rangkaian resistor seri vad = vab + vbc + vcd ir tot = ir1 + ir2 + ir3 r tot = r1 + r2 + r3 paralel...
TRANSCRIPT
Rangkaian resistor
Seri
Vad = Vab + Vbc + VcdIRtot= IR1 + IR2 + IR3 Rtot= R1 + R2 + R3
Paralel
Vab = IRtot
IRtot= I1R1 + I2R2 + I3R3I = I1 + I2 + I3Vab/Rtot = Vab/R1+Vab/R2+Vab/R3
1/Rtot= 1/R1 + 1/R2 + 1/R3
V
R1 I1
R2 I2
R2 I3
I
a b
a b c d
R1 R2 R3
I
V
Resistor21. Hukum Ohm : i
R
P
Q
V
+
-
VPQ = I * R
Series
Resistor2
The First principle to understand about series circuits is that the amount of current is the same through any component in the circuit. This is because there is only one path for electrons to flow in a series circuit. The second principle of series circuits: the total resistance of any series circuit is equal to the sum of the individual resistances. The third principle of series circuits: that the supply voltage is equal to the sum of the individual voltage drops.
Ilustrasi (ibiblio p136)
Parallel
Resistor2
Ilustrasi (ibiblio p142)
The First principle to understand about parallel circuits is that the voltage is equal across all components in the circuit. This is because there are only two sets of electrically common points in a parallel circuit, and voltage measured between sets of common points must always be the same at any given time.
The second principle of parallel circuits: the total circuit current is equal to the sum of the individual branch currents.
The third principle of parallel circuits: Resistances diminish to equal total resistance.
Simpulan
Resistor2
Series Circuits:1.Voltage drops add to equal total voltage.2.All components share the same (equal) current.3.Resistances add to equal total resistance. Parallel Circuits:1.All components share the same (equal) voltage.2.Branch currents add to equal total current.3.Resistances diminish to equal total resistance.
Series Parallel CircuitIlustrasi Ibiblio (200)
Ilustrasi Teknik Pengukuran dengan Voltmeter dan Amperemeter
i1
R
P
Q
S
10V 2 ohm
VQP = 10V; VPQ = -10V
VRS = 10V; VSR = -10V
VQR = 0V; VRQ = 0V
VRP = 10V; VSQ = -10V
VSP = 0V; VPS = 0V
I1 = VRS / 2 ohm = 5 A ; I2 = VSR / 2 ohm = -5A
i2
Resistor2
AAmpere meter
V
Volt meter
2. Hukum Khhircoff 1:
i3
B
F
A
E
10V5 ohm
Loop I (Loop ABEF)
VAF + VBA + VEB + VFE = 0
10 V - i1*2 + (i2-i1)*5 + 0 V = 0
VBE + VCB + VDC + VED = 0
-(i2-i1)*5 + 0 V - i2*7 + 0 = 0
10 V - i1*2 + (i2-i1)*5 = -(i2-i1)*5 - i2*7
i2
2 ohm
7 ohm
C
D
i1
I IILoop II (Loop BCDE)
i3 = (i2-i1)
Resistor2
2. Hukum Khhircoff 2:
This principle is known as Kirchhoff's Voltage Law (discovered in 1847 by Gustav R. Kirchhof, a German physicist), and it can be stated as such:
"The algebraic sum of all voltages in a loop must equal zero"
Kirchhoff's Current Law reads as such:"The algebraic sum of all currents entering and exiting a node must equal zero"
3. Daya Listrik :
i
R
P
Q
V
+
-
PR = I2 * R
P = VPQ*I
W = watt =J/dt = 0,24 cal/dt
Ilustrasi:Resistor akan mengambil daya I2*R = 50 watt dikonversikanmenjadi panas, atau sebesar 12 cal tiap detikJika arus dialirkan selama dua detik, maka energi yang mengalirpada resistor adalah E = P*t = 100 joule = 24 cal
5A
2 ohm
Resistor2
4. Rugi daya :Sifat kabel transmisiR = f (D,L,ρ) → sifat hambatan kabel merupakan fungsi diameter,
panjang dan hambatan jenis
R = ρ L/A
AC
L
induktansi
Rugi Daya
Daya BebanDaya Input
Ilustrasi:
Daya Input = Rugi Daya + Daya Beban100 V
L
50 0hm
200W/100V
Hitung daya input pada rangkaian disamping:Hint: tentukan R lampu, hubungkan seri, tentukan arus, hitung rugi dayaTentukan daya input
Resistor2
Prinsip sekringFuse sebagai kawat penghantar: jika D ↓ maka R ↑ sehingga dengan I ↑terjadi rugi daya ↑ maka suhu penghantar ↑ panas shg sekring melebur dan hubungan terputus
Resistor2
A fuse is nothing more than a short length of wire designed to melt and separate in the event of excessive current. Fuses are always connected in series with the component(s) to be protected from overcurrent, so that when the fuse blows (opens) it will open the entire circuit and stop current through the component(s). A fuse connected in one branch of a parallel circuit, of course, would not affect current through any of the other branches.