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FizikKertas 1PeperiksaanPercubaanNegeri Kelantan 2015

SkemaPemarkahan

1 B 26 C2 A 27 C3 B 28 B4 D 29 A5 B 30 A6 C 31 D7 B 32 D8 B 33 D9 B 34 B

10 D 35 A11 B 36 B

12 B 37 B13 A 38 A14 B 39 A15 D 40 D16 C 41 B17 C 42 D18 A 43 C19 A 44 A20 C 45 D21 B 46 A22 B 47 B

23 A 48 C24 B 49 A25 B 50 A

[ 50 marks ]

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MARKING SCHEME PEPERIKSAAN PERCUBAAN KERTAS 2 2015

NOSOALAN SCHEME SUB

TOTAL TOTAL

SECTION A1(a) Tick inside the box

Can be measured 1 1

(b) (i) 0.2 V 1

2

(ii)

1

(c) 3.6 – 0.2 // 3.4 V 1 1

TOTAL 4 M2(a) A push / pull / something that change shape/

speed/direction/size of the object1 1

(b) (i)

12

(ii) Fx = F cos 1

(c) (i) Decreases 12(ii) There is a frictional force // Net force decreases 1

TOTAL 5 M3 (a)(i) Fission reaction 1

2(ii) 2 1

(b) (i) M1 2.9 X 10 - = m (3X10 )

M2 m = 3.22 X 10 -28 kg (answer and correct unit)

1

12

X

Fx

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(ii)P = 3-

-11

1.5X10

10X2.9

= 1.93 X 10 -8 W (Answer and correct unit)

1

12

TOTAL 6 M4 (a) Specific latent heat of vaporisation 1 1

(b) (i) Tick inside the boxunchanged

12

(ii) To form the bonding between the molecules 1

(c) M1 : State correct equationQ3 + Q 4 = mcθ + mL f M2 : Subtitution

= 0.1(4200)(100 – 0) + 0.1(3.36 x 10 5)M3 : Answer with correct unit

= 75 600 J

1

1

1

3

(d)

1 1

TOTAL 7 M5 (a) A point at principal axis where all the parallel light are

focus/converged after reflected by the mirror 1

1

(b) (i) Object distance in diagram 5.1 < diagram 5.2 1

4

(ii) Image distance in diagram 5.1 > diagram 5.2 1

(iii) The object distance decreases, the image distance increases//vice versa// inversely proportional

1

(iv) Reflection 1

(c)

3 3

TOTAL 8 M6 (a) Wave produced when the direction of vibration of particle is 1 1

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is perpendicular to the direction of propagation of a wave

(b) (i) Depth in region A is more than region B // vice-versa 1

3(ii) The wave length in region A is more than region B // vice-versa

1

(iii) When depth increases, wavelength increases // vice-versa 1

(c) (i) Speed 1

3(ii) M1 As depth decreases, speed decreases

M2 Depth decreases, wave length decreases // v = f λ

1

1

(d) increases 1 1

TOTAL 8 M7 (a) Rate of change of displacement / displacement per time 1 1

(b) (i) K 1

3(ii) Gradient is the biggest 1(iii) Able reduce air friction // Produce more net force 1

(c) (i) M1 Run with increasing speed / run faster

M2 To increase kinetic energy / momentum

1

1

6

(ii) M1 Lighter / low density / low mass pole // Strong pole //High flexibility

M2 Easy to carry / Light // Not easy to break // easy to

bend

1

1

(iii) M1 Thick and soft mattress // land on his back

M2 increases time of impact / reduce impulsive force //toreduce pressure

1

1

TOTAL 10 M8 (a) (i) A region in which there is an electric force // a region

around a charged object experiences electric force1 1

(ii) Oscillating 1 1(b) (i)

1 1

(ii) M1 The heat of burning candle produces positive and 12

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negative ions.

M2 The positive ions which are heavier is pulled towardsnegative plate with a larger proportion flame

1

(c) (i) Shape : CoilReason : high resistance / can produce more heat / increasesurface area

11

(ii) Resistivity: highReason: high resistance /can produce more heat

11

(iii) Melting point: highReason: not easily melt/ can withstand high temperature

11

(d) L 1

TOTAL 12 M

SECTION B9 (a) When an object is partially or fully immersed in a fluid the buoyant force is equal to the weight of fluid displaced.

1 1

(b) (i) Weight of water displaced is equal

Density of sea water is more than river water // vice-versa

Volume of water displaced in sea water is less than in riverwater // vice versa

1

1

1

3

(b)(ii) (a) Density increases volume of water displaced decreases //density is inversely proportional to volume of waterdisplaced

1

2

(ii)(b) Weight of water displaced = buoyant force 1

(c) M1.Density of air decreases as altitude increases

M2.Bouyant force become smaller

M3.At certain height, weight of displaced air equal toweight of the balloon.

M4.Net force zero / forces in equilibrium

1

1

1

1

4

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(d) Aspect Explanation

Material used for thehydrometer: glass

Non corrosive

Length of the stem:long

Bigger range of density ofliquid can be measured

Size of the bulb: big Bigger buoyant force/More volume of liquiddisplaced

Diameter of the stem ;small

More sensitive

Material used at the base ofthe bulb: lead shots // sand

More stable / not tilted /stand upright

1 , 1

1 , 1

1 ,1

1 , 1

1 , 1

10

TOTAL 20 M10. (a) Induced current

Arus Aruhan1 1

(b) 1. Height of magnet in diagram 10.1 is higher Ketinggian magnet dalam Rajah 10.1 lebih tinggi

2. No of turns is the same Bilangan lilitan sama

3. Deflection of Galvanometer in Diagram 10.1 is greaterPesongan Galvanometer dalam Rajah 10.1 lebih besar

4. The more the height of magnet the more the deflectionSemakin bertambah ketinggian magnet semakin besar

pesongan Galvanometer

5. The higher the speed of the magnet the more themagnitude of the current produced.Semakin bertambah laju magnet semakin bertambahmagnitud arus yang terhasil.

1

1

1

1

1

5

(c) (i) 1. There is a cutting of flux// change of fluxTerdapat pemotongan fluks // perubahan fluks

2. Produced induced e.m.f // induced current

Terhasil emf aruhan // arus aruhan

1

12

(ii) 1. Using Fleming’s Right hand rule Guna Peraturan Tangan Kanan Fleming

2. Force is downwards , Magnetic Field from North toSouth,

so the direction of curent from Q to P.

1

12

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Daya ke bawah, medan magnet dari Utara ke Selatan, jadiarah arus dari Q ke P.

(d) Aspect Aspek

ReasoningSebab

copper wire Dawai kuprum good conductor//resistance is very low Pengalir yang baik// rintanganrendah

thicker wire Dawai Tebal

reduce the resistance Kurangkan rintangan

Use a laminated coreTeras berlapis

avoid the Eddy current Elak Arus pusar

Use soft iron coreGuna Teras Besi

Lembut

can be magnetized and demagnetizedeasily/avoid hysteresis .

Boleh di magnetkan dandinyahmagnetkan dengan mudah /elakkan histeris

Winding the secondarycoil on top of the

primary coil Lilitkan gelung sekunder di atas gelung primer

reduce the leakage of magnetic flux Mengurangkan kebocoran fluks.

1 , 1

1, 11, 1

1, 1

1, 1

10

TOTAL 20 M

SECTION C11 (a)

Reciprocal of focal length // Salingan panjang fokus

1 1

(b) 1. The convex lens is aimed/focused to a distant object Kanta cembung di fokuskan kepada objek jauh

2. The screen is adjusted until a sharp image is formed onthe screenSkrin dilaraskan sehingga imej tajam terbentukdiatasnya

3. The distance between the screen and the lens is measured Jarak antara skrin dan kanta diukur

4. Focal length, f = distance between the screen and thelens

Panjang fokus , f = jarak antara skrin dengan kanta

5. Power of lens / kuasa kanta =

1

1

1

1

1

4 (max)

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(c)

Aspect ExplanationLonger focallength // fo > fe

Panjang fokus yang panjang

To produce real, inverted and smallerimage

Hasilkan imej nyata, songsangdan lebih kecil

Highmagnification //>1

Pembesarantinggi

Produce bigger image Hasilkan imej lebih besar

Distance = fo + fe Produce sharp image at normaladjustment // image at infinity

Hasilkan imej tajam pada pelarasannormal

Bigger diameter Diameter lebih

besar

More light can enter objectivelens // more brighter

Lebih banyak cahaya dapat masuk//lebih cerah

P is chosenP dipilih

Longer focal length, highermagnification, Distance betweentwo lenses = fo + fe and

bigger diameter Panjang fokus yang panjang, Pembesaratinggi, jarak antara kanta = fo + fe dandiameter lebih besar

1, 1

1, 1

1, 1

1, 1

1, 1

10

(d) (i) Power = 1 =1 = 10Df 0.1

1

5

(ii) = +

1 = 1 – 1v 10 20v =20 cm

1

1

(iii) m = =

= 3

1

1

TOTAL 20 M12 (a) Semiconductor where hole acts as the majority carrier

Semikonduktor di mana lohong bertindak sebagai pembawacas majoriti

1 1

(b) 1. Pentavalent atoms are doped into pure semiconductor Atom pentavalen didopkan kedalam semikonduktor tulin

2. The structure has free electron more than hole

1

1

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Struktur mempunyai bilangan elektron lebih dari lohong

3. As temperature increases electron will escape as freeelectron leaving an empty space known as hole

Apabila suhu bertambah elektron akan terbebas sebagaielektron bebas meninggalkan satu tempat kosong yang

dinamakan lohong.4. As more electrons escape more free electron will be

produce more than hole // electrons are the majoritycarriers

Bila lebih banyak elektron terlepas, lebih banyak elektronbebas terhasil melebihi lohong.// elektron adalah

pembawa cas majoriti

1

1

4

(c) Aspect Explanation4 diode // more number of

diodes4 diod // lebih diod

Full wave rectification

produced Hasilkan rektifikasi gelombang penuh

Two pairs of diodes parallel to each other2 pasang diod selariantara satu sama lain

Produce forward biasconnection

Hasilkan sambungan Pincang ke depan

Smoothed waveGelombang licin

Same as pure d.c waveSama dengan gelombang a.ttulen

Capacitorkapasitor

To smoothen the output waveUntuk melicinkan gelombangoutput

R is chosen R dipilih

4 diode // more number ofdiodes, Two pairs of diodes

parallel to each other,Smoothed wave , Capacitor

1, 1

1, 1

1, 1

1, 1

1, 1

10

(d) (i) V = 1.5 volt 1

5

(ii) T = 0.1 x 2= 0.2 s

11

(iii) f =

= = 5 Hz

1

1

TOTAL 20 M

END OF MARKING SCHEME.

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PEP PERCUBAAN FIZIK Paper 3 2015

NO MARKING SCHEME SUBMARK

TOTALMARK

1(a)(i) Mass of water / jisim air/m/ 1 1(a)(ii) Increase in the temperature/ /kenaikan suhu// 1

1 1

(a)(iii) Density of water/ ketumpatan air 1 1(b)(i) 25 o 1 1(b)(ii) 8.0,4.4,3.1,2.4,1.9 …..at least 4 reading are correct 1 1(b)(iii) 62,45,39,36,34 …..at least 4 reading are correct 1 1(b)(iv) 37,20,14,11,9 (terima ecf)/ at least 4 reading are correct 1 1

(c) m,kg 1,1

kg m

,oC ,oC

0.125 8.0 62 370.225 4.4 45 200.325 3.1 39 140.425 2.4 36 110.525 1.9 34 9

Symbol dan unit are correctConsistent of value

11

2

(d) / Both axes (symbol and unit) 6 ticks ….. 5 marks/Both correct scale 5 ticks….. 4 marks /At least 4 point are plotted correctly 4 ticks… 3 marks /Straight line 3 ticks …. 2 maks /Line starting origin ≤2 ticks …..1 mark /Best fit

5 5

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(e) Directly proportional 1 1

2(a) (i) f is directly proportional to

f berkadar langsung dengan

1 1

(ii) show on the graph

= 0.9

x = 1.11 m

1

1

1

3

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(a) (iii) - Draw a sufficiently large triangle minimum (8 x 8) cm

- Correct substitution (Follow candidate’s triangle)

m =

= 633.33

- Correct answer and no unit

1

1

1

3

(b) -Correct substitution

v = m

= 633.33 ( )

-Correct answer with correct unit

v = 126.7 ms-1

1

1

2

(c)(i) - The gradient (m) decrease 1 1

(c)(ii) m = , when a increase, m decrease

(d) -State one precaution correctly.1. Position of eyes are perpendicular to the scale of metre

rule toavoid parallax error

2. Repeat the experiment three times and calculate the

average. 3. Experiment is carried out in the field to avoid reflectionof sound.

1 1

JUMLAH 12

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NO MARKING SCHEME SUBMARK

TOTALMARK

3 (a) Apparent depth depends on density of liquid 1 1(b) When density of liquid increases, the apparent depth

decreases1 1

(c) To investigate the relationship between the density of liquid

and apparent depth

1

Manipulated variable : density of liquid // mass of salt 1Responding variable : apparent depthFixed variable : actual depth 1Tall beaker, pin, water, measuring cylinder, salt, triple beambalance, metre rule, retort stand

1

1

Mass of salt,m = 20 g is measured and mixed with volume ofwater, V =100 cm 3. The density of liquid, 1

The mixture is poured into a tall beaker and actual depth ofliquid, D = 20.0 cm is measured. 1

A pin is placed at the base of the beaker as object O.

The pin O is observed vertically above the surface of the liquid.

The position of pin I is adjusted until parallax error betweenthe pin O and the pin I is non- existent.

The position of pin I, the apparent depth, d is measured.

1

The experiment is repeated by using mass of salt, m = 30 g, 40g, 50 g dan 60 g.

1

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Mass of salt,m/g

Density,

/gcm -3

Apparentdepth, d/cm

2030405060

1

Apparent depth, d vs density, graph is plotted

d

1

10

JUMLAH 124 (a) Inference: The strength of electromagnet depends on the magnitude

of current flow1 1

(b) Hypothesis: As the magnitude of current increases the strength ofelectromagnet increases.

1 1

(c) (i) Aim: To investigate the relationship between the magnitude ofcurrent and the number of paper clips attracted

1 1

(ii) Variables:Manipulated: Magnitude of currentResponding: Number of paper clips attractedConstant: Number of turn of solenoid

1

1

2

(iii) Apparatus and material:Power supply, Petri dish, retort stand, paper clips, insulated copperwire, soft iron core, connecting wires.

1 1

(iv) Arrangement of apparatus: 1 1

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(v) Procedure:- Wound 20 turns of wire around a soft iron core.- Switch on the switch and the rheostat is adjusted to 0.2 A.- Moved the Petri dish containing paper clips to the end of the soft

iron core.- Calculate the number of paper clips attracted to the iron core.- Repeat the experiment 4 more times using current 0.4A, 0.6 A, 0.8

A and 1.0 A.

1

1

1

3

(vi)

Electric current,I(A) No. of paper clip attracted0.20.40.60.81.0 1

1

(v)

1

1

JUMLAH 12


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