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PAPER 1 ( FORM 5 )

CHAPTER 2 : LINEAR LAW

Prepared by : Syadiyah Kamis (SMK Batu Sepuluh)

1. The variables š‘„ and š‘¦ are related by the equation =2

3š‘š‘„ , where p is a constant.

When š‘™š‘œš‘”2 š‘¦ against š‘„ is plotted , a straight line graph with gradient of 4 and

the š‘™š‘œš‘”2 š‘¦ ā€“ intercept of š‘š is obtained.

Pembolehubah š‘„ š‘‘š‘Žš‘› š‘¦ dihubungkan oleh persamaan š‘¦ =2

3š‘š‘„ , dengan keadaan p ialah

pemalar. Apabila š‘™š‘œš‘”2 š‘¦ š‘šš‘’š‘™š‘Žš‘¤š‘Žš‘› š‘„ š‘‘š‘–š‘š‘™š‘œš‘”š‘˜š‘Žš‘›, š‘ š‘Žš‘”š‘¢ š‘”š‘Ÿš‘Žš‘“ š‘”š‘Žš‘Ÿš‘–š‘  š‘™š‘¢š‘Ÿš‘¢š‘  š‘‘š‘’š‘›š‘”š‘Žš‘›

š‘˜š‘’š‘š‘’š‘Ÿš‘¢š‘›š‘Žš‘› 4 š‘‘š‘Žš‘› š‘š‘–š‘›š‘”š‘Žš‘ š‘Žš‘› āˆ’ š‘™š‘œš‘”2 š‘¦ š‘–š‘Žš‘™š‘Žā„Ž š‘š diperoleh.

a) Find the value of p.

Cari nilai p.

b) Express m in terms of the logarithm to base 2.

Ungkapkan m dalam sebutan logaritma kepada asas 2. [4M]

2. Given š‘™š‘œš‘”10 š‘¦ = 3 āˆ’ 2 š‘™š‘œš‘”10 š‘„ and š‘¦ = š‘š‘„š‘˜ . Find the values of š‘ and š‘˜.

Diberi š‘™š‘œš‘”10 š‘¦ = 3 āˆ’ 2 š‘™š‘œš‘”10 š‘„ š‘‘š‘Žš‘› š‘¦ = š‘š‘„š‘˜. Cari nilai bagi š‘ š‘‘š‘Žš‘› š‘˜.

[3M]

3. The variables š‘„ š‘Žš‘›š‘‘ š‘¦ are related by the equation 1

š‘¦= š‘„2 + š‘› , where š‘› is a

constant. Diagram 1 shows a straight line graph obtained by plotting

1

š‘¦ against š‘„2.

Pembolehubah š‘„ š‘‘š‘Žš‘› š‘¦ dihubungkan oleh persamaan 1

š‘¦= š‘„2 + š‘› , dengan

keadaan š‘› ialah pemalar. Rajah di bawah menunjukkan graf garis lurus yang

diperoleh dengan memplot 1

š‘¦ against š‘„2.

[3M]

9(( 5,8 )

9((1,4 )

1

š‘¦

š‘„2 0

Diagram 1

4. Diagram 2 shows the graph of y 10 log against x .

Rajah di bawah menunjukkan graf y 10 log lawan x.

The variables x and y are related by the equation = 103š‘„āˆ’2 .

Find the value of h and of k.

Pembolehubah x dan y dihubungkait dengan persamaan š‘¦ = 103š‘„āˆ’2 .

Cari nilai h dan k.

[3M]

h = 4

3

k = āˆ’2

Diagram 2

9(( 0 , k )

9(( h , 2 ) š‘™š‘œš‘”10 š‘¦

š‘„ 0

5. The variables š‘„ š‘Žš‘›š‘‘ š‘¦ are related by the equation š‘¦ = š‘Žš‘š‘„ , where š‘Ž and š‘ are

constant. A straight line graph is obtained by plotting š‘™š‘œš‘”10 y against š‘„ , as shown

in Diagram 3. Find the values of š‘Ž and š‘.

Pembolehubah š‘„ š‘Žš‘›š‘‘ š‘¦ dihubungkan oleh persamaan š‘¦ = š‘Žš‘š‘„ , dengan keadaan

š‘Ž š‘‘š‘Žš‘› š‘ ialah pemalar. Satu graf garis lurus diperoleh dengan memplotkan š‘™š‘œš‘”10 y

melawan š‘„ , seperti ditunjukkan dalam Rajah 3. Cari nilai bagi š‘Ž š‘‘š‘Žš‘› š‘.

[3M]

Diagram 3

9(( 2 , 1.2 )

9(5

š‘™š‘œš‘”10 š‘¦

š‘„ 0

6. The variables š‘„ and š‘¦ are related by the equation š‘¦ = š‘š‘„2 + š‘žš‘„ , where š‘ and š‘ž are

constants. A straight line is obtained by plotting š‘¦

š‘„ against š‘„. If the points

(1 , 9) and (5 , 29) lies on the straight line, find the values of š‘ and š‘ž.

Pembolehubah š‘„ š‘‘š‘Žš‘› š‘¦ dihubungkan oleh persamaan š‘¦ = š‘š‘„2 + š‘žš‘„ , dengan

keadaan š‘ š‘‘š‘Žš‘› š‘ž ialah pemalar. Satu graf garis lurus diperoleh dengan memplot

š‘¦

š‘„ melawan š‘„. Jika titik (1 , 9) š‘‘š‘Žš‘› (5 , 29) terletak di atas garis lurus itu,

cari nilai š‘ š‘Žš‘›š‘‘ š‘ž.

[4M]

7. The non ā€“ linear equation š‘¦ = š‘Žš‘„2 + š‘š‘„ can be reduced to the linear form and the

graph is plotted as shown in Diagram 4.

Find the values of š‘Ž and š‘.

Persamaan tak linear š‘¦ = š‘Žš‘„2 + š‘š‘„ boleh dijadikan bentuk linear dan grafnya

boleh diplotkan seperti yang ditunjukkan pada Rajah 4.

Cari nilai š‘Ž š‘‘š‘Žš‘› š‘.

[4M]

Diagram 4

9(( 1 , 8 )

š’€

š‘æ 0

9(( āˆ’2 , 1)

8. A student wants to reduce a non ā€“ linear relation š‘¦ = š‘Žš‘š‘„+1 into a linear relation by taking

logarithm to the base 10 and plotting a linear graph.

a) If the vertical axis of the graph represents š‘™š‘œš‘”10 š‘¦ , state the representation of the

horizontal axis.

b) If the intercept of the vertical axis is 2 , find the value of a.

Seorang murid ingin menukarkan hubungan tak linear š‘¦ = š‘Žš‘š‘„+1 kepada hubungan

linear dengan mengambil logaritma asas 10 dan memplotkan satu graf linear.

a) Jika paksi mencancang graf itu mewakili š‘™š‘œš‘”10 š‘¦ , nyatakan perwakilan paksi

mengufuknya.

b) Jika pintasan pada paksi mencancang ialah 2, cari nilai š‘Ž.

[3M]

9.

Diagram 5 shows the graph of straight line obtained by plotting š‘¦

š‘„2 against š‘„.

Find

a) š‘¦ in terms of š‘„.

b) value of š‘¦ when š‘„ = 1 .

Rajah 5 menunjukkan graf garis lurus yang diperolehi dengan memplotkan š‘¦

š‘„2 melawan š‘„.

Cari

a) š‘¦ dalam sebutan š‘„.

b) Nilai bagi š‘¦ š‘Žš‘š‘Žš‘š‘–š‘™š‘Ž š‘„ = 1 .

[3M]

Diagram 5

9(6

9(10

š‘¦

š‘„2

š‘„ 0

10.

The variables š‘„ š‘Žš‘›š‘‘ š‘¦ are related by the equation š‘¦ = 3š‘„(5 āˆ’ š‘„).

A straight line graph is obtained by plotting š‘¦

š‘„ against š‘„ , as shown in Diagram 6.

Find the value of š‘Ž and š‘.

Pembolehubah š‘„ š‘‘š‘Žš‘› š‘¦ yang dihubungkan oleh persamaan š‘¦ = 3š‘„(5 āˆ’ š‘„).

Graf garis lurus diperoleh dengan memplotkan š‘¦

š‘„ melawan , seperti yang ditunjukkan

dalam Rajah 6.

Cari nilai bagi š‘Ž š‘‘š‘Žš‘› š‘.

[3M]

Diagram 6

9(( 2 , b )

9((š‘Ž , 0)

š‘¦

š‘„

š‘„ 0

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