biology johor 2011

SULIT*455ltlBiologiKertas ISeptember2011r% jdm

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JABATAN PELAJARANNEGERI JOHOR

PEPERIKSAA.N PERCUBAAN SPM 2OTIBIOLOGIKertas 1September 2011l% jam

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Satu jam lima belas minit

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2.

JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

Kertas soalan ini adalah dalam dwibahasa.

Soalan dalam bahasa Inggeris mendahului soalan yang sepadan dalam bahasaMelayu.

Calon dikehendaki membaca maklumat di halaman belakang kertas soalan ini.

Kertas soalan ini mengandungi 29 halaman bercetakJabatan Pelajaran Negeri Johor

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l . Diagram I shows an organelle.Rajah 1 menunjtftkan satu organel.

Diagram IRaiah I

Which of the following cell possess the organelle in Diagram 1?Antara sel-sel berikut, yang manakah mengandungi organel dalam RajahA Guard cell

Sel pengawalB Muscle cell

Sel ototC Epidermal cell

Sel epidermisD Cheek cell

Sel pipi

Diagram 2 shows a unicellular organism.Rajah 2 menunjukkan satu organisma unisel

DiagramZRajah 2

Which of the following process facilitates the movement of water into the cell?Antara proses berikut, yang manakah mempercepatkan pergerakan air ke dalam seltersebut?

I?

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A

B

C

D

OsmosisOsmosisActive TransPortPengangkutan AhifSimple DiffusionResapan RingkasFacillitated DiffusionResapan Ringkas

Diagram 3Raiah 3

What are the parts labeled I and II?Apakah bahagian berlabel I dan II?

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Diagram 3 shows part of a plasma membrane.nalin S menuniukkan sebahagian daripada membran plasma'

I

l l

D

I II

Hydrophilic headKepala hidrofilik

Hydophobic tailEkor hidrofobik

Hydophobic headKepala hidrofobik

Hydrophilic tailEkor hidro/ilik

Polar headKepala berkutub

Polar tailEkor berkutub

Non-polar headKepala tidak berkutub

Non-polar tailEkor tidak berkutub

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Diagram 4 shows the condition of a plant cell after being immersed in a hypotonicsolution.Rajah 4 menunjukkan keadaan satu sel tumbuhan selepas direndam dalam larutanhipotonik.

Diagram 4Rajah 4

Which of the part labeled P, Q, R and S shows that the cell is turgid ?Yang manakah antara bahagian berlabel P, Q, R and S menuniukkqn bahawa sel inisegah?APBa

5. Diagram 5 shows the molecular structure of two classes of food.Rajah 5 menunjukkan struktur molekul bagi dua jenis kelas makanan.

Diagram 5Rajah 5


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What are the food classes of P and Q?Apakah kelas makanan bagi molehtl P dan Q?

P aA Protein

ProteinLipidLinid

B CarbohydrateKarbohidrat

ProteinProtein

C LipidLipid

CarbohydrateKarbohidrat

D ProteinProtein

CarbohydrateKarbohidrat

Which type of carbohydrate is found in abundance in liver cells?

Apakah jenis karbohidrat yang barryak diiumpai dalam sel hati?

A StarchKanji

B SucroseSulcrosa

C GlycogenGlikogen

D GlucoseGlukosa

Which of the following enzyme is synthesised in pancrease?

Yang manakah antara enzim berikut disintesis di panlcreas?

A SucraseSukrase

B PepsinPepsin

C AmylaseAmilase

D RenninRenin

Which of the following cell does not carry out mitosis ?

Yang manakah antara sel berikut tidak menialankan proses rnitosis ?

A Skin cellsSel-sel kulit

B Hair cellsSel-sel rambut

C Finger nail cellsSel-sel kuku

D Red blood cellsSel darah merah

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The following statement refers to a process in digestion.Pernyataan berihtt merujuk pada satu proses dalam pencernaan.

A process of utilization of digested nutrient to form complexcompounds.Proses penggunaan nutrien untuk membentuk sebatian komplela.

What is the process?Apakah pros es ters ebut?

A AssimilationAsimilasi

B AbsorptionPenyerapan

C DeaminationDeaminasi

D DefaecationPenyahtinjaan

Diagram 6 shows a ruminant digestive system.Which of the part P, Q, R and S is the true stomach of the ruminant?Rajah 6 menunjukkan sistem pencernaan haiwan ruminan.Yang manakah antara bahagian yang berlabel P, Q, R and S merupakan perut sebenarhaiwanruminan?

Diagram 6Raiah 6


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Diagrarn 7 shows the human digestive system'Rajah 7 nenuniukkan sistem pencernaan manusia.

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Diagram 7Rajah 7

Which of the part labelled A, B, C and D is the site where deamination takes place?yang manakah antara bahagian berlabel A, B, C dan D merupakan tempat berlahtnya

deaminasi?

12. Diagram I shows the structure for gaseous exchange in humans.

Rtt\dh S menunJukkan sftuktur untukpertulwran gas manusia

Diagram 8Rajah I

Which of the foltowing are the adaptive characteristics ?Monalah antara yang-berilwt merupalran ciri-ciri penyesuaiannya?I

II

ru

IV

Always moistSentiasa lembabThin and permeableNipis dan telapHas a large surface areaMempunyai luas permuhanyang besarComplete with main blood vesselI"engkap dengan,calur darah utama

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B

c

D

I and III onlyI dan III sahajalI and IV onlyII dan {V sahaJaIII and IV onlyIII dan IV sahajaI, II artd III onlyI,ll, dan III sahaja

Diagram 9 shows tlrec different types of organisms.Rajah 9 menunjukkan tigajenis organisma yang berbeza.

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Diagram 9' Rajah 9 ,/

Which of the following shows the conect respiratory surface of the organisms?Manalcah anlara herikut menunjuklwn permukaan pernafusan yang betul untukorganisma tersebut?

P 0,/ RSkinKulit

TracheolesTrskeol

AlveolusAlveolus

AlveolusAlveolus

SkinKulit

TracheoiesTral<sol

.4lveolusAlveolus

TrachEolesTraksol

SkittKulit

TracheolesTrakeol

AlveolasAlveolas

SkinKulit

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15. Diagram I I shows a graph of the changes in the population of owl and rat in acommunity.Rajah 1 I menunjukkan satu grafperubahan populasi burung hantu dan tihts dalam satukomuniti.

Owl I Burung hantuFiatlTikus

Time / Masa

Diagram I IRajah I I

What is the tlpe of interaction is shown by the the graph?Apakah j enis interaksi yang dituniukkan oleh graf ters ebut?

A Commensal-host relationshipP erhub ungan komens al -p erumahParasite-host relationshipP erhubungan p ar as i t -p erum ahPrey- predator- relationshipP erhubungan tnangs a-p etnangs aEpiphyte-epizoit relationshipP erhubungcm ep ifi t - ep izo it

Which of the following is the main cause of acid rain?Antara yang berikut yang manakah punca utama huian asid?

A Carbon dioxideKarbon diolcsida

B Sulphur dioxideSulfur diolcsida

C Carbon monoxideKarbonmonolaida

D ChlorofluorocarbonsKloroflorokarbon

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Diagram 12 shows a cross section of a young dicotyledon root consisting of a few main

tissues.Rajah I2 menunjukkan keratan rentas akar muda pokok dikotiledon yang terdiri

daripada beberaPa tisu utama.

Diagram 12Raiah 12

What is M?Apakah IuftA Phloem

FloemB Xylem

XilemC Cortex

KorteksD Cambium

Kambium

Which of the following substances causes prothrombin to change to thrombin?

Yang manak ah antara-bahan berikut menyebabkan protrombin bertukar kepada

trombin?A Vitamin K

Vitamin KB Thrombin

TrombinC Calcium ion

Ion kalsiumD Thrombokinase

Trombokinase

Which type of immunity is obtained by injecting antiserum into the body?

Apakahlinis keimunan-yang akan diperoleh dengan menyuntik antiserum ke dalam

badan?A ,4rtificially acquired passive immunity

Keimunan Pasif buatanB Naturally acquired passive immunity

Ke imunan P as if s emul a i adiC Artificially acquired active immunity

Keimunan ahif buatanD Naturally acquired active immunity

Keimunan ah if s emula i adi

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20 What are the functions of the human skeleton ?Apakah fungsi-fungsi rangka manusia?

Diagram 13 shows a human lumbar vertebrae .Rajah 1j menunjukkan sqtu vertebra lumbar mqnusia,

Diagram 13Raiah 13

What is the function of X and Y ?Apakahfungsi X dan Y?

A Protection for spinal cordP er lindun gan b a gt s ar af t unj ang

B Surfaces for muscle attachmentPermukaan untuk pelekatqn otot

C Surfaces for vertebraljointsPermukaan untuk sendi vertebra

D Surfaces forrib articulationPermukaan untuk persendian tulang rusuk.

m

IV

IV

A'rBcD

Supports the bodyMenyokong badanFor locomotionUntuk pergerakanProduces blood cellsMenghasilkan sel darahProtects the internal organs such as heart and lungsMelindungi organ dalaman seperti iantung dan peparu.

I and II only \.III and IV onlyI, II and [V onlyI, U, III and IV

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Diagram 14 shows the growth curve of an insect.Rajah 14 menunjuklmn lenghmg perrumbuhan seekor serangga.

Body length (cm)Panjang badan (sm)

Time (days)Masa (hari)

Diagram 14Rajah 14

What is stage X?Apakah peringkat )QA Ecdysis

ElcdisisB Adult

DewasaC Nymph

NimfaD Instar

Instar

The following statement is about a method of contraception in females.

Pernyataan berihtt adalah tentang satu lcaedah pencegahan kehamilanpada wanita.

A plastic-coated copper coilSatu lingkaran htprum yang bersalut plastik

Can be left in the uterus for monthsBoteh dibiarkan di dalam uterus selama beberapa bulan

Prevents implantation of the embryo in the uterine wallMenghalang penernpelan embrio pada dinding uterus


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What is the method used?Apakah kaedah yang digunakan?A Spermicide

SpermisidB Diaphragm

DiafragmaC Intrawine Device (I[ID)

Alat kontraseptif dalam rahim (IUD)D Female condom

Kondomwanita

24 The following statement is about the hormones that regulate the menstrual cycle.Pernyataan berikut adalah tentang hormon-hormon yang mengqwal atur kitar haid.

a

a

Hormone J - Stimulates the anterior pituitary to secrete LH and FSHHormon J - Merangsang pituitary anterior untuk merembes LH dan FSH

Hormone K - At low level, causes the breakdown of endometrium wall andmenstruationHormon K - Pada paras yang rendah, menyebabkan keruntuhan dindingendometrium dan kedatangan haid

What are hormones J and K?Apakah hormon J dan K?

Hormone JHormon J

Hormone KHormon K

OestrogenEstrogen

ProgesteroneProgesteron


OestrogenEstrogen


Gonadotrophine ReleasingHormone (GnPJ{)

Hormon Perembes Gonadotrof(GnRH)

Gonadotrophine ReleasingHormone (GnRH)

Hormon P erembes Gonadotrof(GnRH)


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A

B

C

D

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Mendel's First Law of Inheritance is also known as Law of Segregation.Hukum Mendel Pertama juga dikenali sebagai Hukum Pengasingan Bebas.

Based on the statement, which stage of cell division is involved in the segregation ofalleles?Apakah peringkat pembahagian sel yang terlibat dalam pengasingan alelTA Prophase I

Profasa IB Metaphasa I

Metafasa IC Anaphase I

Anafasa ID Telophase I

Telofasa I

Diagram 15 shows four different types of plant tissues.Rajah 15 merutnjukkan empat jenis tisu tumbuhan yang berbeza.

Diagram 15Rajah I5

What are the function of the tissues?Ap akah fungs i tis ulis u ter s e but ?

rub'i.H

Y

A

B

C

D

w X Y ZFood storage

SlmoananmakdnanTransport

PensanskutanSupport

SokonpanTransport

PensanskutanFood storage

Simpanan makananTransport

PenpanpkutanTransport

PensanpkutanSupport

SokonsanSupport

SokonganTransport

PengangkutanTransport

PengangkutanFood storageSimpananmakanan

TransportPengangkutan

SupportSokongan

Food storageSimpananmakanan

Food storageSimpananmakanan

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27 The following information refers to a type of tissue.Berikut ialah maklumat mengenai sejenis tisu.

o Specialised to form hair-liked cells called cilia.Mengkhusus untuk membentuk struktur seperti rambut yang dipanggil silia.

o Secrete mucus.Merembeskan mukus

Which of the following organs is made up of the tissue above?Yang manakah antara organ di bawah mengandungi tisu tersebut?A Heart

JantungB Lungs.

PeparuC Small intestine.

Usus kecilD Trachea

Trakea

28 Diagram 16 shows the condition of red blood cell samples which have been placed indifferent concentration of salt solutions M and N.Rajah 16 menunjukkan keadaan sampel sel darah merah yang telah diletakkan di dalamkepekatan larutan gqram yang berbeza M dan N.

Conditionof red blood

cellKeadaan sel

darahmerah

SolutionLarutan

Salt solution MLarutan garam M

Salt solution NLarutan param N

Diagram 16Rajah 16

What are the type of solution M and N compared to the red blood cells?Apakahjenis larutan M dan N berbanding dengan sel darah merah tersebut?

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Solution MLarutan M

Solution NLarutan N

HypotonicHipotonik

HypertonicHinertonik

IsotonicIsotonik

HypotonicHinotonik

HypertonicHioertonik

IsotonicIsotonik

HypertonicHinertonik

HypotonicHipotonik

The graph shows the result of an experiment to determine the concentration of the cellsap ofpotato tissues.Graf menunjukkan keputusan satu eksperimen untuk menentukan kepekatan sap sel ubikentang.

Percentage change in mass / %Perakx perubohan jhim I Yo

Concsntration of sucroee solution I %Kepehatan Isrutan sakrasa / o/o

D

At which point A, B, C or D is the concentration of sucrose solution hypertonic to the cellsap ofpotato tissues?Yang manakah antara titik A, B, C atsu D merupakan kepekatan larutan sulcrosa yanghipertonik terhadap sap sel tisu ubi kentang?

Diagram 17 shows a process in a stage of cell division in a plant.Rajah 17 menunjukkan satu proses dalam peringkat pembahagian sel pada tumbuhan.

t7

B

c

D

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XK-XXDiagram 17

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Which of the following part of the plant does this process occur?Yang manakah antara bahagian tumbuhan berihtt proses ini berlaht?A Anther

AnterB Lateral bud

Tunas sisiC Cambium

KambiumD Root tip

Hujung akar

3l Which statements is true about meiosis?Kenyataan yang manakah benar tentang meiosis?A DNA replication occurs twice in meiosis

Replikasi DNA berlaht dua kali dalam meiosisB Uncontrolled meiosis can cause a disease named cancer

Meiosis tidak terkavval boleh menyebabkan penyakit dinqmakan kanserC The chromosomal behaviour in meiosis I is the same as in mitosis

Perlakuan lcromosom dalam rneiosis I sarna seperti dalam rnitosisD Synapsis and crossing over take place only in prophase I

Sinapsis dan pindah silang hanya berlaku dalam profasa I

32 Diagram 18 shows the various stages of mitosis.Rajah 18 menunjukkan pelbagai peringkat mitosis.

Diagram 18Rajah 18

Which of the following shows the correct sequence of the stages?Yang manakah antara berilrut menuniukkan susunan peringkat yang betul?

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33 Table I shows the differences between light reaction and dark reaction duringphotosynthesis.Jqdual I menuniukkan perbezaan antara tindak balas cahaya dan tindak balas gelapsemasa fotosintesis.

Light reactionTindsk balas cahava

Dark reactionTindak bulas selap

P Takes place in the stromaBerlahu di stroma

Takes place in the granaBerlaku di grana

a Oxygen is releasedOlaieen terbebas

Oxygen is not releasedOlrs i gen ti dak t erb e b as

R Occurs during day timeBerlaku padawahu siant

Occurs during the nightBerlaku padawahu malqm

S Glucose is not formedGlukosa tidak terbentuk

Glucose is formedGlukosa terbentuk

Table IJadual I

Which are the correct differences?Yang manakah perbezaan yang betul?A PandQonly

P dan Q sahajaB PandRonly

P dan R sahajaC QandRonly

Q dan R sahajaD QandSonly

Q dan S sahaja

Which of the following are products of aerobic and anaerobic respiration in musclecells ?Antara yang berikut yang manqkah hasil respirasi aerobik dan anaerobik di dalam selotot?

Aerobic RespirationRespirasi aerobik

Anaerobic RespirationRespirasi anaerobik

Carbon dioxide and waterKarbon dioksida dan air

EthanolEtanol

Carbon dioxide and waterKarbon diolcsida dan air

Lactic acidAsid laktik


EthanolEtonol


Carbon dioxide and waterKarbon dioksida dan air

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A

B

C

D

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35 What is the main cause of euffophication?Ap akah p unc a ut am a eutr ofi kas i ?A Burning of fossil fuels

P embakaran bahan api fos ilB Leaching ofexcess fertilizers

Larut resap lebihan baja tak organikC Thinning of ozone layer

Penipisan lapisam ozonD Greenhouse effect

Kesan rumah hijau

Diagram 19 shows a condition of stomata.Rajah 19 menunjukkan suahr keadaan stomata.

Guard cellsSel pengowal

Diagram 19Rajah 19

Which of the following may cause the condition?Yang manakah antara beribut menyebabkan keadaan tersebut?A High light intensity

Keamatan cahaya yang tinggiB Water enters the guard cells

Air masuk ke dalam sel pengavvalC Potassium ion leaves the guard cells

Ion kalium meninggalkan sel pengawalD High concentration of glucose in the guard cells

Kepekatan glukosayang tinggi di dalam sel penganal

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Diagram 20 shows an elbow joint .Which of the parts labelled A,B,C or D is tough and elastic tissue?Rajah 20 menunjukkan satu sendi siku.Yang manakah antara bahagian berlabel A, B, C dan D ialah tisu yang lcuat dan kenyal?

Diagram 20Rajah 20

A haemodialysis machine is used to eliminate urea from the blood of a personwith damaged kidney .Mesin haemodialisis digunakan untuk menyingkirkan urea daripada darahseseorang yang mengalami kerosakan ginjal.

--\

Which of the following condition enables the process? --->-.-

Yang manakah antara keadaan berikut membolehkan proses tersebut berlaku?

A -€oncentgtion of urea in the blood and in the dialysis fluid is the sameKepekatai ureqdi dalam darah adalah sama dengan kepekatan urea di dalamcecair dialisis

B. Concentration of water molecules in the dialysis fluid is'higher than in the bloodKepekatan molehtl air dalam cecair dialisis lebih tinggi daripada dalam darah.

C Concentration of urea in the dialysis fluid is higher than in the bloodKepekatan urea dalam cecair dialisis lebih tinggi daripada kepekatan urea dalamdarah

D Concentration of urea in the blood is higher than in the dialysis fluidKepekatan urea dalam darah lebih tinggi daripada kepekatan urea dalam cecairdialisis.


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Which of the following is thesystem?Yang manakah antara berikutendolvin?

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similarity between the nervous system and the endocrine

merupakan persamaan antara system saraf dan sistem

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Both work at the same speedKedua-duanya berkerja pada kelajuanyang samaBoth coordinate responses towards stimuliKedua-duanya menyelaras gerak balas terhadap rangsanganBoth use blood as the medium of transmissionKedua-duanya menggunakan darah s ebagai medium pemindahanBoth send signals to one specific effectorKedua-duanya menghantar isyarat ke satu efehor yang spesifik

Diagram 2l shows a chromosomal mutation.Rajah 2l menunjukkan satu mutasi lvomosom.

Diagrarn2lRaiah 21

Which of the following is the type of change in the chromosomal structure that causes themutation?Yang manakah antarajenis perubahan pada struktur kromosom yang berikutm eny eb ab kan p erub ahan ini ?A Deletion

PelenyapanB Duplication

PenggandaanC Inversion

PenyongsanganD Translocation

Translokasi


A

D

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SI'LIT* 23

4l Diagram 22 shows an experiment to investigate the rate of reaction of enzyme pepsin onalbumen.Raiah 22 menuniukkan satu elaperimen untuk mengkaji kadar tindak balas eruim pepsinke atas albumen.

Pepsin solutionLarutan pepsin

AlbumenAlbunen

Diagram22Rajah 22

The pepsin took l5 minutes to digest 0.259 of albumen atZ}0C.How much albumen will be digested in 15 minutes at 30oC?P_epsin nenganbil masa selama I5 rninit untuk mencernakan 0.259 albumen pada 200C.Berapa banyak albumen akan dicernakan dalam masa r s minit pada suhu 30"c?A 0.0gB 0.15 gC 0.25 gD 0.50 g

Table 2 shows the menu taken by a l0 year old boy.Jadual 2 menuniukkan menu yang diambil oteh seorang lcotak-tmnak letaki berusia t0tahun.

Breakfast:Saraoan:

White breadRoti putih

ButterMentega

Full cream milkSusu penuh lcrim

Lunch:Meleenjensah hari:

RiceNasi

Steamed fishIkanhtlauPlain waterAir kosong

Table2Jadual 2


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43

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Which of the following health problem may occur if he continuosly taking this menu fora long time?Yang manakah antara masalah kesihatan berikut akan berlaku sekiranya dia terusmengambtl menu ini untuk j angka mas a yang panj ung?

A ObesityObesiti

B GasritisGastritis

C ScurvyScurvy

D KwashiokorKwashiokor

An experiment was set up to study respiration in organisms.Diagram 23 shows the set up of the experiment.Satu eluperimen telah disedialqtn untuk mengkuji respirasi daktm organism.Rajah 23 menunjukkan penyediaan elxperimen tersebut.

Air goes inUdara masuk---*

GerminatingseedsBiji benih yangbercambah

To filter pumpKe pam penapis

_'>

Potasium hydroxide solution Lime water J Aluminiurn foil Lime water KLnrutsn natrium hidrciesida Air kapur J Pembalut aluminium Alr kapur K

Diagram 23Rajah 2j

Which of the following u,ill be observed after one hour?Antara berikut yang manakah ahan diperhatikan selepas satuiarn?A The lime water K turns cloudy because carbon dioxide is released during seed

germinationAir kapur K menjodi keruh karana lwrbon dioksida dibebaskan semaEa

., percambahan biji benihB The lime water K turns cloudy because carbon dioxide is needed during

photosynthesis.Air kapur Kmenjadi keruh kerana karbon dioksida diperlukan semasafolosintesis

C The lime water K remains clear beeause oxygen is required for seed germination.Air lupur K keful jernih kerana oksigen dipertulmn bagi percambahan biii benih

D The lime water J remains clear because oxygen is released during photosynthesis.Air lwpur J lrekal jernih kerana oksigen dibebaskan semasq prosesfotosintesis


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SUI,IT* 455111

44 Table 3 shows the re sult of an experirnent to study the popul*tion of grasshoppers in *urarea.Juduql 3 ntenunjukkan keputusan satu eksperimen unluk mengkaji populasi belalang disatu krwasan.

Number of capturcdBilangan tangkapan

Numbcr of grasshoppersBilanran helalanc

MarkedBerlanda

UnmarkedTidak Bertanda

First captureTangknpan pertame 180

Second captureTangkapan kedua

+) 100

Iable 3Jadual 3

What is the estimated population sizE of the grasshoppers in the area?Apakah anggaran saiz populasi belalang di kawaran tersebut?A7

B 180

c 261

D 580

Four sanrples of water were taken f'rom river J,K,L, and M and trea-ted with methyleneblue solution to determine the level of pollution in each river'The results were recorded in Table 4.Empal sampel oir telah diambil dari sangai J,K,L, and M dan dirau'al dengan lctnilanntetilena biru untuk menentuksn tahap pencemaran seliap sungai,Keputusan direkodkan dcrlum Jadual 4.

RiverSunsai

Time te.ken fbr the methylene blue solution to dccolouriseMasa vans diqmbil untuk lortttan metilena hiru melunlur

J l.Shour I iamt\ 3.0 hours I iantL 3.5 hours / lartM 5 hours / i'arr

Table 4,ladual 4

ILihat sebelahSUT,IT*

25

45.

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SULIT*

AJBKCLDM

4551/l

Based on the result, which river will have the highest population of fish?Berdasarl@n keputusan , sungai manakah akan mempunyai populasi ikan yang palingtinggi?

Dagnm 24 shows the set-up of the apparatus to investigate the rate of transpiration in aplant using a potometer.The observation is recorded in Table 5.Rajah 24 menunjulcl<nn susunan ratlus untuk nenyiasat ktdar transpirasi dalamt um h uhan menggu na kan Jbt ome t er.Pemerhatian telah direkodkan dalam Jadaol 5.

Plant shootPucuk tumhuhan

46.

RulerPembaris Air bubble

Gelembungudara

Diagram 24Rajah 24

Table 5Jadual 5


f

Time/lt4inuteMasa/minit

0 )

Position of air bubbleicmKedudukan gelembungudara/cm

0 3

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SUL.IT* zt 4551/l

What is the rate of transpiration of the plant ?Apalcah kadar transpirasi tumbuhan iti ?A 0.3 cm minute'r

B

cp

0.3 cm minit'r3.0 cm minute-l3.0 minit'r0.6 cm minift0.6 minit'l6.A cm rnintfl6.0 minifl.

47 Diagram 25 shows muscles in the hind leg of a grasshoppcr,Rajah 25 mewmluklcan otot pada kakt betihangieelcor t r&ong.

L

Diagram 25Rajah 25 .

What happen when the structure J is hoken?Apakah yang berlakujika stuklur J cedera?I

II

ru

ff

A

B

c

D

K ca*not pulled towariis the bodyK tidak boleh ditartk lw arah badan$ cannol propels the gmsbhopper for*ards and upwards into the airK tidak boleh menolak belalang ke hadapan dan ke udaraL cannot contract and causes K eannot be folded into a Z shapeL,tidak bokh melrgecut dan nenyt\babfun K ridak boleh dilipat ks bentuk zK cannot be straightenedK tidak boleh menjadi lurus

I and II onlyI dan II sahajoII and Ill onlyII dan III saha.ja.II and IV onlyII dan IV sahaja.III and [V only

III dan lVsahaja.

ll,ihat.se]slahSULIT*

\

4551/t 02ot I lrakciptalpNJ






SULIT*

48.

455u1

A medical check-up shows that a patient'spancrease is damaged and has to be removed.

P emerilcs aan p erubatan menunj ukkan panlcreasseorang pesakit rosak dan perlu dibuang.

Which of the following should be done by the patient to maintain a normal blood sugarlevel?Antara berikut, manakah yang perlu dilakukan oleh pesakit itu untuk mengekalkan arasgula darah yang normal?A Taking glucose injections

Mengambil suntikan glukosa

B Taking a balanced dietMengamalkan pengambilan gizi yang seimbang

C Taking insulin and glucagon injectionsMengambil suntikan hormon insulin dan glukagon

D Reduce intake of high calory foodMengurangkan pengambilan rnakanan b erkalori tinggi

49 The genotype of a pea plant is RRYy.Which of the following is the possible gamete produced by this pea plant?Genotip s attt pokok pea adalah RRYy.Antara berikut, yang manakah merupakan gamet yang mungkin dihasilkan oleh pokokkacang pea ini?

A. rYB. YvC. RYD. RR

50 A man with blood group AB married a wife with blood group O.What is the percentage of possibility for the couples to have r "rild with blood groupAB?Seorang lelaki mempunyai kumpulan darah AB berkahwin dengan seorang isteri yangberkumpulan darah O.Apakah peratus kebarangkalian untr.tk pasangan suami-isteri ini mempunyai seoranganak yang berkumpulan darah AB?

A0%B 25%c 50%D la0%

END QUESTION PAPERKERTAS SOALAN TAII,IAT


28

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SULIT* 29

INFORMATION FOR CANDIDATES

MAKLUMAT ANTUK CALON

4s5ut

l. This question paper consists of50 questions.

Kertas soalan ini mengandungi 50 soalan.

2. Answer all questions.

Jawab semua soalan

3. Each question is followed by four alternative answers, A, B, C and D. For each question,choose one answer only. Blacken your answer on the objective answer sheet provided.Tiap+iap soalan diikuti oleh empat pilihan janapan, A, B, c danD. Bagi setiap soalan,pilih satu jatvapan sahaja. Hitam ja,vapan anda pada kertas janapin obiikttf yangdisediakan.

4' If you wish to change your answer, erase the blackened mark that you have made. Thenblacken the new answer.

Jika anda hendak menukar jawapan, padamkan tanda yang telah dibuat. Kemudianhi tamkan j aw ap an yang b aru.

5. The diagrams in the questions provided are not drawn to scale unless stated.

Raiah yang mengiringi soalan tidak dilukis mengilat skala kecuali dinyatakan.

6. You may use a non-programmable scientific calculator.

Anda dibenarkan menggunakan kalkulator saintifikyang tidak boteh diprogram.


4551ll @ 2ot I Hak Cipra JpNJ






SULIT*4Ssu2BiologiKertas 2September20tl2%iam

455u2

Nama:

Kelas:

ANGKA GILIRAN


PEPERIKSAAN PERCUBAAN SPM 2011BIOLOGIKertas 2September 20112%iam

4551t2

Dua jam tiga puluh minit

I

JANGAN BUKA KERTAS SOALAN

Tulis nama penuh, kelas, nomborkad pengenalan dan angka gilirananda pada ruang yang disediakan.

Kertas soalan ini adalah dalamdwibahasa

Soalan dalam bahasa Inggerismendahului soalan yang sepadandalam bahasa Melayu.

Cqlon dibenarkan menjawabkeseluruhan atau sebahagian soalananda sama ada dalam bahasaInggeris atau bahasa Melayu.

Calon dikehendaki membacamaklumat di halaman belakangkertas soalan ini.

INI SEHINGGA DIBERITAHU

5.

Untuk kegunaan pemeriksa

Kod Pemeriksa:

Bahagian SoalanMarkahPenuh

MarkahDioerolehi

A

I t2

2 t2

3 t2

4 t2

f, t2

B

6 20

7 20

I 20

9 20

Jumlah

Kertas soalan ini mengandungi24 halaman bercetakJabatan Pelajaran Negeri Johor

455112 o 2ol l Hak cipta JPNJ SULIThttp://edu.joshuatly.com/





SULIT

ForExaminer's

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1(a)

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Section ABahagian A

[60 marks]

160 markahl

Answer all questions in this sectionJawab semua soalan dalam bahagian ini

Diagram I shows the process of synthesis and secretion of extracellular enzymes in

a cel l .Rajah 1 menunjukkan proses sintesis dan perembesan enzim luar sel di dalam satu

sel.

Diagram 1Rajah I

Based on Diagram 1, name X and Y.Berdasarkan Raiah l, namakan X dan Y.

(a)

12 marks)12 markah)






SULIT 4551/2

(b) Extracellular enzymes are enz).mes which are produced in the cell but secretedfrom the cell to function externally.Enzim luar sel adalah enzim-enzim yang dihasilkan di dalam sel tetapidirembeskan daripada sel untuk berfungsi di luar sel.

(i) Give one example of the cell shown in Diagram 1.Berikan satu contoh sel di dalam Rajah l.

I marks)ll markahl

(ii) Explain what will happen to the production of extracellular enzymes if ymalfunctions.Terangkan apayang akan berlaku terhadap penghasilan enzim luar seljikn Ytidak berfungsi.

[2 marks][2 narkah]

(c)Each enzyme has an optimum temperature at which its reaction rate is thefastest. Beyond the optimum temperature , an enzyme is said to be denatured.Setiap enzim mempunyai suhu optimum di mana kndar tindakbalasnyaqdalah malrsimum. Suhu yang melebihi paras optimum akan menyebabknnenzim ternvahasli.

Explain the above statement.Terangkan pernyatoan di qtas.

ForExaminer's

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1(bXD

LE

r(bxiD

t I ; tt r - l

l (c)

l r - lI l2 l

12 marksl[2 markah]

[Lihat sebelahSULIT

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SULIT

ForExaminer's

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l(d)

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t;455112 @ 2011 Hak Cipta JPNJ SULIT

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(d) A housewife uses an amylase-based detergent to wash her blood stained

clothe. She found out that the stain is not removed. Explain why.

S e o r an g sur irum ah m en ggun akan s er b uk p e)nc uc i b er as askan amyl as e untuk

*rn"uii bajunya yang terkena kesan darah. Beliau dapati kesan darah masih

ada. Terangkan menga7 a.

l2 marksl12 markahl

(e) A patient has gallstones that block his bile duct. Explain the effect of this

situation on the digestion of lipid.Seorang pesakit mempunyai batu karang yang menyumbat salur hempedunya.

Terangkan kesan keadaan ini terhadap pencernaan lipid.

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SULIT 455t/2

Diagram 2 shows a cellular component which is found in palisade mesophyll cells of aleaf.Rajah2 menunjukkan satu komponen sel yang boleh dijumpai dalam sel palisadmesofil dalam daun.

Outside the cellLuar sel

Inside the cellDalam sel

Diagram2Rajah2

(a) (i) Name the cellular component inDiagram2.Namaknn komponen sel dalam Rajah2.

ll markslll markah)

(ii) On Diagram 2,name P and Q.Pada RajahZ, namakanP danQ.

[2 marks]

12 markahl

(b)( i )onDiagram2,drawarrow(+)toshowthemovementofoxygenacross the cellular component during day time.Pada Rajah 2, lukis anak panah ( + ) untuk menunjukkanpergerakan oksigen merentasi komponen sel ini pada waHu siang.

[1 mark]

I markahl

[Lihat sebelahSULIT

ForExaminer's

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2(a)(i)

tr2(a)(ii)

2(bxi)

455112 @ 2011 Hak Cipta JPNJ






SULIT

ForExaminer's

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2(bxiD

LE

2(cXD

L_r

TotalM

r=atrza

-

6

(ii) Explain the answer in (b)(i).Terangkan jawapan anda dalam (b)(i).

455r/2

(b)

13 marles)[3 markah]

(c) In an experiment, the palisade mesophyl cell is immersed in distilled water fora certain period of time.Dalam satu el$perimen, sel palisad mesofil ini direndamkan di dalam airsuling untuk tempoh masa tertentu.

(i) Explain what will happen to this cellular component.Terangkan apa akan berlaku pada komponen sel ini.

13 mmlc)13 markah)

(ii) Draw a labelled diagram of the condition of palisade mesophyl cell afterbeing immersed in the distilled water.Lukis rajah berlabel keadaan sel palisad mesofil setelah direndamkondalam air suling.

[2 marks]

[2 markah]

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SULIT 4551t2

Diagram 3 shows the stages in a cell division.Rajah 3 menunjukkan peringkat-peringkat di dalam pembahagian sel.

xDiagram 3

Rajah 3

(a) (i) Name stages X and YNamakan peringkat-peringkat X dan Y

12 marksl12 markahl

Based on Diagram 3, state two differences between the chromosomalbehaviour in stage X and stage Y.Berdasarknn Rajah j, nyatakan dua perbezaan di antara perlakuan lcromosomdi peringkat X dan peringkat Y.

X:

(ii)

'/ Xff:\t ,

-

fio oB" \ t -

r r I I

l::= Ki( . '" ,

ForExaminer's

Use

3(a)(i)

t f rt r - l

3(aXii)

455112 O 2011 Hak Cipta JPNJ

12 marksl[2 markah]

[Lihat sebelahSULIThttp://edu.joshuatly.com/





F-

SULIT

ForExaminer's

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3(bxi)

LI

3(bxii)

tr3(bxiii)

tr

4551/2 @ 2011 Hak Cipta JPNJ SULIT

455r/2

(b) Number of chromosome in somatic cells of this organism is 24.Bilangan lcromosom di dalam sel somatik organisma ini adalah 24.

(i) State the chromosomal number of each daughter cell produced at the end

of the division shown in Diagram 3.Nyatakan bilangan k:romosom di dalam setiap sel anakyang terhasilmelalui pembahagian sel di Rajah 3

ll marklll markahl

(ii) Based on your biological knowledge; give a reason for your answer.Berdasarkan pengetahuan biologi anda, berikan satu sebab untukjawapan anda.

ll marklll markahl

(iii)Explain one important event that takes place during stage X.Terangkan satu peristiwa penting yang berlaku semasa peringkat X.

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SULIT

(c) Based on Diagram 3,division.Berdasarkan Rajah 3,pembahagian sel.

4551t2

draw one ofthe daughter cells produced at the end ofthe

lukiskan salah satu sel anakyang terhasil di akhir

12 marksl12 markahl

(d) Explain what will happen in human if the chromosomes fail to separate duringstage Y.Terangkan apa yang berlaku pada manusia jika lvomosom gagal terpisah semasaperingkat Y.

l2 marksl[2 markahl

pihat sebelahSULIT

455112 @ 20ll Hak Cipta JPNJ

ForExaminer's

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3(d)

| --lTotalA3

G






SULIT

ForExaminer's

Use

a(a)(i)

a(a)(ii)

4551t2

Diagram 4.I and Diagram 4.2, show the tissues in respiratory system in human andin plant respectively.Rajah 4.1 dan Rajah 4.2 masing-masing menunjukkqn tisu-tisu dalam sistemrespirasi manusia dan tumbuhan.

l0

Alveolialveoli

Diagram 4 .1Rajah 4.1

Diagram4.2Rajah 4.2

(a) (i) State the organ in which the tissue in Diagram 4.1 can be found.Nyatakan organ di mana tisu dalam Rajah 4.1 boleh dijumpai.

I mark]lI markahl

(ii) State the function oforgan stated in (a) (i).Nyatakanfungsi organ yang dinyatakan dalam (a)(i).

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SULIT

(b)

l l 4551/2

Explain how gaseous exchange occurs during respiration in Diagram 4.I andDiagram 4.2.Terangkan bagaimana pertukaran gas berlaku semasa respirasi dalamRajah 4.1 dan Rajah 4.2.

Gaseous exchange in Diagram 4.1:Pertukaran gas dalam Rajah 4.1:

Gaseous exchange in Diagram 4.2:Pertukarqn gas dalam Rajah 4.2:

ForExaminer's

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4(b)

l-:I lo l

14 marksl[4 markah]

(c) State two differences befween tissues in Diagram 4.land Diagram 4.2.Nyatakan dua perbezaan antara tisu dalam Rajah 4. I dan Rajah 4.2

[2 marks]| 2 markahl

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Exaniner'sUse

4(d)

L_tr

TotalA4r=

L-r|

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4s5r/2

(d) Srnokers do not r2al!z.e tha! they destroy their respiratory organ during smoking.Explain how this habit will affect the intake of oxygen efficiency.Perokok tidak sedar bahawa mereka akan merosakkan organ respirasi semasamer okok. Ter angkan b agaimana tab i at ini b oreh *r*p"nloruhi

-kecekapan

pengambilan olcsigen.

[4 marlal14 markahl






SULIT 13

5 Diagram 5.1 shows a food pyramidRajah 5.1 menunjukknn piramid maknnan

455U2

Lipid, salt and sugarLemah garam dan gula

^ Meat. chicken. fish and milkQ oosiis, ayam, iknn dan susu

Fruits and vegetablesBuah- b uahan dan s ayur - s ayur an

"

Rice, bread, noodle and potatoes" Nasi, roti, mee dan kenlang

Diagram 5.1Rajah 5.1

(a) P, Q, R and S are the different classes of food that make up the balanced diet.P, Q, R dan S adalah kelas-kelas makanan yang bbrbeza dalam gizi seimbang.

(i) Name the class of food labeled RNamakan kelas makanan berlabel R

(ii) State the functions of food in RNyatakanfungsi makanan di dalam R

lI marklll marknhl

ForExaminer's

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5 (a)

ttl l ' l

ll mark)lI markahl

[Lihat sebelahSIJLIT

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SULIT

ForExaminer's

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5(b)

LT

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455U2

(b) Junk food is food that is high in sugar, salt and fat. Explain the health problemsfaced by individual who continuously taken this food.Makanan rapu adalah makanan yang tinggi kandungan gula, garam danlemak.Terangkan masalah kesihatan yang dihadapi oleh individuyang mengambilmakanan ini secara berterusan.

13 marlal

13 markah)

(c) Table 5 shows the type and quantity of food taken by a moderately active adultman and a boy aged 15 years old.Jadual 5 menunjukkan jenis dan kttantiti makanan yang diombil oleh lelaki dewasasederhana ahif dan kanak-kanak lelaki berumur I5 tahun.

Type offoodJenis

makanan

Quantity taken/gKuantiti diambil/s

EnergyikJper 1009Tenaga/kIper I00g

Energy obtained/kJTenqpa diperolehi/kJ

moderatelyactive adult

manLelaki dewasq

sederhanqaletif

boy aged 15years old

Kanak-kqnaklelaki

berumur 15tahun

moderatelyactive adult

manLelakidewasa

sederhana0hf

boy aged15 years

oldKanak-kanaklelaki

berumurl5 tahun

RiceNasi

300 400 2 000 8000

WhitebreadRoti putih

100 r50 I 500 1500

ButterMenteea

50 50 3 000 1 500 1500

Potatokentans

100 100 500 500 500

MilkSusu

100 200 300 300 600

BananaPisans

50 100 50 25 50

ChickenAvam

200 200 800 1600 1600

Total energy obtainedJumlah tenagq diperolehi

Table 5Jadual 5

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SULIT 455U2

(i) Complete Table 5 by calculating the total energy obtained by each individual.Lengkapkan Jadual 5 dengan menghitung jumlah tenaga yang diperolehi oleh setiapindividu.

12 marlal12 markahl

(ii) Explain why boy aged 15 years old need more daily energy requirement whencompared to moderately active adult man.Terangkan mengapa budak lelaki berumur I5 tahun memerlukan lebih keperluantenaga harian berbanding lelaki dewasa yang sederhana aktif,

l2 marksl12 markahl

(d) Diagram 5.2 shows a boy suffering from nutrient deficiency disease.

i . .+.; .


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5(cXi)

s(c)(ii)






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5(d)

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(i) Identiff the deficiency disease shown in Diagram 5.2.Kenalpasti penyakit kekwrangan nutrien yang dituniukl(an dalam Rajah 5.2

ll marklll markahl

(ii) State the cause ofthe disease and possible efFects on children,Nyatakan punca penyakit dan kemungkinan keson yang dialami oleh kmak-kanak.

12 marlesl12 markahl

I6






SULIT L7 45slt2

Section BBahagian B

[ 40 marks ]140 marlmhl

Answer any two questions from this section.Jawab mana - mana dua soalan daripada bahagian ini.

6. (a) Diagram 6.1 shows the asexual reproduction canied outby Amoeba sp.Rajah 6.1 menunjukkan pembiaknn asela yang dijalankan oleh Amoeba sp.


Describe the process shown in Diagram 6.1.Huraikan proses yang ditunjukkan dalam Rajah 6.I.

[4 marks][4 marlmh]

Amoeba sp. is a unicellular organism which lives in fresh water environment.Althoughlmoeba sp. is made up of only a single cell, it can perform all livingprocesses.Amoeba sp. adalah satu organisma unisel yang hidup dalam persekitaran airtawar. Walau pun Amoeba sp. dibentuk oleh hanya satu sel, ia bolehmelalatlran semua proses kehidupan.

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(b)6

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!=

SULIT 4551/2

Explain the living process that enable Amoeba sp. to survive in fresh water which ishypotonic to the cytoplasmic fTuid of Amoeba sp.Terangkan proses kehidupan yang membolehkan Amoeba sp. unhk tents hidupdalam air tawar yang hipotonik kepada cecair sitoplasma Amoeba sp.

[6 marks]

[6 markah]

(c) Diagram 6.2 shows a human organ which is involved in regulating bodytemperature.

Raiah 6.2 menuniukkan satu organ manusia yang terlibat dalam pengawolan suhubadan.


Based on Diagram 6.2, explatnhow the animal tissues are organised to form theorgan in Diagram 6.2 and their roles in regulating body temperature during a hotday.Berdasarkan Rajah 6.2, terangkan bagaimana tisu haiwqn diorganisasi untukmembentuk organ dalam Rajah 6.2 dan peranan mereka dalam mengawal suhubadan dalom satu hari yang pqnas.

[0 marks]ll0 markahl

18







SULIT 455112

7 (a) Explain why the fertilisation process in flowering plant is known as doublefertilisation.Terangknn mengapa proses persenyawaan pada tumbuhan berbunga dipanggilpers enyrw aan gandadua.

[4 marks][4 markah]

(b) Diagram 7.1 shows the formation of the embryo sac in a flowering plant.Rajah 7.1 menunjukkan pembentuknn pundi embrio dalam tumbuhan berbunga.

t9

ll '

I

c->Embryo sec

Pundi embrio

Based on Diagram 7.1 describe how the formation of the embryo sac occurs.Berdasarkan Rajah 7.1, huraikan bagaimana pembentukan pundi embrio terjadi.

[ 6 marks][6 markahJ

[Lihat sebelahSULIT

I

f i$$Matwe

unbryo sacPundi embrio

matang Diagram7.lRajah 7.1

455112 @2011 Hak Cipta JPNJhttp://edu.joshuatly.com/





r - - !

SULIT 4551/2

(c) Diagram 7.2 shows male and female reproductive organs of a plant.Rajah 7.2 menunjukkan organ pembiakan jantan dan organ pembiakan betina bagitumbuhan.

StamenStamen

20

Stigma

Pollen tubeTiub debunga

Embryo sacPundi

OvaryOvari

Male reproductive organOrgan pembiakan jantan

Female reproductive organOrgan pembiakan betina

DiagranT.2Rajah 7.2

(c) Based on the diagram describe how double fertilization occurs in the plant.B er d as arkan r aj ah, hur a ikankan b a gaim ana p er s eny aw aan gandadua b er I akudalam tumbuhan tersebut.

110 marlcslftO markahJ







SULIT 2l 4551/2

[Lihat sebelahSULIT

(a)Diagram 8.1 and Diagram 8.2 show the impact of human activities to thequality of natural environment.Rajah 8.1 dan Rajah 8.2 menunjukknn impak aktiviti manusia ke atas htalttialam semulajadi.


4551/2 @ 201 1 Hak Cipta JPNJhttp://edu.joshuatly.com/





SULIT 455u2

State the phenomena shown in Diagram 8.1 and Diagram 8.2.Nyatakanfenomena yang ditunjukkan di Raiah 8.1 dan Rajah 8.2.

l l markl

f l markah]

Discuss the differences of both environmental phenomena shown in Diagram 8.1and Diagram 8.2 based on the following aspects:O the causeso the effects ando the ways to overcomeBincangkan perbezaan kedua-duafenornena alam sekitar yang dituniukkan diRajah 8.1 dan Rajah 8.2 berdasarkan kepada aspek-aspek berihtt:O puncao kesandano cara untuk mengatasi

I I0 marks lll0 markahl

Explain the importance of preservation and conservation of tropical rainforest inMalaysia for the purpose of sustainable management of ecosystem.Terangkan kepentingan pemeliharaan dan pemuliharoan hutan huian tropikal diMalaysia untuk tujuan pengurusan berterusan ekosistem.

19 marks I[9 markah]

22

(ii)

(b)







SULIT 455t/2

9 (a) Diagram 9 shows three types of neurones in human being. Duringvoluntary action, all types of neurones must be coordinated to react onstimulus.

Rajah 9 menunjukkan tiga jenis neuron yang terdapst dalam manusia.Semasa tindakan terkawal, semua jenis neuron akan dikordinasiknnuntuk bergerakbalasn.

Efferent neurone Interneurone Afferent neuroneNeuron eferens interneuron Neuron aferens

Diagram 9Rajah 9

Ahmad is a Johore state goal keeper. Explain how Ahmad able to push theball away from the goal post areainthe penalty kick.

Ahmad adalah penjaga gol negeri Johor. Terangknn bagaimana Ahmadmampu menolak keluar bola dari kawasan tiang gol semasa sepaknnpenalty.

[10 marks]| 10 marknhl

(b) Homeostasis is the maintenance of constant internal environment. Thenormal blood sugar concentration in human is 75- 110 mg/100 ml.Homeostasis adalah pengekalan persekitaran dalqm. Aras gula darah yangnormal pada manusia adlah 75-I I0 mg/l00ml.

Explain how to regulate the blood sugar level in the normal range.Terangkan bagaintana mengawal aras gula dalam darah pada julat normal

[1Omarks]I l0 markahl

END OF QUESTION PAPERKERTAS SOALAN TAMAT

455112 @ 2011 Hak Cipta JPNJ fl,ihat sebelahSULIT

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SULIT* 455u2

written in separate answering paper' You may use

and other suilable ways maybt: used lo clarify your

24

l .

,,

INtrOR1VTATION FOR CANDIDATESMAKLUMAT T]NTUKCALON

This question paper consists of twp sections: section A and section B.

Kertss soalan'ini mengandungi dau bahagian: Bthagian A dan Bahngian B'

Answer all tluestions in section A and any hvo questions fronr seetion B-

Jay,ab **rouu soulun dakm Bshagian A dbn mana-ntana dua soalan daripada

Bah*gian B.

The answers to Section A must be written in the space provided in the question paper.

Important steps in any calculation must be shown.Jawapan 6agr Bnh&gi*n A hendawah dittlis pada ruong ynng disediqkan dslam kertas

soclan ini.

6.

,|

8.

9,

4. 'fhe answers to Seetion B must beequations, diagrams, tables, graPhsanswerc.Jmuapan bagi Bahngian B hendaklahboleh menggunakan persamaan, raiah,menJ elaskan i aw cpan anda.

ditulis pada kertas ia*-apttn berasingan' Andajadual, graf dun cara lctin yang,setirtili u[uk

If you wish to change your answsr, neatly cross out the answer thal you have done' Then

urite down the new answer'Jikn attda hendak menukar imt;apan, batslkffi jtn:apan iawapan yang telah dibual.

Kemadian tulis i m,raPttn Yang baru.

Marks allocated for each question of part question are shown in brackets.

Markah yang diperuntukkan hagi seiiap ioalan atqu ceraian soalan dituniuk:kan dalam

kurungan.

The time suggested to answer scction A is 90 minutes and section B is 60 minutes.

Anda dinaiiiati supaya mengambil masa 9t minit unluk me4iawab soalan dalam

Bahrgian A. dan 6A minit untuk B*hagi*n B.

The diagrams in the questions are not drawn to scale unless stated.

Rajah;ang mengiringi soalsn tittak dilukis mengikut skala lcecuali dinyatakan'

You may use a non-programmable soientific calculator'

Ancla dibenarkan menggunakan kalkulatir saintifik yang tidak baleh diprogram'

455112 $ 2or I lrak ciptrr JPNJ SULIThttp://edu.joshuatly.com/





SULIT*455U3BiologiKertas 3September20tll% jam

Nama:

Kelas :

455u3

NO. KAD PENGENALAN


PEPERIKSAAN PERCUBAAN SPM 2OIIBTOLOGIKertas 3September 2011l% jam

455113

Satu jam tiga puluh minit

JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

f .

2.

Tulis nama penuh, kelas, nomborkad pengenalzn dan angka gilirananda pada ruqng yqng disediakqn.

Kertas soalan ini adqlah dalamdwibqhasa

Sohlan dqlam bahasa Inggerismendahului soalqn yang sepadandqlam bahasa Melayu.

Calon dibenarkan meniawabkeseluruhan atau sebahagiqn soalananda sama ada dalam bahasaInggeris atqu bahasa Melayu.

Calon dikehendaki membacamaklumat di halqman belakangkertas soalan ini.

5.

Untuk Kegunaan P emeriks q

Kod Pemeriksa:

SoalanMarkahPenuh

MarkahDiperolehi

I JJ

t t7

Jumlah

Kertas soalan ini mengandungi 12 halaman bercetakJabatan Pelajaran Negeri Johor

[Lihat sebelahSULIT*455113 o 2o1l Hak cipta JPNJ http://edu.joshuatly.com/





SULIT

I .

Tray AKotqk A

Step ILangkah I

Step 2Langkah 2

Step 3

Langkah 3

Step 4Langkah 4

Step 5

Langkah 5

Step 6Langkah 6

X 5cmX X

XXXX

XXXX

XXXX

Tray BKotak B

X X2ssX X X

XXXXX

XXXXX

XXXXX

XXXXX

XXXXX

XXXXX

2

Answer all questionsJawab semua soqlqn

A group of students carried out an experiment to study the effect of intraspesificcompetition on the growth of paddy seedlings.Sekumpulan pelajar menjalankan eksperimen untuk mengkaji kesan persainganInnaspesifik terhadap pertumbuhan anak benih padi.

Diagram I shows the apparatus set-up of the experiment.Rajah I menunjukkan sl$unqn radqs untuk eksperimen tersebut.

X lo. . X X

X

X

X

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[Lihat sebelahSULIT

Tray CKotak C

Diagram 1Rajah I

Three seedlinging trays are filled with 4 kg of garden soil.Tiga kotak semaian diisikan dengan 4 kg tanah kebun.

The trays are labeled as A, B and C.Kotak-kotak semqian dilqbelkqn A, B dan C.

In tray A, 30 paddy seedlings are seedlinged at a distance of l0 cm intervalsIn tray B, 30 paddy seedlings are seedlinged at a distance of5cm intervalsIn tray C, 30 paddy seedlings are seedlinged at a distance of 2cm intervals.Dalqm kotak A, 30 anak benih padi ditanam pada jarak 1 1cm berselang

seliDalam kotak B, 30 anak benih padi ditanam padajarak 5 cm berselang seli,Dalam kotak C, 30 anak benih padi ditanam padajarak 2 cm berselang seli

Each tray is watered daily with the same amount of water for 30 days.Setiap kotak semqian disirant tiapliap hari dengan jumlah air yang sama

banyak untuk 30 hari.

After 30 days, removel0 paddy seedlings randomly from tray A,tray B andtray C. The root of seedlings are washed and wipe dry.Selepas 30 hari, I 0 qnak benih padi dikeluarkan secara rawqk dari kotak A,kotak B dan kotak C. Akar anqk benih dibersih dan dilapkan sehingg kering.

The dry weight of the paddy seedlings is recorded in Table l.Berat kering anak benih padi dicqtatkan dalqm Jaduql l.

455311@ 20llHak Cipta JPNJ






SULIT

ForExaminer's

Use

(a) Record the dry weight of the paddy seedlings in the boxes provided in Table 1.Rekodkan berat kering anak benih padi di dqlam kotak yang disediakqn dalqmJaduql l.

[ 3 marks]

[3 markahJ

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pihat sebelahSLILIT

Distance betweenpaddy seedlings

Jqrak qntara qnakbenih padi (cm)

Dry weight of l0 paddy seedlings / (g)Berat kering 10 anak benih padi / (g)

10

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Distancebetween paddy

seedlingsJarak antara

anak benih padi(cm)

Dry weight of l0 paddy seedlings / (g)Berat kering l0 anak benih padi / (g)

SULIT

Table IJadual l

455U3

[Lihat sebelah

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SULIT

(b) (i) State two different observations made from Table I 'Nyatakan dua pemerhatian yang berbeza yang dibuat daripada Jadual 1.

Observation I :Pemerhatian I :

Observation 2 :Pemerhqtian 2 :

455r/3

ForExaminer's

Use

1(bxi)

1(bxi i)

r:lI 13 |

[Lihat sebelah

SULIT

[ 3 marks][3 markah]

(ii) State the inference which corresponds to the observations in I (b) (i).Nyatakan inferens yang sepadan dengan pemerhatian di I (b) (r.

Inference from observation I :Inferens daripada pemerhatian I :

Inference from observation2 :Inferens daripada pemerhatian 2 :


455311@ 20llHak Cipta JPNJ






ForExaminer's

Use

1(c)

[-I 13 |

1(d)

t=I 13 |

SULIT 455U3

(c) Complete Table 2 based on this experimentLengkapkan Jqduql 2 b erdas arkqn el<s pr ime n i ni

Table2Jqdual 2

(d) State the hypothesis for this experiment'Nyatakan hipotesis bagi elrsperimen ini.


VariablePembolehubah

Method to handle the variableC ar q mensend qli p embolehub ah

Manipulated variableP emb o lehub ah d im anipul as i

Responding variableP emb ol ehub ah b er ger akb alas

Constant variableP emb o I ehub a h d im a I ar kan


[Lihat sebelahSULIT

4513ll @ 201 lHak Cipta JPNJ






SULIT

(e) (i) Construct a table and record all the data collected in this experiment.Bina satu jadual dan rekodkan semua data yang dikumpul dalam eksperimen ini.

Your table should have the following title.Jadual anda hendaklah mengandungi tajukiaiuk berikut.'

Y Distqnce between paddy seedlingsJarqk antarq anak benih padi

) Dry weight of l0 paddy seedlingsBerat kering 10 anak benih padi

F Growth rate of paddy seedlingKadar pertumbuhan anak benih padi

Growth rate Dry weieht of paddv seedlineNumber of days

Kadar Pertumbuhan Berat kerinq anak benih oadiBilangan hari

455r/3


[Lihat sebelahSULIT

455311 @ 20l lHak Cipta JPNJ

ForExaminer's

Use

1(eXi)

r:lI 13 |






1(e)( i i )

t-:lI t3 |

SULIT 455113

(ii) Use the graph paper provided on page 7 to answer this part of question.Using the data in 1(e)(i), draw the graph of the growth rate of paddy seedlings againstthe distance between paddy seedlingGunakan kertas graf yang disediakan dalam di mukasurat 7 untuk menjawab soalqnbahagian ini.Menggunakan data 1@(i), lukiskan graf kadar pertumbuhan anak benih padimelawan jarak antara anak benih padi.


[Lihat sebelah

SULIT

t i-

t--ffiI'i'; 1'' '-i,;1*

455311o 20 t lHak cipta JpNJ






(f)

4551/3

Based on the graph in I (e) (ii) , explain the relationship between the growth rate

of paddy seedling and distance between seedling.Berdasarkan kepada graf di I (e) (ii), terangkan hubungan antara kadarperumbuhan anak benih padi dengan jarak antara anak benih.

This experiment is repeated by increasing the distance between the paddyseedlings to 20 cm.Predict the observation.Explain your prediction.Eksperimen ini diulang dengan menambah jarak antara anak benih padi pada 20cm.Ramalkan pemerhatian.Terangkan ramalan qnda.


(h) Based on the result from the experiment, what is the operational definition ofintraspesific compeJition..Berdasarkan keputusan daripada eksperimen ini, apakah definisi secara operosipers aingan intras pesifik.

[ 3 marks][3 markah|

[Lihat sebelah

SULIT

(e)

4553/1 O 20l lHak Ciota JPNJ

1(0

r-I l3 l

1(s)

t--I l3 l






I

ForExaminer's

Use

1( i )

t--I 13 |

SULIT l0 4551/3

(i) When resources are in limited supply, organisms living in the same habitat willcompete for the same resources.The following is a list of the resources.Apabila sumber-sumber menjadi terhad, organisma hidup di habitat yang sama akanbersaing untuk sumber yang sama.B erikut iqlah s enarai sumb er-sumber ters ebut.

FoodMakanan

WaterAir

SpaceRuang

LightCahaya

Breeding matePasangan mengawqn

In Table 3, classi$'the resources given, according to what are the resourcescompeted by animals and resources competed by plants.Dalam Jadual 3, klasifikasikan sumber-sumber yand diberi, mengikttt apakahsumber-sumber yang disaingi oleh hqiwan dan sumber-sumber yang disaingi olehtumbuhan.

Resources competed by animalSumber-sumber yang disaingi oleh

haiwan

Resources competed by plantSumber-sumber yang disaingi oleh

tumbuhan

Table 3Jadttal3


[Lihat sebelah

SULIT4553/l @ 2ol tHak Cipta JPNJ






SULIT l l

*rl

2. Transpiration is the loss of water vapour by living plants through evaporation to theenvironment. The rate of transpiration is affected by extemal conditions.Transpirasi adalah proses kehilangan wap air oleh tumbuhan hidup melalui sejatan kepersekitaran. Kadar transpirasi ini dipengaruhi oteh keadaan luaran.

Based on the given information, plan a laboratory experiment to study the effect of windspeed on the rate oftranspiration in a plant.Berdasarkqn maklumat yang diberi, rekqbentuk satu eksperimen mqkmal untuk mengkajikesan laju angin ke atas kadar transpirasi dalam satu timbuhqn

The planning of your experiment must include the following aspects:P er anc an gan eks p er im en and a he n daklah m e l iputi os p ek- asp ek b e rikut ;

o Problem statementPenyataan masalah

o VariablesP em b ol ehu b ah-p em b o I e hub ah

' HypothesisHipotesis

r List of materials and apparatusSenarai bahan dan radas digunakan

o ExperimentalprocedureProsedur eksperimen

e Presentation ofdataC qr a data dipers emb ahkan

END OF QUESTION PAPERKERTAS SOALAN TAMAT

4551t3

[Lihat sebelah

SULIT

IF

4553/l @ 20nHak cipta JpNJ






SULIT 4s5U3

INFORMATION FOR CANDIDATESMAKLAMAT UNTUK CALON

1. This question paper consists of two questions. Answer all questions.Kertas soalan ini mengandungi dua soqlan. Jawab semua soalan.

2. Write your answers for Question I in the spaces provided in the question paper.Tuliskanjawapanbagi Soalan I dalamruqngyqngdisediqkandqlamkertas soalqn.

3. The answers for Question 2 must be written in separate answering paper. You may use

equations, diagrams, tables, graphs and other suitable methods to explain your answer.Jawapan bagi Soalan 2 hendaklah ditulis pada kertas jawapan berasingan. Andq bolehmenggunakin persamaan, gambar rajah, jadual, graf dan cara lain yang sesuai untuk

menj el as kan j aw ap an anda.

4. Show your working, it may help you to get marks'Tunjukkan kerja mengirq, ini membantu anda mendapatkan markah'

5. If you wish to change your answer, neatly cross out the answer that you have done. Thenwrite down the new answer.Jika anda hendak menukar jawapan, batalkan jawapan jawapan ltang telah dibuat.

Kemudian tulis iawapan yang baru.

6. The diagrams in the questions are not drawn to scale unless stated.Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan.

7. Mark allocated for each questions or part question are shown in brackets.Markqh yang diperuntukkan bagi setiap soalan qtau ceraian soqlan dituniukkan dalam

kurungan,

8. The time suggested to answer Question I is 45 minutes and Question 2 is 45 minutes.Masa yang dicadangkan untuk menjawab Soalan l'ialqh 45 minit dan Soalan 2 ialqh 45

minit.

9. You may use a non-programmable scientific calculator.Anda dibenqrkan menggunqkan kqlkulator saintifik yang tidak boleh diprogram.

10. Hand in all your answer sheets at the end of the examination'Serahkan kertas soalan ini di akhir peperilcsaan.

Marks awarded I Pemberian markah:

Score/ S/ror Description / Penerangan

aJ

Excellent : The best responseCemerlang : Respons yang paling baik

2Satisfactory : An average response

Memuaskan : Respons yang sederhana

Weak : An inaccurate responseLemah : Respons yang kurang tepat

0No response or wrong response

Respons salah atqu tiada memberi respons

l2

455311 @ 20llHak Cipta JPNJSULIT






lLT-ilT* T.

PERATURAN PEMARKAHANBIOLOGI KERTAS 1

PERCUBAAN SPM 201 I

END OF MARKING SCHEMEnr iD, l . r r rD,, t AI Dtr l t , t DV n tJ, l^ t . r l i t / . r

/ LIV\! a/Vf)r / L jv l t i t ra\ f l / / l ! t / / lJ t l tL!

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:

=

=:

=

-:

-

=

=

=

=

::

-

=:

-

=

=

SOALAN JAWAPAN SOALAN JAWAPAN

I A 26 B

)ft 71 D

3 A 28 D

4 A 29 D

5 A 30 A

6 C 31 D

7 C 32 B

8 D 33 D

9 A 34 B

10 B 35 B

AI1 36 C

t2 D DJ/

13 C 38 D

t4 C 39 B

15 C 40 C

r6 B 4l D

t7 A 42 C

18 D 43 A

L9 A 44 D

20 D 45 D

2l B 46 C

22 A 47 C

)a C 48 C

24 D 49 (-

)< C 50 A

455111 @ 2or I Hak ciota JpNJ






SULIT 2

Marking schemeSection A

45sU2

i1

JUEUNo Marking scheme Mark1(a) Able to name X and Y.

Answer:X: RibosomeY: GolgiapParatus

1I 2

(bxi)

(ii)

Able to give one examPle of the cellAnswer:Pancreas// lleum// stomach epithelial cell// salivary cell

Able to explain ttre effec{ on the production of extracellularenzyme if organelle Ymalfunction.

Sample answers :F: The production of extracellular enzyme is incornpletei

disrupted/ affected.E'l : (wiihout Golgi apparatus/Y), the protein cannot be modified

into extracellular enzYme.E2 : Protein cannot be sorted.E3 : Extracellular enzyme cannot be released/ transported to the

targeted cell/ organ.Any 2

1

tI

1

11

3

(c) Abte to explain denaturation of enzyme.

Sample answers :ffiigh temperatures alter/ change the (three dimensional)

shapd of the active site of enzyme molecules.E2 : substrates thus can no longer fit into the active sites of the

enzyme.E3 : the reaction cannot be canied ouU/ substrate cannot be

hydrolysed.

4I

1

1

2

(d) Able to explain the reason why the blood stained cannot beremoved.

Sample answers :E1 Blood is made uP of Protein.E2 Protein is broken down /digested by Protease (enzyme)'E3 Therefore the use of Amylase (enzyme) in the cletergent

powder would not be effective.Any two

11

1 A

4j i 112 .c lUl l . l l t tk ( ' t l t t t r ' / l ' , ' r ' lhttp://edu.joshuatly.com/





SULIT 455112

MarkMarking schemefo Jr':rai ' l i tre Jtrecfoi-t ia-ria- i:tte ductstc t t re dtgesi ion of

l rpros.

Sampl-e answers :E1 Gallstones blocked the secretion of bile.E2 Lipids cannot be emulsif ied.E3 The rate of lipase reaction will become slower// digestion of

l ipids wil l be disrupted/ is incomplete.The patient might face obesity// become obese.3E

111

E4An

hypertonic to dist i l led waterE2 - Water molecules di f fuse into the cel l by osmosrs

?l _, , :a ^r ; i l i .?--r /c, ,yql l i lD

,* . i1, i ,

Il tt li

TOTAL MARKS

No Marking S!I9!!9 Mark2 (a) (i)

( i i )

Able to name the cellular component'

Answer:Plasma/ cell membrane.

Able to name P and Q.

Answer: ' "P: Phospholipid bilaYerQ: Carrier Protein

I

11 3

(bxi) Am to6-Ew affow to show the movement of oxygen across thiscellular component during day time.

AnswerArow trom inside the cell to outside the cell, pass throughphospholipid bilaYer

1 1

(bxii) Able to explain the answer in (bXi).

Sample answers:E1 lOuiing day time), photosynthesis occurs in the cell to

produce 02.EZ - O2diffuses from higher concentration region to lower

concentration region// 02 diffuses by following theconcentration gradient'

E3 - 02 is non - polar molecule/ small moleculeE4 - 02 diffuses through phospholipid bilayerAny 3

Ab

Samole answerf - f f r rs Cel lu lar component i p lasma membrane is pushed

against the cel l wal l .Et -b ist i l ,ed water is hypotonic to the cel l sap l l Cel l sap is

I

4I

4I

4I

J

1

1

(cXi)

455112 O 201 | tlak LtiPrtt JPNJ ,SL LIl'

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Markinq Schemeof the condi t ion of Pal isade

mesophyl cell after being immersed in the disti l led water.

D- The shape of the cell must be rectangular'The cellwall is drawn with double lineThe vacuole must be large

L - Label vacuole

" Reject other shaPe of the cell.

(c)( i i )

TOTNI MARKS

SULIT455112

3 MarkNo m

Answer:X: ProPhase IY: MetaPhase I

Able to sttte two differences betweenchromosomal behaviour at X and Y'

@ lHomologouschromosomes I| .ruornotomds are ananged I are arranged on the II irnaotry | 13laonase

plate/ equatorial II I o lane I

f f ine lThecentromeresofthe II lt"ororomes are not hold by/ | chromosomes are hold b.y/ II rttr inuO to any spindle fibre. I attached to the spindle fibres' I

l t l ll l ' | = , ; : : II fD3_ Crossilrg over tat<es Ftace I Crossing over has already II I n.1*""n the'non-sister I taken plac,e between the non- iI I cf,romattOs I sister chromatids I

I Anv two.

11 2

3 (a) (i)

1

I

I

2

3 (a) (ii)

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No Marking Scheme Mark( i )(b) Able to state the chromosome number in each of the

daughter cell produced.

Answer:12 chromosomes 1 1

( i i)(b)J Able to state reason for answer in (bXi)

Sample answer:E2 : During meiosis, the cell undergoes two nuclear divisions but

the chromosomes /DNA of each chromosome only replicatesonce.

E3 : Each daughter cell receives half the number of chromosomesfrom the parent cell.

Any one E

1

1 2

3 (bxiii) ante to explain one important event that takes place during stageX

Sample answers;F1: Crossing overE1: An exchange of segments of DNA between non-sister

chromatids of homologous chromosomes'E2: which results in new combinations of genes on achromosomeAny two

11

1 2

3 (c) T5'leE-draw one daughter cell produced at the end of the meioticdivision,

@@zA\,,A\

@@Any one daughter cell with the correct combination ofchromosome

SLILIT 455112

i I Correct drawlng of cirromosortnq (numQer ajld combination) - i i I

455112 O 201 1 Hak CiPta JPNJ SUL]Thttp://edu.joshuatly.com/





No Marking Scheme MarkD1{Correct drawing of the cellnuclear membrane) - D2/

(chromosomes are enclosedlna 1

I 23 (d) Able to explain the effect in a human if the chromosomes fail to

separate during stage Y.

Sample answer:E1: One of the daughter cells produced might contain one extra

chromosome / one lesser chromosomeE2: During fertilization, if the cell with an extra/ lesser

chromosome fuses with a normal sperm, the zigote shallcontain one extra/47 ll one lesser/ 45 chromosome/s

E3: producing Down's / Klinefelter's // Turner's Syndrome baby/offspring.

Any two.

'lI

1

1 2

12

SULIT 455112

UESTIONNo Marking Scheme Mark

4 (a) (i) Able to state organ in which the tissuefound.

Answer:Lungs

in Diagram 4.1 can be

I 2

4 (aXii) Able to state the function of organ named in (a

Samqle answer:Gaseous exchange // respiration.

xi).

4 (b) Able to explain how gaseous exchange occurs during respirationin Diagram 4.1 and 4.2.

Sample answer for Diaqram 4.1 :Fl Oxygen diffuses from alveolus into blood capillaries.E1 Oxygen concentration/ partial pressure in alveolus is higher

than in blood capillaries.F2 Carbon dioxide diffuses from blood capillaries to the alveolus.E2 Carbon dioxide concentrationi partial pressure in blood

capil laries is higher than in alveolus.Max: 2

Sample answer for Diaqram 4.1:F1 Oxygen diffuses into mesophyll cells.E3 Oxygen diffuses into the spaces between mesophyll cells

through stoma.F2 Carbon dioxide diffuses out from the space (between cells/

mesophyll cells) in the leaves to the atmosphere.E4 Carbotr d ioxide concentrat ion/ part ia l pressure in blood

e ani l lar ies is hicrher than i r r a lveolus

4I

1

11

11

1

1

2

nL

455112 i t ;201 | I luk ( . ' iptu. / l ' iY, / S'L'L17-






S{ILIT

ESTION 4

4 (b) Able to explain how gaseous exchange occurs during respirationin Diagram 4.1 and 4.2.

Sample answer for Diaqram 4.1 :F1 Oxygen diffuses from alveolus into blood capillaries.E1 Oxygen concentration/ partial pressure in alveolus is higher

than in blood capil laries.F2 Carbon dioxide diffuses from blood capillaries to the alveolus.E2 Carbon dioxide concentration/ partial pressure in blood

capil laries is higher than in alveolus.Max: 2

Sample answer for Diaqram 4.1:F1 Oxygen diffuses into mesophyll cells.E3 Oxygen diffuses into the spaces between mesophyll cells

through stoma.F2 Carbon dioxide diffuses out from the space (between cells/

mesophyll cells) in the leaves to the atmosphcre.E4 Carbotr dioxide concentration/ partial pressure in blood

e ani l lar ies is hiol rer than in alveolus

1,|I

11

455U2

No Markinq Scheme MarkDIr 'Correct drawing of the cellnuclear membrane) - D2/

(chromosomes are enclosedln d 1

1 23 (d) Able to explain the effect in a human if the chromosomes fail to

separate during stage Y.

Sample answer:E1: One of the daughter cells produced might contain one extra

chromosome / one lesser chromosomeE2: During fertilization, if the cell with an extra/ lesser

chromosome fuses with a normal sperm, the zigote shallcontain one extra/47 ll one lesser/ 45 chromosome/s

E3: producing Down's / Klinefelter's // Turner's Syndrome baby/offspring.

Any two.

1

aI

1 2

12

4 (a) (i) Able to state organ in which the tissue in Diagram 4.1 can befound.

Answer:Lungs

Able to state the function of organ named in (aXi).

Sample answer:Gaseous exchange // respiration.

455112 t t , ;201 | l luk ( . ' ipr t t . / l 'N, / SL'L17-






SIILiTA<<1 l ' llJJI IL

No Markinq Scheme

4 (c\ A.ble to state two differences between ttssue Diaqram 4.1

5(a) i) AO6tfiame the class of food labeled R

5(a)ii)

AnswerRoughage / dietary fibre

Able to state the functions of RAnswerffimutates peristalsis//prevent constipation//absorbing andeliminating toxic substances

5(b) Able to state the health ProblemsArtswerffiGrconsumption of salt (sodium) causes lt lgh blood

pressure leadlng to heart disease /stroKeP2. Overconsumption of sugar causes ovenrveighUobesity

//diabetes//dental cariesp3. overconsumption of l ipid causes obesity//cardiovascular

diseases

t issue in Diagram 4.2

Sample answer:@

I lHuman) | (Plant) |I D1- Alveolus I Lear I

I OZ- Carry out respiration I Carry out photosynthesis I

t t l

Any two D

1

1

1 2

4 (d) m to;iplain how smoking affect the intake of oxygen

9?mple answers:E1: Carbon monoxide.E2: bind with haemoglobin to form carboxyhaemoglobinE3: less oxygen combine with haemoglobin.E4: tobacco tar will be deposited/ logged/ accumulated (inside the

lungs)E5: reduce diffusion of oxYgenE6: Heat from the smokeE7: Dry the surface of the alveoliE8: Oxygen cannot be dissolvedAny four

111

1111 4

12

QUESTIgN 5

Scheme

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SULIT 4551t2

No. Markinq Scheme Marks(cXi)

5(cXii)

5(dxi)

5(dxii)

Able to calculate the energy obtained by each individualAnswerModerately active adult manRice: 6000Totaf energy obtained: 11425

Boy aged 15 years oldWhite bread:2250Total energy obtained: 14500

Able to explain why boy aged 15 years old need more dailyenergy requirement compare to moderately active adult manAnswerP1. Boy aged 15 years old is more active compare to

moderately active adult man.P2. Boy aged 15 years old still undergoing growth process

Able to identifiy the deficiency diseaseAnswerRicket

Able to state the cause of the disease and posible effucts inchildrenAnswerCause: lack of vitamin D/calciuferolPosiOte effects in children: bent ieg

It

1

1

1

1

11

2

2

3

TOTAL MARKS 12

455112 @ 2011 Hak Cipta JPNJ SULIThttp://edu.joshuatly.com/





SULIT 455t/2

No Marking scheme Mark6(a) Able to describe the process shown in Diagram 6.1.

Sample answerP1 - The process is binary fissionP2 - When Amoeba sp. has grown to certain sizeP3 - The nucleus divide by mitosisP4 - Then the cytoplasm divides // Cytokinesis occursP5 * Form 2 genetically identical Amoeba sp.Any 4

1I

11I

4

(b) Able to explain the living process that enable Amoeba sp. tosurvive in fresh water which is hypotonic to the cytoplasmic fluidof Amoeba sp.

Samplg. gnswerPl - The living process is osmoregulationP2 * Osmoregulation in Amoeba sp. involved contractile vacuoleP3 - Fresh water is hypotonic to Amoeba sp.P4 - Water diffuses into Amoeba sp. by osmosis.P5 - Water fills the contractile vacuole lo its maximum sizeP6 - Contractile vacuole contractP7 - Expel the water out of the Amoeba sp.P8 - Thus, Amoeba sp. does not burst

Any 6

11111111 6

(c) Able to explain how the animal tissues are organised to form theorgan in Diagram 6,2 and their roles in regulating bodytemperature during a hot daY.

Sample answerP1 - This organ is skinP2 - Skin consists of epithelial tissues, nerve tissues, muscle

tissues and connective tissues(at least two types of tissues)P3 - Epithelial tissues specialised to form sweat glandP4 - Sweat gland secrete sweat during hot dayP5 - Epithelial tissues specialised to form hair follicle/produce hairPO - Muscle tissues found in skin is erector muscleP7 - (During hot day), erector muscle relax, hair lies flatPB - Muscle tissues (found at wall of afteriole) is smooth muscleP9 - Smooth muscle relax during hot dayp10 - Connective tissues found In the skin is blood tissucsP11 - When smooth muscle of arteriole relax, more blood flow to

the skinP12 - more heat is lostP13 - Nerve tissues is the receptorP14 - Receptor detect the increase of the temperatureP15 - The function of the skin is to lower the body temperature to

normalAnir 10

I1

1I111

11I

1

11.lI

1 ;JTOTAL MARKS

455112 O 2011 Hak cipta JPNJ SULIThttp://edu.joshuatly.com/





SULIT 4551t2

No. Markins Scheme Mark5(cXi)

5(cXii)

5(dXD

5(dxii)

Able to calculate the energy obtained by each individualAnswerModerately active adult manRice:6000Total energy obtained: 11425

Boy aged 15 years oldWhite bread:2250Total energy obtained: 14500

Able to explain why boy aged 15 years old need more dailyenergy requirement compare to moderately active adult manAnswerP1. Boy aged 15 years old is more active compare to

moderately active adult man.P2. Boy aged 15 years old still undergoing growth process

Able to identffiy the deficiency diseaseAnswerRicket

Able to state the cause of the disease and posible effiects inchildrenAnswerCause: lack of vitamin D/calciuferolPosible effects in children: bent leg

1

1

1

1

1

I

11

2

2

3

TOTAL MARKS 12

455112 @ 20ll Hak Cipta JPNJ SULIT






SULIT 10 455v2

uestioNo Markinq scheme Mark

7(a) Able to explain double fertilization

Sample answer:

P1: because there are two fertilizations.

P2: First fertilization happen when one of the male gamete fuseswith the egg cell

P3 : to form zygote (2n).

P4 :The second fertilization happens when the other male gametefuses with the two polar nuclei

P5 : to form a triploid nucleus (3n)/ endosperm.Anv 4

1

1

11

1 4

(b) Able to describe how the formation of the embryo sac processoccurs.

Sample answer:

P1 : The ovule develops from the ovarian tissue.

P2 : lt has an embryo sac mother cell (2n).

P3 : The embryo sac mother cell (2n) undergoes meiosis

P4 : to form a row of four haploid cells / megaspores (n)

P5 : Three of four megaspores die, leaving one megaspore in theovule.

P6 : The nucleus of the megaspore then undergoes mitosis threetimes

P7 : to form 8 haploid nuclei.

P8 : 3 of 8 nuclei migrate to one end of the cell to form antipodalcells.

P9 : Another 2 nuclei, called the pollar nuclei, move to the centre.

P10 : 1 of the 3 nuclei (nearest the opening of the ovule I Imicropyle ) develops into an egg cell/ female gamete, IIP11 : f lanked by 2 synergid cells. I

i(The structure formed is known as the embryo sac - where the Iembryo will develop.) I

Anv six II

Max6

o

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Able to describe how double fertilization occurs in a plant,Sample answers:P1: Megaspores (n) / haploid cells / tetrad develop into pollengrainsP2: The nucleus of each megaspore (n) / haploid cell / divides by

mitosisP3: to form one tube nucleus and one generative nucleus

(When a pollen grain falls on the stigma,) thesecretion of sucrose solution on the stigmastimulates (the pollen grain to germinate to) form pollen tube(During the growth of pollen tube) the generative nucleusdivides mitotically

to produce two male gametes,the two male gametes move/follow behind the tube nucleus(down the pollen tube untilthey) reach the micropyle (andenter ovule fordouble fertilization)

the tube nucleus disintegratesP10 : and the two male gametes enterthe embryo sac.P11 : (During double fertilisation) one male gamete fuses with the

egg cell/ovumP12 : to form a diploid zygote andP13: the other male gamete fuses with the two polar nucleiP14 : to form a triploid nucleus (so double fertilization occurs )Any 10

TOT

SULIT l l 455t/2

4551/2 O 201| Hak Cipta JPNJ SULIThttp://edu.joshuatly.com/





SULIT t2 455U2

I

No Mark Scheme SubMark

TotalMark

8(a) Able to explain the differences between the twohuman activities

Criteria1. State the types of phenomena2. C: Differences in the causes3. E: Differences in the effects4. S: Ditferences in the ways to overcome

Sample answers

Max11

11

Diaqram 8.1 Diasram 8.2F1: (The phenomenon is)acid rain

(The phenomenon is)thinningl depletion of ozonelaver

1 1

The causesC1: Combustion/ Burningoflgssllfuels in Powerstations/ factories/ motorvehicles

Coolants in air conditionersand refrigerators/propellants in aerosol cans/insulatinq foam

2 Max4

C2: release sulphurdioxide/ SOz and oxides ofnitrosen/ NO and NOz

Release chlorofluorocarbon/CFC molecules

2

C3: Form sulphuric acidand nitric acid whencombine with water vapour

Ultraviolet radiation (strikesa chlorofluorocarbon/ CFCmolecules and) causes achlorine atom to breakawayllbreaks the bond torelease the chlorine atom

2

C3: Fallto Earth as acidrain/ snoM hail/ fog/ frosUdew

Chlorine atom (collides and)destroys the ozonemolecule (to form chlorinemonoxide and oxygenmolecule)

2

Any 2 CsThe effectsAgriculture:E1: Leaching of mineralsi/the soil become acidic

Leaf cells and chlorophyllare damaged by ultravioletraysll lower the rate ofphotosynthesis// reducecrop vield

2 Max4

Aquatic ecosystem:E2: Increase acidity in theaquatio ecoaystem// killphyto plankton// destroyedphotosynthetic t issues//accumulate insolublealuminium lons In lakes andrivers which kill aquaticoroanisms

Ultraviolet rays killmicroorganisms/phytoplankton// destroy //disrupt the marine foodchain

2

455112 O 201 I Hak Cipta.lPN.l SULIT






SULIT 13 4s5l12

Health:E3: Acidic soi l re leases ionsof certain heavY metals/contaminate the suPPlY ofdrinking waterl I irritate thelungs/ make breathingdifficulU asthma/ bronchitis.

Prolonged exposure toultraviolet radiation lead toskin cancer/ melanoma/cataract/ weakened theimmune system

2

E4: Corrode metal railing/bridges/ damage buildings/statues/ automobiles/structures made of stone/metal/ historic buildings

Greenhouse effect/ g lobalwarming// damage the eggsof certain amphibians// windpatterns change// climaticchanqes

2

Any 2 EsThe ways to overcome/ SolutionsS1: Use scrubbers (toclean up emissions frompower stations andindustrial plants)

Reduce/ stop/ ban the useof Chlorofluorocarbon/ CFC

2 Max2

32: Use catalYtic converters(to clean up emissions fromvehicle exhausts)

the world comply with theMontreal Protocol to reducethe use of CFCs (to cut theuse of CFC's in half bY thevear 1 997)

2

Any EUt C, E and S are indePendent

8(b) ffiportance of sustainablemanagement of tropical rainforest.

Criteria:Tl- Sustainable management of tropical rai nfo rest2. Explain the importance of conservation and

preservation

Max I I

Qample answersF1'. Replanfing trees in areas that have been logged//reforestationE1: to keep the ecosystems in their natural state (whichprovides aesthetic values for humans) // preserve natu.ralr"rourcu. for outdoor/ recreational activities// eco-tou ris m

// reduce stress// promote healthy life styleE2: to maintain soil ferti l i tYE3: to prevent f lood/ soil eiosion / landslide/ (muddy) flood/(flash) floodL+, to avoid species extinction// to prevent extinction offlora and Iaunal organisms/ speciesE5 : As an economic resource// source of raw materials for

constructlon industry / pil ing I furniture / boats / houses /

oroductlon of chareoal / tannin / food / other suitableot^-nle // orovide foods to human // resources for str-rdy /

I

I

1

1

1

1

education / research

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F2: Selective loggingE5: to maintain a balanced ecosystem// to allow maximuminteraction among the l iving organisms/ biotic factors (inthe ecosystem) and interaction between biotic and abioticfactorsE6: to maintain major sources of human food/ e.g: ulam/ferns/ meats/ honey// sources of medicinal planU eg: herbsE7: to sustain food web/ food chain in the ecosystemE8: to prevent disruption of natural cycle of water/ carbon/balance between photosynthesis and respiration//balance oxygen and COz in the atmosphere ll provide 02llreduce COzE9: to decrease the carbon dioxide level in theatmosphere ll to reduce the greenhouse effecV globalwarmingE10: to maintain the biodiversity of the foresU/ maintaining/ increasing biodiversity / complexity / variety of organisms/ species lflora and faunaE1 1: to avoid lost of wildlife/ potential resourcesE12: to avoid loss of watershed areas // provide naturalwater catchment areaE13: maintaining (normal) weather (patterns) by minimizeclimatic change / drought / harsh climate / maintaintemperatureE14 : As a site for breeding / feeding of flora and fauna /serving as valuable nursery area for organisms

SULIT t4 45sI/2

INo Marking scheme Marke(a) Able to explain how to push the ball away.

P1 (moving ) ball is an externalstimulus

P2 receptor in the eye pick up /detect the ball/ stimulus

P3 the receptor trigger/generate nerve impulses

P4 the nerve impulse transit from the afferent neurons tothe

interneurons in the brain

P5 The brain interprets the nerve impulse (frominterneurons that the ball

ls moving to goal keeper/ahmad)

PO The brain decides what to do to stimulus( to catch orpush away the

comlng ball)l I coordlnate responses

P7 Nerves impulses are transmitted from interneurone toefferentNeurone across the synapse.

455112 @ 20ll Hak Cipta JPNJ SULIT






PB Nerves impulses then transmit to muscles (effector)

Pg The muscles (in arm /leg) carry out the response

P10 Ahmad able to push away the ballfrom goal post.

P11 lmpulse is transmitted across the synapse

P12 between afferent neuron and interneurone llinterneurone and efferent

neuron

Able to explain how to regulate blood sugar level in thenormal range

P1 (The islet cells in the) pancreas secretes insulin a

P2 and glucagon

P3 directly into blood stream.

P4 lf the blood sugar level increase/more than 110mg/100m1, insulin

convert excess glucose to glycogenl

P5 in the liver.

PO Insulin stimulate uptake of glucose byliver/muscle/adipose cell for

respiration..

P7 for cell respiration // to obtain energy

PB blood sugar level decrease to normal range

Pg lf blood sugar level decrease / less than mg/100m1 ,glucagon

convert glycogen to glucose

P10 glucagon promotes lipid breakdown

Pl1 to release fatty acid /energy

?12 blood sugar level increase to normal range.

SULIT

PERATURAN PENIARKAHAN TAMAT

l5 4s5t/2

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. SULIT*4551/3PeraturanPemarkahanBiologiKertas 3September20rr

4551/3

JABATAN PELAJARAI.{ NEGBRI JOHOR

PEPERIKSAAN PERCUBAAN

SIJIL PELAJARAN MALAYSIA aOIL

PERATURAN PEMARKAHAN

BIOLOGI

Kertas 3

TJNTUK KEGUNAAN PEMERIKSA $AHAJA

AMARAN

Peraturan Pemarkahan ini SULIT'Kegunaannya khusus untuk pemeriksa yang berkenaan sahaja.

sebirang maklumat dalam peraturiur pemarkahan ini,iduk boleh

dimaklumkan kepada sesiapa. Peraturan pemarkahan ini tidak boleh

dikeluarkan dalam apa-apabentuk media'

ff iahan ini mengandungi 14 halaman bercetakJabatan Pelajaran Negeri Johor


4551/3 o 2ol I Hak cipto JPNJhttp://edu.joshuatly.com/





455t/3SULIT*4551/3PeraturanPemarkahanBiologiKertas 3September20tr

JABATAN PELAJARAI{ NBGERI JOHOR

PEPERIKSAAN PERCUBAAN

SIJIL PELAJARAN MALAYSIA 2OIT

PERATURAN PEMARKAHAN

BIOLOGIKertas 3

UNTUK KEGUNAAN PEMERIKSA $AHAJA

AMARAN

Peraturan Pemarkahan ini SULIT'Kegunaannya khusus untuk pemeriksa yang berkenaan sahaja.

Sebiang maklumat dalam peratuftur pemarkahan inilidak boleh

dimaklumlan kepada sesiapa. Peraturan pemarkahan ini tidak boleh

dikeluarkan dalam apa-apabentuk media'

ff iahan ini mengandungi 14 halaman bercetak


4551/3 @2ot I HakciptaJPNJ

Jabatan Pelajaran Negeri Johor






SULIT* 2


PERCUBAAN SPM 2O1I

4551/3


MARK SCHEME ScoreNo

1(a)lKB0603 -Measuring

UsingNumbersl

Distance between PaddYseedlings /(cm)

Dry weight of 10 paddYseedlings / (g)

10 41

5 22

2 8

Able to iecord all the data correctly,

Sample answers;3

Accept any dryweight values

between

40-4221 -23

7 -9

Abitto record 2 data correctlY 2

fficorrectly 1

Not able to respond / wrong response. 0

(b) (i)lKB06o1 -

Observationl

Cr i ter ia:P1 : Distance between paddy seedlingsP2 : Dry weight of 10 PaddY seedlings

1.2.3.

[horizontal ob seruation]At dirt"nre 10 cm , the dry weight of (10 )paddy seedlings is 40 g.At dist.nr" 5 cm , the dry weight of (10 )paddy seedlings is 22 g.At distance 2 cm , the dry weight of (10) paddy seedlings is 8 9.

[vertical obseruation]ine Ory weight of 10 paddy seedlings fordistanc! 10 im is higher than at distance 5cml2 cmllvice versa.

1.

23

At distance 10 cm , the dry weight of 10 paddy seedlings ishighest.

Atlistance 5 cm , the dry weight of 10 paddy seedlings is lowAt distance 2 cm , the dry weight of 10 paddy seedlings is thelowest.

1. Distance influences dry weight of paddy seedlings '2. The dry weight of paddy seedlings is ditferent for each distance.

le answedeljdeg-lgye! :

Use thescoring

summaryprovided,

4551/3 o 20l I Hak cipta JPNJ






. SULIT* 2


PERCUBAAN SPM 2011

45s1i3


No MARK SCHEME Score

1(a)[K80603 -Measuring

UsingNumbersl

Distance between paddyseedlings /(cm)

Dry weight of 10 paddyseedlings / (g)

10 41

5 222 I

Able to record all the data correctly.

Sample_answ-els:3


between

40-4221 -23

7 -9

Abfe to record 2 data correctlY 2

Able to record 1 data correctlY 1

Not able to respond / wrong response. 0

(b) ( i)

lKB0601 -Observationl

Criteria:P1 : Distance between paddy seedlingsP2 : Dry weight of 10 paddY seedlings

Sample qnswers for accurate observatiot (P1 + P2):

[h orizontal ob se rv ation]1. At distance 10 cm , the dry weight of (10 )paddy seedlings is 40 g.2. At distance 5 cm , the dry weight of (10 )paddy seedlings is 22 g.3. At distance 2 cm , the dry weight of (10) paddy seedlings is 8 g'

[v e rti c al o b se rv ati o n]1 . The dry weight of 10 paddy seedlings for

distance 10 cm is higher than at distance 5cml2 cmllvice versa.

Sample answer for: in,accuratg obseryation (only.Pl / P2):

1 . At distance 10 cm , the dry weight of 10 paddy seedlings ishighest.

2. At distance 5 cm , the dry weight of 10 paddy seedlings is low3. At distance 2 cm , the dry weight of 10 paddy seedlings is the

lowest.

$anople answer for idea lev.el :

1. Distance influences dry weight of paddy seedlings ,2. The dry weight of paddy seedlings is different for each distance.

Use thescoring

summaryprovided.

455113 0 2ol r t-tak cipta JPNJ






SULIT*455U3

[Lihat sebelahSULIT'I

(b) (ii)lKB0604 -Makinglnferencel

Able to state

O! e I n a ccuraie- o bGMii oiOne lnaccurai-oGervatr'on one InaccurqG oGilEii6i

One. I naccurate oOservatr'on

OrJe Inaccurate observation

Able to state the inference for the observations in (b) (i)

Criteria:P1 ; Growth rateP2: intraspesific competition / competition for water / minerals /nutrients / light

ll more / less water

1.

2.

[hoizontal inference/(At distance ]0 9m),.there is row (intraspesific) competition so theglowth (rate) of paddy ptant is high.(At distance 5 cm), there is lowhigh (intraspesifi) competition sothe growth (rate) of paddy ptant is trigi\now.(At distanc? ? "y),

there is high (intiaspesific )competition so thegrowth (rate) of paddy plant is tow.

[veftical inference/4. At distance 10 cm, there is lower intraspesific competition so thegroMh rate of paddy plant is higher than at oistanCe

-5imt2 cm llvlce versa.

1. (At distance 10 cm),there is low intraspesific competition .2' (At distance 10 cm), the groMh rate oi proov pr'it i."nigh.3. (At distance 2 cm), the gioMh rate of picov'piant iriornl

S-amqle answer fqr iCea.level:

1. There is competition among the paddy seedlings.

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SconAble to state Scorb

One accurate inferense And One accurate inferense 3One accurate inferense And One Inaccurate inferense 2

One lnaccurate inferense And One lnaccurate inferenseOne accurate inferense And One ldea level 1One accurate inferense And One Wronq inferense

One lnaccurate inferense And One ldea levelOne ldea level And One ldea level

One Inaccurate inferense And One Wronq inferense 0One ldea level And One Wrono inferense

III

I

I

j

II

II

(c)[KBo610 -ControllingVariablel

nOte to itate alt 3 variables and methods to handle each variablecorrectly. (6 ticks)

Sample ?nswer

Variable Method to handle the variable

Manipulated variable

Eistance between paddYseedlings

Use differeht distance betweenpaddy seedling / Use the distancesat 10cm, 5 cm, 2 cm.

Responding Variable:

Dry weight of paddyseedlings

GroMh rate

Measure and record dry weight ofpaddy seedli lgsusing the balanceor

calculate tfie grovuth rateusing formulagrowth rate= Drv weight of 1,0 paddv plglt

30days

Constant variable

Volume garden soil//

Type of paddy Plant //

Size of truy

Fix the volume of garden soil at 4kg

Fix the same type of paddy plant

Fix the same size of tray

Abletostate4-St icks 2

Abletostate2-3t icks 'lI

No response or incorrect respons or 1 ticks only n

SULIT* 4551/3

[Lihat sebelahSULIT*455U3 0 2olr ttak cipta JPNJ






(d)

lKB06x 1 -Stat<l

Hypoth,esisI

Able to state the hypothesis relating the manipulated variable and theresponding variable correctlY :

Pl : manipulated variable (distance between paddy

seedlings)P2 : responding variable (dry weight /growth rate of paddy plant)

H : relationshiP of Pl and P2

Samolq answer

1. The further the distance between paddy seedlings, the higher

the growth rate pf./ dry weigh of paddy plant

1. When the distance decrease, the growth rate / dry weight ofpaddy plant will be decrease.

Note;:rnust write

r,ate of

3

P1 +P2+H

| (e) (i)| [K80606 -I CommunicI ating clata l

Able to state a hypothesis relating the manipulated variable and theresponding variable but less accurate.

Sample-?nswer:

1, Different distance between paddy seedlings will increasethe dry weight of paddy plant differently.

2. Distance influence the the growth rate / dry weight of paddynlqnf

Able to state one idea of a hypothesis.

Samplg anpwer

1. The different distance give intraspesific competition

0

Able to construct a table correctly with the following aspects

T- Title in the table with correct unitsD - All data collected are correctC - Growth rate calculated are correctly

1 mark1 mark1 mark

Distancebetweenpaddlr

. . , , . , i i i l ; ,$

i l Ci 'dr)

Dry weight of 1ppaddy seedlings

/(g)

Growth rate i(g/days)

10 41 1.4 i l 1.36

5 2? 0.7 il 4.73

2 I 0.3 i l 0.27


between

40-4221-237-9

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1I

,]






Any two correct aspects 2

Any one correct aspects 1

No response or incorrect respon 0

(e) (ii)lKB0607 -Correlatingtime andspace l

Able to draw the graph correctly which include the following aspects

P(paksi) : correct title with units and scale of x-axis and y-axis

T(Titik) : Transfer all three points correctly

B(bentuk) : Corect and line graph(line graph joining the 3 Points)

- 1 mark- 1 mark

- 1 mark

3

Any two correct aspect 2

Any one aspect conect 1

No response or incorrect response 0

(f) Able to state the relationship between the growth rate of paddyseedlings and the distance base on criteria :

R1 - Relationship :when the distancp between paddyseedlings increases, the growth rate of Paddyseedlings increases.

// vice versaR2 * Explanation 1 : lower: intraspecific compelition/ less

competition for space / water/ nutrient / lightR3 - Explanation 2 : dry weight is increase / height increases

Sample answer:

1. As distance between paddy seedlings increases the growthrate of paddy seedling increases. This is because thereis lower intraspesific competition and ceuse the dry weight /height of the paddy seedlings to increase,

3

..Expl-an,ation 2can accept

more leaves.

Able to explain the relationship base on any two criteria.

Sample answgL

1. When the distance between paddy seedlings increases,the growth rate of paddy plant increaaes because theintraspesific competition is low.

SULIT* 6 455u3

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tu

SULIT*

(g)IKB 0605 -Predictingl

A6le io expEtn the relationship based one criteria only'

Sample answer:

1. As distance increases, the growth rate of paddy seedlingincreases.

No response or incorrect resPons 0

utcome of the experiment correctlywith the following criteria:

C1 - the dry weight more than 41 g l increasesCZ - because longer distance give more water / nutrient

Space / light / the intraspesific competetitiondecreases

C3 - the growth rate of paddy seedling increases

Sample answer

1. The dry weight more than 41 g because longer distance givemore water / nutrient / space to the paddy seedling.So the growth rate of paddy seedling increases

Any two criteria stated 2

Any one criteria stated 1

No response or incorrect resPonse

m to Amne-peration a I ly i ntras pesific co m petitionK1 - paddy plants compete between themselvesK2 -in the seedling tray for the limited resources lwater I

nutrientsK3 - The growth rate of paddy/ dry weight of paddy

seediings / competition of paddy is affected by thedistance between the seedlings

Sample answer:

1. Intraspesific competition is the growth of paddy seedlings in thetray that is shown by the dry weight of paddy seedling '

0

h)lKBo60e -

defineoperationall

v

Any two criteria stated 2

Any one criteria stated

fheoriticql definition (1 mark)

I nterspecific com petition is com petition between organisms/individuals of the same speicies in the same habitat for the sameresources that are l iqited supply - .No response or incorrect resPonse U

4551/3

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f .

SULIT* 4551

( i)

K80602

Classify

Able to classify the all resources for the organism correcly .

Sample answer,i

All 8 ticks

3

6-7 ticks. 2

3-5 ticks 1

No response or incorect response 0

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I3

;sebelahSULIT*






' . t

. SULIT* I

QUESTION 2

455u3

[L ihat sebelahSULIT*

11DP('ur, Criteria Qnnro

K8061201

ldentifyingProblemStatement

Able to write a problem statement correctly base on 3 criteria:P1: Manipulated variables : wind speedP2: Responding variables : Rate of transpiration / time

taken for air bubble to move a distance of 2cmH : Relationship in question form.

Sample Answer1. Does wind speed affect the fate of transpiration of a

plant?2. How does wind speed atfect the rate of transpiration of

a plant?3. What is the effect of wind speed on the rate of

transpiration?

3

Able to write a problem statement but less correctly base on 2criteria.

Samole Answer1. The rate of transpiration is affected by the wind speed.2. What are the effect of wind speed on the rate of

transpiration.

2

Abte to give an idea about the problem statement base on 'tcriteria.

Sample Answer1. Wind speed atfect the transpiration of a plant.2. Transpiration is influenced by wind speed.

.lI

No response or incorrect resPonse0

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Aspect Criteria Score

VariablesAble to state all the three variables correctlv

Sample Answer

1. M.anipulated varjablgWind speed

2. RespoIdinq variableL The Time taken for the air bubble to move at a

distance of 2 cm2. The rate of transpiration

(Any one)3. Fixed variable

1, Type of plant / balsam plant2. Relative humidity3. Temperature4. High intensity

(Any one)

EachVariable

1m

3 marks

SULIT* 10 4551/3

[Lihat sebelahSIII,IT' '

Able to state the hypothesis based on the following criteria

P1 - Manipulated variable :Wind speed / Fan Speed/ Distance of fan

P2- Responding variable : Rate of transpiration/ time taken for the air bubble to rnoveat a distance of 2 cm distance

: Increase/decrease / higher/shorter

1. The higher the wind speed / closer the distance of fan, thehigher the rate of transpiration of a plant.

2. The higher the wind speed, the shofier t ime taken of airbubble to move for 2 cm distance

3. When the wind speed increases the rate of transpirationincreases

[note: hypothesis with wrong conclusion is accepted]

K8061202

Hypothesis

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;n) ,2 cntena

,

, SULIT* 11

1. When the wind speed increases the rate of reactionIncreases

2. The higher the wind speed, the higher the transpiration of aplant.

3. The wind speed affect the rate of transpiration of aplant.

Able to write a hypothesis at idea level/ based onPll P2.Wrong concept

Sample Answer

1.Wind speed affect I influence the transpiration of a plant2. Rate of transpiration affects the wind speed

No response or incorrect resPonse

455u3


Aspect Criteria Score

1(8061205

,lVlaterialsandApparatus

Able to list all materials and apparatus needed to carry out theexperiment successfullY.

Sample Answer

Apparatus : potometer, stopwatcf't, cutter,(A) beaker, meter ruler, basin , marker/thread,

Materials : balsam planVany suitable leafy plant , water,Vaseline/grease, dry cloth

(M) 7 A+4M

3

Any 5-6A+3M 2

Any 3-4 A'+ 2 M 1

Incomplete list or wrong or no response

2A+1M1A+1M

0

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SULIT* 12 4551/3

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K8061 204

Procedure

Able to wnte all the steps ln carrylng oul Ine experlrnenlsuccessfully.

Kl : Steps to set up the apparatuq (any 5 )

K2 : Steps to handle the fixed variable (any 1)

K3 : Steps to handle the responding variable (any 1)

K4 : Steps to handle the manipulated variable

K5 : Precautionary steps / steps taken to get accurate resiults/readings

Scoring RubricAll 5K present 3

Any3-4KPresent 2

Any 2K present 1

No response or incorrect resPonse 0

455113 o 2ol I Hak cipta JPNJ






Sample Answer

BalsNrrr nlant

The leafy shoot is selected from a plant and cut off the shootusing a sharP knife.

ahoot idto the hole in the cork of

infir,ouucfin=iaoubble in the capillary tube

Fdomeims sealed using vaseline to make

e 2 cm (using a marker/thread)'

aratus dfY bY using a dry cloth

furn on tne fan using fan sPeed 1"The fan sPeed is recorded.

n for the air bubble to move a

distance of 2 cm is recorded in a table

G@Ieme rate of transpiration by using the

formula = lenqth (cm) ortime (min) t ime (min)

" SULIT*

Procedure

Repeat thefan speed

same leafy shoot bUt withthe fan turned off.

455u3

ILihat sebelahSULIT*

13

experiment bY using the2, tan speed 3 and with

Ail data is recorded in table

@ated to get average readings

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tt

SULIT* 14 4551/3 '

Aspect Crlt6ria Score

Communi-cating data

Able to draw a complete table to repord the relevant data base on the 2criteria:

r Titles for operating MV and operating RV with units:Wind speed ,and Time taken for air bubble to move a distance 0f 12 cm (min)

o Responding Variable with unit:Rate of transpiration (min'1)

Samole Answer

2m

Wind speed

Time taken for air bubble to

move a distance bf 2 cm (min)

Rate of

transpiration

(cm min'1) or (min'1)

1

2

3

0

Any one criteria 1m

No response or incorrect resPonse 0

END OF MARKING SCHEMEP E MTUMN P EMARK4HAN TAMAT

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biology johor 2011

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