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    SEKOLAH MENENGAH KEBANGSAAN AGASEH

    PEPERIKSAAN PERTENGAHAN TAHUNTINGKATAN EMPAT 2010

    MATEMATIK

    Kertas 2

    Dua jam tiga puluh minit

    Pemeriksa

    Bahagian SoalanMarkah

    Penuh

    Markah

    Diperoleh

    A

    1 5

    2 3

    JANGAN BUKA KERTAS SOALAN INI

    SEHINGGA DIBERITAHU

    1. Kertas soalan ini mengandungi dua bahagian :Bahagian A dan Bahagian B. Jawab semuasoalan daripada Bahagian A dan empat soalan

    dalam Bahagian B.

    2.Jawapan hendaklah ditulis dengan jelas dalam

    ruang yang disediakan dalam kertas soalan.Tunjukkan langkah-langkah penting. Ini bolehmembantu anda untuk mendapatkan markah.

    3.Rajah yang mengiringi soalan tidak dilukismengikut skala kecuali dinyatakan.

    4.Satu senarai rumus disediakan di halaman 2 & 3

    5.Anda dibenarkan menggunakan kalkulatorsaintifik yang tidak boleh diprogram.

    3 4

    4 5

    5 5

    6 4

    7 7

    8 4

    9 5

    10 5

    11 5

    B

    12 12

    13 12

    14 12

    15 12

    Jumlah

    SULIT

    1449/2

    Matematik

    Kertas 2

    Mei 2010

    2

    12 jam

    1449/2

    NAMA :

    TINGKATAN :

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    Kertas soalan ini mengandungi 22 halaman bercetak

    MATHEMATICAL FORMULAE

    The following formulae may be helpful in answering the questions. The symbols given are the onescommonly used.

    RELATIONS

    1 am x an = a m+ n

    2 am an = a m n

    3 ( am )n = a mn

    4 A-1

    = bcad

    1

    ac

    bd

    5 P ( A ) =)(

    )(

    Sn

    An

    6 P ( A ) = 1 P(A)

    7 Distance = 2 21 2 1 2( ) ( )x x y y +

    8 Midpoint, (x, y ) =

    ++

    2,

    2

    2121 yyxx

    9 Average speed =

    10 Mean =

    11 Mean =

    12 Pythagoras Theorem

    c2 = a2 + b2

    13 m =12

    12

    xx

    yy

    14-intercept

    -intercept

    ym

    x=

    1449/2 SULIT2

    1449/2 [Lihat sebelah

    SULIT

    distance travelled

    time takensum of data

    number of data

    sum of (class mark frequency)

    sum of frequencies

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    SHAPES AND SPACE

    1 Area of trapezium =2

    1 sum of parallel sides height

    2 Circumference of circle = d= 2 r

    3 Area of circle = r2

    4 Curved surface area of cylinder = 2 rh

    5 Surface area of sphere = 4 r2

    6 Volume of right prism = cross sectional area length

    7 Volume of cylinder = r2

    h

    8 Volume of cone =3

    1 r2h

    9 Volume of sphere =3

    4 r3

    10 Volume of right pyramid =3

    1 base area height

    11 Sum of interior angles of a polygon = ( n 2) 180

    12arc length angle subtended at centre

    circumference of circle 360=

    o

    13area of sector angle subtended at centre

    area of circle 360=

    o

    14 Scale factor , k=PA

    PA '

    15 Area of image = k2 area of object

    1449/2 [Lihat sebelah

    SULIT

    3

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    Answerall questions.

    1. (a) (b)4.13

    [5 marks]

    Answer :

    (a)

    (b) (i)

    (ii)

    2 If = {x : 1 x 10 , x is an integer}

    E= {x :x is a multiple of 4}

    F= {x :x is a factor of 20}

    (a) List all the elements in setE,

    (b) Find ( )n E F .

    1449/2 SULIT4

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    [3 marks]

    Answer :

    (a)

    (b)

    3 The Venn diagrams in the answer space show sets P, Q andR. Given thatP Q R.

    On the diagram provided in the answer space, shade the region which represents the set

    (a) (Q R)',

    (b) P' (R Q').

    1449/2 [Lihat sebelah

    SULIT

    5

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    [4 marks]

    Answer :

    (a) (b)

    4

    Diagram 1

    1449/2 SULIT6

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    In Diagram 1 , O P Q R is a parallelogram and O is the origin. Find

    (a) the gradient of the straight line QR,

    (b) the equation of the straight line PR,

    (c) the coordinates of the point Q .

    [5 marks]

    Answer :

    a)

    b)

    c)

    5 (a)State whether the following statement is true or false.

    3 33 9 or 8 2= =

    (b) Write down two implications based on the sentence below.

    The inverse matrix of a 2 2 matrix exists if and only if the determinant is 0

    (c) Given the number sequence 3, 8, 15, 24, .. and

    1449/2 [Lihat sebelah

    SULIT

    7

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    3 = 1 2 + 2(1)

    8 = 2 2 + 2(2)

    15 = 3 2 + 2(3)

    24 = 4 2 + 2(4)

    Make a general conclusion by using the induction method for the numerical

    sequence above.

    [5 marks]

    Answer :

    (a)

    (b)

    (c)

    6 Calculate the value of v and of w that satisfy the following simultaneous linearequations:

    3 4 8

    28 4

    3

    + =

    =

    v w

    v w

    [4 marks]

    Answer:

    1449/2 SULIT8

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    .

    7 In Diagram 2,PQ andRSare parallel to thex-axis andPSis parallel toRT.

    1449/2 [Lihat sebelah

    SULIT

    9

    xO

    P Q (5,5)

    R (h, 4) S(3,4)

    T

    DIAGRAM 2

    y

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    Find the

    (a) equation of the linePQ,

    (b) gradient of the linePS,

    (c) value of h, hence, find the equation of lineRT.

    [7 marks]

    Answer:

    (a)

    (b)

    (c)

    8 Solve the quadratic equation )1(22

    )3(3xx

    xx

    +=+

    [4 marks]

    Answer:

    1449/2 SULIT10

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    9 (a) Find the value of

    85

    102109

    and express the answer in standard form.(b) Express 2.8410-4 as a single number.(c) Calculate the value of 60.12 0.382 0.01, correct to three significant figures.

    [5 marks]

    Answer :

    (a)

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    11

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    (b)

    (c)

    10

    Diagram 3 shows the frequency polygon of the

    marks of a group of students in a test.

    (a) State the modal class and the frequency of

    the modal class.

    (b) Calculate the mean mark.

    12 15 18 21 24 27

    30 33

    Marks

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    Diagram 3

    [5 marks]

    Answer:

    (a)

    (b)

    11

    Diagram 4 shows the number of

    students who like to play three games. Given = A

    B C, set A = {students who like to play

    badminton}, set B = {students who like to play

    tennis} and set C {students who like to play

    squash }. State the number of students who

    (a) like to play all the three games,

    1449/2 [Lihat sebelah

    SULIT

    13

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    (a) like to play badminton and squash only,

    (b) like to play one game only.

    Diagram 4

    [5 marks]

    Answer:

    (a)

    (b)

    (c)

    Section B

    [48 marks]

    Answerall questions in this section.

    1449/2 SULIT14

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    12. (a) Write down two implications based on the following sentence.

    k3= 216 if and only ifk = 6.

    (b) State whether the following statements are true or false.

    (i) 743 = or 1046 = .

    (i)2

    1= 0.5 and 87 is a prime number.

    (c) Complete the premise in the following argument.

    Premise 1 : Alleven numbers are divisible by 2.

    Premise 2 : ______________________________

    Conclusion : 36 is divisible by 2. [4 marks]

    Answer: (a)

    (b) (i)

    (ii)

    (c)Premise 2: ____________________________________________

    13 (a) Solve each of the following quadratic equations.

    (i) 15

    62

    =

    +x

    x

    (ii) xx

    612

    =

    [6 marks]

    Answer:

    1449/2 [Lihat sebelah

    SULIT

    15

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    (a) (i)

    (ii)

    (b)

    Diagram 4

    In Diagram 4,PQR is a right-angled triangle. If the area of the shaded region is 40 cm2,

    1449/2 SULIT16

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    find the value ofx.

    [6 marks]

    Answer:

    (b)

    14 The data in Table 1 shows the mass, in kg, for 50 students.

    49 54 76 59 55 50 70 70 65 62

    45 76 51 63 58 51 63 55 68 67

    53 79 46 69 76 64 57 71 63 63

    64 45 57 72 55 71 61 60 70 65

    56 66 67 52 65 75 60 57 67 54

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    SULIT

    17

    TABLE 1

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    (a) Construct a grouped frequency table for the data using class intervals 45 49,

    50 54 and so on.

    [3 marks]

    Answer:(a)

    Mass(kg) Midpoint Frequency45 49

    50 54

    (b) Using a scale of 2 cm to 5 kg on the horizontal axis and 2 cm to 1 student on the

    vertical axis, draw a frequency polygon for the above data.

    [5 marks](c) Use the frequency polygon to

    (i) find the modal class

    (ii) calculate the mean mass of the students.

    [4 marks]

    Answer:

    (b) Refer graph on page 19

    (c) (i)

    (ii)

    1449/2 SULIT18

    Graph for Question 14

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    5 (a) Table 2 shows the number of books read by 45 students in a class.

    Books read by the

    student

    0 1 2 3 4 5 6 7 8

    No of students 16 5 6 5 6 4 0 1 2

    Find

    (i) the median,

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    19

    TABLE 2

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    (ii) the mean.

    [4 marks]

    Answer:

    (a) (i)

    (ii)

    (b) Table 3 in the answer space shows the marks scored by 200 candidates in a test.

    (i) Complete Table 3 by filling in the cumulative frequencies.

    [2 marks]

    (ii) By using a scale of 2 cm to 10 marks on the x-axis and 2 cm to 20candidates on they-axis, draw an ogive for the given data.

    [4 marks]

    (iii) Candidates in the first quartile must sit for the examination again.

    What is the highest mark for the candidates who reseat the

    examination?

    [2 marks]

    Answer:

    (b) (i)

    Marks CandidatesCumulative

    Frequency

    11 20 18

    21 30 22

    31 40 3541 50 43

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    51 60 30

    61 70 23

    71 80 21

    81 90 8

    (ii) Refer graph on page 22.

    (iii)

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    21

    TABLE 3

    Graph for Question 15

    END OF QUESTION PAPER

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