skema biology paper 123 trial spm 2013 mrsm del jsu

8/10/2019 Skema Biology Paper 123 Trial Spm 2013 Mrsm Del Jsu

1/43

rc

MAJLIS AI} IANAH RAKYAT

ANSWER

SCIMME

BIOLOGY

PAPER 1

4551/1

TRIAL SPM

2013

www.

myschoolch

i ld ren

.com

Kertas soalan mp lain terdapat di :

www.myschoolchildren.com


2/43

QUESTION

NO

ANSWER

QUESTION

NO

ANSWER

1.

B 26.

D

2.

B

27.

B

3.

B

28.

D

4

B

29.

A

5.

D

30.

C

6.

A

31.

A

7.

B

32.

D

8.

A 33. c

9.

c

34.

c

10.

C

35. A

11.

C

36.

D

L2.

A

37.

A

13. D

38.

c

t4.

c

39.

D

15.

A 40.

B

15.

c

4L.

A

L7.

c 42.

B

18.

A

43.

A

19. A

44.

B

24. D

45.

D

21.

B 45.

D

22.

A

47.

C

23.

A

48.

D

24.

B

49.

D

25.

B

50.

C

MARA TRIAL 2013

EXAMINATION

ANSWER

SCHEME

PAPER

1

www.

myschoolchild

ren.com




3/43

eBr.rl-G

sc trhitrs

PAPER

2

QUESTTON

1

1

(a)(i)

Able

to name

the

structure

correctly

Answer:

P

:

Rough Endoplasmic

Reticulum/

Rough

ER

tNI

a

: Mitochondria

tI',U

(Reject

:

RER)

1

1

2

(ii)

Able

to

state the

function

of

the

structures.

P

:

To transport proteins

synthesized/made

by

ribosome

tF'tr

a

:

To

generate/produce/provide/supply

energy

tFI

(Reject:

give

energy/

site

for

cellular

respiration)

I

1

,)

(b)

Able to explain

how

the

abundance

of organelle

R enable

the

cells

to

carry

out

photosynthesis

efficiently.

Answer

:

Fl

: Contains

more

chlorophyll

tC}

El

: To

absorb

/capturel

trap

more sunlight

/

light

energy

/light

intensity

/

chemical

energy

IF']

E2

: To

produce

more

glucose

/

photosynthesis

product

/

organic

substances

/

organic

material

tFI

(Reject:food/starch)

(Any

two)

1

1

1

Max2 2

(c)(i) Able to

explain the

role of

R

in

osmoregulation

Answer:

Fl

: R

is

contractile vacuole

El

:

regulate

water contenUosmotic

pressure

E2 :

water

diffuses into R/contractile vacuole

by

osmosis

E3

: R/contractile

vacuole

expand to

marimum

size

E4

:

R/contractile vacuole moves to

the

plasma

membrane

E5 :

R/contractile

vacuole contracts to expel the

(excess)water

(Any

two)

Max2

1

I

t

1

1

1

7

01

:

(water)

ClPl: diffuses

into

the contractile

vacuole by

osmosis

02: contractile

vacuole

Cl'Pz: expand

(when

water

diffuses

in)

I

C:condition

I

lP:process/phenomena

I

lR=resrrlf

I

I

1




4/43

C/P3

:

move

to

plasma

rnembrane

CfP4:

the vacuole

contracts

R : regulate water content/osmotic

pressure

(Any

two)

1

1

1

1

a

(cXii)

Able

to

explain

the function

of

S

to

obtain

food.

Answer:

Fl

: sweeps

food

particles

into

cytostome/

mouth /

groove

/ oral

canal

El:

for

digestion

prooess

/

break

down

into

smaller

particles /

hydrolysis

1:

,1

O

:

cilia

ClPl

:

sweeps

food

particles

into cytostopel

mouth

/

groove

lt

.

oral

canal

Ctyz:

for

digestion

process

/

break down

into

smaller

particles

/

,l'

I

(cXiii)

Able to explain the

effects

of

the

respiratory

inhibitor

to the

,

Parameciumsp

Answer :

Fl

:

(the

respiratory

inhibitor)

inhibits

cellular

respiration

ll

mitochondria

cannot'

function

El

: cannot

generate

energy

EZ

:

cellular activities/active

transport cannot

occur

EZ

:

Paramecium

sp

eventually

dies

(tuty

two)

I

t:

:

I

1

Max2

2

ALTERNATIF

(using

science

text)

O :

inhibitor

ClPl :

inhibits

cellular

respiration

process

//

mitochondria

cannot function

C|PZ

:

cannot

generate

energy

/

cellular

activities

cannot

occur

R :

Paramecium

sp

eventually

dies

(Anv

two

I

1

1

2

TOTAL

L2

'

l'S'

s-

.*P'

:V-

$-

.:\,

.s

dv

sT.

\'

\..\

rti'

jp

(-

at

:k

vl

.a

\

.Cr"

^qi

r.r\L

ql

(-,

-g)

,\.)

+Kertas soalan mp lain terdapat di :



5/43

4

QUESTIOI\

;

Items

Marking

Criteria

Marks

aXi)

Able

to

name

the

condition

the

plant

cell.

Answers:

Plasmolysed

/

Flaccid Reject:

Plasmolysis)

I

1

ii)

Able

to explain

the

process

Answers:

F : solution

X

is

hypertonic

to the

cell

sap of

the

plant

celU/cell

sap is

hypotonic

to

solution

X/concentration

of

water

molecules)

outside

the

cell is lower than

the

cell

sap

El: water

diffuses

out

by

osmosis

Reject:

move)

E2 :

vacuole

/

cytoplasm

shrinks

/

plasma

membrane

is

pulled

away

from the

cell

wall

1

1

1

Max

2 2

ALTERNATIF

using

science

text)

O1:

solution

X

CtPl:

is

hypertonic to

the cell sap

of

the plant

cellllcell sap

is

hypotonic

to

solution Xllconcentration

of water

molecules)

outside

the

cell

is

lower

than

the

cell

sap

02

:

water

CIPZ

:

diffuses

out

by

osmosis

ClP3

:

vacuole

/ cytoplasm

shrinks

/

plasma

membrane is pulled

away

from

the

cell

wall

R

:

the

cell

is

plasmolysed

/

flaccid

1

1

I

I

Max2 2

bxi)

Able to

state

the

condition

Answer :

Deplasmolysed

/

Turgid

Rej

ect : Deplasmolysis)

I

1

b) ii)

Able

to

explain

the

effects

of solution

Y to

the

plant

cell.

Answer

:

F

: solution

Y is

hypotonic to

the

cell

sap

of

the

plant

cell/lcell

sap

of

the plant

cell

is hypertonic

to solution

Y//concentration

of

water

molecules)

outside

the

cell

is

higher than

the

cell sap

E1: water

diffuses

into

the

plant

cell

by osmosis

Reject:

move)

E3

:

vacuole

expands

/

plasma

membrane

is

pushed

towards

the

cell

wall

I

the

plant

cell

become

turgid

Max 2

I

1

1

2




6/43

ALTEITNATIF

(using

science text)

O1 :

solution Y

C/Pl : is hypotonic

to

the

cell

sap

of

the

plant

celV/concentration

of

water

(molecules)

outside

the

cell is

higher than

the

cell

sap

ot?:

water

CtY/.:

diffirses into

the

plant

cell

by

osmosis

R

:

vacuole

expands

/

plasma

membrane

is

pushed

towards

the

cell

wall

/

the

plant

cell

become

turgid

1

1

I

Max

2

2

(c)

Able to

explain

why the mango can

be

kept for longer

period.

Sample

answers3

:

F

:

sugar

solution

is hlpertonic

to

the

cell

sap of mango/lcell

sap of

mango is

hlpotonic

to

the sugar

solution

El

:

water diffrrses out

by

osmosis

EZ

: bacteria cannot

grow

(without

water) /

die /

dehydrated

1

I

1

Mor 3

3

ALTTRNATIF

(using

science text)

01

:

sugar

solution

C/Pl

:

hypertonic to the cell

sap of

mango

OZ : water

Cn2:

diffiises

out by osmosis

R

:

bacteria cannot

grow

(without

water) I

die

/

dehydrated

1

?i

1

1

Ma,x

3

3

(d)

Able to explain

the importance of drinking isotonic

water

Answer

Fl

:

isotonic

drink

is a

solution which

has

equal

concentration

/

osmotic

pressure

with the fluid

in

the

body

cells

El

:

to balance

the

water

content in body

cells

/

fluid

El

:

to

prevent

dehydration

llto

replace the

water

loss

I

t

I

3

TOTAL

t2




7/43

QUESTIONS

3

Item

Marking

Criteria

Marks

a)

Able to

name

structure

X and

Y.

Answer:

Structure

X: Alveolus

Structure

Y:

Gills

tNl

tNI

1

I

2

b)

Able

to explain

onesimilar

characteristic

in

structure X

and

Y

to

increase

efficiency

of

gaseous

exchange.

Answer:

F 1 :

have

many

/

numerous

structures

El

:

To

increase

total surface

area

F2

: surrounded

by

network

of blood

capillaries

E2

:

for

efficient

transport

of

gases

F3 :

the wall

is

one cell

thick//

thin wall

E3

: easier

for

gases

diffusion

Rej

ect:

Moist surface)

Any

lF

and

respective E

I

1

I

1

I

1

Max

2 2

ALTERNATIE

using

science

text)

N

=

name

C

=

characterestic

F

:

function

N

:

Structure

X

and

structure

Y

C1 : have

many

/

numerous

tiny

structures

Fl

: To increase

total

surface

area

C2 :

surrounded

by

dense

network of

blood

F2

: for

efficient

transport

of

gases

C3 : the wall

is one cell

thick

F3

:

easier for

gases

to diffi.rse

capillary

1

1

1

1

I

I

Max 2

2




8/43

(c)

Able to

explain

effects

of

smoking

in

the

effrciency

of

gaseous

I

exchange in stru-cture

X.

I

Answer:

I

I

Fl

:TarNicotine/Chemical

substance I

I

El:

Deposited on

the

wall

of alveolus

I

1

E2 :Block

the

diffirsion

of

gasses

actoss

the

wall

of,alveolus

I

1

F2

:HeatlHigh

temperature ,'

E3 :causes

the

wall

of

alveolus

become

dry

E4

:Less

gasses

dissolve

E5

:

competes

with

oxygen

to

gombine

with

ha,-emoglobin

/

has

higher

affinity

towards oxygen

E6

: less

oxygen

supplied

to

body

cells

Any

lF

and

resPective

E

, I

Mor2

2

(d)

Aspect

Part P

(aerobic) Part

Q

(anaefobic)

1+1

,

t,.

1+1

4

Products

of

the

respiration

Energy

/

ATP,

carbon

dioxide

and

water

Energy

I ATP,'ethanol

and

carbon

dioxide

Explanation

of

the

process

Complete

brcakdown

/

oxidised

of

glucose

ll

Require

oxygen

lncomplete

I

partiallY

breakdown

of

glucose

ll

'Doesn?t

require

oxygen

(e)

Able

to

explain

the importance

of

warming

up

Sample

answer

3

Fl :

increase

the

rate

of

heartbeat

Et :

more

oxygen

can be

transport(to

the

muscle

cells)

//

transportation

of

oxygen

is

faster

E2

:

increase

the

rate

of

cellular

respiration

(in

muscle

cells)

FZ

:

increase

the temperature

in

the

muscles

E3

:

loosen

up

the muscles

and

joints

I

prevent muscle

cramp

Any

F

with

corresponding

E

1

1

I

1

1

Max

2

2

12




9/43

tuESTI,St{

4

Item

Markins

Criteria

Marks

(aXi)

Able

to

fill

the

table

with

the correct

name

of

molecules

and

enzymes

involved

Answer:

4

4

Malto

s e/S ucrose/Lactose

Maltase/Sucrase/Lactase

F

at

I lipid

/

triglycerides

lipase

(ii)

Able

to explain

the

effects

of diet

rich

in

fat.

Answer

Fl:

fatllipid/molecule

N

contain high

level

of

cholesterol

El

:

deposited

on

(the

inner

wall

of)

artery

E2

:

increase

blood

pressure

/ cause arteriosclerosis

/

hypertension

Any two Mor 2

1

1

1

2

ALTERNATIF

(using

science

text)

O

: fatllipid/rnolecule

N

CtPl

: contains

high

level

of cholesterol

CtPz

: deposited

on

(the

inner

wall

of) artery artery

R

:

increase

blood

pressure

/

cause

arteriosclerosis

/

hypertension

1

1

1

Max2 2

(b)

(i)

Able to

state

the

food

which

supplies the

most

energy.

Answer:

Rice

INI

1

1

(ii)

Able

to

state the

food

which helps to

prevent

scurvy.

Answer:

Orange

tNI

I

I

(iii)

Able

to

calculate

the

total amount

of

energy.

Answer:

Rice:

1530

kI x

2

:3060

kJ

Fish

:

320

kJ

x 1.5

:

480 kJ

rotal

energy:;lf8lj

.

480

kr

I

1

1

a

J

(c)

Able

to

explain

why

egg has double amount

of

energy than

fish

Sample answeri

Egg

contain

more fat than

fish

1

I

TOTAL

12




10/43

Question

5

Item

Answer

Mark

(aXi)

Able

to explain the

role of

polythene

bag according

to the

]

different

in reducing the

temperature.

Answer:

PlantA

Fl

:

polythene

bag traps water

vapour

(from

kanspiration)

El :

more water vapour

around

the leaves

E2

: increase

in

humidity

(inside

the

polythene

bag)

y

two

Plant

B

F2:

rate

of transpiration increases /higher

An

I

i

EZ

:

more water move

up through

>rylem

2

2

(b)

Able

to explain

why

Plant

B

shows

higher

loss in mass

,

,

,

Fl

:

more loss

in mass

of

the

plant

B

El

:

the leaves in Plant

B

are

not

covered

(by polythene

bag)

E2

:,more

water

valrcur

are released

to the

surounding

through

F

with

any E

1i

... :

1

,1,

Malr

2

2

ALTERNAJIF

(using

science

text)

Ol

: Plant

B

ClPl

:

the leaves

in

are

not

covered

(by

polythene

bag)

CtPz:

more water

vapour

are

released to the

surrounding

I

rate

of transpiration

is

higher

R

:

more loss

in

mass

of

the

plants

I

I

I

Max2

2

(c)

Able

to

suggest

one

way

and explain

Answer:.

Suggestion

: remove /

cut

offthe

leaves

llplace

the

pot

under

a

shaded area

/

under

a big

tree

Explanation :

no

/

less

stomata,

less

water

loss

low temperature /

high

humidity

/

less

light

intensity/slow

air movement

1

I

2




11/43

(c)

10

Abf

to

.xr,'

I

ai

ntlre

.ff..

i-,*trn

*

;it. *b

cn.:li

oi,

i

i*

.., ,i*t

and

iight

intensity

on

the

yield

of

crops.

Answer

:

Temperature

F

1

:

increase

the

enzymatic

activity

/

maximum

rate

/

optimum

El

:yield

of

crops

increases

Carbon

dioxide

F2 :the

rate

of

photosynthesis

increased

/

maximum

/

photosynthesis

product

increase

El

:

increase

the

yield

of

crops

ALTERNATIF

(using

science

text)

Ol

:Temperature

CtPl

: increase

the

enrymatic

activity /

maximum

rate

/

optimum

R

:

yield

of

crops

increases

02

: Carbon

dioxide

CtP2

:

the

rate of

photosynthesis

increased

/

maximum

/

photosynthesis

product

increase

R:

increase

the

yield

of

crops

=

\r

6

6




19/43

18

Item

Number

MARKING

CRITERIA

MARKS

F1 :

Typhoid

/

Cholera

Pl

:

caused

by

bacteria

I vibrio

cholerae

I

Salmonetta

typhii)

spread

through

contaminated

food

and

drink

ll

the

feaces

of

infected

people

reach

food tluough

unwashed

hand

Food

poisoning

caused

by

bacteria

I

Salmonella

sp.)

spread

through

contaminated

food,

drinks

and utensil

Malaria

disease

caused

by

protozoa

Plasmodium

sp.) transmitted

by vector

Anophele.r

sp.

mosquito

F4:

Dengue

fever

P4:

caused

by

virus)

transmitted

by

vector

Aedes

mosquito

Any

2 F

and 2P

accordingly

1

1

1

Max

4




20/43

19

Item

Number

MARKTNG

CzuTERIA

MARKS

7

(c)

Able

to explain

similarities

and differences

between

interaction

in

Diagram

7.2(i) and Diagram

7.2(ii)

www.

myschoolch

i

ld

ren

.com

Anv

3

*

Criteria

PQRST

Diagrarn 7.2

(i)

Diagram 7.2

(ii)

T

Al :

The

interaction

is

intraspecifi

c

competition

81: The

interaction

is

interspecifi c

competiiion

Qr

M

:

Competition

is between

members

ofthe

same

species

llbetureen

species X

andspecies

X or between

species

Y

and species

Y.

B2

:Competition

is between

members

from different species//

between species

X

and

species

Y.

Q2

A 3 : The

strong /

dominant

member

win

/ remain but the

weak one die /become

extinst.

83 :

The strong

/

dominant

specibs win

the competition

but

the weaker species

become

extinct /

migrate

to other

area

I

die

Q3

44

: The

population is

always

in

dynamic

equilibrium /

stable

/

constant

only

84

:

Population

of

weaker

sPecies

decrease

and

the

dominant

species increases.

I

I

I

I

Mur

3

3

S

I :

Both

interaction

involve

organism

living

together

in

the

same

habitat

52

:

Both interactions

compete

for

the sa:ne

resourc eVwater/nutri

ent/space

53

:

Both

interactions

compete for

the

limitedre sources/water/nutrient/space

P

:

Process

q

=

Quality/Quantity

R

=

Reaction

S:

Structure

T

=

Terminolory

At

least

one

similarities

1

I




21/43

20

ITEM

NUI\{BER

MARKII{G

CRITERIA MARKS

7

d)

Able explain

how scientific

names derived on Linneaus

binomial system

P

1

:

Each

organism

has

two

names

in

Latin

P2

:

The

first

name

must begin

with capital letter

P3

:

The

first

name

refer to

the

genus

name)

P4

:

The

second

name

begin

with small letter

P5

:

The

second

name refer

to

the

species

name)

P6:

Both

genus

and

species narne must

be written in itallic

P7

:

alternatively,

the words

can be underlined

P8:

For example

Panthera

is the

genus

of both organisms,

but

they

are

of

different

species)

P9

:

Lion belongs

to

species

lgq

while

tiger belongs

to

species

tigris

1

1

1

1

1

1

1

1

1

Max 6 6

TOTAL

20




22/43

2t

Question

8

ITEM

I\[T]MBER

MARKTNG

CRITERIA

MARKS

8

(a)

Able to explain the body s

response

towards

the

entry

of

bacteria

into

the

body

Fl

: the

second line of

body

defense

rhechanism

Pl :

Pathogen

/ bacteria

succeed

in

penetrating the

skin

/

enter

the body through

skin

P2

: Chemicals /

proteins

/

antigens

(produced

by

pathogens

)

P3

:

Attracts

the

phagocytes /

neutrophil

/

macrophage

/

phagocytes

(to

injected

area

)

P4

:

The

phagocytes

surround

the

pathogen

using

pseudopodiurn

:

P5

The

phagocytes engulf

the pathogen

forming

vacuoles

/

phagosomes

P6 :

Lysosomes

secretes

lysozymes

and

release

the

lyso4mres

into

the vacuole

/

phagosomes

,.

P7

:

The

lyso4mes

kitl /

destroy

/

digest

/

hydrolise

the

phagosytes

:

P8

:

The

phagocytes

release /

egest

the

digested

product from

the

cell

P9:

The

process

is known

as

phagocytosis.

1

I

I

1

I

1

1

1

I

1

Mar

4

I

I

4




23/43

22.

ITEM

NUMBER

IVIARKTNG

CRTTERIA

ALTERNATIF

using

science

text)

Name

of the

process/mechanism

:

the

second

line

of body

defense

01 :Pathogen

lbactena

t

ClPl

:

penetrating

the

skin

/ enter

the

body

through

skin

02 :

Chemicals

/

proteins

/ antigens

produced

by

pathogens

)

ClPz:

Attracts

the

phagocytes

/

neutrophyls

/

macrophage

I

phagocytes

to

injected

area)

03

:

phagocytes

C/P3

: surround

the

pathogen

using

pseudopodium.

C/P4:

engulf

the pathogen

forming

vacuoles

/

phagosomes

04

:

The

phagocytes)

ClPs

: release

/

egest

the digested

product

from

the cell

R: The

process

is

known as

phagocytosis.

05

: Lysosomes

ClP6 :

secretes

lysozymes

and release

the lysozymes into the

vacuole

/

phagosomes

C|PT

:

kill

/

destroy

/

digest /trydrolise the

phagocytes

lVIARKS

I

1

Max 4




24/43

23

Item

Number

MARKXNG CRITERIA

MARKS

8(b)

Able

to

explain

how

the

lymph

is drained

back

into

the

blood

P

I

:

(From

the

lymphatic

vessel),

the

llmph

is

drained

into

thoracic duct

P2

: and

the

right lymphatic

duct.

P3

:

The

thoracic

duct receives lymph

from

the

left side

of

the

head / neck /

chest

/

left

upper limb

llentte body

below

the

rib

P3

:

The right

lymphatic

duct

receive lymph

from

the

right

armt

I shoulder area il

ndht

side

of

the

head

/

neck

P4 : The

right lynphatic

duct

empties

it s

lymph

into

the

right

subclavian vein

(

entering

back into

the

blood

circulating

system

)

P5

:

The

thoracic duct empties

its lymph into

the

left

zubclavian.

P6

:

The

valves

prevent

back

flow

of

lymph

P7

:

Muscular contracti

on

ll

peristalsis movement / intestinal

//

pressure

changes

dr:ring

inhalation

and

exhalation

breathing action

push

the

lymph to

rflow

forward

1

I

I

1

I

I

I

1

1

Mur

6

6




25/43

24

Item

Number

MARKING

CRTTERIA MARKS

8(b)

ALTERNATIF

(using

science

text)

01

:

lymph

C/P 1

:

(From

the lyrnphatic

vessel),

drained

into thoracic

duct

C/P2:

and the

right lymphatic

duct.

02

:

(The

thoracic

duct)

ClPz: receives

lymph

from

the

left

side

of the

head

I

neck

I

chest

I

left upper

limb

llentfue

body below the

rib

03 :

(The

right

lyrnphatic

duct)

ClP3

:

receive

lymph

from

the

right

arm /

shoulder

arca

/l

right

side

of

the

head

/

neck

ClP4: The

right lymphatic

duct empties

it s

lyrnph

into

the

right

subclavian

vein

(

entering back into the

blood

circulating

system

)

04 :

(The

thoracic

duct)

C|PS

:

empties

its

lymph into the left

subclavian.

05

:

The

valves

ClP6

:

prevent

back flow

of lymph

06

:

Skeletal muscle/smooth muscle

C|PT

:

contraction

llperistalsis

movement

i

intestinal //

pressure

changes

during

inhalation

and exhalation

breathins action

1

1

I

1

I

1

1

1

1

CiPS:

push

the lymph

to flow forward

1

Max

6

6

www,myschoolchildren.com www.myschoolchildren.com




26/43

25

Item

Number

MARKTNG

CRIT'ERIA

MARKS

8c)

i)

Students

are

able

to

explain

the formation

of

lymph

Fl

:

Diameter

of

arteriole end is larger

compared

to

the

blood capillary

F2

:

cause

high

hydrostatic

pressure

at the

arteriole

end of

blood

capillary

i

F3

:

Some

of the'bloodplasmais;filtered/forced

into

the

spaces

between

the cellVintercellular

spaces

(Reject:

diffirse)

F4 :

forming

interstitial

fluid

,

',i

1

F5

: contains

of

the

interstitial fluid

are

nutrients/

oxygen/

amino' acid/

glucosel

water/,

ions.

F6

:

except

large'

moleculeslRBC/plasma

protein

/fibrinogen/globulin/platelets

:

F7:

Some

/

85-90 ,ofthe interstitial

fluid

arereabsorbed

intothe

blood

capillary'(at

venule

end)-

F8:

Some/

lff/o

is

absorbed

into

the'lynphatic

capillary/

'

vessels(forming

lympU

lymphatic

fluid).

;'

Any

6F

;'

.,

'

,,.

i

ii) Students

are able

to

explain body

defense

mechanism

F9:

Lymph nodes

produce

lymphocytes'

F10

:Lymphocytes

produce

antibodi

e s/lysine/op

s

onin/ag

gl

utinin/antitoxin

Fl I :

Deshoy

pathogen/

neutalize

the

toxin

produced

by,the

:

pathogen.

F13 : PhagocyteVneutrophiVmonocytes engulf

and

.

'

i

destroy/digestlhydrolyze

pathogen

:Any

4F

I

I

1

I

1

I

1

Ma>r 6

ll

t,

l,

I'

r

I

**o

6

4

TOTAL

20




27/43

26

MARKING

CRITERIA

MARI(S

ALTBRNATI{

(using

science

text)

O1

:

arteriole

C/P1

:

Diameter

of

arteriole

end

is

larger

compared

to the

blood

capillary

ClPz:

cause

high

hydrostatic

pressure

at

the arteriole

end

of

blood

capillary

02

: blood

plasma

ClP3

:

Sorne

of

the

blood

plasma

is

filtered/forced into

the

spaces between

the cells/intercellular

spaces

c/p4:

forming

interstitial

fluid

(Reject:

diffuse)

ClPs

:

contains

of

the

interstitial

fluid

are

nutrients/

oxygen/

amino

acid/

glucose/

waterl ions.

C/P6: except

large

molecules/RBC/plasma

protein

/

fi brino

gen/gl

o bul in/pl

atel et

s

03:

interstitial

fluid

C|PT

:

Some

I 85-90

(of

the

interstitial

fluid) are

reabsorbed

into

the

blood

capillary

(at

venule

end).

C/P8 : Some/

10

is

absorbed

into

the

lymphatic capillary/

Vessels (forming

lymph/

lymphatic

fluid).

Any

6F

ii) Students

are

able

to explain body defense mechanism

04

: Lymph

nodes

ClPg

:

produce

lymphocytes

05 : Lymphocytes

C/P 10

:

produce

antibodies/lysine/opsonin/

agglutinin

/antitoxin

CIP

1 1

:

Destroy

patho gen/

neutralize

the

toxin

produced

by

the pathogen.

06 : Phagocytes/neutrophil/monocytes

C/PIZ

:

engulf

and

destroy/digestlhydrolyze

pathogen

C/Pl3

: Phagocytosis

occur

07

: Lymph nodes

ClPl4

:

filtered

pathogen

Any

4F

1

1

1

1

1

1

Max 6




28/43

27

Question

9

ITEM

I\TUMBER

MARKING

CRITERIA

MARKS

e(a)

P1

x

Parents

PhenotSrpe

:

Genotype :

Meiosis

Gamete:

Random

Fertilization

Genotype

Fl:

Phenotype

Fl:

Rabbit P

White

fur, black

eyes

Rabbit

Q

Black fur,

red

eyes

Bbrr

P4

P5

and

P6

P7

P8

Black

fur,

black

eyes

Notes;

n

must have

word meiosis

and

seggregotion

lines

ii)

gametes

must be

circled

fiil must

hqve

word

random

fertilization

and lines

Pl:

The

genotype

for Rabbit

P is

bbn

and the

genotype

for

Rabbit

Y

is

BBRr

P2 :

genotlpe

bbrr consist

of

b,recessive

allele

for

white

fur

and

r,

recessive

allele

for

black

eyes.

P3

:

genotlrye

BBRr consist of

B,

dominant

allele

for

black

fur

and

R

and r

for

dominant

and

recessive

allele

for

red eyes and black

eyes

respectively

P4

:During

meiosis

P5

: Gamete

produced

for

Rabbit

P

arebr.

P6:

Gamete

produced

for

Rabbit

Q

are

BR

and Br.

P7

: Random fertilisation

occur

P8

:

bet'ween

gametes

br from

Rabbit

P

and

gamete

Br from

Rabbit

Q

produced

genotype

of

Rabbit

Bbrr.

P9: Dominant

allele,B

is inherited

from

Rabbit

Q,

while

recessive

allele,b

is

inherited

from

Rabbit

P

Pl0:

Recessive alleles,

r

is

inherited from

both parent,

P

and Q

Pl 1: The Dresence

of

(dominant)

allele,Band(recessive)

allele

b,




29/43

28

i i

sho ;v:the

phe,rotype

black

fur.

i

P12:lihe

presence

of

(recessive)

allele,r and

(recessive)

allele

r,

showsthe

phenotype

black

eyes

Any 6

1

Max

6

ITEM

NUMBER

MARKING

CRITERIA

MARKS

e(bxi)

AbIe to

discuss

the

advantages

of

using

genetic

engineering

Technology

in agriculture

Sample

answer

The advantages

:

F1

: Resistance toward disease/pest resistant

increase

Pl :

because

it

alters the

genetic

information

in

plants.

F2

:

The

quality

of

agricultural

product

increases

P2

: because

food/fruit/crop

yield

product

have

higher

vitamin/mineral/nutritional

content

F3 :

Foo

dl tn;Jrtl

Crop

yield

can

be

harvested

shortly

after

planting/in

shorter

time

P3

:

because

it

shorten

maturity

period

F4

:

Food/ fruit/ crop

yield supply is sufficienVmore

food

can

be supply to the

people

P4

:

because the

quatity

of

crops

yeild

increases

ANY 3

F

AND 3P ACCORDINGLY

1

1

1

1

1

1

1

1

Max

6 6

TOTAI-,

20




30/43

29

MARKING CRITERIA

State

fotr

differences

between

Down s

syndrome and

haemophilia

based on

these

criteria.

1. Cause

2.

hlunober

of

chromosomes

3. Characteristics

4. Inheritance

Cause

by

chromosomal

mutation

of

chromosomes

numbers

2l

Cause

by

a recessive

allele

found

on the

X

sex chromosome.

Abnormalll4T

Number

of

chromosomes

NormaU/46

Blood

unable

to clot

ave flatlbroadllbroad

faces//slanted

eyell

protoding

tongue//tend

to

be

mentally

retarded

Characterestics

Not

inherited




31/43

SULIT

45s113

A}.iSWER

SCFIEivfE

PAPER

3

TRIAL

BIOI-CGl ]013

No.

Vlark

Scheme

Score

1

(u)

Able

to

record

all

3 readings

for

the

time taken

to obtain 30

heartbeats

correctly

Samole answer

3

Numbers

of

laps

Bilangan pusingan

The

time taken

to

obtained

30

heartbeat

(s)

Masa untuk

memperoleh

30 denyutan

iantuns

(s)

1

20

2

12

J

10

www.

myschoolch

ild

ren.com

Able

to

record

any 2

readinss

correctly

2

Able

to record

any

1 reading

correctly I

No

response

or incorrect

response

0

1(bxi)

Able

to

state

2 different

observations correctly following these

criteria:

C

l.-manipulated

variables

C2-Responding

variables

C3-correct value with unit

Sample answer

Vertical

1. The time taken

to obtain

30

heartbeats

after running

one round

is 20 seconds.

2.The time

taken

to obtain 30 heartbeats

after

running

two

rounds

is 12 seconds.

3. The time taken


after

running

three

rounds

is 10 seconds.

Horizontal

4. The time taken

to

obtain 30 heartbeats after running one

lap

is the

longest

compared

to after

running

two

and

tluee

laps.

3

AbIe

to

state one

observations

correctly

and

one

-

two

inaccurate

observation

Sample

answer

Uertical)

1.The

time

taken to

obtain

30 heartbeats

after

running one

lap

is the longest.

2.

The time taken to obtain

30 heartbeats

after

running

three

laps

is the

shortest

(Horizontall

3. The

time

taken to

obtain

30 heartbeats

after running

one

lap

is

longer

than

when

running

three

laps

that

is

12 seconds.

2

455L CI

2013 Hak Cipta

Bahagian

Pendidikan Menengali

MARA

SULIT




32/43

SULIT

4551t3

ANSETR

SCHEME

PAPER

-?

TRTAL

BIOLOGY

2013

Able

to

state the

obsenation

at idea

level

l.The

longest

time

is 20

seconds.

2. The

shortest

time is

10

seconds.

3. The

time taken

to

obtain

30 heartbeat

decreases.

1

No response

or

incorrect

response

0

1(bxii)

Able

to

make

two

inferences

correctly

Note

:

inference

must

matsh to

the observation

Cl

- number

of laps

ran

by

an

athlete and

the

condition

of

time

taken

to

obtain

30 heartbeat

C2 -

rate

of heartbeat

increases

/ decreases

C3

-

o*Jgg,l ngeded

by

muscle,3efl

large/small

Sarnple

answer

(Verticall

1.

When

the

boy

mns

one lap, the

time taken

to

obtain

30

heartbeat is

the longes ,

because

the rate

of heartbeats

is

decrepsesAower due to

muscle

cells'needs

a small amount

bf'oxygen

.

.

:

2. When

the

boy nms threq laps,

the

time

taken

to

obJain

30

heartbeat is

shortest becausb

the

iati: of

hiartUeats is increases/tiigher due to muscle

cells

needs

a

large

ambunt

of oxygen

fiforizontail.

3.The

time

taken

to obtain 30

heartbeats

after

nrnning

one

lap

is

longer

because

the

cells need

small

amowrt

of oxygen

comfared

to

when

running three

laps

cl

+

c2+c3

3

AbIe

to

make

one

correct inference and one - two inaccurate

inference

Eampls

answer

(Verticall

l.The

time

taken

to obtain 30 heartbeats after

running

one

lap

is the longest

because

rate

of

heartbeat

is the

lowest.

2.

The

time

taken


after

running three

laps is the

shortest

because

rate

of

heartbeat

is the highest

(Horizontal)

l.The

time

taken

to

obtain 30

heartbeats after

running

one lap /three

laps

is

longer/shorter

than

when running

three/one lap because

rate

of

heatbeat for one/three

laps lower/higher than

three/one lap.

Any 2C

2

AbIe

to

state the

inference

at idea

level

SAmple

anlwers

1.Rate

of

heartbeats

increases

1

No

response

or

incorect

response

0

4551

@2013

Hak Cipta Bahagian

Pendidikan

Menengah

MARA

SULIT




33/43


34/43

SULIT

4s51/3

ANS\frIER

SC}MME

PAPFR

3

TRIAL

BIOLOGY

2OI3

No.

Mark Scheme

, Score

I

(d)

I

Able

to

state

a

hypothesis

correctty

following

aII

criteria

:

C

I

: number

of laps

C

2

:

time,

taken

to,

obtain

30 heartb

eatsllrute

of

heartbeat

C3

: Clear/concreterelationship

,,;

Sampleanswer:r

,

1. As

the

number

of

laps increases,

the

time

tiken

to obtain

30

heartbedts

decreases

2.

The

more

the

nuurber

of laps,

the

shorter the

time

taken

to

obtain

30 heartbeats

(vice

versa)

,

.

,

;

;

.i,

.

,,r,.

,

1

3.

As the number

of

laps

increasgsr

the,rate

dheartbeat

elso,,incpases

i

i

(viceversa)

..:,,,:::

I

i:,

;.'..

.0,'iL,,r,..

_

.;

.

,

..,.,. ,i,,.i;

,

All 3C

3

Able

to make

a hypothesis

relating

the

manipulated

variable and

the responding

variable

inaceurately

Sample

answer

:

'

::

i

l.The

time

taken

to obtain

30

heartbeats

llThe

rate

of

heartbeat

is

affectedbynunrberoflaps

.:

.,

..i.,.,..,:,ri.

:i,].

Any

2C

,

tL

Able

to

make a

hypothesis

at

idea

level

sqmpleanswgr:

'i'

ij''-'

i'

l.TG

time

tut r

to

obtain

30 heartbeats

decreases

,

,',

,

'

2.The

rate

of

heartbeat

increases

Only

1C

I

No

response

or

incorrect

response

0

4551 @

2013

Hak Cipta Bahagian

Pendidikan Menengah MARA

ST]LIT




35/43

SULIT

4s5U3

/\NSWER

SCTIEME

PAPER

3

TIUAL

BIOLOGY 2013

Ni;.

Mark Scheme

Score

1

e) i)

Able

to

construct a

table

and

record all

the data correctly

Sample

answer

Note :

T)

Titles

with

correct

unit

-

I

mark

D)

Record

all

the data

correctly

-

I

mark

C)

Calculate

and

record all

the

rate

of

heartb eat

-

I

mark

3

Any

two correct 2

Any

one correct 1

No

response

or

incorrect

response

0

No.

Mark

Scheme

Score

1

e) ii)

Able

to draw a

graph

correctly

A

: Uniform

scale

on both axis

-

1

mark

PT :

Able

to

plot

all

3

points

correctly

S

:

Able to

connect all

point

smoothly

Refer

to

graph

provided

-

1

mark

-

I mark

J

Aoy

two

criteria correct

2

Uniform scales

on

either

the

horizontal-axis or

the

vertical-axis

1

No

response

or

incorrect

response

0

4551

o

2013 Hak

Cipta Bahagian

Pendidikan

Menengah

MARA

SULIT




36/43

SULIT

455U3

A].iSWER

SCI{EME

PAPER

3

TRIAI,

BIOI,OGY

2013

l(0

Able

to explain the

relationship

between

the

number of

laps and

the

rate

of heartbeat

based on

the following

aspect:

R

-

able

to

state the

relationship

El

-

able

to

explain

u y the

rate

of

heartbeat affected

by

the

number

of

round

EZ

-

able to

give

a

reason

Sample answer

,t

-

.

As the ntrmber

of laps increases

,

the

rate

of

heartbeat

increases,

,

,'

to

pump

more

blood

(into

circulation).Thefore

rate of cellular

respiration

increases//generate more energy/ATP

Note:

Rmustcotrect,..:

:. i.,.

.;.i.

.i

.,,..Rt,NryZBn

3

Able to interpret

the

relationship

incoppJetety

R'h

lE

,

2

Able to interpret

the

relationship at idea

lpvel,

,

R

only

I

No response or.incor.rect

response

0

No.

Mark Scheme

Score

1(e)

Able

to

define

the

heartbeat

rate

operationally

based on

the

result

of this

experiment.

Pl- Fact

classification

PZ

-

t:me taken

to

obtain

30 heartbeat

(RV)

// observation

P3

-

(RV)

influence

ll affected

by

MV)

Sample

answer :

The rate

of

heartbeat is

the

number

of

heartbeat

per

minute

(P1)

which

can be determine by time

taken to obtain

30

heartbeats

(P2),

and

it

is

affected

by the

number

of

laps

(P3).

All

PL,P2

and

P3

3

Any

two

correct

Any

2P

2

Any one

correct

Only

lP

I

No response

or incorrect

response

0

7

4551 @

2013 Hak

Cipta

Bahagian

Psndidikm

Menengalr MARA

SULIT




37/43

1

(ir)

Able to

predi.t

ttr.

.,

the

following

criteria:

Pl

:

The rate

of

heartbeat

will

be less

than

1.5

s'1.

P2

=

less

glucose

and

oxygen

is

transported

to the muscle

cells

/

tissues

P3= rate

of cellular respiration

decreases //less energy

is

producedi/

less

muscle

contractions.

Sample

answers

The

rate

of

his heartbeat

will be

Iess

than

1.5

s-1', because

less

glucose

and oxygen

is

transported

to the muscle.

Therefore the

rate

of cellular

respiration

decreases//,

less energy

is

produced//

less muscle

contractions

1

Able

to

predict

the

outcome

of the

experiment

incompletely

P+

1E

2

Able

to

predict

the outcome

of the

experiment

at idea

Ievel

P

only

1

No response

or incorrect

response

0

1

(i)

Able

to

classify

all

Samole answer

6

activities

correctly

J

Aerobic

resoiration

Anaerobic

Respiration

Archery

Watering

Plant

Walking

Sprinting

100m

Fermentation

in

yeast

Plant

in

waterlogged

condition

Able to list

4-5

condition

correctly

2

Able

to

list 2-3 condition

correctly

I

No

response

or

incorrect

response

0

SULIT

45sl13

ANSWER

SCI-IEME PAPER

3

TRJ,{L

BIOLOGY 2013

t)

E

t3)

t'l t

v

rD

(D


38/43

SULIT

ANIS ,ER

SCI{EI,,,{E

PAPER. 3

TRI,A..L

BIT}LOGY 2013

Graph

of

the rate

of

heartbeat

against the

number of

laps

45sU3

4551

a 2013

Hak Cipta

Bahagan Psndidikan

Meneng.ah

MARA

SULIT




39/43

s' :rLIT

Question

2

4s5113

,,].NS WER

SCI]E]V{E

P.\,PER 3

TR{AL BIOI,OGY 2013

No.

Mark

Scheme

Score

2(i)

Able

to

state the

problem

statement

relating

the manipulated

variable

with

the

responding

variable correctly

that

include criteria:

'

P

1-Manipulated

variables

-

Sources of

water

pollutiotr

X, Y and

Z

.

P2-Responding

variables Tirne to decolourise

methylene

blue

solution//level

of

water

pollution

'

P3-concrete

relationship

between

the

variables

in

question

form

and

question

symbol

[?]

Sample

answers:

1.

Does/Do

the

time

taken

for methylene

blue

solution

to

decolourise

(P2)is

the

shortest(P3)

in

source

XllY/lZ, compare

to

source

Y

and ZllX

and

ZllX

and

Y(Pl)?

2.

DoeslDo the water

sample

from

source

WlYllZ

is

the

most

polluted

compare to water sample

from

source

Yand

Z/lZ

andX/lX

and

Y?

3. DoeslDo

the

water

sample

from

source

XINI/Z is

the Ieast

polluted

compare

to

water

sample

from

source Yand ZllZ and )V/)(

and Y?

4. Do/Does

the time

taken

for

methylene blue solution to decolourisei/level

of

water

pollution

is

affected by

water sample from

source X,Y and

Z

?

5. What is the

level

of water

pollution

from

the

(source)

X,

Y andZ?

6.

DoeslDo

the level

of

water

pollution

from the

(source)

X,

Yand

Z

are

different?

Pl+P2+P3

J

Able

to

state a

problem

statement

inaccurately

Sample

answers:

l.DoeslDo

the level

of

water

pollution//time

taken

for

methylene blue

solution

to

decolourise

from

the

(source)Xll,Y

ll

Z is

the

lower//shorter?

Any

2P

2

Able

to state

a

of

problem

statement

at idea level

Sample answers:

DoeslDo the

level

of

water

pollution is different?

Any

lP

1

No

response or

incorrect

response

0

4551

O

2013 Hak Cipta Ilahagiiui

Pencliclika.n Menengalr

tvIARA

i0

SULIT




40/43

SI]LIT

4551/3

ANSWER SC}IEME

PAPER

3

TRIAL BIOLOGY

2013

No.

Mark

Scheme

Score

2(ii)

Able

to

state

the hypothesis

relating

the manipulated variable

to

the

responding variable correctly:

C2.

RV

C3

-

Clear/concrete

relationship

between

MV

and RV

(compare)

:

Sample

answers:

I

.The

water

sarrple

from

source

X

(C

1)

is

the most

polluted/

methylene

blue dgcolourise

faster/fastest

(C2)

compare/than

(C3)

to

Y

andZ

(C1)

(vice

funu)

2.T\e

water

sample

from

source

X(Cl)

is

the

most

polluted/

methylene

blue

decolourisation

is

the fastest.

.

r i..

'

r

r.l

cl

+

c2+c3

3

Able

to

state

a

liypothesis

inaccurately

Sample

answers:

The

water sample

from source X

(Cl)

is

polluted/

shows

faster

decolourisation

of

methylene

blue.

...(incomplete

CI)

Any

2C

,,,

^

2

Ableto

statethe

ideabfthe'hlpothesis.

'

I

:

':'

i

i'

r":

.i

';{

"i'

I

Sample

answers:

1. The

water

sample

from

sorlrce X(Cl)

is

polluted.

2.The

time

taken

for

methylene

blue solution to decolourise

decreases//increases

Any'1i

I

No response

or incorrect response

0

11

4551

@ 2013 Hak Cipta

Bahagian Pendidikan Menengah MARA

SULIT




41/43


42/43

SULIT

455y3

ANS\IER

SG{EME PAPER

3

TRIAT

BI{}LOGY

2OI3

N0.

Mark

Scheme

Score

2(v)

AbIe

to

describe

the

steps

of

the

experiment

procedure

or

method

K'S

1.

The reagent

bottles

ane

labelled

A,

B and

C Kl.

2.

The

water

samples

are

taken

from

three

different

source

of

X

(effluent

water),

Y

(tape

water)

and

Z(spring

water)

KI

3.

250

ml

of the

water

sample

from

source

A

is

measured

by using

the

measwgs,c.ylinder,

thgo

put,into p

fegge.nt

bottte labeiied

e

KI

KI

4.

By using

a

long needle

syringri,

aAd

f

ffi

of methylene

blqe

solution

at

the

bottom

of the

water sample

't

K1

K6

5.

Close

the

bofile immediately

to

prevent

atnospheric oxygen

from

dissolving

into the

water

samples

I

K6

6. do

not

shake

the

bottle

to

prevent

afinospheric

oxygen

from

dissolving

into

the

water

samples

K6

7 . Repeat

step

3

-

5

using

water

samples

Y

and Z K2

8.

Make dure'to

use

the

sarne amount

biwater

admpG in6eiy'--'

repeatedexperimeui

:'

'

i

:

'

''1

K4

9.

Keep the bottles

in the diik

place (ctipboard)

to

prevent

photosynthesis

being carried out by

algae

in

the

water

sample

and

start the stopwatch

K6

KI

10.

Observe

the

bottles

every

l0

minutes

K3

I

l. Measure

and record

the

time taken

for the methylene

blue to

decolor:rise

by using

a stopwatch

K3

12.

Tabulate

the data.

K5

Notes

:

Kl

:

Preparation

of materials

&

apparatus

K2

:

Operating

manipulated

variable

K3

:

Operating responding variable

K4

: Operatingfixed

variable

K5:

Data

communication

Kd

: Precaution

Note:At

least

4Kl

Able

to

state

all

6K

AbIetort t.4-5K

3

2

Abletoltfte2-3K

_.

Able

to state lK or

no response

or incorrect

response

I

0

4551

@ 2013

Hak

Cipta

Bahagian

Pendidikan

Menengah MARA

13

SULIT




43/43

No.

Mark

Scheme

Score

2(vi)

Able

to

construct a

table

to record data based

on the

following

criteria:

C 1 :

Manipulated variables

with

parameter

and unit

C2:

Operating

responding

variables

and

responding

variables

with

unit

Sample

answers:

Source

of

water

samples

Time

taken

for

methylene

blue

solution

to decolourise

(hours)

or

(days)

Level

of

water

pollution

x

Y

Z

or

Source

of

water

samples

Time taken

for

methylene

blue

solution

to

decolourise

(hours)

or

(days)

Level

of

water

pollution

1

2

a

J

4

Average

x

Y

Z

2

SULIT

ANSWER.

SCI-IEME

PAPER

3

TRIAL

BIOLOG'Y

2 I3

free

Q

papsrs,

free

skenra ai

.

wwyu.myschr:olchildren.conr

45sll3

skema biology paper 123 trial spm 2013 mrsm del jsu

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