maths spm paper 2

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SULIT 1449/2(GMP) 1449/2 Mathematics (P) Kertas 2 Peraturan Pemarkahan 2011 PERCUBAAN SPM 2011 PAHANG D.MAKMUR MATHEMATICS Kertas 2 PERATURAN PEMARKAHAN UNTUK KEGUNAAN GURU MATA PELAJARAN SAHAJA

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Page 1: Maths SPM Paper 2

SULIT 1449/2(GMP)1449/2 Mathematics (P)Kertas 2 PeraturanPemarkahan2011

PERCUBAAN SPM 2011PAHANG D.MAKMUR

MATHEMATICS

Kertas 2

PERATURAN PEMARKAHAN

UNTUK KEGUNAAN GURU MATA PELAJARAN SAHAJA

Peraturan pemarkahan ini mengandungi 15 halaman bercetak [Lihat sebelah

1449/2(GMP) © 2011 Hak Cipta MPSM Pahang

1 1449/2(GMP)

Page 2: Maths SPM Paper 2

Question Solution and Mark Scheme Marks

1 (a)

(b)

Note:

' correctly shaded, award K1

K1

K2

3

1449/2(GMP) © 2010 Hak Cipta JUJ Pahang

P Q R

P Q R

P Q R

Page 3: Maths SPM Paper 2

3 1449/2(GMP)

Question Solution and Mark Scheme Marks

2

3

4

+ =1232

h = 10

TPQ or QPT

Tan = or equivalent

56 .31 o or 56o 19

(a) (i) and (ii) or

(b) (i) If 3p > 12 , then p > 4 (ii) If p > 4 , then 3p > 12

(c) 2n3 – 3 where n = 3, 4, 5, 6, …

Note :

2n3 – 3 only 2n3 – 3 n = 3, 4, 5, ….. award K12n3 - 3 n= 1,2,3,4 ,…

K1

K1

K1

N1

P1

K1

N1

P1P1

P1P1

K1N1

4

3

6

Page 4: Maths SPM Paper 2

1449/2 © 2011 Hak Cipta MPSM Pahang 4

1449/2

Question Solution and Mark Scheme Marks

5

6 (a)

(b)

or or equivalent

Note Attempt to equate the cooficence one the unknowns, award K1

or or equivalent

OR

or equivalent

(K2)

Note:

as final answer, award N1

or or equivalent

or equivalent

K1

K1

N1

N1

P1

P1K1

N1

K1

N1

4

6

Page 5: Maths SPM Paper 2

1449/2(GMP) © 2011 Hak Cipta MPSM Pahang 5 1449/2

Question Solution and Mark Scheme Marks

7

8

or equivalent

OR

K1

or 1.5

Note:

1. Accept without “ = 0”.

2. Accept three terms on the same side, in any order.

3

4. Accept answer from three correct term without factorisation for Kk2.

p = – 11

q = 1

Note:

or award P1

K1

K1

N1

N1

P2

P1

P1

4

Page 6: Maths SPM Paper 2

9 (a)

(b)

or

Note:

1 . Do not accept or

.

2 . as final answer, award N1 .

3 . Do not accept solutions solved not using matrix method.

or

+

93.33 cm2

or

+ + ( 14 + 14 +

14+14)

85.33 cm

Note: 1 . Accept for K mark. 2. Correct answer from incomplete working, award Kk2

K1

N1N1

K1

K1

N1

K1

K1

N1

6

[Lihat sebelah1449/2 © 2011 Hak Cipta MPSM Pahang 7 1449/2

6 1449/2

1449/2 © 2011 Hak Cipta MPSM Pahang

Page 7: Maths SPM Paper 2

Question Solution and Mark Scheme Marks

10(a)

(b)

(c)

11(a)

(b)

{ MA, MT, MH, MS,AM, AT, AH, AS, TM, TA, TH, TS, HM, HA, HT, HS, SM, SA, ST, SH } Note : Two wrong listing award P1

{ AM, AT, AH, AS }

=

{ MT, MH, MS, TM, TH, TS, AM, AT, AH, AS, HM, HT, HS, SM, ST, SH }

= or

=

Note:

or award K1

P2

K1

N1

K1

N1

K1

N1

K2

N1

6

5

Page 8: Maths SPM Paper 2

1449/2 © 2011 Hak Cipta MPSM Pahang

8 1449/2

Question Solution and Mark Scheme Marks

12(a) (i)

(ii)

(iii)

(b)(i)(a)

(b)

(ii)

(7, 7 ) (2, 8)

(9, 4)

Note: point (9, 4) marked or ((3 , 0) seen or (3, 0) marked , award P1

V : Reflection in the line x = 2 Note:

1. P1 : reflection

W : Enlargement centre A or (1, 1) with scale factor 2 Note:

1. P2: Enlargement centre N or Enlargement scale

factor

2. P1: Enlargement

- 18

= 54

7

Page 9: Maths SPM Paper 2

1449/2 © 2011 Hak Cipta MPSM Pahang 9 1449/2

Question Solution and Mark Scheme Marks

13(a)

(b)

(c)(i)

(ii)

(d)

6.67

-13.33

Graph

Axes drawn in correct directions uniform scale for and All 7 points and *2 points correctly plotted or the curve passes through these points for and

. A smooth and continuous curve without any straight line and passes through all 9 correct points using the given scale for and . Note: 1. 7 or 8 points correctly plotted, award K1 2. Ignore curve out of range.

Note: 1. Allow P marks if values of x and of y are shown on the graph. 2. Values of x and y obtained by calculation, award P0 Or from wrong graph, award P0

Identify equation or Straight line correctly drawn Values of x :

, Note: 1. Allow N marks if values of x are shown on the graph. 2. Values of x obtained by calculation, award N0

K1

K1

P1

K2

N1

P1

P1

K1

K1

N1N1

2

4

2

4

Page 10: Maths SPM Paper 2

12

[Lihat sebelah1449/2 © 2011 Hak Cipta MPSM Pahang

10 1449/2

-4 -3 -2

5

10

15

-1

20

1 2 3

y

40

---5

10

-15

-20

Page 11: Maths SPM Paper 2

11 1449/2

Question Solution and Mark Scheme Marks

14(a)

(b)

(c)

Class interval Frequency Midpoint15 - 19 3 17

20 - 24 7 22

25 – 29 15 27

30 – 34 11 32

35 - 39 7 37

40 - 44 12 42

45 - 49 5 47

Class Interval : (II to VII Frequency : (I to VII)

Midpoint : (I to VII) Note: Allow one mistake in frequency for P1.

25 - 29

Mean =

= 32.67

Refer graph on page

Axes drawn in correct direction, uniform scale for and

* 7 bars correctly drawn

Note: 5 or 6 bars correctly drawn , award K1

P1

P2

P1

P1

K2

N1

P1

K2

N1

4

3

4

1449/2 © 2011 Hak Cipta MPSM Pahang

III

IV

V

II

VI

I

VII

Page 12: Maths SPM Paper 2

Any correct information from the histogram drawn N1 112

[ Lihat sebelah1449/2 © 2011 Hak Cipta MPSM Pahang SULIT

Graph for Question 14 Graf untuk Soalan 14

1449/2 © 2011 Hak Cipta MPSM Pahang

Money spent17 22 27 32 37 42 47

2

4

6

8

14

10

12

16

frequency

Page 13: Maths SPM Paper 2

[Lihat sebelah13 1449/2

Question Solution and Mark Scheme Marks

15(a)

Correct shape with rectangle PQRT and semicircle RST . All solid lines.

PQ < QR Measurements correct to ± 0.2 cm (one way) and P, Q , = 90o ± 1o

K1

K1

N1 3

P Q

RT

S

Page 14: Maths SPM Paper 2

Question Solution and mark scheme marks

15(b)(i)

(ii)

Correct shape with rectangles APED and PQVQ All solid lines. AP = PQ < QV . EV < UV Measurements correct to ± 0.2 cm (one way) and All angles at vertices of rectangles = 90o ± 1o

K1

K1

N2 4

1449/2 © 2011 Hak Cipta MPSM Pahang

14 1449/2

A P Q

D E

U V

QR

WV

S

X

E F

E F

Page 15: Maths SPM Paper 2

16

(b)

(c)

(d)(i)

(ii)

Correct shape with rectangles QRWV and RSXW All solid lines.( Ignore PE and EF) Correct trapezium PTFE with PE and EF dashed line

QR >QV >RS , RF =FW

Measurements correct to ± 0.2 cm (one way) and All angles at vertices of rectangles = 90o ± 1o

25o E

Note: 25o or , award P1

Location of Z ( 60o S, 25o E )

(180 – 60 - 60) × 60 3600 nm

Distance =

= 3900 nm

3900 =

Longitude P =

=

K1

K1

K1

N2

P2

P1

N1N1

K1

K1

K1

N1

K1

K1N1

5

12

2

3

2

5

12

X

Z

END OF MARK SCHEME

15 1449/2

Page 16: Maths SPM Paper 2

1449/2 © 2011 Hak Cipta MPSM Pahang