paper 3b zulaili guru1
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Paper 3
Zulaili Yaacob&
Mohamad Hussaini
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SECTION A : Question 1
1(a)(i) Manipulated variable : ____________________
1(a)(ii) Responding variable : ____________________
1(a)(iii) Constant variable : ____________________
EXAMPLE:
A student carries out an experiment to investigate the relationship
between temperature, , and the volume, V, of trapped air. A beaker
is filled with cold water until the air column in the capillary tube is
totally immersed. A thermometer is put into the water to determine
the temperature of the water. The arrangement of the apparatus for
the experiment is shown in Figure 11.1.
Temperature,
Volume, V
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SECTION A : Question 1
1(a)(i) Manipulated variable : ____________________
1(a)(ii) Responding variable : ____________________
1(a)(iii) Constant variable : ____________________
1
2
0
l
1
Figure 11.2:
Temperature, = 30 C
length, l= cm
m.v
r.v
Temperature,
Length, l
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SECTION A : Question 1
1(a)(i) Manipulated variable : ____________________
1(a)(ii) Responding variable : ____________________
1(a)(iii) Constant variable : ____________________(depends on the experiment)
Which of the following is possibly a constant variable?
A) Mass B) Thermometer C) Air
A) Water B) Stopwatch C) Time
A) Length B) Air column C) Ruler
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SECTION A : Question 1
1(b) Based on Figures 11.2, 11.3, 11.4, 11.5, and 11.6, determine l
when is equal to 30 C, 35 C, 40 C, 45 C and 50 C.
Tabulate your results for l and Vfor each value of in the space below.
/ C l / cm V / cm3
30
35
40
45
50
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SECTION A : Question 1 Spot the errors
t1 t
2 t
mean T T2 l
17 17.6 17.3 0.87 0.76 20
22.4 22 22.2 1.11 1.23 30
25 24.6 24.8 1.24 1.54 40
28 28.8 28.4 1.42 2.02 50
30.8 31 30.9 1.55 2.4 60
No unit!
Not consistence!
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SECTION A : Question 1 Spot the errorsUnit at the wrong place!
l t1 t
2 t
mean T T2
20.0 cm 17.0 s 17.6 s 17.3 s 0.87 s 0.76 s2
30.0 cm 22.4 s 22.0 s 22.2 s 1.11 s 1.23 s2
40.0 cm 25.0 s 24.6 s 24.8 s 1.24 s 1.54 s2
50.0 cm 28.0 s 28.8 s 28.4 s 1.42 s 2.02 s2
60.0 cm 30.8 s 31.0 s 30.9 s 1.55 s 2.40 s2
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SECTIONA : Question 1 Spot the errorsWrong unit!
Not consistence!
l/ cm t1/ s t
2/ s t
mean/ s T/ s T2/ s
20.0 17.0 17.6 17.3 0.865 0.748
30.0 22.4 22.0 22.2 1.11 1.232
40.0 25.0 24.6 24.8 1.24 1.537
50.0 28.0 28.8 28.4 1.42 2.016
60.0 30.8 31.0 30.9 1.545 2.387
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SECTION A : Question 1 Spot the errors!
No error!
l/ cm t1/ s t
2/ s t
mean/ s T/ s T2/ s2
20.0 17.0 17.6 17.3 0.87 0.76
30.0 22.4 22.0 22.2 1.11 1.23
40.0 25.0 24.6 24.8 1.24 1.54
50.0 28.0 28.8 28.4 1.42 2.02
60.0 30.8 31.0 30.9 1.55 2.40
GOOD ANSWER!
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SECTION A : Question 1
BAD GRAPH!
GOOD GRAPH!
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SECTION A : Question 1
What is a GOOD graph?
1) Starting at origin (0,0)
2) Write quantitiesand units on x-axis
and y-axis
3) Has uniform scale
4) All points are transferred correctly
5) Draw onestraight line and intersect
any of the axes
6) Distribute other points equally
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SECTION A : Question 1
Accepted graph
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SECTION A : Question 1
Rejected graph
more than 1 cm
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SECTION A : Question 1
Rejected graph
more than 0.5 cm
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SECTION A : Question 1
Conclusion
a
b
A) a is inversely proportional to b
B) a is directly proportional to b
C) a is linearly increasing with b
a
b
A) a is inversely proportional to b
B) a is directly proportional to b
C) a is linearly increasing with b
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SECTION A : Question 1
Conclusion
A) a is inversely proportional to b
B) a is directly proportional to b
C) a is linearly increasing with b
A) a is inversely proportional to b
B) a is directly proportional to 1/b
C) a is linearly increasing with 1/b
a
b
a
1/b
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SECTION A : Question 2
2(a)(i) Relationship
A) a is inversely proportional to b
B) a is directly proportional to b
C) a is linearly increasing with b
A) a is inversely proportional to bB) a is directly proportional to 1/b
C) a is linearly increasing with 1/b
a
b
a
1/b
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SECTION A : Question 2
2(a)(i) Relationship
a
b
A) a is inversely proportional to b
B) a is directly proportional to b
C) a is linearly increasing with b
a
b
A) a is inversely proportional to b
B) a is directly proportional to b
C) a is linearly increasing with b
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SECTION A : Question 2
2(a)(ii) Determine Corresponding Value
h/ cm
P/ Nm-2
1.0 2.0 3.0
1.0
2.0
3.0
4.0P = 4.0 Nm-2
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SECTION A : Question 2
2(a)(ii) Determine Corresponding Value
1/m/ g-1
/ C
0.1 0.2 0.3
1.0
2.0
3.0
4.01/m = 0.3 g-1
m = 3.3 g
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SECTION A : Question 2
2(b)(i) Determine Gradient
1/m/ g-1
/ C
0.1 0.2 0.3
1.0
2.0
3.0
4.0
Gradient, m = 4.0 C
0.3 g-1
m = 13.33 C g
y
x
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SECTION A : Question 2
2(b)(ii) Calculation problem (involving the gradient)
Reminder!
1) Use the value of gradient obtained in previous
question
2) Check for the conversion of units
3) Substitute figures at the correct places
4) Write the final answer in decimal number (Do
not give the answer in fraction!!!)
5) Do not forget the UNIT
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SECTION A : Question 2
2(c) Calculation problemReminder!
1) Check for the conversion of units
2) Substitute figures at the correctplaces
3) Write the final answer in decimal number
(Do not give the answer in fraction!!!)
4) Do not forget the UNIT
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SECTION A : Question 2
2(d) Precaution
Reminder!
1) It is NOT SAFETY PRECAUTION!!!
Take few readings and find the average toreduce random error
Position of eyes is perpendicular to the
scale to avoid parallax error
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Paper 3
Section B
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Variables : Air pressure , Temperature.Manipulated :Responding :
Constant :
temperature
Air pressure
Volume of air
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inference
MV affects RV
affectstemperatureair pressure
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hypothesis
When
increases, ,
increases
Temperature
Air pressure
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aim
To investigate therelationship between
andtemperature
pressure
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Method of controlling manipulated
variable
Manipulate variable : temperature
control : the first temperature
Heat up the water to 20 0C
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Method of measuring responding
variable
Responding variable : pressure
Measure pressure using : Bourdon gauge
Using Bourdon gauge , measure the
pressure and record the data
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Analyse data
Temperature / K Pressure / Nm-2
20
30
40
50
60
Graph
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Graph
Temperature / K
Pressure / Nm-2
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i bl
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variables
Manipulated :
Responding :
Constant :
length
resistance
diameter
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inference
_ affectslength
resistance
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hypothesis
When increases,
, increases
length
resistance
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aim
To investigate the relationship between
andlengthresistance
M h d f lli i l d
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Method of controlling manipulated
variable
Manipulated variable : length
Control : the first length : 15 cm
Measu re 15 cm leng th o f w ire and
connect both end at po int A and B
M h d f i di
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Responding variable : resistance
Measure potential difference using :
Method of measuring responding
variable
Measure potential difference using
volmeter and calculate the resistance.Record data
voltmeter
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Analyse dataLength / cm Potential difference / V Resitance /
15
20
25
30
35
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Length
Resistance
cm
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Cuba soalan muka surat 5
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