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CONFIDENTIAL

3472/1

3472/1 NO. KAD PENGENALAN

Matematik

Tambahan

ANGKA GILIANPa!e" 1

#e!tembe"

2$$4 %A&ATAN PENDIDIKAN #A&A'

2 (am

)%IAN #ETAA #EPTEM&E 2$$4

ADDITIONAL MATHEMATICS

PAPER 1 Dua jam

%ANGAN &)KA KETA# #OALAN INI

#E'INGGA GI*EN T'ATTA')

1. Tuliskan angka giliran and nombor kad !ng!nalan anda ada ruang "ang

dis!diakan.

#. Calon dik!$!ndaki m!mba%a ara$an di

$alaman # .

&. '!r(as soalan ini $!ndakla$ dis!ra$kan di

ak$ir !!riksaan.

'!r(as soalan ini m!ngandungi 1) $alaman b!r%!(ak.

3472/1 +Lihat #ebe,ah

Kod Pemeriksa

Soalan

Marks

P!nu$

Marks

Di!rol!$1 #

# *

& *

* &

+ *

) &

, &

- *

&

1/ &

11 &1# &

1& &

1* *

1+ &

1) &

1, &

1- #

1 &

#/ &

#1 *

## *

#& &

#* &

#+ &

%-m,ah



CONFIDENTIAL

3472/1

Rumus0rumus b!riku( bola$ m!mban(u anda m!njaab soalan. Simbol0simbol "ang gi2!n ($a( is

"ang biasa digunakan.

ALGE&A

1a

a)bb /

#

*# −±−= -

a

bb

)

)

alog

loglog =

# nmnmaaa

+=× d na! n 314 −+=

& nmnmaaa

−=÷ 1/ 5314#6#

d nan

% n −+=

* mnnm

aa =34 11 1−= n

n ar !

+ nmmn aaa logloglog += 1# 17

1

314

1

314≠

−

−=

−

−= r

r

r a

r

r a%

nn

n

) nmn

maaa logloglog −= 1& 7

1 r

a%

−=∞ 1<r

, mnm a

n

a loglog =

KALK)L)#

1d/

du0

d/

d0u

d/

dyu0 y +== 7 * Luas di baa$ l!ngkung

8 ∫ b

a

y d/ a(au

##

70

d/

d0u

d/

du0

d/

dy

0

u y

−== 8 ∫

b

a

/ dy

+ Isiadu janaan

&d/

du

du

dy

d/

dy×= 8 ∫

b

a

y#

π d/ a(au

8 ∫ b

a

/#

π dy

3472/1

CONFIDENTIAL

CONFIDENTIAL

3472/1

&



#TATI#TIK

1 1

/ / ∑= , ∑

∑=i

ii

2

# 2 #

# ∑∑= .

/. / - 394

9

r n

n P r n

−=

& #

##34 /

1

/

1

/ /−=

−= ∑∑

σ 9394

9

r r n

n3 r

n

−=

* #

##34

/ .

./

.

/ / . −=

−=

∑∑

∑∑

σ 1/ 34343434 B A P B P A P B A P ∩−+=∪

+ 3 .

4 1

5mm

3#

1

4

−+= 11 1734 =+== −

6 p6 p3 r 7 P r nr

r

n

) 1//1

×=o8

8 # 1# Min 8 np

1& np6=σ

1*σ

µ −= /

9

GEOMETI

1 :arak 8 #

#1

#

#1 3434 y y / / −+−

# Ti(ik (!nga$ 4; 7 " 3 8

++#7#

#1#1 y y / /

& Ti(ik "ang m!mba$agi sua(u (!mb!r!ng garis

++

++

=nm

myny

nm

m/n/ y / #1#1 7374

* Luas s!gi(iga 8 3434#

1&1#&1#1&&##1 y / y / y / y / y / y / ++−++

+ ## y /r +=

) ##<

y /

j yi /r

+

+=

3472/1

CONFIDENTIAL

CONFIDENTIAL

3472/1

TIGONOMETI

*



1 Panjang l!ngkok 7 θ j s =

# Luas s!k(or 7 θ #

#

1 j 5 =

& 1sin ##

=+ Akos A

* A A sek ## (an1+=

+ Akot Akosek ## 1+=

) A A sin##sin = kos A

, A Akos Akos ##

sin# −= 8 1# # −kos

8 1 = # sin A#

- BkosA AkosB B A sinsin3sin4 ±=±

B AkosAkosB B Akos sinsin34 =±

1/ B A

B A B A

(an(an1

(an(an3(an4

±=±

11 A

A A

#(an1

(an##(an

−=

1#3

)

B

b

A

a

sinsinsin==

1& b))ba #### −+= kos A

1* Luas s!gi(iga 8 ab#

1 sin C

3472/1CONFIDENTIAL

+



CONFIDENTIAL

Answer all 6uestions

1. >i2!n ($a( &7&

#? ≠

−→ /

/ / . and &#? +→ / / g . @ind 34 / .g in ($!

siml!s( orm. 6# marks5

Answer :

;;;;;;;;;

#. Diagram 1 s$os ($! maing o un%(ion 1− . and g . >i2!n ($a(

un%(ion ba/ / . +→? and un%(ion 7? /a

b / g → %al%ula(! ($! 2alu!s o

a and b .

6* marks5

Answer : a 8 BBBBBB..

b 8 BBBBBB..

3472/1 +Lihat ebe,ah

CON

FIDENTIAL

3472/1 or

e/amineruse

1

#

#

*

#

&

*

g 1− .

Diagram 1

)



CONFIDENTIAL

3472/1

or </aminer

use

&

*

*

&

&. On! o ($! roo(s o ($! !ua(ion 1#)# # −=+ p / / is (i%! o ($! o($!r

roo( i($ p is %ons(an(. @ind ($! roo(s and ($! 2alu! o p. 6* marks5

Answer :root:;;;;;;;; p=;;;;;;;;;..

*. @ind ($! rang! o i /1314 ## =−++− p / p / do!s no( $a2! ($! r!al roo(s

6& marks5

Answer:;;;;;;;;;;.

3472/1

CONFIDENTIAL

,



CONFIDENTIAL

+. I y / 1/1/ log#log& =− 7 s(a(! / in (!rms o y . 6* marks5

Answer:

;;;;;;;;;;.

). Sol2! ($! !ua(ion##11

1)*# +−−

=⋅ / / /

. 6& marks5

Answer:;;;;;;;;;;.

,. M is a oin( on ($! lin! $i%$ joining ($! oin( 4& 7 )3 and

411 7 #3 su%$ ($a( M 8 &M. @ind ($! %oordina(! o oin( M .

6& marks5

Answer:

;;;;;;;;;;.


CONFIDENTIAL

3472/1

or

e/aminer

use

+

*

)

&

,

&

-



CONFIDENT

IAL

ore/aminer

use

-

*

&

3472/1

-. @ind ($! !ua(ion o ($! !r!ndi%ular bis!%(or (o ($! lin! joining i($ ($! oin(s A4* 7# 3 and F40# 7 )3 . 6 * marks5

Answer:

;;;;;;;;;;.

. >i2!n ($a(&#3+434 += / / . . @ind ($! 2alu! o 314G − . .

6& marks5

Answer:;;;;;;;;;;

3472/1

CONFIDENTIAL



CONFIDENTIAL

1/. @ind ($! s(andard d!2ia(ion or ($! s!( o ($! numb!rs +7 )7 )7 *7 ,.

6& marks5

Answer:;;;;;;;;;;.

11. P!rim!(!r o a s!%(or is &/ %m. @ind ($! ar!a o ($! s!%(or i ($! radius is- %m . 6& marks5

Answer:

;;;;;;;;;;.

1#. >i2!n ($a( ($! irs( ($r!! (!rms or an ari($m!(i% rogr!ssion ar! )7 #;17 +;.

@ind ($! %ommon di!r!n%! o ($! ari($m!(i% rogr!ssion. 6& marks5

Answer:;;;;;;;;;;.


CONFIDENTIAL

3472/1

or

e/aminer use

1/

&

11

&

1#

&

1/



CONFIDENTIAL

or

e/aminer use

1&

&

1*

*

3472/1

1&. In a g!om!(ri% rogr!ssion7 !a%$ o ($! (!rms is osi(i2!. I s!%ond

(!rm is ) and ($! or($ (!rm is 7&

#*# ind ($! 2alu! o ($! irs(

(!rm. 6& marks5

Answer ?

BBBBBBBB.

1*. T$! 2ariabl!s / and y ar! r!la(!d b" an !ua(ion #& b/a/ y += su%$

($a( a and b ar! %ons(an( . A s(raig$( lin! gra$ is ob(ain!d b"

lo((ing # /

y agains( / as s$on in Diagram # . Cal%ula(! ($! 2alu!

o a and b . 6* marks5

# /

y 417)3

4 & 7* 3

/

Diagram #

Answer ? a 8 BBBBBB b 8 BBBBBB

3472/1

CONFIDENTIAL

CONFIDENTIAL 3472/1

11



1+. E2alua(! d/ /

/ /∫

+−#

1

#

3&34&46&

marks5

Answer ?

BBBBBBBB.

1) >i2!n ($a( ∫ =&

1

1/34 d/ / g 7 ind ($! 2alu! o k in !ua(ion

∫ =−&

1

1#534#6 d/k/ / g 6& marks5

Answer ? k 8 BBBBBBB..BB

6Lihat ebe,ah

3472/1

CONFIDENTIAL

or

e/aminer

use

1+

&

1)

&

1#



CONFIDENTIAL

3472/1 or

e/aminer

use

1,

&

1-

#

1,. >i2!n ($a( ji p )# −= and jik 6 .−= . I p is arall!l i($ 6 7ind ($! 2alu! o k . 6 & marks5

Answer ?k8BBBBBB

1-. >i2!n ($a( />P = and y>? = . OR is arall!l i($ S and >% = 2%P .

@ind P8 in (!rms o / and y . 6 # marks5

R

O S P

Answer ?BBBBBBBBB.

3472/1

CONFIDENTIAL

1&



CONFIDENTIAL

1. I1&

+sin = A and oo

1-// ≤≤θ 7 ind ($! 2alu! o A#sin . 6& marks5

Answer : ;;;;;;;;;;.

#/. Sol2! ($! !ua(ion o)/sin#kos −=θ or oo#,/1-/ <<θ .

6& marks5

Answer :

;;;;;;;;;;.

#1. Ho man" numb!rs o *0digi( !2!n numb!r gr!a(!r ($an )/// %an b!

orm!d rom ($! digi(s #7 +7 )7 , and i($ou( r!!(i(ionJ6* marks5

Answer : ;;;;;;;;;;.

+Lihat ebe,ah

3472/1 or

e/aminer

use

1

&

#/

&

#1

*

3472/1 CONFIDENTIAL

1*



CONFIDENTIAL

3472/1 or

e/amine

r use

##

*

#&

&

##. T$! robabili(" ($a( a durian in a bo; is ro((!n is+

1. I & durian ar!

randoml"

%$os!n rom ($! bo;. @ind ($! robabili(" ($a(4a3 all ($r!! durian ar! ro((!n.4b3 onl" on! durian is ro((!n. 6* marks5

Answer :@a

;;;;;;;;.. @b

;;;;;;;;..

#&. A %ommi((!! ($a( %onsis(s o m!mb!rs ar! orm!d (o sol2! ($! Malaria dis!as!

robl!m. T$a( %ommi((!! ar! s!l!%(!d rom ) ro!ssional7 + nurs!s7 and & so%ial ork!rs. Cal%ula(! ($! numb!r o a"s ($a( %ommi((!! %an b! orm!d su%$ ($a(

i( %onsis(s o & ro!ssional and a( l!as( on! so%ial ork!r. 6& marks5

Answer : ;;;;;;;;;;.

3472/1

1+



CONFIDENTIAL

CONFIDENTIAL

3472/1

#*. >i2!n ($a( ($! robabili(" o a bo" gi2ing bir($ in a amil" is

+

&. I ($a(

amil" $as + %$ildr!n7 ind ($! robabili(" ($!r! is !;a%(l" & bo"s.6& marks5

Answer :

;;;;;;;;;;.

#+. T$! $!ig$( o a grou o bo"s ar! normall" dis(ribu(!d i($ a m!an o1+/.& )m and s(andard d!2ia(ion + )m . Cal%ula(! ($! robabili(" ($a( a bo" is

%$os!n and $is $!ig$( is l!ss ($an 1+& )m. 6& marks5

Answer :

;;;;;;;;;;.

KETA# #OALAN TAMAT

3472/1

or

e/aminer use

#*

&

#+

&

1)



CONFIDENTIAL

1,



CONFIDENTIAL

Jawab semua soalan

1. >i2!n ($a( &7&

#? ≠

−→ /

/ / . and &#? +→ / / g . @ind 34 / .g in

b!n(uk (!rmuda$. 6#

marks5

&3&#4

#

−+ / + P1

/

1 + P2

Answer : /

1 + P2

#. Diagram 1 s$os !m!(aan bagi un%(ion 1− . and g . >i2!n ($a(

un%(ion ba/ / . +→? and un%(ion 7? /a

b / g → $i(ungkan ($! 2alu! o

a and b . 6* marks5

*

diagram 1

&1− . g #

*3&41 =− . a(au 4*3 8 & a(au #3*4 = g + P1

a4*3 b 8 & a(au #3*4 =a

b a(au 4b = 2a

%uba m!n"!l!saikan # !ua(ion +P3

&

1

=b and &

#

=a + P4 Answer :;;;;;;;;;


CON

FIDENTIAL

3472/1ntuk

Kegunaan Pemeriks

a

1

#

#

*

1-



CONFIDENTIAL

3472/1

ntuk Kegunaan

Pemeriksa

&

*

*

&

&. Sa(u dariada un%a !ua(ion 1#)# # −=+ p / / is dua kali un%a "ang

sa(u lagi7 d!ngan k!adaan p is %ons(an( . @ind un%a0un%a (!rs!bu(

and ($! 2alu! o p . 6* marks5

HTPP ? &#

)# −=

−=+ α α + P1

1−=α and #314# −=− + P2

HDPP ?#

1#3#4

+−=

pα α +P1

#

1#314# # +−

=− p

+P3

#

&−= p +P2

Answer : pun)a: "1 and "2 +P2

p=#

&−

+P2

*. @ind rang! ($! 2alu! o i /1314 ## =−++− p / p / (idak m!mun"ai

un%a n"a(a . 6& marks5

313414*35146 ## p p −−+− 0 $ +P1

/&#+ # <−+ p p a(au @p C 3@PD1 E - + P2

+

&1 <<− p + P3

Answer:+

&1 <<− p . + P3

3472/1

CONFIDENTIAL

1



CONFIDENTIAL

+. I y / 1/1/ log#log& =− 7 n"a(akan / in s!bu(an y . 6* marks5

&

1/ 1/log + P1

/

1///log1/ + P2

#1///

y /

= + P3

#

1///

y / = + P4

Answer: #

1///

y / = + P 4

). S!l!saikan !ua(ion ##111)*# +−− =⋅ / / / . 6& marks5

3#14## /− a(au 3#4*# + / / / *#1# −+− a(au /&1# − + P1

-*&1 +=− / / + P2

1−= / + P3

Answer: 1−= / + P3

,. M is sa(u (i(ik ada garis "ang m!n"ambungkan (i(ik 4& 7 )3 and

411 7 #3 sua"a M 8 &M. @ind koordina( (i(ik M . 6& marks5

Tunjukkan gambadiagram (i(ik 7 M 7 d!ngan nisba$ "ang b!(ul

1 M & +P1

*

11+ a(au

*

1-# + + P2

3

*

#/7

*

#/4 a(au 4 + 7 + 3 + P3

Answer: @ & +P3


CONFID

ENTIAL

3472/1

ntuk

kegunaan

pemeriksa

+

*

)

&

,

&

#/



CONFIDENTIAL

untuk

kegunaan pemeriksa

-

*

&

3472/1

-. @ind !ua(ion garis !mba$agi dua sama s!r!njang k!ada garis lurus

"ang m!n"ambungkan (i(ik A4* 7# 3 and F )37#4− . 6*

marks5

(i(ik (!nga$ AF 8 4 1 7 * 3 + P1

mAF &

#

)

*

#*

)#−=−=

+−

+ P2

mA& #

& + P3

+&# += / y ata-#

+

#

&+= / y ata- /+&# =−− / y + P4

Answer: +&# += / y ata-#

+

#

&+= / y ata- /+&# =−− / y + P4

. >i2!n ($a(&#3+434 += / / . . @ind ($! 2alu! o bagi 314G − . .

6& marks5

/ / #3+4& ## + a(au ## 3+4) + / / + P1 >an(ikan 1−= / k! in / / #3+4& ## + a(au

## 3+4) + / / +P2

#1)− + P3

Answer: #1)− + P3

3472/1

CONFIDENTIAL

#1



CONFIDENTIAL

1/. @ind sisi$an iaai bagi s!( nombor0nombor + 7) 7)7 * 7 , . 6& marks5

Min 8 3).+43+

#-43

+

,*))+4 atauatau

++++ + P1

A(au +

1)#+

*1)&)&)#+ atau++++ +P1

/*.1&).&1*.&# atau−=σ + P2

/1-.1=σ + P3

Answer:; /1-.1=σ + P3

11. P!rim!(!r bagi s!bua$ s!k(or bula(an is &/ %m . @ind luas s!k(or

bula(an i(u i j!jari bula(an is - %m . 6& marks5

*

,

-

1*1*- === θ θ atau + P1

L-a #3-34

*

,4

#

1 + P2

L-a +) %m# + P 3

Answer: L-a +) + P 3

.

1#. >i2!n ($a( (iga s!bu(an !r(ama bagi sua(u janjang ari(m!(ik is ) 7 #;1 7 +; .

@ind b!Ka s!un"a janjang ari(m!(ik i(u. 6& marks5

31#4+)1# +−=−+ / / / + P1

*−= / + P 2

1&−=d +P3

Answer: 1&−=d +P3

+Lihat ebe,ah

CONFIDENTIAL

3472/1

untuk

kegunaan pemeriks

a

1/

&

11

&

1#

&

##



CONFIDEN

TI

A

L

untuk

kegunaan pemeriksa

1&

&

1*

*

3472/1

1&. In sua(u janjang g!om!(ri7 s!(ia s!bu(an is osi(i . I s!bu(an

k!dua is ) and s!bu(an k!!ma( is 7&

#*# ind ($! 2alu! o s!bu(an

"ang !r(ama. 6& marks5

)=ar a(au&

#*#& =ar + P1

&

#=r + P2

1**=a + P3

Answer ?BB1** +P3

1*. P!mbol!$uba$ / and y di$ubungkan ol!$ !ua(ion #& b/a/ y += d!ngan

k!adaan a and b is %ons(an( . >ra garis lurus di!rol!$ d!ngan

m!mlo(# /

y m!laan / s!!r(i "ang di(unjukkan in Diagram # .

Hi(ungkan ($! 2alu! o a and ($! 2alu! o b .6* marks5

# /

y 41 7)3

Diagram #

4& 7* 3 /

1#

#

&1

*)−=−=

−−

=m +P1

Pada (i(ik 4& 7* 3

* 8 014&3 C

C 8 , +P2

,#

+−= / /

y +P3 antikan m an

#& , / / y +−=

a 8 1− b8 , +P4

Answer ? a 8 1− 7 b8 , +P4

CONFIDENTIAL 3472/1

#&



1+. T$! 2alu! okan d/ /

/ /∫

+−#

1

#

3&34&46&

marks5

51

6

1#

−−

+− / / a(au 5

6

/ / + + P1

51

165

#

#6 +−+ +P2

+.&#

,−− atau +P3

Answer ? +.&#

,−− atau + P 3

1) >i2!n ($a( ∫ =&

1

1/34 d/ / g 7 ind ($! 2alu! o k in !ua(ion

∫ =−&

1

1#534#6 d/k/ / g 6& marks5

>an(ikan

∫ =

&

1

1/34 d/ / g iai(u #41/3 + P1

#

#k/ + P1

3#

1

#

&4

#

−k 8 - + P2

#=k + P3

Answer ? #=k + P3

6Lihat ebe,ah

3472/1

CONFIDENTIAL

untuk

kegunaan

pemeriksa

1+

&

1)

&

#*



CONFIDENTIAL

3472/1untuk

kegunaan

pemeriksan

1,

&

1-

#

1,. >i2!n ($a( ji p )# −= and jik 6 .−= . I p s!lari d!ngan 6 7ind ($! 2alu! o k . 6 & marks5

k λ =# a(au 34) −=− λ

+ P1

&

#=λ + P2

&=k + P 3

Answer :? &=k + P 3

1-. >i2!n ($a( />P = and y>? = . OR s!lari d!ngan S and >% = 2%P .

@ind P8 in s!bu(an / and y . 6 # marks5

R

O S P

y / P? +−= + P1

34&

1 / y P8 −= + P2

Answer ? 34&

1 / y P8 −= + P2

3472/1

CONFIDENTIAL

#+



1. I1&

+sin = A and oo

1-// ≤≤θ 7 ind ($! 2alu! o bagi A#sin . 6&

marks5

1&1#−=kosA + P 1

AkosA A sin##sin = ata- 31&

1#34

1&

+4# − + P 2

1)

1#/− + P3

Answer 51)

1#/− +P3

#/. S!l!saikan !ua(ion o)/sin#kos −=θ d!ngan k!adaan oo#,/1-/ <<θ .

6& marks5

-))./− + P1

o+1/# =θ +P2

o#++=θ + P3

Answer : o#++=θ + P3

#1. F!raaka$ bilangan nombor g!na * digi( "ang l!bi$ b!sar dariada

)///

"ang daa( dib!n(uk dariada digi( #7 +7 )7 , and (ana ulangan J 6* marks5

1-1#&& =××× +P1 1#1#&# =××× + P2

1- 1# (amba$kan # k!mungkinan dari P1 and P# + P3

&/ + P4

Answer : ;&/ + P4 ;;;.

+Lihat ebe,ah

CONFIDE

NTIALuntuk kegunaan

pemeriksa

1

&

#/

&

#1

*

3472/1 CONFIDENTIAL

#)



CONFIDENTIAL

3472/1untuk

kegunaan

pemeriksa

##

*

#&

&

##.+

1 dariada durian in s!bua$ ko(ak didaa(i rosak. I & biji durian

diili$ s!%ara raak dariada ko(ak (!rs!bu( . 'ira k!barangkalian ba$aa

4a3 s!mua k!(iga0(iga durian rosak.4b3 $an"a s!biji durian sa$aja rosak. 6* marks5

4a3&3

+

14

+

1

+

1

+

1atau×× + P1 4b3

+

1

+

*

+

*

+

*

+

1

+

*

+

*

+

*

+

1

1#+

1 + P2 ata- &

+

*

+

1 #

×

+P1

1#+

*- + P2

Answer @a1#+

1 + P2

4b31#+

*-

+ P2

#&. Sa(u jaa(ankuasa "ang (!rdiri dariada ) orang a$li !rlu dib!n(uk un(uk

m!nga(asi masala$ !n"aki( malaria . :aa(ankuasa i(u diili$ dariada ) orang

akar 7 + orang jururaa( and & orang a(!nand. Hi(ung bilangan %ara jaa(ankuasa i(u bol!$ dib!n(uk i jaa(ankuasa i(u m!s(i (!rdiri dariada &

orang akar and s!kurang0kurangn"a s!orang a(!nand . 6& marks5

1&

#+

&) 3 3 3 ⋅⋅ #

&1

+&

) 3 3 3 ⋅⋅ &&

/+

&) 3 3 3 ⋅⋅

8 11#/&+#/&1/#/ ××+××+×× +P1

8 )// &// #/ +P2

8 #/ +P3

Answer : #/ +P3

#,



3472/1

CONFIDENTIAL

CONFIDENTIAL

3472/1

#*. >i2!n ($a( k!barangkalian bagi k!la$iran s!orang anak l!laki in s!bua$

k!luarga is+

&

. I k!luarga i(u m!mun"ai + orang anak 7 ind

k!barangkalian ba$aa (!rdaa( (!a( & orang anak l!laki .

6& marks5

P48&3 +P1

8#&

&+

&

#

+

&

3 +P2

8 &*+)./)#+

#1)atau +P3

Answer : &*+)./)#+

#1)atau +P3

#+. Tinggi s!kumulan l!laki m!ngiku( sa(u (aburan normal d!ngan min

1+/.& )m and sisi$an iaai + )m . @ind k!barangkalian s!orang l!laki "ang

diili$ s!%ara raak dariada kumulan i(u m!mun"ai (inggi kurang

dariada 1+& )m. 6& marks5

P4; 1+&3

8 P

−

<+

&.1+/1+& 9 a(au P ( )+*./< 9 +P1

3+*./4P1 >− 9 a(au 1 0 /.#*) +P2

8 /.,/+* +P3

Answer : -.'-4 +P3

untuk

kegunaan pemeriksa

#*

&

#+

&

#-



3472/1

CONFIDENTIAL

:IAN SETARA

ADDITIONAL MATHEMATICS SPM

P!n"!laras? Pn. :ud" Lian !! Ling

4S!k(or P!ngurusan Akad!mik7

:aba(an P!ndidikan N!g!ri Saba$3

A$li Pan!l?

1. C$!ong N"uk Tai7 SM'4P3 Likas7 'o(a 'inabalu.#. C$ung Su 'iong7 SM:' Tiong Hua7 Sandakan.

&. P$oon C$i! @un7 SM' T!nom7 T!nom.

*. S$irn!" C$ua7 SM' Hol" Trini("7 Taau.

+. Suriani$ S!an7 SM' Tamaruli7 Tamaruli.). T$!r!sa L!! C$oon Moi7 SM' S(. Mi%$a!l P!namang7 P!namang.

,. Ting 'ai C$u7 Mak(ab Saba$7 'o(a kinabalu.-. !o$ S!k >o$7 SM' Agas!$7 La$ad Da(u.

#

mat tamb k1 sep

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