bengkel teknik menjawab soalan upsr 2008 zon sibuti

8/10/2019 Bengkel Teknik Menjawab Soalan UPSR 2008 Zon Sibuti

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Musuh utama kecemerlangan

bukanlah kekurangan fizikal, sosial

atau ekonomi tetapi mental.

Saya tidak kalah apabila saya

berada di bawah. Saya hanya kalah

sekiranya saya tidak bangun semula

dari bawah.

RAJIN itu adalah punca segala

kejayaan dan MALAS pula punca

segala kegagalan.

(Dr. Shukri Abdullah)


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Strategi belajar secara

sistematik dan berkesan Dari segi mental

Mahir: fakta asas (4 operasi), guna rumus(formula), guna dan tukar unit serta

perkaitannya. Dari segi fizikal

Cergas: bersedia lebih awal sebelumpeperiksaan bermula (latihan bersistem dan

berjadual) Dari segi emosi

Sentiasa tenang: doa dan tawakal


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UPSR Mathematics

Paper 1 (Kertas 1)015/1Paper 2 (Kertas 2)015/2

Mulai 2003 soalan Matematik UPSRdikemukakan dalam dwibahasa (BahasaMalaysia dan Bahasa Inggeris). Bagaimanapun,calon hanya perlu memberi tumpuan penuhuntuk menjawab dalam satu bahasa yangdipilih.


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Topic Type of

question

Duration Number of

questions

Marks

Whole numbers

Mixed numbers

Fractions

Decimals

Percentage

Money

Shape & space

Measurement: mass,

length & volume of

liquid

Data handling

Multiple

choice

Answer all

questions

1 hour 40 40

Paper 1 015/1


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1. UTAMAKAN SOALAN YANG MUDAH

Examples:

(1) 40.129.047 =

A 4.06 B 4.14 C 10.36 D 10.99

(2) RM350RM192.05 + 15 sen =

A RM157.80 B RM158.10

C RM162.20 D RM162.80

(3) 0.5 million + 400 000 =

A 0.9 million B 0.09 million

C 0.45 million D 0.405 million

PENTING


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2 356 709647 935

768 1711 452 355

+ 84 953

Contoh :

3

Jawapan :2

2

2

1

3

0

3

1

3

3

2

5


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5. WASPADA TERHADAP PENGG

PENTING

Example:

A shop sells 630 red and yellow rosesaltogether. The shop sells 124 more red

roses than yellow roses.

How many yellow roses does the shopsell?

A. 568 B. 516 C. 382 D. 253


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6. MEMPASTIKAN SEMUA SOALAN

TELAH DIJAWAB.

Semua 40 soalan telah dijawab

Jangan conteng kertas jawapan. Hitamkan jawapan dengan penuh. Gunakan pensel 2B

Contohnya: (A) (B) (C) (D) Padamkan dengan bersihjika hendak menukar jawapan.

PENTING


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LEARNING

AREA

TYPE OF

QUESTIONS

DURATION NUMBER OF

QUESTIONS

MARKS REMARKS

Basic skill

exclude

data

handling

Not involve

difficult

problem

solving

Subjective

Calculation

process

Answer all

the

questions

40 minutes 20 40

Answer in

space

provided

Marking

scheme

-

Calculation

process

- Finalanswer

Paper 2 015/2


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Langkah-langkah menjawab soalan:

1) Soalan 1 markah = 1 minit (max) atau kurang

1 minit.2) Soalan 2 markah dan 3 markah = gunakan

masa seminimum mungkin iaitu kurangdaripada 2 minit.

3) Masa yang lebih digunakan untuk menyemakjawapan (sekiranya ada)

4) Pastikan tulisan anda KEMAS dan JELAS.

5) Setiap soalan perlu ditunjukkan langkahpengiraan yang TERATUR dan LENGKAP.Pastikan jawapan akhir mengikut kehendaksoalan.Langkah pengiraan mempunyai

taburan markah yang tertentu. Walaupun


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LULUS?????

Pass at least C : 18 questionsPaper 118 marksPaper 2

Lu lus sekurang-kurangnya Gred C

: 18 soalan - kertas 1

: 18 markah - kertas 2

Gred A :

perform both papers BUT Paper 2 determines

candidate to get Gred A. Gred A : Lulu s kedua-dua kertas dengan

cemerlang TETAPI Kertas 2 menentukan calon

un tuk mendapatkan Gred A.


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~Kejayaan dan

kemenangan hanya lahmilik orang yang

berusaha~

Percaya kepada diri sendiri ialah rahsia pertama

untuk mencapai kejayaan

- Ralph Waldo marson


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Topic analysis

PAPER 2: KOD 015/2


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PENTING!!!!!

Salin soalan denganJELAS dan TEPAT.

Jawapan yang dibawa kebawah mesti JELAS dan

TEPAT.Pastikan unit/jawapan

ditulis berdasarkan


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PENTING!!!!!

Penukaran unit mestiditulis dengan JELAS.

Sekiranya soalanmenggunakan

rumus/formula, gantikandengan nilai yangsepatutnya.


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PENTING!!!!!

Gunakan Sistem 1, 2, 3 dalampenyelesaian masalah.

1: Ayat matematik

2: Langkah pengiraan

3: Jawapan akhirJangan tinggalkan tempat

kosong.


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QUESTION 1 TO 5

1 MARK)


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TOPIC ANALYSIS

WHOLE NUMBERS

FRACTIONS, DECIMALS &

PERCENTAGEMEASUREMENT : MASS,

LENGTH & VOLUME OF LIQUID

TIME

SHAPE & SPACE


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WHOLE NUMBERS

Write number in

numeralor inwordsDetermine place value

and digit valueRound off


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State the digit value of 4 in the

number 45 090. (UPSR 2007)

45 090

40 0 00

Underlined digit 4

Replace other digits with 0


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5 7 3 4 9

State the place value of the numeral

7 in 57 349. (UPSR 2004)

Determine place value for each digit

OTHThTTh

Underlined digit 5

ThousandsAnswer


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Write fifty thousand and three in

numerals. (UPSR 2006)

TTh Th H T O

Draw place value chart

Insert digit in the place value column

5 0 30 0

Empty column: insert 0


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Round off 38 572 to the nearest ten

thousand. (UPSR 2003)

3 8 5 7 2

Underlined digit in ten thousands

Circle the digit on the right

Less than 5 +0, if 5 or more +1, on circled digit

+1

4 0 0 0 0


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FRACTIONS, DECIMALS &

PERCENTAGE

Write fractions inwords,numeral, simplest formandequivalent fraction

Decimals: place valueanddigit valueConversion


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Convert 0.13 to a fraction.

(UPSR 2004)

Answer:

0 . 1 3 =13

0. 1 3 100

tenths

hundredths

001


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Convert 3.09 to a mixed number.

(UPSR 2005)

Answer:

3 . 0 9 =9

3. 0 9 100

ones

3

tenths

hundredths

001


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Convert 93% to decimals. (UPSR 2006)

93% =93

100

93 100 = 9 31 0 00

= 0.93


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Diagram 1 shows the weight of a apple.

(UPSR 2004)

What is the weight, in g, of the apple?

0

250

750

1

kg

500

Diagram 1


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1 kg

250

500

750

01 kg

250

500

750

01 kg

250

500

750

0

250 5 = 50g

50

50

5050

50

250 + 100 = 350gAnswer:


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TIME

Read a clock face

12-hour system

24-hour system


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Diagram 2 shows Azwans dinner time.

(UPSR 2007)

Diagram 2

Write the time in the 24-hour system


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1

2

3

4

56

7

8

9

10

1112

8.00 p.m.

5 mins

10 mins

15 mins

20 mins

Answer 2020 hours0800 + 1200 = 2000

24-hour system

After 12.00 p.m.

+ 1200


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SHAPE AND SPACE

Namethe shape

2 D shapes : square, rectangle,

triangle, circle etc.

3 D shapes: cube, cuboid, cone,

pyramid, cylinder etc.

Characteristicsof the shapeEdge, vertex, side, flat surface, curve

surface etc


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Diagram 3 shows a cuboid. (UPSR 2007)

State the number of vertices.

vertex

8 vertices


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Table 1 shows the characteristics of a

three dimensional shape. (UPSR 2006)

Number of vertices 8

Number of equal edges 12

Name three dimensional shape.

edgevertex

cube


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Always do your best........

What you plant now ,

you will harvest later

Og Mandino


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QUESTION 6 TO 15

(2 MARKS)


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TOPIC ANALYSIS:

WHOLE NUMBERS, FRACTIONS, DECIMALS,PERCENTAGE, TIME, MONEY, MASS, LENGTH,

VOLUME OF LIQUID, SHAPE SPACE.

BASIC OPERATIONS (+, -, X, )MIXED OPERATIONS

CONVERSION OF UNIT

PERIMETER AREAVOLUME OF 3D SHAPES

AVERAGE


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UPSR 2002

5

21

5

4+ =

16

5

655

1

11 + 1

1

5 21

5


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UPSR 2002

45.37.09 =

45.3

- 7.09

10 102

1283 .

03


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0.72 9 = ____ (UPSR 2002)

0 . 7 29

0

0707 2

0 8

7 2

-

-

. 98

7

65

4

32

1

0

0

1

2

34

5

67

8

9

0

UPSR 2002


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100 5= 2020 5= 4

96 4 =

100

25 X 96

Answer:

UPSR 2002

Calculate 25% of 96

5

20

25 5= 55 5= 1

24

1

4


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(UPSR 2003)

Find the value of of RM270.5

2

RM270x52 = RM108

2 X RM270 = RM 540

RM540 4 = RM108


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UPSR 2007

6 days x 9 = __ weeks __ days

Notes: 1 week = 7 days

6 x 9 = 54

54 7 = 7 remainder 5

Answer: 7 weeks 5 days


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(UPSR 2006)

Diagram 6 shows the time Sue Lan

reaches her school in the morning.

Diagram 6

She leaves her

house at 6.45 a.m.

How longdoes it

take her to reach

her school?


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Hour Minute

7 15

45-

Anwer: 30 minutes

6

6 +60

30


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Hour Minute

3 3530+

3 65601+ -

4 5

Answer: 4 hours 5 minutes

T th t


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(UPSR 2006)

3 years 7 months + 5 years 8 months =

____years __________months

(UPSR 2005)4 hours 15 minutes + 1 hour 50

minutes

Try these out:


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.00

(UPSR 2004)

RM9RM0.75 + RM2.35 =___

RM9

RM0.75

81

9 10

-

RM8.25

RM2.35+RM10.60

1

T bl 1 h th titi f t


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Table 1 shows the quantities of notes

and coins. ( UPSR 2005)

Money Quantity

RM5 4

50 sen 3

Calculate the total value of the money.

TABLE 1


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Answer:

RM 5 x 4 = RM 20

RM 5 + RM 5 + RM 5 + RM 5 = RM 20

@

50 sen + 50 sen + 50 sen = 150 sen

50 sen x 3 = 150 sen @

150 sen 100 = RM1.50

C ti d


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Continued

RM 20 + RM 1.50 =

RM 20.00+ RM 1.50

RM 21.50

(UPSR 2007)


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(UPSR 2007)

Calculate 4.03 km750 m.

Give your answer, in m.

CONVERSION OF UNIT

4.03 km = ______ m km m

x 1000

10004. 0 3 x 1000= 4030 m


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1 km = 1000 m

4

4.03 km - 750 m

0 3

7 5 0

0

-

2 8 03

Answer:

3 280 m3 19 10


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(UPSR 2006)

Calculate 2.05 kg x 12.

Give your answer, in g.(UPSR 2007)

Calculate 1.27 l 10.Give your answer, in ml.

Try these out:


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Diagram 4 consists of three triangles,

PQR, RSU and STU of the samesize.

(UPSR 2005)

8 cm

6 cm

10 cm

P

Q

RS

U T

Calculate the

perimeter,in cm, of the

whole

diagram


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Jangan takut menghadapi kegagalan kerana

dengan kegagalan kita beroleh pengetahuan

tentang kekurangan dan kelemahan diri kita ,

yang ditakuti ialah gagal untuk kali kedua

dalam perkara yang sama

-Hamka


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QUESTION 16 TO 20 3 MARKS)


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TOPIC ANALYSIS: PROBLEM SOLVING

INCLUDE WHOLE NUMBERS,PERCENTAGE , MONEY,

MEASUREMENT (MASS, LENGTH

& VOLUME OF LIQUID ),TIME,

SHAPE & SPACE AND AVERAGE.

THE PROBLEM SOLVING WILLCOMBINE 2 OR MORE SKILLSIN

A QUESTION.

TIPS


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TIPSProblem solving:Penyelesaian masalah (cara-caranya)

a) Read the questionBaca soalan yang diberi

b) Extract the informationKumpul maklumat:

What is given? Apa yang diberi?What is asked for? Apa kehendak soalan?What opeartion is needed?Apa operasi yang diperlukan?

c) Calculate step by step.

Kira (langkah pengiraan yang TERATUR danLENGKAP)d) Check the answer

Semak semula

Ahmad Bala and Chong collected used tins The


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Ahmad, Bala and Chong collected used tins. The

averagenumber of tins collected by the 3 boys was

16. Ahmad and Chong collected 9 and 17 tins,

respectively.

Calculate the number of tins collected by Bala.

(UPSR 2003)

Follow the flow of the question

Total value of unit : average x number of unit

Average : Total value of unitNumber of unit

Manipulate the formula

Average : Total value of unit


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Average : Total value of unitNumber of unit


22 tins48179 =

16 x 3 = 48 tins

Answer:

Diagram 6 shows a collection of three


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Diagram 6 shows a collection of three

types of shapes. (UPSR 2007)

Calculate the percentage of of the whole collection.

Calculate the percentage of of the whole collection.


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=100%x20

5

= 5 pieces

Total shapes = 20

x 100%

1

4

=

20%

ANSWER:

20

55 x 100 20

Musa has RM100. He buys a pair of


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y p

shoes for RM72.90 and 3 pens for

RM4.50 each.

How much money does he have left?

(UPSR 2004)

RM4.50 X 3 = RM13.50RM72.90 + RM13.50 =

RM100.00RM86.40 =

penTotal

RM13.60

Left

Answer


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Linas mother used of 2 kgof

sugar to bake a cake.How much sugar did she use?

Give your answer, in g. (UPSR 2003)

1

4

1

4

x 2000 g =

500 g2 kg = 2000 g

1 x 2000 4


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Notes to remember!

Topic/

Fraction

Mass

(kg=g)

Length

(km=m)

Volume of liquid

(l=ml)

1

2

0.5 kg

500 g

0.5 km

500 m

0.5l

500 ml

1

4

0.25 kg

250 g

0.25 km

250 m

0.25l

250 ml

3

4

0.75 kg

750 g

0.75 km

750 m

0.75l

750 ml

A bottle contains 1 5 l of water


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A bottle contains 1.5lof water.

of the water is split.

How much is the volume, in ml, of water is left

in the bottle? (UPSR 2004)

5

2

TOPIC/

FRACTION

MASS LENGTH VOLUME

OF LIQUID

0.2kg = 200g 0.2km = 200m 0.2l= 200ml

0.4kg = 400g 0.4km = 400m 0.4l= 400ml

0.6kg = 600g 0.6km = 600m 0.6l= 600ml

0.8kg =800g 0.8km =800m 0.8l=800ml

1

5

25

3

5

4

5


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Answer:

1 500 m200 m =

1.5 x 1000= 1 500 m

1 300 m 1 500

2001 300

-

Table 1 shows the time taken by Mohan


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Table 1 shows the time taken by Mohan

to revise his lesson. (UPSR 2007)

4

3

Subject Time taken

Mathematics 1 hour 30 minutes

Science hour

Mohan starts his revision at 2.15 p.m.At what timedoes Mohan finishhis revision?


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Answer:


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Answer:

2 151 30

3 4545903

1 60-+

+

+

304

at 4 30p m

MinuteHour

Diagram 5 shows a rectangle PQRS


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Diagram 5 shows a rectangle PQRS

and a square PKLM. (UPSR 2005)

P

3 cm

M

K

L

S12 cm

7 cm

Q

R

Calculate the area, in cm2,

of the shaded region.

Area: Length x Breadth


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Area: Length x Breadth

12 cm x 7 cm = 84cm2PQRS

PKLM 3 cm x 3 cm = 9cm2

Shaded

region84cm29cm2= 75cm2

Answer: 75cm2

(UPSR 2007)


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(UPSR 2007)

Diagram 4 shows a rectangle JKLM

and a right angled triangle LKN.J

M L

K N6 cm

8 cm

JKN is straight line.The length of KN is equal tothe length of KL.

Calculate the area, in cm2, of the coloured region.

JK N6

cmJKN is straight line.


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Formula for AREA of Triangle:

1

2x Base x Heigth

1

2

x (6 cm + 8 cm) x 6 cm

14 x 6 =

2 1

3

=

42 cm2

M L8

cm

JKN is straight line.

The length of KN is equal tothe length of KL.

Calculate the area, in cm2, of the coloured region.

(UPSR 2006)


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(UPSR 2006)

Table 2 shows the number of classes

and the averagenumber of pupils inYear One and Year Two.

YearNumber of

classes

Average number of

pupils

One 4 31

Two 3 35

Find the differencebetween thenumber of pupils in Year One and Year

Two.





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g u f unNumber of unit



Year 1: 31 x 4 = 124

Year 2: 35 x 3 = 105Difference: 124 - 105 15 pupils






Table 2 shows the length of 4 ribbons


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g

bought by Karina. (UPSR 2005)

Ribbon Length

Blue 4.2 m

Green 1.25 m

Yellow 0.5 m

Red 2.25 m

Calculate the averagelength,in m, of the ribbons.

TABLE 2

Average : Total value of unitAverage : Total value of unit


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g fNumber of unit

Average:

4.2 m + 1.25 m + 0.5 m + 2.25 m4

= 8.20 m = 2.05 m

4

g fNumber of unit


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~Tiada kejayaansemanis madu tanpa

usaha sepahithempedu ~

RENUNGKAN!!!!


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RENUNGKAN!!!!

Some people watch it happened. Somepeople wonder what has happened. Somepeople makes it happened!

Perjalanan seribu langkah dimulai denganperjalanan satu langkahKegemilangan masa depan, dicorakkan

oleh tangan Anda.

Fikir kejayaan, usaha ke arah kejayaan.Ambil keputusan untuk menjadi orangberjaya hari ini juga!

STANDING IN THE EYES OF THE WORLD


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Pahit getir hidup, dan pengorbanan

Terpaksa dihadapi, demi kejayaan

Terdidik sejak mula,tabah berusaha

Tanpa cuba melangkah,

tak kemana, Di mana kau berada

Pencapaian tak tiba dengan mudah

( korus )

Kini

"Standing In The Eyes Of The World"

Hanyalah selangkah dari nyata

Keazaman membara dijiwa

Menanti saat bebas merdekaTiba masa kau melangkah gagah

Bersemangat ke arah matlamat sedaya

upaya, Engkau terunggul

Wajar

"Standing In The Eyes Of The World"

Harapan yang pernahterkulai layu

Kembali segar mekar bawah

bayanganmu

Setiap manusia ingin berjaya

Namun tak semua miliki tuahEngkau menghampirinya

Kesempatan telah pun tiba...

Salin soalan :JELAS & TEPAT


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Salin soalan :JELAS & TEPAT

5900 + 7891405 =

5900789+

6689

66891405-

UPSR 2006

798

6698

6698

52935284

Jawapan :JELAS & TEPAT


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Jawapan :JELAS & TEPAT

5900 + 7891405 =

5900789+

6689

66981405-

5293

UPSR 2006

bengkel teknik menjawab soalan upsr 2008 zon sibuti

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