15 kelantan skema
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FizikKertas 1PeperiksaanPercubaanNegeri Kelantan 2015
SkemaPemarkahan
1 B 26 C2 A 27 C3 B 28 B4 D 29 A5 B 30 A6 C 31 D7 B 32 D8 B 33 D9 B 34 B
10 D 35 A11 B 36 B
12 B 37 B13 A 38 A14 B 39 A15 D 40 D16 C 41 B17 C 42 D18 A 43 C19 A 44 A20 C 45 D21 B 46 A22 B 47 B
23 A 48 C24 B 49 A25 B 50 A
[ 50 marks ]
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MARKING SCHEME PEPERIKSAAN PERCUBAAN KERTAS 2 2015
NOSOALAN SCHEME SUB
TOTAL TOTAL
SECTION A1(a) Tick inside the box
Can be measured 1 1
(b) (i) 0.2 V 1
2
(ii)
1
(c) 3.6 – 0.2 // 3.4 V 1 1
TOTAL 4 M2(a) A push / pull / something that change shape/
speed/direction/size of the object1 1
(b) (i)
12
(ii) Fx = F cos 1
(c) (i) Decreases 12(ii) There is a frictional force // Net force decreases 1
TOTAL 5 M3 (a)(i) Fission reaction 1
2(ii) 2 1
(b) (i) M1 2.9 X 10 - = m (3X10 )
M2 m = 3.22 X 10 -28 kg (answer and correct unit)
1
12
X
Fx
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(ii)P = 3-
-11
1.5X10
10X2.9
= 1.93 X 10 -8 W (Answer and correct unit)
1
12
TOTAL 6 M4 (a) Specific latent heat of vaporisation 1 1
(b) (i) Tick inside the boxunchanged
12
(ii) To form the bonding between the molecules 1
(c) M1 : State correct equationQ3 + Q 4 = mcθ + mL f M2 : Subtitution
= 0.1(4200)(100 – 0) + 0.1(3.36 x 10 5)M3 : Answer with correct unit
= 75 600 J
1
1
1
3
(d)
1 1
TOTAL 7 M5 (a) A point at principal axis where all the parallel light are
focus/converged after reflected by the mirror 1
1
(b) (i) Object distance in diagram 5.1 < diagram 5.2 1
4
(ii) Image distance in diagram 5.1 > diagram 5.2 1
(iii) The object distance decreases, the image distance increases//vice versa// inversely proportional
1
(iv) Reflection 1
(c)
3 3
TOTAL 8 M6 (a) Wave produced when the direction of vibration of particle is 1 1
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is perpendicular to the direction of propagation of a wave
(b) (i) Depth in region A is more than region B // vice-versa 1
3(ii) The wave length in region A is more than region B // vice-versa
1
(iii) When depth increases, wavelength increases // vice-versa 1
(c) (i) Speed 1
3(ii) M1 As depth decreases, speed decreases
M2 Depth decreases, wave length decreases // v = f λ
1
1
(d) increases 1 1
TOTAL 8 M7 (a) Rate of change of displacement / displacement per time 1 1
(b) (i) K 1
3(ii) Gradient is the biggest 1(iii) Able reduce air friction // Produce more net force 1
(c) (i) M1 Run with increasing speed / run faster
M2 To increase kinetic energy / momentum
1
1
6
(ii) M1 Lighter / low density / low mass pole // Strong pole //High flexibility
M2 Easy to carry / Light // Not easy to break // easy to
bend
1
1
(iii) M1 Thick and soft mattress // land on his back
M2 increases time of impact / reduce impulsive force //toreduce pressure
1
1
TOTAL 10 M8 (a) (i) A region in which there is an electric force // a region
around a charged object experiences electric force1 1
(ii) Oscillating 1 1(b) (i)
1 1
(ii) M1 The heat of burning candle produces positive and 12
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negative ions.
M2 The positive ions which are heavier is pulled towardsnegative plate with a larger proportion flame
1
(c) (i) Shape : CoilReason : high resistance / can produce more heat / increasesurface area
11
(ii) Resistivity: highReason: high resistance /can produce more heat
11
(iii) Melting point: highReason: not easily melt/ can withstand high temperature
11
(d) L 1
TOTAL 12 M
SECTION B9 (a) When an object is partially or fully immersed in a fluid the buoyant force is equal to the weight of fluid displaced.
1 1
(b) (i) Weight of water displaced is equal
Density of sea water is more than river water // vice-versa
Volume of water displaced in sea water is less than in riverwater // vice versa
1
1
1
3
(b)(ii) (a) Density increases volume of water displaced decreases //density is inversely proportional to volume of waterdisplaced
1
2
(ii)(b) Weight of water displaced = buoyant force 1
(c) M1.Density of air decreases as altitude increases
M2.Bouyant force become smaller
M3.At certain height, weight of displaced air equal toweight of the balloon.
M4.Net force zero / forces in equilibrium
1
1
1
1
4
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(d) Aspect Explanation
Material used for thehydrometer: glass
Non corrosive
Length of the stem:long
Bigger range of density ofliquid can be measured
Size of the bulb: big Bigger buoyant force/More volume of liquiddisplaced
Diameter of the stem ;small
More sensitive
Material used at the base ofthe bulb: lead shots // sand
More stable / not tilted /stand upright
1 , 1
1 , 1
1 ,1
1 , 1
1 , 1
10
TOTAL 20 M10. (a) Induced current
Arus Aruhan1 1
(b) 1. Height of magnet in diagram 10.1 is higher Ketinggian magnet dalam Rajah 10.1 lebih tinggi
2. No of turns is the same Bilangan lilitan sama
3. Deflection of Galvanometer in Diagram 10.1 is greaterPesongan Galvanometer dalam Rajah 10.1 lebih besar
4. The more the height of magnet the more the deflectionSemakin bertambah ketinggian magnet semakin besar
pesongan Galvanometer
5. The higher the speed of the magnet the more themagnitude of the current produced.Semakin bertambah laju magnet semakin bertambahmagnitud arus yang terhasil.
1
1
1
1
1
5
(c) (i) 1. There is a cutting of flux// change of fluxTerdapat pemotongan fluks // perubahan fluks
2. Produced induced e.m.f // induced current
Terhasil emf aruhan // arus aruhan
1
12
(ii) 1. Using Fleming’s Right hand rule Guna Peraturan Tangan Kanan Fleming
2. Force is downwards , Magnetic Field from North toSouth,
so the direction of curent from Q to P.
1
12
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Daya ke bawah, medan magnet dari Utara ke Selatan, jadiarah arus dari Q ke P.
(d) Aspect Aspek
ReasoningSebab
copper wire Dawai kuprum good conductor//resistance is very low Pengalir yang baik// rintanganrendah
thicker wire Dawai Tebal
reduce the resistance Kurangkan rintangan
Use a laminated coreTeras berlapis
avoid the Eddy current Elak Arus pusar
Use soft iron coreGuna Teras Besi
Lembut
can be magnetized and demagnetizedeasily/avoid hysteresis .
Boleh di magnetkan dandinyahmagnetkan dengan mudah /elakkan histeris
Winding the secondarycoil on top of the
primary coil Lilitkan gelung sekunder di atas gelung primer
reduce the leakage of magnetic flux Mengurangkan kebocoran fluks.
1 , 1
1, 11, 1
1, 1
1, 1
10
TOTAL 20 M
SECTION C11 (a)
Reciprocal of focal length // Salingan panjang fokus
1 1
(b) 1. The convex lens is aimed/focused to a distant object Kanta cembung di fokuskan kepada objek jauh
2. The screen is adjusted until a sharp image is formed onthe screenSkrin dilaraskan sehingga imej tajam terbentukdiatasnya
3. The distance between the screen and the lens is measured Jarak antara skrin dan kanta diukur
4. Focal length, f = distance between the screen and thelens
Panjang fokus , f = jarak antara skrin dengan kanta
5. Power of lens / kuasa kanta =
1
1
1
1
1
4 (max)
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(c)
Aspect ExplanationLonger focallength // fo > fe
Panjang fokus yang panjang
To produce real, inverted and smallerimage
Hasilkan imej nyata, songsangdan lebih kecil
Highmagnification //>1
Pembesarantinggi
Produce bigger image Hasilkan imej lebih besar
Distance = fo + fe Produce sharp image at normaladjustment // image at infinity
Hasilkan imej tajam pada pelarasannormal
Bigger diameter Diameter lebih
besar
More light can enter objectivelens // more brighter
Lebih banyak cahaya dapat masuk//lebih cerah
P is chosenP dipilih
Longer focal length, highermagnification, Distance betweentwo lenses = fo + fe and
bigger diameter Panjang fokus yang panjang, Pembesaratinggi, jarak antara kanta = fo + fe dandiameter lebih besar
1, 1
1, 1
1, 1
1, 1
1, 1
10
(d) (i) Power = 1 =1 = 10Df 0.1
1
5
(ii) = +
1 = 1 – 1v 10 20v =20 cm
1
1
(iii) m = =
= 3
1
1
TOTAL 20 M12 (a) Semiconductor where hole acts as the majority carrier
Semikonduktor di mana lohong bertindak sebagai pembawacas majoriti
1 1
(b) 1. Pentavalent atoms are doped into pure semiconductor Atom pentavalen didopkan kedalam semikonduktor tulin
2. The structure has free electron more than hole
1
1
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Struktur mempunyai bilangan elektron lebih dari lohong
3. As temperature increases electron will escape as freeelectron leaving an empty space known as hole
Apabila suhu bertambah elektron akan terbebas sebagaielektron bebas meninggalkan satu tempat kosong yang
dinamakan lohong.4. As more electrons escape more free electron will be
produce more than hole // electrons are the majoritycarriers
Bila lebih banyak elektron terlepas, lebih banyak elektronbebas terhasil melebihi lohong.// elektron adalah
pembawa cas majoriti
1
1
4
(c) Aspect Explanation4 diode // more number of
diodes4 diod // lebih diod
Full wave rectification
produced Hasilkan rektifikasi gelombang penuh
Two pairs of diodes parallel to each other2 pasang diod selariantara satu sama lain
Produce forward biasconnection
Hasilkan sambungan Pincang ke depan
Smoothed waveGelombang licin
Same as pure d.c waveSama dengan gelombang a.ttulen
Capacitorkapasitor
To smoothen the output waveUntuk melicinkan gelombangoutput
R is chosen R dipilih
4 diode // more number ofdiodes, Two pairs of diodes
parallel to each other,Smoothed wave , Capacitor
1, 1
1, 1
1, 1
1, 1
1, 1
10
(d) (i) V = 1.5 volt 1
5
(ii) T = 0.1 x 2= 0.2 s
11
(iii) f =
= = 5 Hz
1
1
TOTAL 20 M
END OF MARKING SCHEME.
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PEP PERCUBAAN FIZIK Paper 3 2015
NO MARKING SCHEME SUBMARK
TOTALMARK
1(a)(i) Mass of water / jisim air/m/ 1 1(a)(ii) Increase in the temperature/ /kenaikan suhu// 1
1 1
(a)(iii) Density of water/ ketumpatan air 1 1(b)(i) 25 o 1 1(b)(ii) 8.0,4.4,3.1,2.4,1.9 …..at least 4 reading are correct 1 1(b)(iii) 62,45,39,36,34 …..at least 4 reading are correct 1 1(b)(iv) 37,20,14,11,9 (terima ecf)/ at least 4 reading are correct 1 1
(c) m,kg 1,1
kg m
,oC ,oC
0.125 8.0 62 370.225 4.4 45 200.325 3.1 39 140.425 2.4 36 110.525 1.9 34 9
Symbol dan unit are correctConsistent of value
11
2
(d) / Both axes (symbol and unit) 6 ticks ….. 5 marks/Both correct scale 5 ticks….. 4 marks /At least 4 point are plotted correctly 4 ticks… 3 marks /Straight line 3 ticks …. 2 maks /Line starting origin ≤2 ticks …..1 mark /Best fit
5 5
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(e) Directly proportional 1 1
2(a) (i) f is directly proportional to
f berkadar langsung dengan
1 1
(ii) show on the graph
= 0.9
x = 1.11 m
1
1
1
3
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(a) (iii) - Draw a sufficiently large triangle minimum (8 x 8) cm
- Correct substitution (Follow candidate’s triangle)
m =
= 633.33
- Correct answer and no unit
1
1
1
3
(b) -Correct substitution
v = m
= 633.33 ( )
-Correct answer with correct unit
v = 126.7 ms-1
1
1
2
(c)(i) - The gradient (m) decrease 1 1
(c)(ii) m = , when a increase, m decrease
(d) -State one precaution correctly.1. Position of eyes are perpendicular to the scale of metre
rule toavoid parallax error
2. Repeat the experiment three times and calculate the
average. 3. Experiment is carried out in the field to avoid reflectionof sound.
1 1
JUMLAH 12
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NO MARKING SCHEME SUBMARK
TOTALMARK
3 (a) Apparent depth depends on density of liquid 1 1(b) When density of liquid increases, the apparent depth
decreases1 1
(c) To investigate the relationship between the density of liquid
and apparent depth
1
Manipulated variable : density of liquid // mass of salt 1Responding variable : apparent depthFixed variable : actual depth 1Tall beaker, pin, water, measuring cylinder, salt, triple beambalance, metre rule, retort stand
1
1
Mass of salt,m = 20 g is measured and mixed with volume ofwater, V =100 cm 3. The density of liquid, 1
The mixture is poured into a tall beaker and actual depth ofliquid, D = 20.0 cm is measured. 1
A pin is placed at the base of the beaker as object O.
The pin O is observed vertically above the surface of the liquid.
The position of pin I is adjusted until parallax error betweenthe pin O and the pin I is non- existent.
The position of pin I, the apparent depth, d is measured.
1
The experiment is repeated by using mass of salt, m = 30 g, 40g, 50 g dan 60 g.
1
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Mass of salt,m/g
Density,
/gcm -3
Apparentdepth, d/cm
2030405060
1
Apparent depth, d vs density, graph is plotted
d
1
10
JUMLAH 124 (a) Inference: The strength of electromagnet depends on the magnitude
of current flow1 1
(b) Hypothesis: As the magnitude of current increases the strength ofelectromagnet increases.
1 1
(c) (i) Aim: To investigate the relationship between the magnitude ofcurrent and the number of paper clips attracted
1 1
(ii) Variables:Manipulated: Magnitude of currentResponding: Number of paper clips attractedConstant: Number of turn of solenoid
1
1
2
(iii) Apparatus and material:Power supply, Petri dish, retort stand, paper clips, insulated copperwire, soft iron core, connecting wires.
1 1
(iv) Arrangement of apparatus: 1 1
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(v) Procedure:- Wound 20 turns of wire around a soft iron core.- Switch on the switch and the rheostat is adjusted to 0.2 A.- Moved the Petri dish containing paper clips to the end of the soft
iron core.- Calculate the number of paper clips attracted to the iron core.- Repeat the experiment 4 more times using current 0.4A, 0.6 A, 0.8
A and 1.0 A.
1
1
1
3
(vi)
Electric current,I(A) No. of paper clip attracted0.20.40.60.81.0 1
1
(v)
1
1
JUMLAH 12