Heat] Specification Reason High boiling point It will not easily change into gas when absorb heat from the engine Low viscously It will not freeze during cold weather // can flow at low temperature High specific heat capacity It can absorb a big quality of heat with small rise in temperature A low ability to react with metals The metal parts of the engine will not corrode easily K because of its high boiling point, low viscosity, high specific heat capacity and low ability to react with metals. Question 9 [light] Specification Reason Type of objective lens is convex lens To converge the light and produce real image Focal length of the objective lens is big To get higher magnification power D < f0 + fe To get virtual and magnified image Diameter of the objective lens is large More light can be captured, the image formed is brighter Lens S because lens used is convex lens, focal length of the objective lens is big, D D < f0 + fe and diameter of the objective lens is large. 23. SULIT 23 Question10 [Electricity] Specification Reason Thin diameter High resistance Coil wire Increase length / resistance Parallel arrangement If one panel not function, others still function High melting point Withstand high temperature G, because thin diameter, coil wire, parallel arrangement and high melting point. Question 11 Characteristics Explanation Curved shape Produce radial magnetic field Soft iron Easily to magnetized and demagnetized Soft spring Can detect small current // more sensitive // can measured small current Linear scale Uniform deflection // force produced directly proportional to current. T is chosen because curved shape, soft iron, soft spring and linear scale. Question 12 Specification Reason Low resistivity to reduce heat loss in the cables Low density The cables will be lighter Low rate of oxidation Not easily rust / corrode Low rate of thermal expansion The cables will not expand under hot weather Cable Q because it has low resistivity, low density, low rate of oxidation, low rate of thermal expansion. Question 13 Specification Reason Low density of the coil Lighter // less mass High frequency of rotation The rate of change of magnetic field, more current induced Use 4 diodes Full wave rectification to get a d.c Heat capacitor in the circuit To smooth the direct current obtained Circuit I because it has low density coil, high frequency of rotation, consist 4 diodes and has capacitor in the circuit 24. SULIT 24 Question 14 Specification Reason The valency of the intrinsic semiconductor is 4 When it is doped, the conductivity of the semiconductor increases The valency of the doping substance are 3 or 5 Valency of 3 is used to produce hole as majority charge carrier (P type) and valency of 5 is used to produce electron as majority charge carrier (N type) Size of the atom of the doping substance is almost same as the size of the substance Can maintain the crystallize structure of the substance / give good effect in the doping process Substance T because the valency of the intrinsic semiconductor is 4, the valency of the doping substance are 3 or 5 and the size of the doping substance is almost the same as the size of the substance. The type of pure semiconductor is silicon because it has greater power handling (not easy overheated. Question 15 [radioactive] Specification Reason Gamma Has high penetrating power Long half life Long lasting Solid Easy to handle Low ionizing power Does not ionize healthy cells / does not cause cell mutation K is chosen because it radiated gamma ray, the half life is long, the state of matter is solid and has low ionizing power. uestion 16 [Radioactive] Specification Reason Type of ray is Alpha Stronger ionizing power Long half life Long lasting State of matter is solid Easy to handle / does not spill or evaporate Logic gate: NOT To inverse input L is chosen because type or ray is alpha, long half life, solid and use logic gate NOT 25. SULIT 25 SECTION V CONCEPTUALIZATION (Paper 2 Section A Question 5/6; Section B ) Question 1 [Force and Pressure] 1. Density of sphere A is less than B 2. Weight A is less than B 3. The weight of water displaced by A is less than B 4. The larger the weight of sphere, the bigger the weight of water displaced 5. Weight of water displaced = upthrust // When the weight of water displaced increase, upthrust increase Question 2 [Force and Pressure] (a) Density is mass per unit volume (b) i Level of the boat is higher in the sea than in the river. ii Water displaced in the sea is less than in the river. iii Density of sea water is higher than river water. (c) i The lower the density of water, the greater the volume of water displaced. ii Weight of the boat = Weight of the water displaced (d) Archimedes principle Question 3 [Heat] (a)(i) The temperature of air increase The volume of air increase (ii) The mass of air constant (b)(i) When the temperature increase the volume of air increase (ii) Charles Law (iii) Temperature increases, kinetic energy increases The rate of collision between molecules and wall increases/ pressure increases To keep the pressure constant, volume increases/expand Question 4 [Waves] (a) Length between the two crest / trough / consecutive wave front (b) (i) Wavelength in Diagram 4.2 is greater than 4.1 (ii) Wavelength remains constant after passing through the gap (c) Curvature of the wave pattern in Diagram 4.2 is greater (d) The greater the wavelength, the more circular the wave pattern (e) Diffraction 26. SULIT 26 Question 5 [Electromagnetism] (a) Diagram 5.1 has less number of turns compare to Diagram 5.2 Deflection of pointer in Diagram 5.1 is smaller than Diagram 5.2 (b) P = North Q = South (c) The larger the number of turns, the higher the induced current produced (d) Faradays Law (e) Increase the speed of the relative motion between the coil and the magnet // Use a stronger magnet (f) Direct Current Generator (D.C. Dynamo) //Alternating Current Generator (A.C. Dynamo) // Moving coil microphone // Transformer Question 6 [Force and Motion] (a) The energy an object has because of its position. (b) Load in Diagram 6.1 is higher than in Diagram 6.2. Gravitational potential energy in Diagram 6.1 is higher Work done in Diagram 6.1 is greater The higher the position of the load, the greater the work done The greater the work done, the greater the gravitational potential energy // Work done = gravitational potential energy Question 7 [Force and Motion] 1. Mass of the coin is greater than the leaf 2. Both objects reach the ground at the same time 3. The falling position of both objects is the same 4. Gravitational acceleration is the same 5. Gravitational acceleration does not depend on mass Question 8 [Force and Pressure] 1. Reading of spring balance in the oil/Diagram 8(c) is greater than in the water/Diagram 8(b) 2. Weight lost in the water/Diagram 8(b)is greater than in oil/Diagram 8(c) // vise versa 3. Density of water is greater than density of oil 4. The greater the density of liquid, the greater the weight lost 5. The greater the density of liquid, the greater the buoyant force 27. SULIT 27 Question 9 [Force and Pressure] 1. Density of air in Diagram 9(a) is higher than in Diagram 9(b)// vice versa 2. The number of load in Diagram 9(a) is greater than in Diagram 9(b)// vice versa 3. The height of the balloons in both Diagram 9(a) and Diagram 9(b) are equal 4. When the density of the air increase, the buoyant force increase 5. As the density of the air increase, the weight of the load carried increased// . As the density of the air decrease, the weight of the load carried also decreased Question 10 [Force and Pressure] 1. The mass of the fish is the same 2. The volume of the fishing net immersed in the water is the least in Diagram 10.3 and the largest in Diagram 10.1 3. When the weight of water displaced is smaller, the force needed is greater 4. Buoyant force is equal to weight of water displaced 5. The greater the weight of water displaced, the greater the buoyant force Question 11 [Light] 1. Density of glass block in Diagram 11(a) is smaller than density of glass block in Diagram 11(b) 2. Refractive index of glass block in Diagram 11(a) is smaller 3. Angle of refraction in Diagram 11(a) is greater than angle of refraction in Diagram 11(b) 4. The higher the density, the smaller the angle of refraction 5. The higher the refractive index, the smaller the angle of refraction. Question 12 [Light] 1. Lens K is thicker than lens J 2. Light ray refracted more in lens K than lens J. 3. Focal length of lens K is shorter than lens J. 4. The thicker the lens, the greater the light refracted 5. The thicker the lens, the shorter the focal length 28. SULIT 28 Question 13 [Light] 1. Distance between the double-slit and screen, D, i n Diagram 13.1(a) is smaller 2. Distance between two successive bright fringes, x, in Diagram 13.1(b), is smaller 3. The number of fringes in Diagram 13.1(b) is bigger 4. The width of fringes in Diagram 13.1(b) is smaller 5. When the distance between the double-slit and screen, D, increases, the distance between two successive fringes, x, increases Question 14 [Waves] 1 . Number of oscillations in Diagram 14(a) is greater than in Diagram 14(b) 2. The amplitude of the wave in Diagram 14(a) is the same as in Diagram 14(b) 3 . The diameter of guitar string in Diagram 14(a) is smaller than diameter of the string in Diagram 14(b) 4. When the diameter of the string increases , the frequency of the wave decreases 5 . The higher the frequency , the higher is the pitch// As the frequency of the sound decreases, the pitch of the sound also decreases Question 15 [Electricity] 1. Diagram 15.1 connected in series and Diagram 15.2 connected in parallel 2. The reading of ammeter in Diagram 15.2 is greater than in Diagram 15.1 3. The reading of voltmeter is the same 4. The effective resistance in Diagram 15.2 is smaller than in Diagram 15.1 5. When the effective resistance increases, the current flow decreases. 6. When the circuit is in parallel connection, the effective resistance is smaller Question 16 [Electromagnetism] 1. The N-pole in Diagram 16(a) moved into the solenoid, the N-pole of the magnet in Diagram 16 (b) moved away from the solenoid. 2. The galvanometer pointer in Diagram 16(a) deflects to the right, the galvanometer pointer in Diagram 16(b) deflects to the left. 3. When N-pole is moved into the coil, the top of the coil is a N-pole, and tends to repel the magnet 4. When the N-pole is moved away from the coil, the top of the coil is a S-pole, and thus attracting the receding N-pole. 5. Lenzs Law which states that the direction of the induced electromotive force acts in such a way as to oppose the action which produces it 29. SULIT 29 Question 17 [Electronic] 1 The bulb in Diagram 17.2 does not light up while the bulb in Diagram 17.1 lights up 2. In diagram 17.2 the negative terminal of the cell is connected to the anode. 3. When the anode of the diode is connected to the positive terminal of a cell, the bulb lights up 4. When the diode is in forward bias connection, the current flow 5. Diode allows current to flow in one direction only Question 18 [Radioactivity] (ii). Difference: Nuclear fission involves the fission of heavy nucleus. Nuclear fusion involves the combination of light nuclei Similarities: Decrease/loss of mass after the process occurs. Neutrons are produced. E = mc2 // loss of mass/ mass defect directly proportional to the energy released . Question 19 [Radioactivity] 1. Exponential graph 2. The time taken for the activity to become half of its initial value is constant 3. The time taken for the activity of P to be half of its initial value is constant //5 hrs 4. The time taken for the activity of Q to be half of its initial value is constant //100 s 5. Half-life VI PROBLEM SOLVING [QUALITATIVE] (Paper 2 Section A: Question 7; Section B Question 9/10 ) QUESTION 1 Suggestion Reason Thermometer is made from transparent glass that is strong It is not easily broken The capillary tube is made narrow and thin It is more sensitive The shape of the thermometer is round/streamline It has a magnifying effect The liquid has low freezing point It can measure very low temperature/ not freeze at low temperature Thin glass bulbs wall Absorb / transfer heat faster 30. SULIT 30 QUESTION 2 Suggestion Reason Aerodynamic shape / stream line/ torpedo Reduce air resistance Low density material // Strong material// high boiling point Lighter // Does not break easily// does not melt easily Has liquid oxygen Boosting combustion // supply oxygen for combustion Retro rocket /Has several stages that can slip/strip off To decrease mass Increase the size of combustion chamber More space for the fuel to be burnt QUESTION 3 Suggestion Reason Strong material Do not break easily Low density Small mass / lighter //o increase the acceleration Streamline javelin To reduce air resistance The athlete runs with high speed /has to increase his speed/acceleration To increase kinetic energy/energy/force/ momentum Throw at an angle of 45o / Throw with a great force To get maximum horizontal distance of throwing QUESTION 4 Suggestion Explanation Shape of the shuttle conical shape /oval /diagram / aerodynamic Allow for better / fast air flow//produce more lift force // reduce air resistance Material used for shuttle feather / small mass/ low density Light// high velocity/ acceleration //further distance travelled//reduce inertia // smaller mass Material used for base of the shuttle cork/ small mass/ low density Light// high velocity/ acceleration //further distance travelled//reduce inertia // smaller mass Material used for the string of the racquet strong/ low elasticity Not easily broken //withstand high force High tension Short time impact// high impulsive force 31. SULIT 31 QUESTION 5 Suggestion Reason 1 Balloon should be large size To create sufficient buoyant force due to greater weight of surrounding air displaced. 2 Balloon material is made of light weight material like nylon The total weight of the balloon is less than the buoyant force//reduce weight 3 Balloon material should also have a high melting point. It will not disintegrate when exposed to hot air 4 The part of the balloon (the skirt) near the burner must be fire resistant /coated with fire resistant material So that it doesnt catch fire easily 5 The burner burns (liquefied) propane/gas Warms up the air in the balloon 6 A large fan is needed initially To blow enough air into the balloon 7 The basket must be made off light and flexible/safe material (e.g. rattan or cane woven) Prolong the collision time between basket and ground// reduce impulsive force when basket hits the ground 9 Best times to launch the balloon are early morning and late afternoon when the air is cooler Cool air is denser, providing more buoyant forc QUESTION 6 Suggestion Reason Specific heat capacity of the wok is low Heat up faster / temperature increase faster Thermal conductivity of the wok is high Can conduct heat faster Melting point of wok is high Can withstand high temperature Specific heat capacity of the oil is low Heat up faster Boiling point of oil is high Will not change to vapour easily // cooking at higher temperature 32. SULIT 32 QUESTION 7 Suggestion Reason Put ice in the cointainer Ice absorbs heat out from the packet drinks. Add a little water to the ice Heat transfer is faster through the heat conduction. Container has high specific heat capacity Heat up slower. White container Does not absorb heat Insulator // low density Avoid absorb heat from outside into the container // lighter QUESTION 8 Modification Reason Concave mirror Sunlight ray will converge / focus to the tank // absorb more heat Radius of curvature is smaller Reflect more light /focus light at shorter distance// reduce energy lost Black Absorb more heat Low specific heat capacity The temperature rise up faster Bigger size Receive/collect more light QUESTION 9 Suggestion Reason Convex mirror The image formed is virtual, upright an diminished Large diameter Wider field view strong Withstand change in weather / does not break easily Less thickness Avoid multiple image formed / clearer image At the sharp corner Can reflect the light from opposite direction 33. SULIT 33 QUESTION 10 Suggestion Reason Frequency of signal is low Longer wavelength/ diffraction easier The location of transmitter higher no blocking / capture more signal the number of transmitter is more / many increase the strength of signal/ increase energy of signal / reduce energy lost during transmission The strength of signal is higher have more energy / can move further The distance between two transmitter is closer increase the strength of signal/ increase energy of signal QUESTION 11 Suggestion Reason Attach switch for each lamp To allows each lamp to be switched on and off independently Connect the metal fitting lamp to the earth wire/cable To flows electron (extra) to earth to avoid lethal shock Parallel Voltage across both bulbs is 240 V / if one bulb blows another bulb can still function. Using only 240 V light bulb To ensure the bulbs light up with normal brightness Step down transformer / adapter Reduce the voltage from 240 V to 12 V. QUESTION 12 Suggestion Reason Soft spring Give a greater sensitivity/ can detect small changes Small density Small mass / light Curve in shape of the magnet Radial magnetic field, create uniform strength of magnetic field around the coil copper coil To reduce energy loss / Low resistance material of the coil Place the seismometer in direct contact with the earth to convert very small motions of the earth into electrical signals 34. SULIT 34 QUESTION 13 Suggestion Reason OR gate The gate's output is ON if either one sensor is ON Thermistor Resistance decrease when temperature increase At R1 and R2 Base voltage increase, when the temperature increase. Base current flows, collector current flows. Alarm will triggered. Replace the lamp or at the collector circuit It converts the electrical signal into sound energy/ Alarm triggered when collector current flow. Relay switch To switch on the alarm which is use a greater voltage QUESTION 14 Component Function Filament To heat up the cathode Cathode Emits electrons Control Grid Controls the number of electrons// control the brightness of the image on the screen Focusing anode Focuses the electrons into a beam Accelerating anode To accelerate electrons to towards the screen Y-plates To deflect the electron beam vertically X-plates To deflect the electron beam Horizontally QUESTION 15 Suggestion Reason Use forcep/robot The distance between the source and the body is far Wear a mask/goggle The radiation does not penetrate our eyes Use a lead box/container with thick concrete To prevent radiation leakage to surroundings Keep the exposure time as short as possible The body is not exposed to the radiation for a long time Wear a film bandage To detect the amount of radiation exposed Put radiation symbol on the storage box To inform the users of dangerous contents of the box Wear coat lined with lead To protect the body from the radiation 35. SULIT 35 SECTION VII PROBLEM SOLVING [QUANTITATIVE] (Paper 2 Section C Question 11/12 ) 1. (i) impulse = mv mu = 1.5 ( -35-40) = 112.5 kg ms-1 (ii) Impulsive force = mv-mu t = 140.625 N 2. (i) 900 N (ii) F 900 N = 1000 (2) F = 2 900 N 3. (i) v = 18 x1000 = 5 ms-1 60 x 60 a =v u t = 5 0 10 = 0.5 ms-2 (ii) F = ma = ( 202) (0.5) = 101 N 4. (i)Spring constant P , k =F = 6N x 12 cm = 0.5 Ncm-1 Spring constant Q, k = F = 3N x 12 cm = 0.75 N cm-1 5. (i) Buoyant force = weight of the boat V g = 250 (10) V = 0.25 m-3 (ii) Weight of the boat + weight of the load = buoyant force 2500 + WL = 1000 (4) (10) 36. SULIT 36 WL= 40 000 2500 = 3 7500 N Mass of load = 3 750 kg 6. (i) F = 500 x 40 = 20 000 N (ii) Resultant force = 20 000 800 (10) = 12000 N (iii) F = ma a = 12 000 800 =15 ms-2 7. (i) F1 = F2 A1 A2 F2 = 6N ( 1.2) 0.2 = 36 N (ii) V1 = V2 A1h1 = A2h2 h2 = 1.2 (0.2) 1.2 = 0.2 cm 8. (i) F = Vg = 1020 (2)(10) = 20 400 N (ii) Buoyant Force = weight of the boat + weight of the box 20 400 N = 15 000 + W W = 5 400N 9. (i) Mass,m =V = 800 x 0.004 = 3.2 kg (ii) Pt = mc 2 500 (t) = 3.2 (2 000) (130) t = 332.8 s 37. SULIT 37 10. (i) 1/f = 1/u+1/v 1/-15 = 1/20 + 1/v v = - 8.6 cm (ii) Magnification = v/u = 8.6 / 20 = 0.43 (iii) virtual, upright and diminished 11. (i) 1/f = 1/v + 1/u 1/5 = +1/v v = -3.33 cm (ii) m = v/u =3.33/2 = 1.67 times 2 2 12. (i) sin = 0.75 = 48.6o (ii) = 41.8 oC (iii) sin b = 0.9642 b = 74.6o = 15.4o 1 1 1 1 1 13. (i) 4 cm (ii) 5 Hz (iii) 20 cm s-1 2 1 2 38. SULIT 38 14. (i) Np= Vp Ns Vs = 240 12 = 20 Ratio = 20 : 1 (ii) P = IV I = 60 /12 = 5 A (iii) 80 = Po x 100 Pi 80 = 60x 100 Ip (240) Ip = 0.3125A 15. eV = me v2 1.6 x 10-19 (3 x 103) = (9.0 x 10-31) v2 v = 3.27 x 107 m s-1 16.(i) (i) 1 1/8 (ii) (iii) 3T = 3 X 8 days = 24 days (ii) 32 days = 32/8 = 4 T 20 mg 10 mg 5 mg 2.5 mg 1.25 mg or ()4 X 20 = 5/4 = 1.25 mg SECTION VIII A Paper 3 Section A Question 1 a (i) Angle of incidence / i (ii) Angle of refraction / r // sin r (iii) Refractive index of the glass block (b) & (c) i sin i r sin r 39. SULIT 39 15o 0.2588 11o 0.1908 30o 0.5000 20o 0.3420 45o 0.7071 29o 0.4848 60o 0.8660 36o 0.5878 75o 0.9659 41o 0.6561 (d) Draw graph sinr against sin i corecltly (e) sin i is directly proportional to sin r Question 2 QUESTION ANSWER MARK 5 a) (i) d increases as t increase 1 a) (ii) Draw a dotted line at t = 0.4 s d = 0.46 m 1 (show on the graph) 1 (answer + unit) b) (i) Draw a tangent line at t = 0.5s Draw a big triangle (shown on the graph) Gradient, m = PQ = 1.64 - 0 QR 0.7 0.31 = 4.2051 ms -1 1 1 1 (shows the working) 1 (correct answer + unit; 2 to 4 d.p.) b) (ii) a = 2m = (2)( 4.2051) T 0.5 = 16.8204 ms -2 1 (substitution) 1 (answer + unit)c) (i) Velocity 1 c) (ii) Velocity increases as time increase 1 40. SULIT 40 QUESTION ANSWER MARK d) Avoid parallax error by making sure the eye is perpendicular to the scale of metre rule when measuring displacement 1 TOTAL 12 41. SULIT 41 SECTION VIII B EXPERIMENT (Paper 3 Section B) Question1 [Force and Motion] No Answer (a) Inference The force affects the acceleration (b) Hypothesis The greater the force, the greater the acceleration (c) i. Aim ii. Variables iii. List of apparatus and materials To investigate the relationship between the force and the acceleration Manipulated variable : Force. F (weight of the load) Responding variable : acceleration, a Fixed variable : Mass of the trolley, m A trolley, runway, ticker- timer, ticker-tape, power supply,metre rule and wooden block States the workable arrangement of the apparatus Set up Set up the apparatus as shown in the diagram. States the method of controlling the manipulated variable Use load of F = 0.5 N to pull the trolley down the runway. States the method of measuring the responding variable Switch on the power supply and release the trolley. Cut the ticker tape into 5-tick strips and a tape chart for the motion of the trolley is made. Calculate the acceleration of the using t uv a and record the data. a.c power supply 42. SULIT 42 No Answer Repeat the experiment at least 4 times Repeat the experiment by using F = 1.0 N, 1.5 N, 2.0 N, 2.5, N and 3.0 N. Tabulating of data Force, F/ N acceleration , a /cms-2 0.5 1.0 1.5 2.0 2.5 3.0 State how data will be analysed Plot graph of acceleration against Force a/cms-2 F/N 43. SULIT 43 QUESTION 2 (FORCE AND MOTION) No Answer (a) Inference The mass affects the acceleration (b) hypothesis The greater the mass, the smaller the acceleration (c) i. Aim ii. Variables iii. List of apparatus and materials To investigate the relationship between the mass and the acceleration Manipulated variable : mass. m Responding variable : acceleration, a Fixed variable : Mass of the trolley, m A trolley, runway, ticker- timer, ticker-tape, power supply,metre rule and wooden block States the workable arrangement of the apparatus Set up the apparatus as shown in the diagram. Use load of F = 0.5 N to pull the trolley down the runway. States the method of controlling the manipulated variable Use trolley with the mass, m = 500 g States the method of measuring the responding variable Switch on the power supply and release the trolley. Cut the ticker tape into 5-tick strips and a tape chart for the motion of the trolley is made. Calculate the acceleration of the using t uv a and record the data. Repeat the experiment at least 4 times a.c power supply 44. SULIT 44 No Answer Repeat the experiment by using m = 1000 g, 1500 g, 2000 g and 2500 g Tabulating of data Mass, m/ g acceleration , a /cms-2 500 1000 1500 2000 2500 3000 State how data will be analysed Plot graph of acceleration against Mass a/cms-2 m/g Question3 [Force and Motion] No Answer (a) Inference The speed affects the position of the driver when the car stops suddenly (b) Hypothesis The greater the speed, the longer the distance to stop (c) i. Aim To investigate the relationship between the speed and the distance ii. Variables Manipulated variable : the height , h (the more the height, the greater the speed) Responding variable : the distance, s Constant variable : the mass, m iii. List of apparatus and materials runway, load, trolley, ticker timer and ticker tape, power supply, metre rule. 45. SULIT 45 No Answer Labeled diagram: Measure the height, h =10.0 cm of the inclined plane from the surface. Let the trolley moves down the inclined plane. Calculate the speed of the trolley, v from the ticker tape obtained. Measure the forward distance of the load, s Repeat the experiment with h = 15.0 cm, 20.0 cm, 25.0 cm, 30.0 cm and 35.0 cm. height, h / cm speed, v (cms-1) Forward distance, s (cm) 10.0 15.0 20.0 25.0 30.0 35.0 The graph(axis) of s against v or h is drawn TOTAL Question 4 [Force and Motion] No Answer (a) Inference The compression of the spring affects the vertical distance of the projectile (b) hypothesis The greater the compression of the spring, the greater the vertical distance of the projectile (c) i. Aim ii. Variables iii. List of apparatus and materials To investigate the relationship between the compression of the spring and the vertical distance of the projectile Manipulated variable : compression of the spring. x Responding variable : vertical distance of the projectile, a Fixed variable : Mass of the ping pong ball, m A spring, ping pong ball,metre rule Inclined plane h s h s 46. SULIT 46 No Answer States the workable arrangement of the apparatus Set up the apparatus as shown in the diagram. States the method of controlling the manipulated variable Compress the spring, x = 1.0 cm with the ping pong ball States the method of measuring the responding variable Release the ping pong ball Measure the maximum distance of the ping pong ball, h using metre rule. Repeat the experiment at least 4 times Repeat the experiment by using x = 1.5 cm, 2.0 cm, 2.5, cm and 3.0 cm. Tabulating of data Compression of the spring, x/ cm vertical distance of the projectile , h /cm 1.0 1.5 2.0 2.5 3.0 State how data will be analysed 47. SULIT 47 No Answer Plot graph of h against x h/cm x/cm Question 5 [Force and Pressure] No Answer (a) (b) (c) ( i ) Inference State a suitable inference The pressure exerted on the surface depends on the area of contact. Hypothesis State a relevant hypothesis When the area decrease, the pressure increases (i) Aim State the aim of experiment To investigate the relationship between the area of contact and pressure (depth of hole). (ii) Variables State the suitable manipulated variables and responding variable (Quantity that can be measured) Manipulated variable : Area of contact object. Responding variable : pressure exerted (depth of hole) State the constant variable Force applied (using 1 kg load) (iii) List of Apparatus and Materials State the complete list of apparatus and materials Vernier caliper, soft plasticine, ruler, Load 1 kg, the object with different surface area but same weight. Draw the functional arrangement of the apparatus 48. SULIT 48 No Answer (v) State the method to control the manipulated variable Measure the bottom area of the wooden block with vernier caliper/ruler, A1 cm 2 . Place the wooden block on the plasticine. Place the 1 kg load on the top of the wooden block. State the method to measure the responding variable Remove the load and wooden block. Measure the depth of hole using vernier caliper and record it. Repeat the experiment at least 4 times with the values Procedure 2 and Procedure 3 are repeated using A2,A3,A4,and A5 (Note : Based on SPM standard , at least five manipulated values required.) State how the data tabulated with the title MV and RV Area of contact/ cm 2 Depth,x /mm A1 A2 A3 A4 A5 State how the data is analysed, plot a graph RV against MV Depth,x/mm Area of contact,A/ cm 2 Question 6 [Force and Pressure] No Answer (a) Inference State a suitable inference The pressure of liquid is depends on the depth (b) ypothesis State a relevant hypothesis The pressure of liquid increases as its depth increases. (c) (ii) Aim State the aim of experiment To investigate the relationship between the pressure and depth. (ii) Variables State the manipulated variable and the responding variable Manipulated : Depth, h Responding : The pressure of liquid, P (difference of length of the liquid in 49. SULIT 49 No Answer manometer, y) State ONE variable that kept constant The density of liquid (iii) List of Apparatus and Materials Complete list of apparatus and materials Tall beaker, thistle funnel, manometer, metre rule Arrangement of apparatus : State the method of controlling the manipulated variable 1. Set up the apparatus as shown in the diagram. 2. Immerse the thistle funnel into the water until depth, h = 6.0 cm State the method of measuring the responding variable 3. Measure the difference of length of the liquid in manometer, y by using ametre rule. Repeat the experiment 4. Repeat the experiment using h = 8.0 cm, 10.0 cm, 12.0 cm and 14.0 cm. Tabulation of data: h, cm difference of length of the liquid in manometer, y / cm 6.0 8.0 10.0 12.0 14.0 50. SULIT 50 No Answer Analyse the data . y/ cm Depth, h / cm Question 7 [Heat] No Answer (a) Inference State a suitable inference The type of fin affects the absorption of heat energy. (b) Hypothesis State a relevant hypothesis The smaller the specific heat capacity, the less the time taken to increase the temperature of the water in the tank (c) (i) Aim State the aim of experiment To investigate the relationship between the specific heat capacity and the time taken to increase the temperature (ii) Variables State the manipulated variable and the responding variable Manipulated : The specific heat capacity, c Responding : increase the temperature, State ONE variable that kept constant time taken to increase the temperature, t Complete list of apparatus and materials 5 different material of 1 kg of metal block with different specific heat capacity, thermometer, ac power supply, heater, oil, felt, stop watch 51. SULIT 51 No Answer Arrangement of apparatus : State the method of controlling the manipulated variable 1. Set up the apparatus as shown in the diagram. 2. Measure the initial temperature of the aluminium block, T1 State the method of measuring the responding variable 1. Switch on the power supply and simultaneously start the stop watch 2. Switch off the power supply after 5 minutes and record the maximum temperature, T2 using the thermometer. 3. Calculate the change in temperature, = T2 - T1 Repeat the experiment 4. Repeat the experiment using copper, glass, plumbum and steel blocks with different specific heat capacity. Tabulation of data: solid block specific heat capacity, c (J kg -1 o C -1 ) , o C aluminium copper glass plumbum steel Analyse the data . , o C specific heat capacity, c (J kg -1 o C -1 ) 52. SULIT 52 Question 8 [Heat] No Answer (a) Inference State a suitable inference The rate of cooling of an object depends on its volume//mass. (b) Hypothesis State a relevant hypothesis The rate of cooling of water increases as its volume//mass decreases. (c) (ii) Aim State the aim of experiment To investigate the relationship between the rat e of cooling of water and its volume//mass. (ii) Variables State the manipulated variable and the responding variable Manipulated : volume //mass of water Responding : Rate of cooling State ONE variable that kept constant Initial temperature / Final temperature Complete list of apparatus and materials Beaker 250 cm 3 , measuring cylinder, water, electric heater.stopwatch, thermometer, triple beam balance. Arrangement of apparatus : State the method of controlling the manipulated variable 5. Apparatus is set as shown in the above figure. 6. Water is heated to 55 o C. 7. 50 g // 50 cm 3 of water is placed in a 250 ml beaker with a thermometer immersed in the water. 53. SULIT 53 No Answer State the method of measuring the responding variable 8. The stopwatch is started when the temperature of the water is at 50 o C. The stopwatch is stopped when the temperature reaches 35 o C. The time, t is recorded. Repeat the experiment at least 4 times 5. The experiment is repeated using mass of water...................// volumes of water 100 cm 3 , 150 cm 3 , 200 cm 3 and 250 cm 3 . Tabulation of data: Mass, m (g) Time, t (s) 50.0 100.0 150.0 200.0 250.0 Analyse the data . Time, t (s) Mass, m (g) Total marks12 Question 9[HEAT] No Answer (a) Inference State a suitable inference The volume of gas depend on its temperature (b) Hypothesis State a relevant hypothesis .The volume of gas increases as its temperature increases (c) (iii) Aim State the aim of experiment To investigate the relationship between the volume of gas and its temperature. 54. SULIT 54 No Answer (ii) Variables State the manipulated variable and the responding variable Manipulated : Temperature Responding : The volume of gas State ONE variable that kept constant Mass of gas List of Apparatus and material Complete list of apparatus and materials Capillary tube, thermometer, water, metre rule and sulphuric acid Arrangement of apparatus : State the method of controlling the manipulated variable 9. Apparatus is set as shown in the above figure. 10. Water is heated to 30 0 C. State the method of measuring the responding variable 11. The vertical column of trapped air is measured by using metre rule. Repeat the experiment at least 4 times 4. The experiment is repeated using the temperature 40 0 C, 50 0 C, 60 0 C and 70 0 C. Tabulation of data: Temperature, T ( o C) Volume of gas, V (cm 3 ) 30 40 50 60 70 Analyse the data . 55. SULIT 55 No Answer Volume of gas Temperature Total 12 Question 10 [Light] No Answer Inference State a suitable inference The image distance/size of image depends on the object distance (a) Hypothesis States a relevants hypothesis The longer the object distance, the smaller the image distance/size of image (b) Aim State the aim of experiment To study the relationship between the object distance and the/image distance// the height of the image (c ) (Variables State the manipulated variable and the responding variable Manipulated variable : Object distance, u Responding variable : image distance, v // height of the image State ONE variable that kept constant Fixed variable : The power of the lens. Complete list of apparatus and materials Convex lens, meter rule, screen, lens holder, object 56. SULIT 56 No Answer States the workable arrangement of the apparatus States the method of controlling the manipulated variable The object distance is measured to be u = 20.0 cm. States the method of measuring the responding variable The image distance // the height of the image that formed on the screen is measured using the meter rule. Repeat the experiment at least 4 times The experiment is repeated by using different values of u = 25 cm, 30 cm, 35 cm, 40 cm dan 45 cm. Tabulating of data The object distance, u (cm) The image distance, v (cm) 20.0 25.0 30.0 35.0 40.0 State how data will be analysed Plot graph ofobject distance against the image distance // the height of image Graph of v against u The image distance // The height of image(cm) The object distance, u (cm) 57. SULIT 57 Question11 [Waves] No Answer 1 (a) Inference The color of monochromatic light affects the distance between two consecutive fringes (b) hypothesis The greater the wavelength, the greater the distance between two consecutive fringes (c) iv. Aim v. Variables vi. List of apparatus and materials To investigate the relationship between the force and the distance between two consecutive fringes Manipulated variable : the wavelength, Responding variable : the distance between two consecutive fringes Fixed variable : the distance between the source of monochromatic light to the screen, D A power supply, monochromatic light source of different colors, single slit, Youngs double slits, screen, meter rule States the workable arrangement of the apparatus Set up the apparatus as shown in the diagram. States the method of controlling the manipulated variable Use red color of light with the wavelength, 1 States the method of measuring the responding variable Switch on the power supply and observe the alternately bright and dark fringes Measure the distance between 2 consecutive bright fringes, x and record the data 58. SULIT 58 No Answer Total 12 Repeat the experiment at least 4 times Repeat the experiment using 4 different colors with different wavelength, 2 , 3, 4 and 5 Tabulating of data wavelength, (m) The distance between two consecutive fringes, x (cm) 1 2 3 4 5 State how data will be analysed Plot a graph of x against The distance between two consecutive fringes, x (cm) The wavelength, (m) Question 12 [Waves] No Answer 1 (a) Inference The displacement of the string affects the loudness (b) hypothesis The greater the displacement of the string, the greater the amplitude (c) Aim Variables To investigate the relationship between the displacement of the string and the distance between two consecutive fringes Manipulated variable : the displacement of the string, d Responding variable : the amplitude, x Fixed variable : the tension of the string A stretched string, a microphone, a CRO 59. SULIT 59 No Answer Total 12 vii.List of apparatus and materials States the workable arrangement of the apparatus Set up the apparatus as shown in the diagram. States the method of controlling the manipulated variable Use red color of light with the wavelength, 1 States the method of measuring the responding variable Switch on the power supply and observe the alternately bright and dark fringes Measure the distance between 2 consecutive bright fringes, x and record the data Repeat the experiment at least 4 times Repeat the experiment using 4 different colors with different wavelength, 2 , 3, 4 and 5 Tabulating of data displacement of the string The distance between two consecutive fringes, x (cm) 1 2 3 4 5 State how data will be analysed Plot a graph of x against The displacement of the string, x (cm) The wavelength, (m) 60. SULIT 60 Question 13 (Electric) No Answer (a) Inference Brightness/Current depends on the thickness/diameter/cross sectional area of the wire (b) hypothesis The current I increases when the diameter of the wire increase (c) (i) Aim Variables viii. To investigate the relationship between current and the diameter of a wire Manipulated variable : diameter of the wire Responding variable : current Fixed variable : the length of wire (iii) List of apparatus and materials Dry cells, voltmeter, ammeter, conductor wire, switch (iv) Procedure (v) Use conductor wire with diameter of, d = 0.2mm. Record the reading of the ammeter and tabulate the data. Repeat the experiment using d = 0.4mm, 0.6mm, 0.8mm and 1.0mm V A 61. SULIT 61 No Answer (vi) Diameter/mm Current/A 0.2 0.4 0.6 0.8 1.0 A (vii) TOTAL 12 No Answer Inference Inference : The heating effect of a conductor is affected by the current. hypothesis Hypothesis : The larger the current, the higher the temperature of the water which is being heated Aim Variables Aim : To investigate the effect of current on heating Variable: MV : current ,I RV : temperature , Constant Variable : volume of water , inertial temperature of water List of apparatus and Beaker, ammeter, immersion heater, thermometer, connecting wire, rheostat and stop watch Current/A Diameter/mm 62. SULIT 62 No Answer materials Arrangement of apparatus: Procedure Pour 200cm3 of water into the beaker and measure its temperature. Switch on the circuit and adjust the rheostat until the reading of ammeter is 1.0 A. The stop watch is started. The final temperature is recorded after 2 minutes. Step repeated by adjusting the rheostat so that the ammeter readings are 2.0 A, 3.0 A, 4.0 A and 5.0 A. Tabulation of data Current, A Increase in temperature, C Analysis of data. Sketch the graph of increase in temperature against current. TOTAL 12 Question 15 (Electromagnet) No Answer 15(a) Inference The number of dry cells affects the movement of the hammer (b) Hypothesis: The bigger the current flow , the stronger the electromagnet (the more the number of pins attracted) 63. SULIT 63 Aim : To investigate the relationship between the electric current and the strength of the electromagetic No Answer No Answer Variables Variables : Manipulated : electric current flow, I Responding :the number of pins attracted, n Constant Variable: Thenumber of turns of the coil List of apparatus Solenoid, large iron nail, iron pins,ammeter , rheostat and power supply. Arrangement of apparatus: (labeled diagram) Control of Manipulated Variable : Wind the insulated wire around the large iron nail with 50 coils . Switch on the circuit and adjust the rheostat until the current flow I = 0.5 A Measurement of Responding Variable : Bring the container filled with iron pins until it touches the solenoid Record the number of iron nails attracted by the solenoid, n Repeat the experiment with I = 1.0 A, 1.5 A, 2.0 A and 2.5 A with a constant number of turns. Tabulation of data Electric current, I (A) No of nails attracted 0.5 1.0 1.5 2.0 2.5 Analysis of data. Sketch the graph of n against I TOTAL 12 64. SULIT 64 Answer No (b) Hypothesis: The bigger the current flow , the stronger the electromagnet (the more the number of pins attracted) 1 (c) Aim : To investigate the relationship between the electric current and the strength of the electromagnetic 1 Variables : Manipulated : electric current flow, I Responding :the number of pins attracted, n 1 Constant Variable: Thenumber of turns of the coil 1 List of apparatus :Solenoid, large iron nail, iron pins,ammeter , rheostat and power supply. 1 Arrangement of apparatus: (labeled diagram) 1 Control of Manipulated Variable : Wind the insulated wire around the large iron nail with 50 coils . Switch on the circuit and adjust the rheostat until the current flow I = 0.5 A 1 Measurement of Responding Variable : Bring the container filled with iron pins until it touches the solenoid Record the number of iron nails attracted by the solenoid, n 1 Repeat the experiment with I = 1.0 A, 1.5 A, 2.0 A and 2.5 A with a constant number of turns. 1 Tabulation of data Electric current, I (A) No of nails attracted 0.5 1.0 1.5 2.0 2.5 1 65. SULIT 65 Analysis of data. Sketch the graph of n against I 1 TOTAL 12