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  • 7/30/2019 Lecture+8+Mak Xrd

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    PHY 3201 FIZIK KEADAAN PEPEJAL

    CHAPTER 2 : Wave Diffraction

    and the Reciprocal Lattice

    Diffraction of wave by crystals

    Scattering wave amplitude

    Brillouin Zones

    Fourier analysis of the basisBertha Rntgens

    Hand 8 Nov, 1895

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    Learning outcomes :

    By the end of this topic, student can able to : Explain Braggs Law.

    Explain the diffraction of wave by crystal.

    Explain and construct the reciprocal lattice.

    Explain the use of x-ray diffraction method

    for material characterization.

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    X-Rays

    X-rays were discovered in

    1895 by the German

    physicist Wilhelm Conrad

    Rntgen and were so namedbecause their nature was

    unknown at the time.

    He was awarded the Nobelprize for physics in 1901.

    Wilhelm Conrad Rntgen

    (1845-1923)

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    Diffraction of waves by crystal

    The wavelength of X-rays is in the range of

    few angstroms, which is comparable to theinteratomic spacing in crystals. Thus X-raysare diffracted by the periodically arrangedatoms in a crystal i.e. crystals act as a three-dimensional diffraction grating for X-rays.

    Therefore crystal structures can bedetermined by the study of diffraction of X-rays

    In 1913, W. L. Bragg presented a simple

    explanation of the diffracted beams from acrystal.

    Sir Will iam Henry Bragg (1862-1942),

    Will iam Lawrenc e Bragg (1890-1971)1915, the father and son were awarded the

    Nobel prize for physics "for their services in

    the analysis of crystal structure by meansof Xrays".

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    Experimental setup

    (How do we produce x-rays?)

    X-ray production is via Bremstrahlung radiation. The

    electrons are produced typically from a tungsten source,

    are accelerated towards a metal such as copper, and when

    they hit the surface, they slow down. This .brakingradiation. is a broad band of light which is emitted as the

    electron slows down (charged particles under acceleration

    emit radiation)

    (Eg:

    Molybdenum)

    35 KV

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    X-Ray Spectrum of Molybdenum

    X-Ray spectrum ofMolybdenum is obtained whenMolybdenum is used as targetmetal.

    K and K are characteristic

    of an element. For Molybdenum K occurs at

    wave length of about 0.07nm.

    Electrons of n=1 shell of targetmetal are knocked out bybombarding electrons.

    Electrons of higher level dropdown by releasing energytoreplace lost electrons

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    Consider a monochromatic, parallel beam of X-raysincident on a set of parallel crystals plane of Miller

    indices

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    Now consider interference between reflections

    from successive planes:

    Constructive interference

    occurs only when

    n = AB + BC

    AB = BCn = 2AB

    Sin = AB/d

    AB = d Sin

    n = 2 d Sin

    = 2 dhkl Sin hkl

    Braggs law

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    What happens during a diffraction experiment?X-rays of a single wavelength (and therefore, energy) are

    incident upon a crystal. The incoming rays are of the

    proper wavelength for diffraction (on the order of the

    interatomic spacing), and thus we see diffraction peaks

    at certain values of , the scattered beam angle. Eachone of these peaks is from a plane of atoms within the

    crystal. This is an elastic process.

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    10/18PHY 3201 FIZIK KEADAAN PEPEJALDiffraction peaks are observed as a function ofscattered angle

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    There are many types of X-ray camera

    to sort out reflections from different crystal

    planes. We will study only three types of X-

    ray photograph that are widely used for the

    simple structures.1.Laue photograph

    2.Rotating crystal method

    3.Powder photograph

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    X-Ray Diffraction Method

    Laue Rotating Crystal Powder

    Orientation

    Single Crystal

    Polychromatic Beam

    Fixed Angle

    Lattice constant

    Single Crystal

    Monochromatic Beam

    Variable Angle

    Lattice Parameters

    Polycrystal (powdered)

    Monochromatic Beam

    Variable Angle

    X-RAY DIFFRACTIONMETHODS

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    THE POWDERMETHOD

    In powder or polycrystalline diffraction, if possible, we

    normally grind the sample down to particles of about

    0.002 mm to 0.005 mm cross section. The ideal sample is

    homogeneous and the crystallites are randomly

    distributed. The sample is pressed into a sample holder.

    Ideally we now have a random distribution of all possible

    h, k, l planes. If we have a truly random sample, each

    possible reflection from a given set of h, k, l planes willhave an equal number of crystallites contributing to it.

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    THE POWDERMETHOD

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    THE POWDERMETHOD

    An x-ray beam diffracted from a lattice plane can be

    detected when the x-ray source, the sample and the

    detector are correctly oriented to give Bragg

    diffraction.A powder or polycrystalline sample contains an

    enormous number of small crystallites, which will adopt

    all possible orientations randomly

    Thus for each possible diffraction angle there arecrystals oriented correctly for Bragg diffraction

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    Debye ScherrerCamera

    Each set of planes in a

    crystal will give rise to a cone

    of diffraction. These cones

    intersect a strip of

    photographic film located inthe cylindrical camera to

    produce a characteristic set

    of arcs on the film.

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    Powder diffractionfilm

    When the film is removed from the camera,

    flattened and processed, it shows the diffraction

    lines and the holes for the incident andtransmitted beams.

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    There are a number of various setups for studying crystalstructure using x-ray diffraction.

    In most cases, the wavelength of the radiation is fixedand the angle is varied to observed diffraction peakscorresponding to reflections from differentcrystallographic planes.

    Using the Bragg law, one can then determine thedistance between the planes.

    However, Bragg law is oversimplified, where it

    Says nothing about intensity and width of x-raydiffraction peaks

    Neglects differences in scattering from different atoms Neglects distribution of charge around atoms.

    Hence, to fully understand, we need a deeper analysis todetermine the scattering intensity from the basis of atom.